Answer:
sorry dunno
Step-by-step explanation:
:c
How many three-digit numbers can be formed using elements from the set {1, 2, 3, 4, 5, 6} if no element may be used more than once in a number and the number must be odd?
Answer:
60
Step-by-step explanation:
A 3-digit number can be odd only when the third digit in it would be odd.
So,
The 3rd digit becomes the most limiting which can be (1, 3, or 5).
Now,
Since we have 3 alternatives to pick the third digit, it can be done in three ways. For every of these 3 ways, 5 digits will be left to select the 1st. Thus, the number of ways to select 3rd and 1st digit = 3 * 5 = 15 ways
After picking the 1st and 3rd digits, we are left with 4 ways to pick the other 4 digits. Thus, the total number of ways to select all the digits would be;
3 * 5 * 4 = 60 ways
Hence, 60 is the correct answer.
Evaluate the following expressions using the chip method. SHOW ALL WORK!!!
Answer:
a. -7 b. -20c. 7Step-by-step explanation:
a. -9+2, in this case, it is -7 because you take the bigger number and subtract it by the lower number. If the bigger number is negative your answer will be negative, if the bigger number is positive it will be positive it is just really a basic subtraction problem just add the sign.b. In multiplication +++=+ ++-=- and a -+-=+ do your problem without thinking about the signs and then add the signs with the formula I showed you.c. ---=+Hope this helps :)!
On a coordinate plane, rhombus W X Y Z has points (negative 3, 1), (1, 4), (5, 1), and (1, negative 2). Rhombus WXYZ is graphed on a coordinate plane. What is the area of the rhombus?
Answer:
B. 20 Units
Step-by-step explanation:
unit test review edge 2021
The area of rhombus WXYZ as shown in the diagram given with the given vertices is: 24 units².
What is the Area of a Rhombus?Area of a rhombus = pq/2, where p and q are the diagonals of the rhombus.
Find the lengths of diagonals XZ and WY:
XZ = |4 -(-2)| = 6 units
WY = |-3 - 5| = 8 units
Area of rhombus WXYZ = 1/2(XZ × WY) = 1/2(6 × 8)
Area of rhombus WXYZ = 24 units².
Learn more about the area of a rhombus on:
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Could someone help me solve this please.
Answer: maybe 20 % at least because it might me adding
Can some solve this question for me plz
I think 'D' is the correct answer.
A carpenter can make at most 20 tables and at most 30 chairs per day. Each table requires 3 hours of labor and each chair 2 hours of labor. The maximum total hours of labor that the carpenter has at his disposal is 96.
Answer:
Step-by-step explanation:
Nicole is playing a video game where each round lasts \dfrac{7}{12}
12
7
start fraction, 7, divided by, 12, end fraction of an hour. She has scheduled 3\dfrac343
4
3
3, start fraction, 3, divided by, 4, end fraction hours to play the game.
How many rounds can Nicole play?
9514 1404 393
Answer:
6 3/7 rounds
Step-by-step explanation:
(3 3/4 h)/(7/12 h/round) = (15/4)×(12/7) rounds = 45/7 rounds
= 6 3/7 rounds
Answer:
45/7 rounds
6 3/7 rounds
Step-by-step explanation:
Here is the full question
Nicole is playing a video game where each round lasts 7/12 fraction of an hour. She has scheduled 3 3/4 fraction hours to play the game. How many rounds can Nicole play? rounds
Number of rounds she can play = total time she has scheduled / length of each round
length of each round = 7/12
total time she has scheduled = 3 3/4
3 3/4 ÷ 7/12
3 3/4 x 12/7
convert to the total time scheduled to an improper fraction
to convert to improper fraction, take the following steps :
Multiply the whole number (3) by the denominator (4) = 3x 4 = 12
Add the numerator to the answer gotten in the previous step = 14 + 3 = 15
divide the number gotten in the previous step by the denominator = 15/4
× = rounds or rounds
Hope this helped:)
Tell me if it’s wrong :(
How much will the payment be on a 2021 Jeep car costing $29,000 at 3.25 APR Interest on a 72 month loan with no down payment?
9514 1404 393
Answer:
$443.87
Step-by-step explanation:
The amortization formula tells you the payment.
A = P(r/12)/(1 -(1 +r/12)^(-12t))
where P is the loan amount at annual rate r for t years.
A = $29,000(0.0325/12)/(1 -(1 +0.0325/12)^(-72)) = $443.87
The monthly payment will be $443.87.
George Johnson recently inherited a large sum of money; he wants to use a portion of this money to set up a trust fund for his two children. The trust fund has two investment options: (1) a bond fund and (2) a stock fund. The projected returns over the life of the investments are 6% for the bond fund and 10% for the stock fund. Whatever portion of the inheritance he finally decides to commit to the trust fund, he wants to invest at least 30% of that amount in the bond fund. In addition, he wants to select a mix that will enable him to obtain a total return of at least 7.5%.
Required:
a. Formulate a linear programming model that can be used to determine the percentage that should be allocated to each of the possible investment alternatives.
b. Solve the problem using the graphical solution procedure.
Answer:
a. [tex]B+S = 1 [/tex]
[tex]0.06B+0.1S \geq 0.075 [/tex]
[tex]B \geq 0.3 [/tex]
Objective function:
[tex]R=0.06B+0.1S[/tex]
b) See Attached picture
30% in bonds and 70% in stocks
Step-by-step explanation:
a.
In order to solve the first part of the problem we need to take into account that the problem wants us to determine the percentage that should be allocated to each of the possible investment alternatives. In that case, the sum of the percentages must be equal to 1 (which means that we will have 100 of the trust fund)
so that gives us our first restriction for the problem.
B+S=1
Next, the problem tells us that the projected returns over the life of the investments are 6% for the bond fund and 10% for the stock fund. It also states that he wants to select a mix that will enable him to obtain a total return of at least 7.5%, so we can take this information and get the second restriction from it:
[tex]0.06B+0.1S \geq 0.075 [/tex]
Next, the problem tells us that whatever portion of the inheritance he finally decides to commit to the trust fund, he wants to invest at least 30% of that amount in the bond fund, so that's where the last restriction comes from:
[tex]B \geq 0.3 [/tex]
now, the idea is to optimize the investment, this is get the greatest amount of money out of the trust fund, so the objective function is:
[tex]R=0.06B+0.1S[/tex]
which represents the return on the investment.
b)
For part b we can start by graphing each of the restrictions:
[tex]B+S = 1 [/tex]
This will be a single line, you can draw the line by setting B=0 first so you get:
0+S=1
S=1
So the first point to plot will be (0,1)
next, we can set s=0 to get:
B+0=1
B=1
so the second point to plot will be (1,0)
so you can plot the two points and connect them with a straight line. This is the green line on the uploaded graph.
Next we can graph the second restriction:
[tex]0.06B+0.1S \geq 0.075 [/tex]
we can use the same procedure we used for the previous graph, in this case the points would be:
(0 , 0.75) and (1.25, 0)
and again connect the two points with a straight line. Next we need to decide which region of the graph to shade for which we can pick two arbitrary points on each side of the line, for example we can pick:
(0,0) and (2,2) and see which one makes the inequality true:
for (0,0) we get:
[tex]0.06B+0.1S \geq 0.075 [/tex]
[tex]0.06(0)+0.1(0) \geq 0.075 [/tex]
[tex]0 \geq 0.075 [/tex]
Which is false, therefore we need to shade the other region of the graph:
for (2,2) we get:
[tex]0.06B+0.1S \geq 0.075 [/tex]
[tex]0.06(2)+0.1(2) \geq 0.075 [/tex]
[tex]0.32 \geq 0.075 [/tex]
Which is true, so we shade the region of the graph that contains that point. (see red graph)
now we graph the third restriction:
[tex]B \geq 0.3 [/tex]
In order to graph this third restriction we just need to draw a vertical line at B=0.3 and shade everything to the right of that line. (Blue graph)
Now, we can analyze the graph, in this case we need to locate the points where the green line crosses the red and the blue line which gives us the following coordinates:
(0.3, 0.7) and (0.625, 0.375)
these two points can be found by setting the first restriction equal to each of the other two restrictions if you are to do it algebraically. If you are using a graphing device, you can directly read them from the graphs.
So once we got those points, we can see which one gives us the greatest percentage of return.
let's test the first point (0.3, 0.7)
[tex]R=0.06B+0.1S[/tex]
[tex]R=0.06(0.3)+0.1(0.7)[/tex]
R=0.088
so this distribution gives us 8.8% in return, let's test the second point:
(0.625, 0.375)
[tex]R=0.06B+0.1S[/tex]
[tex]R=0.06(0.625)+0.1(0.375)[/tex]
R=0.075
so this distribution gives us 7.5% in return.
In this case the best distribution for us is 30% in bonds and 70% in the stock fund to get a return of 8.8%
PLEASEEEE HELPPPPPPP!!!!!
To find S or T add them together:
3/5 + 1/3
Rewrite the fractions to have a common denominator
9/15 + 5/15 = 14/15
Answer: 14/15
Step-by-step explanation:
Here is your answer . Hope it helps.
B
15x+7
6x+2y|
y +3
2y + 1
С
E
The triangles are congruent. Find the length of each hypotenuse.
A. 3
B. 5
C 17
Answer:
Hypothenus = 22
Step-by-step explanation:
From the question given above, we were told that the triangles are congruent (i.e same size). Thus,
AC = EF
BC = DE
To obtain the length of each Hypothenus, we shall determine the value of y and x. This can be obtained as follow:
For y:
AC = y + 3
EF = 2y + 1
AC = EF
y + 3 = 2y + 1
Collect like terms
3 – 1 = 2y – y
2 = y
y = 2
For x:
BC = 5x + 7
DE = 6x + 2y
y = 2
DE = 6x + 2(2)
DE = 6x + 4
BC = DE
5x + 7 = 6x + 4
Collect like terms
7 – 4 = 6x – 5x
3 = x
x = 3
Finally, we shall determine the length of each Hypothenus. This can be obtained as follow:
Hypothenus = BC
Hypothenus = 5x + 7
x = 3
Hypothenus = 5x + 7
Hypothenus = 5(3) + 7
Hypothenus = 15 + 7
Hypothenus = 22
OR
Hypothenus = DE
DE = 6x + 2y
y = 2
x = 3
Hypothenus = 6(3) + 2(2)
Hypothenus = 18 + 4
Hypothenus = 22
A store offers packing and mailing services to customers. The cost of shipping a box is a combination of a flat packing fee of $5 and an amount based on the weight in pounds of the box, $2.25 per pound. Which equation represents the shipping cost as a function of x, the weight in pounds?
f(x) = 2.25x + 5
f(x) = 5x + 2.25
f(x) = 2.25x − 5
f(x) = 5x − 2.25
Answer:
f(x) = 2.25x + 5
Step-by-step explanation:
The cost from the weight in pounds of the box can be represented by 2.25x, since the charge is $2.25 per pound.
The flat fee of $5 can be represented in the function by adding 5 to 2.25x.
Put these together in function notation:
f(x) = 2.25x + 5
So, the equation is f(x) = 2.25x + 5
I’m new and i need help!!
Please help me of you know the answers.
Answer:
2, x, 2x
Step-by-step explanation:
A) 2
They are even numbers, so it is going to be 2.
B) x
It is going to only be x because the exponents are even and odd.
C) 2x
It is going to be 2x because the numbers are even but the exponents are even and odd.
Hope this helps.
If the number of observations for each sample is 150 units, what is the 3-sigma upper control limit of the process
Complete Question
Complete Question is attached below
Answer:
[tex]UCL= 0.25[/tex]
Step-by-step explanation:
From the question we are told that:
Sample size[tex]n=150[/tex]
Sample Variants [tex]s=7[/tex]
Sigma control limits [tex]Z = 3[/tex]
Therefore
Total number of observations is Given as
[tex]T_o=n*s[/tex]
[tex]T_o=150 *7[/tex]
[tex]T_0=1050[/tex]
Generally
Summation of defectivee
[tex]\sum np=23+34+15+30+25+22+18[/tex]
[tex]\sum np= 167[/tex]
Generally the equation for P-bar is mathematically given by
[tex]P-bar=\frac{\sum np}{T_o}[/tex]
[tex]P-bar=\frac{167}{1050}[/tex]
[tex]P-bar=0.16[/tex]
Therefore
[tex]Sp=\sqrt{\frac{P-bar(1-P-bar)]}{ n}}[/tex]
[tex]Sp=\sqrt{\frac{[0.159(1-0.159)]}{150}}[/tex]
[tex]Sp=0.03[/tex]
Generally the equation for 3-sigma upper control limit of the process is mathematically given by
[tex]UCL = P-bar + Z*Sp[/tex]
[tex]UCL= 0.16 + 3*0.03[/tex]
[tex]UCL= 0.25[/tex]
What is the volume of the prism? 2inches, 2 1/4 and 4 inches
Hi there!
»»————- ★ ————-««
I believe your answer is:
18in³
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
Assuming that the figure is a rectangular prism:
⸻⸻⸻⸻
[tex]\boxed{\text{Volume of a rectangular prism is:}}\\\\V = l * w * h\\-----------\\V = 2 * 2.25 * 4\\\\\boxed{V = 18}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Choose ALL of the following functions that represent exponential decay. f(x) = 5(2/3)^x
Answer:
exponential decay
Step-by-step explanation:
The function is in the form
y = ab^x where a is the initial value and b is the growth or decay rate
If b >1 then it is growth
b < 1 then it is decay
f(x) = 5(2/3)^x
a = 5
b = 2/3
2/3 <1 so it is decay
For a certain company, the cost for producing x items is 55x+300 and the revenue for selling x items is 95x−0.5x2.
Part A. Set up the expression
Part B. Find the values of x that create a profit of $300
Part C. Is it possible to profit $15,000
Answer:
The right answer is:
(A) [tex]40x-300.25[/tex]
(B) [tex]15[/tex]
(C) [tex]383[/tex]
Step-by-step explanation:
Given:
Producing x items,
= [tex]55x+300[/tex]
Revenue x items,
= [tex]95x-0.5^2[/tex]
= [tex]95 x-0.25[/tex]
Part A:
= [tex]R(x)-C(x)[/tex]
By putting the values, we get
= [tex](95x-0.25)-(55x-0.25)[/tex]
= [tex]40x-300.25[/tex]
Part B:
We know,
P(x) = $300
⇒ [tex]300=40x-300.25[/tex]
[tex]40x=600.25[/tex]
[tex]x=\frac{600.25}{40}[/tex]
[tex]=15.00625[/tex]
or,
[tex]=15[/tex]
Part C:
We know,
P(x) = $15,000
⇒ [tex]40x-300.25=15000[/tex]
[tex]40x=15300.25[/tex]
[tex]x=\frac{15300.25}{40}[/tex]
[tex]=382.50625[/tex]
or,
[tex]=383[/tex]
The values of x that create a profit of $300 is 60 or 20 items.
What is profit?Profit is the difference between revenue and cost, it is given by:
Profit = revenue - cost
a) From the situation:
Profit (P) = 95x−0.5x² - (55x + 300)
P = -0.5x² + 40x - 300
B) For a profit of $300:
-0.5x² + 40x - 300 = 300
-0.5x² + 40x - 600 = 0
x = 60 and x = 20
c) For a profit of $15000:
-0.5x² + 40x - 300 = 15000
-0.5x² + 40x - 15300 = 0
The equation cannot be solved
The values of x that create a profit of $300 is 60 or 20 items.
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It cost $52 to use 800 kWh of electricity. How much will 650 kWh cost?
Hello!
$52 ..... 800kWh
$x ..... 650kWh
_____________
52/x = 800/650 <=>
<=> 52 × 650 = 800x <=>
<=> 33800 = 800x <=>
<=> 800x = 33800 <=>
<=> x = 33800/800 <=>
<=> x = 338/8 <=>
<=> x = 169/4 <=>
<=> x = 42,25$
Good luck! :)
Omar keeps his sneaker collection carefully arranged on the floor of his closet. 8 pairs of
sneakers fit perfectly side-by-side from one end of the closet to the other. The closet is 60
inches wide.
How wide is each pair of sneakers?
Answer:
7.5 inches wide. I wasnt wrong. for a second i thought it was asking for the width of each individual sneaker.
Answer:
each pair of sneakers are 7.5 inches wide
Is the following shape a square? How do you know?
.8
C.
A
0
O A. No, the opposite sides are not parallel.
B. Yes, the opposite sides are parallel, and all sides are the same
length
O C. No, the sides are not congruent.
D. Yes, the adjacent sides are perpendicular, and all sides are the
same length
6,10,16,24,34 nth term can youll please find
Answer:
the next number is going to be46
Answer:
the next number will be 46
Where did this part came from how did this value came from
Answer:
Sin (theta) has the same value for the both value of theta, so both applies.
Answered by GAUTHMATH
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. P(X > 3), n = 5, p = 0.2
Answer:
0.0064
0.00032
Step-by-step explanation:
Given the details:
P(X > 3), n = 5, p = 0.2
The binomial distribution is related using the formula:
P(x = x) = nCx * p^x * q^(n-x)
q = 1 - p = 1 - 0.2 = 0.8
P(X > 3) = p(x = 4) + p(x = 5)
P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064
P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032
f(x)=-2x^2+x-5 find f(-6)
f(x) = 2x² + x - 5
f(-6) = 2(-6)² + (-6) -5
=> f(-6) = 2(36) -11
=> f(-6) = 72 - 11
=> f(-6) = 61
the expression -6x-7(4+3) is equivalent to?
Answer:
x(12y+4)
2 0 l e t t e r s
Are the following triangles similar by the angle-
angle similarity theorem?
A.No, the triangles don't have three angles.
B.Yes, one of the triangles is smaller than
the other.
C.Yes, two pairs of congruent angles are
marked.
D.No, the triangles don't share two pairs of
congruent angles.
Answer:
D. No, the triangles don't share two pairs of congruent angles.
Step-by-step explanation:
Two triangles can only be proven similar from the AA (Angle-Angle) similarity theorem if it can be deduced that they share two congruent angles.
In this case, both triangles share one angle, however no other angles can be deduced to be congruent. Therefore, the triangles cannot be proven similar from the AA similarity theorem because they do not share two pairs of congruent angles (corresponds with answer choice D).
Answer:
D.No, the triangles don't share two pairs of congruent angles.
Step-by-step explanation:
We know that angle M equals angle H and that angle I equals the unmarked angle.
We do not know that angle N equals angle O so we cannot state that the triangles are similar
Find the equation of the line through the points (-2,1) and (5,-20)
Answer:
y = -3x - 5
Step-by-step explanation:
First find the slope: (-20 - 1) / (5 - (-2)) = -3
Then plug in one set of points into the equation y = mx + b.
1 = -3(-2) + b
1 = 6 + b
b = -5
So you can get the equation: y = -3x - 5
Two buses leave towns 576 kilometers apart at the same time and travel toward each other. One bus travels 12
h
slower than the other. If they meet in 3 hours, what is the rate of each bus?
km
Rate of the slower bus:
Rate of the faster bus:
Answer:
Rate of slower bus; 90 km/h
Rate of faster bus; 102 km/b
Step-by-step explanation:
We know that formula do distance is;
Distance = speed/time
We are told that One bus travels 12h slower than the other.
Let speed of slower bus be x.
Thus;
Speed of faster bus = x + 12
Speed of slower bus = x
After 3 hours, distance by faster bus = 3(x + 12)
Speed of slower bus = 3x
Since the towns are 576 km apart, then;
3(x + 12) + 3x = 576
Divide through by 3 to get;
x + 12 + x = 192
2x + 12 = 192
2x = 192 - 12
2x = 180
x = 180/2
x = 90 km/h
Faster bus speed = 90 + 12 = 102 km/h
Vertical asymptotes and holes always occur at x values that are??
HELP PLEASE!!
Answer:
These asymptotes are very important characteristics of the function just like holes. Both holes and vertical asymptotes occur at x values that make the denominator of the function zero.
PLEASE ANSWER!!
What is the remainder for the synthetic division problem below?
2/ 3 1 2 -7
A. 25
B. 17
C. -29
D. -39
A: 25.
Explanation: Check the attached image.
For synthetic division, you just need to multiply the 1st number of the polynomial by the divisior, and then, add it up to the next number; then, the coefficient will be multiplied by the divisor, and so on and so forth until you reach the last number... that last coefficient at the end is the reminder that you've been asked for