Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score
of a man 72.4 inches tall. (to 2 decimal places)

Answers

Answer 1
Answer:  1.21

Work Shown:

z = (x - mu)/sigma

z = (72.4 - 69.0)/(2.8)

z = (3.4)/(2.8)

z = 1.2142857 .... which is approximate

z = 1.21

Answer 2

Z-score of a man who is 72.4 inches tall is 0.45.

Understanding the concept of the z-score helps us gauge how far a value is from the mean in terms of standard deviations.

A z-score, denoted as , measures the deviation of a data point from the mean in terms of standard deviations. It's calculated using the formula:

= ( - ) /

Where:

- is the value we want to find the z-score for (72.4 inches in this case).

- is the mean of the dataset (69.0 inches).

- is the standard deviation of the dataset (2.8 inches).

Plugging in the values:

= (72.4 - 69.0) / 2.8 = 1.25 / 2.8 ≈ 0.446

Rounded to two decimal places, the z-score is approximately 0.45.

This means that a man who is 72.4 inches tall is roughly 0.45 standard deviations above the mean height of adult men.

In other words, his height is a bit taller than the average height by about 0.45 times the standard deviation.

This positive value indicates that the man's height is above the mean. If the z-score were negative, it would mean the height is below the mean. By using z-scores, we can compare data points from different distributions and understand how unusual or typical a particular value is within its dataset.

Z-scores help us quantify the relative position of a data point, providing a standardized way to interpret its significance in the context of the dataset's characteristics.

In summary, the z-score of a man who is 72.4 inches tall is approximately 0.45, indicating that his height is slightly above the average height of adult men.

To know more about Z-Score here

https://brainly.com/question/33665002

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