According to the equation below, if 2.00 g of PCl5 react completely, how many grams of HCl will be produced?


PCl5+4H2O→H3PO4+5HCl

Answers

Answer 1

Answer:

1.75 g HCl

Explanation:

PCl₅ + 4H₂O → H₃PO₄ + 5HCl

First we convert 2.00 g of PCl₅ into moles, using its molar mass:

2.00 g ÷ 208.24 g/mol = 0.0096 mol PCl₅

Then we convert PCl₅ moles into HCl moles, using the stoichiometric coefficients of the equation:

0.0096 mol PCl₅ * [tex]\frac{5molHCl}{1molPCl_5}[/tex] = 0.048 mol HCl

Finally we convert HCl moles into grams, using its molar mass:

0.048 mol HCl * 36.45 g/mol = 1.75 g HCl


Related Questions

PLEASE HURRY! What is the name of this alkane?


A skeletal model has a hexagon ring with points at the top and bottom. C H 3 is bonded to the top point, and a carbon and another C H 3 are bonded to the bottom right point.

1-methyl,3-ethylnonane
1-methyl,5-ethylisohexane
1-ethyl,3-methylcyclohexane
1-ethyl,5-methylcyclohexane

Answers

Answer:

C. 1-ethyl, 3-methylcyclohexane

(Photo for proof at the bottom.)

Explanation:

The 1-ethyl is because you start numbering from the longest branch, towards the next closest branch. Prefix "eth-" means two, there are 2 carbons in the longest branch. 3-methyl is because the next branch is at number 3, and prefix "meth-" means 1, there is 1 carbon in that chain. "Cyclo" in cyclohexane means the skeletal model is shaped like a ring, and the "hexane" means there are 6 carbons in the ring. Prefix "hex" means 6.

Here's a photo of the unit review on Edge. Refer to the 2nd attachment for a visualization.

Please click the heart if this helped.

Answer:

C. 1-ethyl,3-methylcyclohexane

Explanation:

Help will give brainliest no “click this link”

Answers

The longest continuous carbon chain comprises five carbon atoms connected by single bonds, so the root name will be pentane. There is a methyl group (—CH3) attached to carbon 3 (since this molecule is symmetrical, the methyl substituent will always be on carbon 3 regardless of which end you begin counting). Thus, the name of this molecule would be 3-methylpentane.

Which of the following methods of fossil formation is formed in dry areas due to a lack of moisture?

a
Mummification
b
Casts and molds
c
Amber fossil
d
Carbonization

Answers

I don’t know the answer but my guess would be mummification

The methods of fossil formation in dry areas due to a lack of moisture is mummification. The correct option is a.

What is mummification?

Mummification is the process of deliberately drying or embalming flesh to preserve the body after death.

This typically entailed removing moisture from a deceased body and desiccating the flesh and organs with chemicals or natural preservatives such as resin.

Mummification served the purpose of keeping the body intact so that it could be transported to a spiritual afterlife.

The body was stripped, positioned on a slanted table, and washed in natron solution (a naturally occurring salt used both as soap and a preservative).

The brain was extracted from the skull through a hole in the ethmoid bone (the bone separating the nasal cavity from the skull cavity).

Thus, the correct option is A.

For more details regarding mummification, visit:

https://brainly.com/question/899330

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T/F___ At the eutectic composition, an alloy can solidify at a constant temperature.___ For effective dispersion strengthening, the dispersed phase should be needle-like, as opposed to round___ Intermetallic compounds are usually hard and brittle.___ For effective dispersion strengthening, the dispersed phase should be continuous.___ Stoichiometric intermetallic compounds exist overa range of compositions.___ Faster solidification results in smaller interlamellar spacing

Answers

Answer:

TRUEFALSETRUEFALSEFALSETRUE

Explanation:

At the eutectic composition, an alloy can solidify at a constant temperature : TRUE . this is because at eutectic composition the type of reaction that takes place there is invariant reaction in its thermal equilibrium For effective dispersion strengthening, the dispersed phase should be needle-like, as opposed to round : FALSE. because the rounded shape will not cause a crack. Intermetallic compounds are usually hard and brittle : TRUE. because Intermetallic compounds prevents dislocation movements and this makes them brittle and hardFor the effective dispersion and strengthening, the dispersed phase should be continuous : FALSE. this is because the dispersed precipitate must be small and not continuous Stoichiometric intermetallic compounds exist over a range of compositions : FALSEFaster solidification results in smaller interlamellar spacing : TRUE

.35L sample of helium gas is collected at 295 K and 0.98 ATM what volume would this gas occupy at STP

Answers

Answer:

0.3857 litres is the answer

What's the bond between two atoms of hydrogen?​

Answers

Answer:There is a iin dipole attraction between two hydrogen atom

Explanation:

The same atoms have the ion dipole attraction between them the same atoms repel each other

Can tell the answer pls

Answers

Explanation: where the article????

How much energy ( in joule ) does the Sun emit in one day (24 hours)? I've previously answered with 3.32, but it was incorrect. Please help thanks.

Answers

It is about 3.86 which is 10⁶⁶ watts

Answer:

410 quintillion Joules or 430,000,000,000,000,000,000 Joules

Help it’s about Binary compounds and transition metals

Answers

Answer:

Cr 6+ & SO4 2-

Explanation:

Sulfate is a polyatomic ion that has a charge of 2-. There are three of them in the chemical formula so it equates to a 6- total charge. Thus, chromium must have a 6+ charge to give the compound a neutral charge.


Compare the number of moles calculated in parts a) 0.03 and b). 0.064. Which of the three possible reactions discussed is consistent with these results?

Answers

Answer:don’t click link ur gonna get ur info taken

Explanation:

Determine the amount of current going through a 50ohms; resistor with a voltage of 120 v

Answers

Answer:

98.356 ohms is the answer

Identify the most and the least basic compound in each of the following sets. Leave the remaining answer in each set blank. a) Sodium acetate: _______ Ammonia: _______ Sodium ethoxide: _______ b) Sodium acetate: _______ Sodium chloroacetate: _______ Sodium fluoroacetate: _______ c) Sodium acetate: _______ Sodium methoxide: _______ Sodium phenoxide:

Answers

Answer:

The correct answer is -

a) Sodium acetate: least Ammonia: _______ Sodium ethoxide: most

b) Sodium acetate: most Sodium chloroacetate: _______ Sodium fluoroacetate: least

c)  Sodium acetate: least Sodium methoxide: most Sodium phenoxide:

Explanation:

A) In this case the basicity can be found by the stability of the base, Sodium acetate is the most stable base due to resonance stabilization of acetate anion. Sodium acetate is the least basic as the lone pair of electrons involved in the resonance here. An ethoxide ion has more electrons to donate an electron pair easily.

Thus, the correct answer is - Sodium acetate is the least basic while sodium ethoxide is the most basic.

B) Fluroacetate gives a very strong acid and the acetate gives the least strong acid among all three as described in case of a), thus, the most basic is acetate and the least is fluoroacetate.

]C) comparing the acidity of the acids formed by the addition of a proton to the anions is an easy and correct way to find the basicity of compounds.

Acetate ion adds a proton ⇒ acetic acid

methoxide adds a proton ⇒ methanol

phenoxide ion adds proton ⇒ phenol

As it is known that the stronger the acid, the weaker is the conjugate base formed by the loss of the proton.

acetic acid is the strongest acid because it can easily give up its proton to form acetate. Methanol is the weakest among all three and hence methoxide anion is the strongest base.

Thus, the correct answer is - sodium acetate is the least basic while sodium methoxide is the most basic.

Suppose you have a 1:1:1 by weight mixture of three solid compounds, salicylic acid 4-nitroaniline naphthalene. You dissolve 1 gram of this mixture in diethyl ether, and place a tiny drop of the ether solution on a TLC plate. After developing the TLC plate, you see three spots. Which compound would would you expect to have the largest Rf value

Answers

Answer:

The correct answer is - 4-nitroaniline.

Explanation:

It is given that all three solid compounds salicylic acid + 4-nitroaniline + naphthalene are equal in the ratio in the mixture and then 1 gram of this mixture is dissolved in the diethyl ether and run a drop of the solution on TLC plate. This plate shows three spots.

The salicylic acid and naphthalene would stay dissolved in the diethyl ether solution due to the 4-nitroaniline could be extracted by adding aqueous acid and involve in the aqueous layer and thus spot of 4-nitroaniline would be with largest Rf value.

Is chemistry required to get into speech language pathology?​

Answers

Answer:

As of right now (4-7-2021), the physical science requirement for the SLP certificate must be met by completing coursework in the areas of either chemistry or physics.

How many moles of NaOH are contained in 56.0 mL of a 2.40 M solution of 1 point
NaOH in water? (**Use only numerical answers with 3 significant figures.
The units are given in the question.)
Your answer

Answers

Answer:

1.34 mol

Explanation:

Molarity, which is the molar concentration of a solution, can be calculated by dividing the number of moles (n) by the volume (V).

That is;

Molarity (M) = n/V

According to the information provided in this question;

M = 2.40M

V = 56.0 mL = 56/1000 = 0.056 L

Since molarity = n/V

number of moles = M × V

n = 0.056 × 24

n = 1.34 mol

I a doing an exam in science pls help.


What type of energy comes from the motion of tiny particles of matter?

Answers

Answer:

heat

Explanation:

Answer:

Thermal Energy

Explanation:

True or False?

Weak bases dissociate
completely into (OH)- and
metal cations.

Answers

Answer:

False

Explanation:

When weak bases dissociate, an equilibrium is established rather than dissociating 100%. So OH- and metal ions are partially ionized.

Lipids include:
A. fats and water
B. Oils and carbohydrates
C. Waxes and sterols

Answers

I’m pretty sure it’s A

Answer: C

waxes and sterols

Explanation:

edge 2021

1. What volume of a 2.50M Kl(aq) is needed to make 200 ml of a 1.OOM KI)aq)?

Answers

Answer:

80 ml

Explanation:

From the question,

Applying Dilution formular

MV = mv................... Equation 1

Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.

make V the subject of the equation

V = mv/M............. Equation 2

Given: m = 1.00 M, v = 200 ml, M = 2.50 M

Substitute these values into equation 2

V = (1.00×200)/2.50

V = 80 ml

Help me I'm desperate :( no links or u will be reported

Answers

Answer:

Here is the answer from somewhere in the internet

Where are electrons found in an atom?

Answers

Answer:

outside the nucleus

Explanation:

When NH3(g) reacts with O2(g) to form N2O(g) and H2O(l), 342 kJ of energy are evolved for each mole of NH3(g) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer: [tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

Explanation:

The skeletal thermochemical equation for the reaction is:

[tex]NH_3(g)+O_2(g)\rightarrow N_2O(g)+H_2O(l)+342kJ[/tex]

The balanced  thermochemical equation for the reaction is:

[tex]2NH_3(g)+2O_2(g)\rightarrow N_2O(g)+3H_2O(l)+684kJ[/tex]

When 1 mole of [tex]NH_3[/tex] reacts with oxygen , heat released = 342 kJ

Thus when 2 moles of [tex]NH_3[/tex] reacts with oxygen , heat released = [tex]\frac{2}{1}\times 342 kJ=684kJ[/tex]

A 1.om sample of dry air at
at 25°c at 786mmHg contains 0.925g Nitrogen Plus other gases including oxygen, argon and carbon dioxide. what is the partial pressure of Na with the air sample.

Answers

Answer:

Is the question not supposed to be what is the partial pressure of Nitrogen not Sodium

Calculate the percent composition of C in carbon dioxide.

Answers

Answer:

27.27%

Explanation:

answer is 27.3%
have a good day!

What mass of nitrogen (N2) is needed to produce 0.125 mol of ammonia (NH3)? Input a numerical answer only. N2 + 3H2 ---> 2NH:

Please help me ​

Answers

Given the following equation: I N2(g) + 3H2(g) → _2_NH3(e) a. ... Calculate the number of grams of NH3 produced by the reaction of 5.40 g of ... C. How many grams of nitrogen are needed to produce 15.3 g of NH3?
98 KB

Very sorry if this is wrong!

A student dissolves 15.0 g of ammonium chloride(NH4Cl) in 250. 0 g of water in a well-insulated open cup. She then observes the temperature of the water fall from 20.0 oC to 16.0 oC over the course of minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction:
NH4Cl(s) rightarrow NH4+(aq) + Cl-(aq)
You can make any reasonable assumptions about the physical properties of the solution. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction.
1. Is this reaction exothermic, endothermic, or neither?
2. If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case.
3. Calculate the reaction enthalpy deltaHrxn per mole of NH4CI.

Answers

Answer:  

1) Endothermic.  

2) [tex]Q_{rxn}=4435.04J[/tex]  

3) [tex]\Delta _rH=15.8kJ/mol[/tex]

Explanation:  

Hello there!  

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.  

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

[tex]Q_{rxn}=-(15.0g+250.0g)*4.184\frac{J}{g\°C}(16.0-20.0)\°C\\\\ Q_{rxn}=4435.04J[/tex]    

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

[tex]\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol[/tex]

Best regards!  

Best regards!

wich strong nucleophil h2s or water??and why??

Answers

According to my notes, nucleophilicity order is directly proportional to basicity order in an aprotic medium, and is inversely proportional to basicity order in protic medium. And H2O is a stronger base than H2S, so it should be the strong nucleophile, but the answer is given as H2S is the stronger nucleophile.

hope this helped, good luck <3

How many mL of 0.715 M HCl is required to neutralize 1.25 grams of sodium carbonate? (producing carbonic acid)
I really couldn't find the answer since molarity and volume for sodium carbonate are not given.
I will mark the correct answer with steps as best answer.

Answers

Answer:

34 mL

Explanation:

We'll begin by calculating the number of mole in 1.25 g of sodium carbonate, Na₂CO₃. This can be obtained as follow:

Mass of Na₂CO₃ = 1.25 g

Molar mass of Na₂CO₃ = (23×2) + 12 + (16×3)

= 46 + 12 + 48

= 106 g/mol

Mole of Na₂CO₃ =?

Mole = mass /molar mass

Mole of Na₂CO₃ = 1.25 / 106

Mole of Na₂CO₃ = 0.012 mole

Next, we shall determine the number of mole HCl needed to react with 0.012 mole of Na₂CO₃.

The equation for the reaction is given below:

Na₂CO₃ + 2HCl —> H₂CO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 2 moles of HCl.

Therefore, 0.012 mole of Na₂CO₃ will react with = 0.012 × 2 = 0.024 mole of HCl.

Next, we shall determine the volume of HCl required for the reaction. This is illustrated:

Mole of HCl = 0.024 mole

Molarity of HCl = 0.715 M

Volume of HCl =?

Molarity = mole /Volume

0.715 = 0.024 / volume of HCl

Cross multiply

0.715 × volume of HCl = 0.024

Divide both side by 0.715

Volume of HCl = 0.024 / 0.715

Volume of HCl = 0.034 L

Finally, we shall convert 0.034 L to mL

This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.034 L = 0.034 L × 1000 mL / 1 L

0.034 L = 34 mL

Therefore, 34 mL of HCl is needed for the reaction.

The amount of HCl required for counterbalancing 1.25 g of Na2CO3(Sodium Carbonate) would be:

- [tex]34 ml[/tex]

Given that,

Mass of Na2CO3 [tex]= 1.25 g[/tex]

To find the Moles of Na2CO3, we will find the molar mass of Na2CO3,

Molar Mass of or Na2CO3 [tex]= 106 g/mol[/tex]

So,

Moles of Na2CO3 [tex]= mass /molar mass[/tex]

[tex]= 1.25/106[/tex]

[tex]= 0.012 mol[/tex]

To determine the quantity of HCl required to display the reaction with 0.012 mol of Na2CO3

[tex]Na_{2} CO_{2} + 2HCl[/tex][tex]H_{2}CO_{3} + 2NaCl[/tex]

While balancing the equation, we know that [tex]0.012[/tex] × [tex]2 = 0.024 mole of HCl[/tex] is necessary to process the reaction.

Now,

As we know,

HCl moles [tex]= 0.024[/tex]

Molarity of HCl [tex]= 0.715 M[/tex]

∵ Quantity of HCl required = Moles/Molarity

[tex]= 0.024 / 0.715[/tex]

[tex]= 0.034 l[/tex] [tex]or 34ml[/tex]

Thus, 34 ml is the correct answer.

Learn more about 'Molarity' here:

brainly.com/question/12127540

The compound FeCl3 Is made of.

Answers

Answer:

iron and chlorine

Explanation:

A 72.0 g sample of an organic solid is dissolved in 180mL of water. The solid is extracted using one 60 mL extraction in the first extraction of an organic solvent which has a partition (distribution) coefficient with water of 10. The first extraction removed 55.4 g of solid from water. What are the numbers that need to go in box A and B to calculate the volume of solvent (y) that would be necessary to remove an additional 7.0g from the remaining sample dissolved in water. You DON'T have to complete the calculation to solve for y.

Answers

Answer:

[tex]V_{7.0}\approx 235ml[/tex]

Explanation:

From the question we are told that

mass of sample [tex]M=72.0 grams[/tex]

volume of water [tex]V=180 mL[/tex]

volume for extraction [tex]V'=60mL[/tex]

partition (distribution) coefficient water [tex]d=10[/tex]

initial extraction removal [tex]x=55.4g[/tex]

Generally the equation for the weight of sample [tex]x_n[/tex]  is mathematically given by

[tex]x_n=x*(\frac{DV}{DV+V'})^n[/tex]

[tex]x_n=55.4(\frac{10*180}{10*180+60})^1[/tex]

[tex]x_n=53.613g[/tex]

Generally the weight extracted [tex]x_e[/tex] is therefore

[tex]w_e=x-x_n[/tex]

[tex]w_e=55.4-53613[/tex]

[tex]w_e=1.787[/tex]

[tex]w_e=1.787[/tex] is extracted with 60ml solvent .

Therefore volume of solvent (y) that would be necessary to remove an additional 7.0g

[tex]V_{7.0}=\frac{60}{1.767}*7[/tex]

[tex]V_{7.0}=235.030ml[/tex]

[tex]V_{7.0}\approx 235ml[/tex]

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