A wireless router is what kind of networking device?
Select one
a. End device
b. Intermediary device
c Peripheral Device
d. Connecting Device​

Answer:

Right-click on any empty area of the taskbar and click “Taskbar Settings.” In the settings window, turn on the “Use small taskbar icons” option. As you can see, almost everything is the same except that the icons are smaller and you can cram a few more into the space.

Answer:

680564733841876926926749214863536422911

Explanation:

2¹²⁹ - 1 = 680564733841876926926749214863536422911

Answer:

DCUKE

Explanation:

Given that,

Code for JAVA = LCXC

To find,

Code for BASIC = ?

As we observe the pattern,

In "JAVA", every letter moved two-letter forward in their alphabetical order or we can say that every third alphabet of the given letter is used to make the code:

J + 2 = L

A + 2 = C

V + 2 = X

A + 2 = C

Similarly,

B + 2 = D

A + 2  = C

S + 2 = U

I + 2  = K

C + 2 = E

Thus, DCUKE is the code for BASIC.

The code for BASIC given the code for JAVA is; DCUKE

We are given the code for JAVA as LCXC

From that code for "JAVA", we see that every letter is moved forward two letters in their alphabetical order. This means

Similarly for BASIC;

Thus, finally the code for BASIC is DCUKE

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Answer:

A. true

Explanation:

because 5s is the.................

Answer:

False

Explanation:

They are not applied in the hardware and software of information systems.

Answer:

Here the code is  given as,

Explanation:

Code:

#include <math.h>

#include <cmath>  

#include <iostream>

using namespace std;

int main() {

int v_stop = 0,count = 0 ;

int x;

double y;

int t_count [100];

double p_item [100];

double Total_rev = 0.0;

double cost_trx[100];

double Largest_element , Smallest_element;

double unit_sold = 0.0;

for( int a = 1; a < 100 && v_stop != -99 ; a = a + 1 )

  {

     cout << "Transaction # " << a << " : " ;

     cin >> x >> y;

  t_count[a] = x;

  p_item [a] = y;

  cost_trx[a] = x*y;

  v_stop = x;

  count = count + 1;

  }

  for( int a = 1; a < count; a = a + 1 )

  {

   Total_rev = Total_rev + cost_trx[a];

   unit_sold = unit_sold + t_count[a];

  }

  Largest_element = cost_trx[1];

  for(int i = 2;i < count - 1; ++i)

   {

      // Change < to > if you want to find the smallest element

      if(Largest_element < cost_trx[i])

          Largest_element = cost_trx[i];

   }

Smallest_element = cost_trx[1];

  for(int i = 2;i < count - 1; ++i)

   {

      // Change < to > if you want to find the smallest element

      if(Smallest_element > cost_trx[i])

          Smallest_element = cost_trx[i];

   }

  cout << "TRANSACTION PROCESSING REPORT     " << endl;

  cout << "Transaction Processed :           " << count-1 << endl;

  cout << "Uints Sold:                       " << unit_sold << endl;

  cout << "Average Units per order:          " << unit_sold/(count - 1) << endl;

  cout << "Largest Transaction:              " << Largest_element << endl;

  cout << "Smallest Transaction:             " << Smallest_element << endl;

  cout << "Total Revenue:               $    " << Total_rev << endl;

  cout << "Average Revenue :            $    " << Total_rev/(count - 1) << endl;

  return 0;

}

Output:

Answer:

128 KB      

Explanation:

Given data :

The block size = 512 bytes

Block pointer size = 2 bytes

In an indexed allocation, a special block named Index Block contains all the pointers to the blocks that the file had occupied.

Therefore, the maximum number of block pointer in 1 block :

[tex]$=\frac{\text{block size}}{\text{pointer size}}$[/tex]

[tex]$=\frac{512}{2}$[/tex]

= 256

Thus, a block can hold maximum 256 pointers.

It is given the level of indexing is one. So,

Maximum size of the file =  maximum number of block pointers in 1 file x block size

                                          = 256 x 512

                                          [tex]$=2^8 \times 2^9$[/tex]

                                          [tex]$=2^{8+9}$[/tex]

                                           [tex]$=2^{17}$[/tex]

                                          [tex]$=2^7 \times 2^{10}$[/tex]

                                          [tex]$=128 \times 2^{10}$[/tex]

                                          = 128 KB   (∵ 1 KB = [tex]2^{10} \ B[/tex] )

Therefore, the largest file that 1 level if indexed allocation method can handle is 128 KB.

Answer:

The conditional statement and its flowchart can be defined as follows:

Explanation:

Conditional statement:

if x>100 Then //defining if that check x value greater than 100

y=20//holding value in the y variable

z=40//holding value in z variable

End if

Answer: Send status report when I complete an assigned task

Explanation:

In order to be aware of their progress, the option to choose is the "Send status report when I complete an assigned task".

To do this click on options on the tools menu, then click on task options. Then, after the keep updated copies of the assigned tasks on my task list has been selected in the check box, one will then select "Send status reports when the assigned tasks are completed".

Answer: its bad

Explanation:

Answer:

Lagging in offline games suggests there is something wrong with the computer, not the internet. There are various speed tests you can use to determine the speed of your internet! One being https://www.speedtest.net/ which is a more well known and trusted site. Depending on how old your computer is or if it is a laptop not build for games can influence your gameplay experience greatly.

Answer:

The modified program in Python is as follows:

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))  

for i in range(triangle_height):

   print(triangle_char * (i+1))

Explanation:

This gets the character from the user

triangle_char = input('Enter a character:\n')

This gets the height of the triangle from the user

triangle_height = int(input('Enter triangle height:\n'))  

This iterates through the height

for i in range(triangle_height):

This prints extra characters up to the height of the triangle

   print(triangle_char * (i+1))

Here's the modified program that incorporates the requested changes:

python

Copy code

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))

print('')

for i in range(1, triangle_height + 1):

   line = triangle_char * i + ' ' * (triangle_height - i)

   print(line)

This program uses a loop to iterate from 1 to triangle_height. In each iteration, it creates a line by concatenating triangle_char repeated i times with spaces (' ') repeated (triangle_height - i) times. The resulting line is then printed.

For example, if the user enters % as the character and 5 as the height, the output will be to make sure to maintain the indentation properly in your code for it to work correctly.

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Explanation:

A Linear data structure have data elements arranged in sequential manner and each member element is connected to its previous and next element. This connection helps to traverse a linear data structure in a single level and in single run. Such data structures are easy to implement as computer memory is also sequential.

Answer:

Explanation:

1) Chart area: This is the area where the chart is inserted. 2) Data series: This comprises of the various series which are present in a chart i.e., the row and column of numbers present. 3) Axes: There are two axes present in a chart. ... 4)Plot area: The main area of the chart is the plot area

Answer:

Explanation:

The following is written in Python, it contains all of the necessary object attributes and methods as requested and creates the three objects to be printed to the screen. The first uses user input and the other two are pre-built as requested. The output can be seen in the attached image below.

class Pet:

   _name = ''

   _animalType = ''

   _age = ''

   def __init__(self, name, age, animalType):

       self._name = name

       self._age = age

       self._animalType = animalType

   def setName(self, name):

       self._name = name

   def setAnimalType(self, animalType):

       self._animalType = animalType

   def setAge(self, age):

       self._age = age

   def getName(self):

       return self._name

   def getAnimalType(self):

       return self._animalType

   def getAge(self):

       return self._age

   def __str__(self):

       print("My Pet's name: " + str(self.getName()))

       print("My Pet's age: " + str(self.getAge()))

       print("My Pet's type: " + str(self.getAnimalType()))

name = input('Enter Pet Name: ')

age = input('Enter Pet Age: ')

type = input('Enter Pet Type: ')

pet1 = Pet(name, age, type)

pet1.__str__()

pet2 = Pet("Sparky", 6, 'collie')

pet3 = Pet('lucky', 4, 'ferret')

pet2.__str__()

pet3.__str__()

Answer:

an optical instrument used for viewing very small objects, such as mineral samples or animal or plant cells, typically magnified several hundred times

Answer:

A microscope is a laboratory instrument used to examine objects that are too small to be seen by the naked eyes.

Answer:

Explanation:

The following code is written in Java. It creates the method as requested which takes in a parameter of type Scanner and opens the passed file, reads all the elements, and prints the lowest-priced element in the file. A test case was done and the output can be seen in the attached picture below.

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

class Brainly{

   public static void main(String[] args) throws FileNotFoundException {

       Scanner console = new Scanner(System.in);

       System.out.print("file location: ");

       String inputLocation = console.next();

       File inputFile = new File(inputLocation);

       Scanner in = new Scanner(inputFile);

       lowestPrice(in);

   }

   public static void lowestPrice(Scanner in) {

       double smallest = in.nextDouble();

       while(in.hasNextDouble()){

           double number = in.nextDouble();

           if (number < smallest) {

               smallest = number;

           }

       }

       System.out.println(smallest);

       in.close();

   }

}

Answer:

Algorithm and flowchart are the powerful tools for learning programming. An algorithm is a step-by-step analysis of the process, while a flowchart explains the steps of a program in a graphical way. Algorithm and flowcharts helps to clarify all the steps for solving the problem.

Answer and Explanation:

C is a low level language and does not have classes. The language isn't based on object oriented programming(OOP) but is actually a foundation for higher level languages that adopt OOP like c++. Using c++ programming language we can implement the class, flower, with its three variables/properties and functions/methods since it is an object oriented programming language.

Answer:

" Non-persistent" is the right response.

Explanation:

An electronic [tex]\sf\purple{spreadsheet}[/tex] is an application you use to perform numeric calculations and to analyze and present numeric data.

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

An electronic spreadsheet is an application you use to perform numeric calculations and to analyze and present numeric data.

You may examine and show numerical data as well as execute numerical calculations using an electronic spreadsheet.

Microsoft Excel, Sheets, and Apple Numbers are a few examples of electronic spreadsheets.

Text, number, logical, and error data are the four categories of data. Each type can be used for a variety of tasks, so knowing which to use and when to use it is crucial.

You might also keep in mind that while exporting data into a spreadsheet, some data types might change.

You may examine and show numerical data as well as execute numerical calculations using an electronic spreadsheet.

Thus, the answer is electronic spreadsheet.

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Answer: Its............ A Chromebook type of Chromebook...??

Explanation:

Ion know I aint a geek, geezer -_- (Thats a lie)

Answer:

Here is the output.

Explanation:

import java.util.Arrays;  

public class Main{  

   public static void main(String[] args){        

       int[] array={43,42,23,42,4,56,36,7,8,676,54};

       System.out.println(Arrays.toString(array));

       printArray(array,"*");

       System.out.println(""+getFirst(array));

       System.out.println(""+getLast(array));

       System.out.println(Arrays.toString(getAllButFirst(array)));

       System.out.println(""+getIndexOfMin(array));

       System.out.println(""+getIndexOfMax(array));

       System.out.println(Arrays.toString(swapByIndex(array, 1,2)));

       System.out.println(Arrays.toString(removeAtIndex(array,3)));

       System.out.println(Arrays.toString(insertAtIndex(array,3,65)));

   }  

   //---1----

   public static void printArray(int[] arr, String sep){  

       for(int i=0; i<arr.length-1;i++){  

           System.out.print(" "+arr[i]+" "+sep);  

       }  

       System.out.println(" "+arr[arr.length-1]);  

   }  

   //---2----  

   public static int getFirst(int[] arr){  

       return arr[0];  

   }

   //---3----  

   public static int getLast(int[] arr){  

       return arr[arr.length-1];  

   }  

   //---4-----  

   public static int[] getAllButFirst(int[] arr){  

       int[] anotherArray=new int[arr.length-1];  

       for(int i=1; i<arr.length;i++){  

           anotherArray[i-1]=arr[i];  

       }

       return anotherArray;

   }

//---5------  

   public static int getIndexOfMin(int[] arr){  

       int index=0;  

       int min=arr[0];  

       for(int i=1; i<arr.length;i++){  

           if(min>arr[i]){  

               min=arr[i];  

               index=i;  

           }  

       }

       return index;  

   }  

   //---6------  

   public static int getIndexOfMax(int[] arr){  

       int index=0;  

       int max=arr[0];  

       for(int i=1; i<arr.length;i++){  

           if(max<arr[i]){  

               max=arr[i];  

               index=i;  

           }  

       }  

       return index;  

   }  

   //---7------  

   public static int[] swapByIndex(int[] arr, int a , int b){  

       int temp=arr[a];  

       arr[a]=arr[b];  

       arr[b]=temp;  

       return arr;  

   }  

   //---8------  

   public static int[] removeAtIndex(int[] arr, int index){  

       int[] anotherArray = new int[arr.length - 1];  

for (int i = 0, k = 0; i < arr.length; i++) {  

if (i == index) {  

continue;  

}  

anotherArray[k++] = arr[i];  

}  

// return the resultant array  

return anotherArray;  

   }  

//---9------  

   public static int[] insertAtIndex(int[] arr, int index, int element){  

       int[] anotherArray = new int[arr.length + 1];  

for (int i = 0, k=0;k < arr.length+1; k++) {  

if (k == index) {  

anotherArray[k]=element;  

               continue;  

}  

anotherArray[k] = arr[i++];  

}  

// return the resultant array  

return anotherArray;  

   }  

//---10------  

   public static boolean isSorted(int[] arr){  

       for(int i=0; i<arr.length-1;i++){  

           if (arr[i+1]<arr[i]){  

               return false;  

           }  

       }  

       return true;  

   }  

}

Which XXX declares a student's name.

public class Student {

   XXX

   private double myGPA;  

   private int myID;

   public int getID() {

        return myID;

   }

}

Group of answer choices

a. String myName;

b. public String myName;

c. private myName;

d. private String myName;

private String myName;

To declare a student's name, the following should be noted.

i. The name of the student is of type String

ii. Since all of the instance variables (myGPA and myID) have a private access modifier, then myName (which is the variable name used to declare the student's name) should be no exception. In other words, the student's name should also have a private access.

Therefore, XXX which declares a student's name should be written as

private String myName;

Option (a) would have been a correct option if it had the private keyword

Option (b) is not the correct option because it has a public access rather than a private access.

Option (c) is not a valid syntax since, although it has a private access, the data type of the variable myName is not specified.

Option (d) is the correct option.

Explanation:

The following six steps must be followed to solve a problem using computer.

Problem Analysis.

Program Design - Algorithm, Flowchart and Pseudocode.

Coding.

Compilation and Execution.

Debugging and Testing.

Program Documentation.

Answer:

Electronic boards

Videoconferencing ability

Search engines

Cloud services

Computing softwares

Explanation:

Technology tools are used to simplify task bring ease, comfort as well as better satisfaction :

The use of electronic boards for teaching is an essential tool for students and educators alike as it provides great features aloowibg teachers to write and make drawings without hassle. This clear visual display goes a long way to aide student's understanding.

Videoconferencing breaks the barrier that distance and having to travel bring swhen it comes to learning. With this tools, students and educators can now organize classes without having to be physically present un the same class room.

Search engines : the means of finding solutions and hints to challenging and questions is key. With search engines, thousands of resources can now be assessed to help solve problems.

Cloud services : this provud s a store for keeping essential information for a very long time. Most interestingly. These documents and files can be assessed anywhere, at anytime using the computer.

Computing softwares : it often seems tune consuming and inefficient solving certain numerical problems, technology now p ovide software to handles this calculation and provides solutions in no time using embedded dded to codes which only require inputs.

Answer:

Configure an automatic reply.

Explanation:

Dan's best option would be to configure an automatic reply. This reply will instantly be sent to any individual that messages Dan requesting a meeting. Once configured, Dan will no longer need to manually respond to each one of the messages and it will instead be handled automatically. These messages will also be automatically moved to the outbox where the messages that have been sent usually go.

Answer:

C

Explanation:

Answer:

B: ztest(dataframe, null hypothesis value)

The Python method that is used to perform a test of hypothesis for a population mean with an unknown population standard deviation is d. ttest_1samp(dataframe, null hypothesis value).

Thus, the only Python method to carry out hypothesis testing with unknown population standard deviation is the t-test, which is given in option d.

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Answer:

The following classifications can be made of the computer systems:

1. According to size.

2. Functionality based on this.

3. Data management based. 

Explanation:

Servers:-

Servers are only computers that are configured to offer clients certain services. Depending on the service they offer, they are named. For example security server, server database.

Workstation:-

These are the computers which have been designed mainly for single users. They operate multi-user systems. They are the ones we use for our daily business/personal work.

Information appliances:-

They are portable devices that perform a limited number of tasks such as basic computations, multimedia playback, internet navigation, etc. They are commonly known as mobile devices. It has very limited storage and flexibility and is usually "as-is" based.

Answer:

Explanation:

The following is written in Java. It creates a while loop that requests price from the user and goes adjusting the quantity and subtotal as more prices are added. If 0 is entered it breaks the loop and outputs the quantity, subtotal, tax, and grand total to the user.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int quantity = 0;

       double subtotal = 0;

       double tax, grandTotal;

       while (true) {

           System.out.println("Enter a price: ");

           double price = in.nextDouble();

           if (price == 0) {

               break;

           } else if (price > 0) {

               quantity += 1;

               subtotal += price;

           }

       }

       tax = subtotal * 0.075;

       grandTotal = subtotal + tax;

       System.out.println("Quantity: $" + quantity);

       System.out.println("Subtotal: $" + subtotal);

       System.out.println("Tax: $" + tax);

       System.out.println("GrandTotal: $" + grandTotal);

   }

}