Mathematics High School

a worker at a landscape design center uses a machine to fill bags with potting soil. assume that the quantity put in each bag follows the continuous uniform distribution with low and high filling weights of 8.1 pounds and 13.1 pounds, respectively.

Answers

Answer 1

By assuming a continuous uniform distribution, the landscape design center can estimate the probability of bags being filled within specific weight ranges or analyze the distribution of the filled weights. This information can be useful for quality control purposes, ensuring that the bags are consistently filled within the desired weight range.

The continuous uniform distribution is a probability distribution where all values within a given interval are equally likely to occur. In this case, the interval is defined by the low and high filling weights of the potting soil bags, which are 8.1 pounds and 13.1 pounds, respectively.

The uniform distribution assumes a constant probability density function within the defined interval. It means that any value within the range has the same likelihood of occurring. In this context, it implies that bags filled with potting soil can have any weight between 8.1 pounds and 13.1 pounds, with no particular weight being favored over others.

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Related Questions

Determine the convergence or divergence of the sequence with the given nth term. if the sequence converges, find its limit. (if the quantity diverges, enter diverges. ) an = 5 n 5 n 8

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The limit of the sequence as n approaches infinity is 1. Since the sequence converges to a specific value (1).

To determine the convergence or divergence of the sequence with the given nth term, let's examine the expression:

an = 5n / (5n + 8)

As n approaches infinity, we can analyze the behavior of the sequence.

First, let's simplify the expression by dividing both the numerator and denominator by n:

an = (5n/n) / [(5n + 8)/n]

= 5 / (5 + 8/n)

As n approaches infinity, the term 8/n approaches zero since n is increasing without bound. Therefore, we have:

an ≈ 5/5

an ≈ 1

Hence, the limit of the sequence as n approaches infinity is 1.

Since the sequence converges to a specific value (1), we can conclude that the sequence converges.

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