A vending machine company wants to check three of its machines to determine if they are properly dispensing 12 ounces of coffee. Their data is given below α = 0.01.
Row Machine A Machine B Machine C
1 11.5 10.3 11.1
2 12.1 9.7 11.3
3 11.6 10.4 11.9
4 12.0 10.7 11.5
5 11.1 9.9 11.7
6 12.2 10.1 11.3
H0: μA = μB = μC
Ha: Not all means are equal
One-way ANOVA: Machine A, Machine B, Machine C
Source DF SS MS F P
Factor 2 8.363 4.182 31.73 0.000
Error 15 1.977 0.132
Total 17 10.340
P-value: _____
Decision: _____
Is there a significant difference between the vending machines A, B, and C? Use α=0.05.
A. No, there is no significant difference between the means.
B. Yes, there is a significant difference between the means.
C. The F-test cannot be used to answer whether or not there is a significant difference between the means.

Work Shown:

A = P*(1+r)^t

A = 21450*(1+(-0.08))^5

A = 21450*(1-0.08)^5

A = 21450*(0.92)^5

A = 21450*0.6590815232

A = 14137.29867264

A = 14,137.30

Notice how I used a negative r value to indicate depreciation rather than growth.

Answer: -10

Step-by-step explanation: All you have to do is plug the values into the equation. -4+2(-3). Then you solve the equation using PEDMAS.

1. -4+2(-3)

2. -4+(-6)

3.-4-6

4.-10

Answer:

8

Step-by-step explanation:

-b + 2y

if

b = 4

and

y = 3

then:

-b + 2y = -4 + 2*6 = -4 + 12

= 8

4 zeroes basically means [tex]10^4[/tex]

$80=2^3\cdot 10$ and $70=7\cdot10$

there will be $10^2$ when you take the product not $10^4$

hence it will have 2 zeroes not 4

Answer:

The Width = 65.44 inches

The Height = 36.81 inches

Step-by-step explanation:

We are told in the question that:

The width and height of an newer 75-inch television whose screen has an aspect ratio of 16:9

Using Pythagoras Theorem we known that:

Width² + Height² = Diagonal²

Since we known that the size of a television is the length of the diagonal of its screen in inches.

Hence, for this new TV

Width² + Height² = 75²

We are given ratio: 16:9 as aspect ratio

Width = 16x

Height = 9x

(16x)² +(9x)² = 75²

= 256x² + 81x² = 75²

337x² = 5625

x² = 5625/337

x² = 16.691394659

x = √16.691394659

x = 4.0855103303

Approximately x = 4.09

For the newer 75 inch tv set

The Height = 9x

= 9 × 4.09

= 36.81 inches

The Width = 16x

= 16 × 4.09

= 65.44 inches.

Answer:

Step-by-step explanation:

Given that:

p = 0.61

If X is the the number of students in a randomly selected group  of a sample size n = 50

The expected value and the standard deviation can be computed as follows:

The expected value E(X) = np

The expected value E(X) =  50 × 0.61

The expected value E(X) = 30.5

The required standard deviation = [tex]\sqrt{np(1-p)}[/tex]

The required standard deviation = [tex]\sqrt{30.5(1-0.61)}[/tex]

The required standard deviation = [tex]\sqrt{30.5(0.39)}[/tex]

The required standard deviation = [tex]\sqrt{11.895}[/tex]

The required standard deviation = 3.4489

The required standard deviation =  3.45

(b) Fill in the missing quantity. (Round your answer to the nearest whole number.)

There is an approximately 2.5% chance that _____ or more teenagers in the group will shop at the mall during the next week.

From the given information:

Now, we can deduce that:

the mean = 30.5

standard deviation = 3.45

Using the empirical rule:

At 95% confidence interval;

[μ - 2σ,  μ + 2σ] = [ 30.5 - 2(3.45) , 30.5 + 2(3.45)]

[μ - 2σ,  μ + 2σ] =  [ 30.5 - 6.9 , 30.5 + 6.9]

[μ - 2σ,  μ + 2σ] = [ 23.6, 37.4]

The 2.5% of the observations are less than 95% confidence interval and 2.5% observations are greater than 95% confidence interval.

The required number of teenagers is = the upper limit of the 95% confidence interval = 37

There is an approximately 2.5% chance that __37___ or more teenagers in the group will shop at the mall during the next week.

Answer:

Step-by-step explanation:

Hello, we can write

(1) p(x)=(x-a)q(x)+r

[tex]\boxed{\sf v}[/tex] True

It means that p(a)=0 * q(a) + r = r

so the first one is true.

[tex]\boxed{}[/tex] False

The second one is not to be proven true from the remainder theorem.

[tex]\boxed{\sf v}[/tex] True

For x different from a we can divide the equation (1) by (x-a).

[tex]\boxed{}[/tex] False

We cannot say anything on q(a).

[tex]\boxed{\sf v}[/tex] True

If the rest is 0 then it means that p(a) = 0

[tex]\boxed{\sf v}[/tex] True

If p(a) = 0 it means that the rest r = 0 and then p(x)=q(x)(x-a)

Thank you

The probability that the average price is between $153 and $155 is 0.04.

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

The average price of a math textbook =$158

The standard deviation =$26

The mean= 158

n =number of textbooks randomly chosen which is 40

n=10

Then

σ = 26

σₓ = σₓ/√n

= 26/√40

Therefore. σₓ² = 16.90

For the group of 48, find the probability that the average price is between $153 and $155.

The probability that the average price is between $153 and $155

= 0.04

Learn more about probability here;

https://brainly.com/question/11234923

#SPJ1

Step-by-step explanation:

[tex]Area = \: \frac{bh}{2} \\ : b = 16.9 \: h = 10.4 \\ [/tex]

[tex]Area = \frac{16.9 \times 10.4}{2} = \frac{175.76}{2} = 87.88 {ft}^{2} [/tex]

Base = 16.9

height = 10.4

Area = ½b×h

A = ½(16.9×10.4)

A = ½(175.76)

Area = 175.76/2

A = 87.88ft²

Answer:

[tex]\Large \boxed{\mathrm{87.88 \ ft^2 }}[/tex]

Step-by-step explanation:

[tex]\displaystyle area \ of \ triangle \ = \ \frac{base \times height }{2}[/tex]

[tex]\displaystyle area \ of \ triangle \ = \ \frac{16.9 \times 10.4 }{2}[/tex]

[tex]\displaystyle area \ of \ triangle \ = \ \frac{175.76}{2}[/tex]

[tex]\displaystyle area \ of \ triangle \ = \ 87.88[/tex]

Answer:

third option

Step-by-step explanation:

Given f(x) then f(x) + c represents a vertical translation of f(x)

• If c > 0 then shift up by c units

• If c < 0 then shift down by c units

Given

g(x) = [tex]3^{x}[/tex] + 5 ← this represents a shift up of 5 units

Thus g(x) is the graph of f(x) translated up by 5 units

Answer:

[tex]\boxed{\sf{Option \: 3}}[/tex]

Step-by-step explanation:

g(x) is translated up 5 units compared to f(x). In a vertical translation, when the graph is moved 5 units up, 5 is added to the function. When the graph is moved 5 units down, 5 is subtracted from the function. The graphs are shifted  in the direction of the y-axis.

Answer:

see below

Step-by-step explanation:

7g can be "split" as 7 * g. The "*" means multiplication so a verbal form of this expression could be "7 times a number g" or "The product of 7 and a number g".

Answer:

x <-3

Step-by-step explanation:

15 <-5x

divide both sides by 5 but since the coefficient of x is negative after dividing the sign changes.

x <-3

Answer:

x < −3

I hope this helps!

Responder:

Juanita = 11, madre = 33

Explicación paso a paso:

Dado lo siguiente:

Suma de sus edades = 44

En 11 años, Juanita tendrá la mitad de la edad de su madre

Sea la edad de la madre = my la edad de juanita = j

m + j = 44 - - - - (1)

(j + 11) = 1/2 (m + 11)

j + 11 = 1/2 m + 5,5; j - 1/2 m = - 5,5; 2j - m = - 11

2j - m = - 11 - - - - (2)

Desde (1): m = 44 - j

Sustituyendo m = 44- j en (2)

2j - (44 - j) = - 11

2j - 44 + j = - 11

3j = - 11 + 44

3j = 33

j = 11

De 1)

m + j = 44

m + 11 = 44

m = 44 - 11

m = 33

Answer:

the work done by the force field = 24 π

Step-by-step explanation:

From the information given:

r(t) = 3 cos (t)i + 3 sin (t) j + 2 tk

= xi + yj + zk

∴

x = 3 cos (t)

y =  3 sin (t)

z = 2t

dr = (-3 sin (t)i + 3 cos (t) j + 2 k ) dt

Also F(x,y,z) = 6xi + 6yj + 6k

∴  F(t) = 18 cos (t) i + 18 sin (t) j +6 k

Workdone = 0 to 2π ∫ F(t) dr

[tex]\mathbf{= \int \limits ^{2 \pi} _{0} (18 cos (t) i + 18 sin (t) j +6k)(-3 sin (t)i+3cos (t) j +2k)\ dt}[/tex]

[tex]\mathbf{= \int \limits ^{2 \pi} _{0} (-54 \ cos (t).sin(t) + 54 \ sin (t).cos (t) + 12 ) \ dt}[/tex]

[tex]\mathbf{= \int \limits ^{2 \pi} _{0} 12 \ dt}[/tex]

[tex]\mathbf{= 12 \times 2 \pi}[/tex]

= 24 π

Answer:

No solution

Step-by-step explanation:

Given equation is,

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0[/tex]

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}[/tex]

[tex]\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]  if x ≠ ±1

[tex](\frac{2}{1-x})^2=\frac{4+x}{1-x}[/tex]  [Squaring on both the sides of the equation]

[tex]\frac{4}{(1-x)}=(4+x)[/tex]

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

Answer:

Could you please help me Genius??????

Answer:

25  Answer A

Step-by-step explanation:

Use similar triangles, and the proportion derived from the quotient of a leg to the hypotenuse:

[tex]\frac{15}{9} =\frac{x}{15} \\x=\frac{15^2}{9} \\x=25[/tex]

Answer:

-12

Step-by-step explanation:

-7+(-5)=

-7-5=

-12

Answer:  1) $300     2) $624

Step-by-step explanation:

[tex]\begin{array}{l||l|l}\underline{\quad \text{Item}\qquad \qquad \qquad \qquad}&\underline{\text{Income} }&\underline{\text{Expense}}\\\text{Net Pay}&5000&\\\text{Interest on Deposits}&0&\\\text{Income from Investments}&225&\\\text{Rent}&&3000\\\text{Utilities}&&250\\\text{Satellite Dish}&&175\\\text{Cell Phone Plan}&&135\\\text{Car Payment}&&385\\\text{Groceries}&&200\\\text{Insurance}&&380\\\underline{\text{Recreation}\qquad \qquad \qquad}&\underline{\qquad \quad }&\underline{400\qquad}\\\end{array}[/tex]

TOTALS                              5225      4925

Net Cash Flow = Income - Expenses

                        = 5225 - 4925

                        = 300

*************************************************************************************

[tex]\dfrac{25\ hours}{week}\times \dfrac{\$8}{hour}\times 4\ weeks\times 78\%\\\\\\=25\times \$8 \times 0.78\\\\= \$624[/tex]

Answer:

A.

Step-by-step explanation:

So we are given the function:

[tex]f(x)=7x+8[/tex]

To find the inverse of the function, we simply need to flip f(x) and x and then solve for f(x). Thus:

[tex]x=7f^{-1}(x)+8\\x-8=7f^{-1}(x)\\f^{-1}(x)=\frac{x-8}{7}[/tex]

So the answer is A.

Answer:

[tex]\large \boxed{\mathrm{Option \ A}}[/tex]

Step-by-step explanation:

f(x) = 7x+8

Write f(x) as y.

y = 7x + 8

Switch variables.

x = 7y + 8

Solve for y to find the inverse.

x - 8 = 7y

[tex]\frac{x-8}{7}[/tex] = y

Answer:

[tex]\boxed{\sf C. \ x\geq -4}[/tex]

Step-by-step explanation:

[tex]-8x+4\leq 36[/tex]

[tex]\sf Subtract \ 4 \ from \ both \ sides.[/tex]

[tex]-8x+4-4 \leq 36-4[/tex]

[tex]-8x\leq 32[/tex]

[tex]\sf Divide \ both \ sides \ by \ -8.[/tex]

[tex]\frac{-8x}{-8} \leq \frac{32}{-8}[/tex]

[tex]x\geq -4[/tex]

Answer:

I canot answer this

Step-by-step explanation:

Answer:

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Step-by-step explanation:

Given that:

A baseball player has a batting average (probability of getting on base per time at bat) of 0.215

i.e

let x to be the random variable,

consider [tex]x_1 = \left \{ {{1} \atop {0}} \right.[/tex]  to be if the baseball player has a batting average or otherwise.

Then

p(x₁ = 1) = 0.125

What is the probability that they will get on base more than 6 of the next 15 at bats

So

[tex]\mathtt{x_i \sim Binomial (n,p)}[/tex]

where; n =  15 and p = 0.125

P(x>6) = P(x ≥ 7)

[tex]P(x>6) = \sum \limits ^{15}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=7} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 - \sum \limits ^{6}_{x=0} ( ^{15 }_x ) \ (0.215)^x \ (1 - 0.215)^{15-x}[/tex]

[tex]P(x>6) = 1 -0.9735[/tex]

[tex]\mathbf{P(x>6) = 0.0265}[/tex]

Answer:

No solution

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write out systems of equations

-x + 3y = 3

x - 3y = 3

Step 2: Rewrite equations into slope-intercept form

3y = 3 + x

y = 1 + x/3

-3y = 3 - x

y = -1 + x/3

Step 3: Rewrite systems of equations

y = x/3 + 1

y = x/3 - 1

Since we have the same slope for both equations but different y-intercepts, we know that both lines are parallel. If that is the case, they will never touch or intersect each other. Therefore, we have no solution.

Answer:

The answer is 4 + 4 + 4 - 4 = 8

Step-by-step explanation:

The four fours problem is one of the problems given in the book "The Man Who Calculated" by Malba Tahan, a Brazilian-born professor of mathematical sciences.

There are many complicated problems in this book made with the intention of using logic to find a value.

The 4 fours problem is based on using these numbers and using any operation to result in the numbers 1 through 10.

Answer:

The second quartile in the data set is $130 per night.

Step-by-step explanation:

Quartile is a type of quantile which divides the number of data set into even numbered sub groups. The second quartile is median of data set. This means that 5% of data lies within this point. The middle value between the median and highest value of data set. The second quartile in the data set must be 50% so the statement is not correct.

Answer:

-20x / (x-12) = y

Step-by-step explanation:

3/x  - 5/y  = 1/4

Multiply each side by 4xy to clear the fractions

4xy ( 3/x  - 5/y  = 1/4)

Distribute

12y - 20x = xy

Subtract 12y from each side

-20x = xy -12y

Factor out y

-20x = y(x-12)

Divide each side by (x-12)

-20x / (x-12) = y

Given that a random variable X is normally distributed with a mean of 2 and a variance of 4, find the value of x such that P(X < x)=0.99   using the cumulative standard normal distribution table

Answer:

6.642

Step-by-step explanation:

Given that mean = 2

standard deviation = 2

Let X be the random Variable

Then X [tex]\sim[/tex] N(n,[tex]\sigma[/tex])

X [tex]\sim[/tex] N(2,2)

By Central limit theorem;

[tex]z = \dfrac{X - \mu}{\sigma} \sim N(0,1)[/tex]

[tex]z = \dfrac{X - 2}{2} \sim N(0,1)[/tex]

P(X<x) = 0.09

[tex]P(Z < \dfrac{X-\mu}{\sigma })= 0.99[/tex]

[tex]P(Z < \dfrac{X-2}{2})= 0.99[/tex]

P(X < x) = 0.99

[tex]P(\dfrac{X-2}{2}< \dfrac{X-2}{2})=0.99[/tex]

[tex]P(Z< \dfrac{X-2}{2})=0.99[/tex]

[tex]\phi ( \dfrac{X-2}{2})=0.99[/tex]

[tex]( \dfrac{X-2}{2})= \phi^{-1} (0.99)[/tex]

[tex]( \dfrac{X-2}{2})= 2.321[/tex]

X -2 = 2.321 × 2

X -2 = 4.642

X = 4.642 +2

X = 6.642

Answer:

q = 0.105uC

Step-by-step explanation:

We can determine the force on one ball by assuming two balls are stationary, finding the E field at the lower right vertex and calculate q from that.

Considering the horizontal and vertical components.

First find the directions of the fields at the lower right vertex. From the lower left vertex the field will be at 0° and from the top vertex, the field will be at -60° or 300° because + charge fields point radially outward in all directions. The distances from both charges are the same since this is an equilateral triangle. The fields have the same magnitude:

E=kq/r²

Where r = 20cm

= 20/100

= 0.2m

K = 9.0×10^9

9.0×10^9 × q /0.2²

9.0×10^9/0.04

2.25×10^11 q

These are vector fields of course

Sum the horizontal components

Ecos0 + Ecos300 = E+0.5E

= 1.5E

Sum the vertical components

Esin0 + Esin300 = -E√3/2

Resultant = √3E at -30° or 330°

So the force on q at the lower right corner is q√3×E

The balls have two forces, horizontal = √3×E×q

and vertical = mg, therefore if θ is the angle the string makes with the vertical tanθ = q√3E/mg

mg×tanθ = q√3E.

..1

Then θ will be...

Since the hypotenuse = 80cm

80cm/100

= 0.8m

The distance from the centroid to the lower right vertex is 0.1/cos30 =

0.1/0.866

= 0.1155m

Hence,

0.8×sinθ = 0.1155

Sinθ = 0.1155/0.8

Sin θ = 0.144375

θ = arch sin 0.144375

θ = 8.3°

From equation 1

mg×tanθ = q√3E

g = 9.8m/s^2

m = 3.0g = 0.003kg

0.003×9.8×tan(8.3)

0.00428 = q√3E

0.00428 = q×1.7320×E

Where E=kq/r²

Where r = 0.2m

0.0428 = kq^2/r² × 1.7320

K = 9.0×10^9

0.0428/1.7320 = 9.0×10^9 × q² / 0.2²

0.02471×0.04 = 9.0×10^9 × q²

0.0009884 = 9.0×10^9 × q²

0.0009884/9.0×10^9 = q²

q² = 109822.223

q = √109822.223

q = 0.105uC

Answer:

1.86

Step-by-step explanation:

Given the following :

X : - - - - 0 - - - - 1 - - - - 2 - - - - - 3 - - - - 4

P(x) - 0.37 - - 0.28 - - 0.22 - - 0.22 - - 0.12

The mean of the distribution can be calculated by evaluated by determining the expected value of the distribution given that the data above is a discrete random variable. The mean value can be deduced multiplying each possible outcome by the probability of it's occurrence.

Summation of [P(x) * X] :

(0.37 * 0) + (0.28 * 1) + (0.22 * 2) + (0.22 * 3) + (0.12 * 4)

= 0 + 0.28 + 0.44 + 0.66 + 0.48

= 1.86

Answer:

I know the answer

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form. y = f(x) = a + bx. A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.