All the following statements are true. Which one makes it possible to learn of the existence of extrasolar planets without seeing the planets themselves?Planets exert gravitational tugs on their stars that cause stars to orbit around the center of mass of their planetary systems.

Answer:

Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1

:. acceleration, a=v2+v1Δt ..(i)

When body falls from height h1,

then u=o,v1,a=gandS=h1

As, v21=u2+2aS,

:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1

Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2

As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2

Putting values in (i) we get,

a=2–√gh2+2–√gh1Δt)

a=2–√×9.8×3+2–√×9.8×40.01

= 1652m/s2.

Explanation:

Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.

Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.

The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.

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Important Formula:

[tex]s=\dfrac{d}{t}[/tex]

__________________________________________________________

[tex]d=85m[/tex] (measured in meters)

[tex]t=13s[/tex] (measured in seconds)

[tex]s=?[/tex] (measured in meters per second; m/s)

__________________________________________________________

[tex]s=\dfrac{d}{t}[/tex]

[tex]s=\dfrac{85}{13}[/tex]

__________________________________________________________

[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]

To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo

[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]

The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]

The given parameters:

- Applied force on the spring [tex]$=F$[/tex]

- Extension of the spring [tex]$=x_0$[/tex]

The work done by stretching the spring to the given distance is calculated as follows;

[tex]W=\frac{k x_0}{3}[/tex]

[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]

Thus, the work done by stretching the spring to the given distance is

[tex]W=\frac{k x_0}{3}[/tex]

measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

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The value of R so that the response is critically damped using the equation is 25.0Ω.

Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.

The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω

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The unit of G is found out to be m³/kg * s².

The force of gravitational attraction is represented by the equation.

F = (G m₁ m₂)/r²

where,

F is the magnitude of the gravitational attraction on either body

m₁ and m₂ are the masses of the bodies,

r is the distance between them

G is the gravitational constant

We need to find the unit of G,

G = (F * r²)/(m₁ m₂)

Let us place the units for the above formula,

G = (N * m²)/kg²

N = kg m/s²

G = (kg * m * m²)/ kg² * s²

G = m³/kg * s²

Thus, the correct option is m³/kg * s².

The question is incomplete. The complete question is 'Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.

F= Gm1 m2 /r^2

where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?

a. kg^3/ms^2

b. kgs^2/m^3

c. m^3/kgs^2

d. m/kgs^2

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Main Answer:

The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]

Explanation:

if the block will slide a distance 'L' then syoped;

The initial velocity given to the block is V m/s

So, Total K.E given will goes to gain in potential energy and work done by friction .

K.E=1/2mv^2

P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh

And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L

so,

KE+WD by friction = gain in P.E

[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]

Hence by solving we get :

[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L

So the distance = L

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The coefficient of static friction between feet and ground is 0.2522.

Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.

The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as

fs =μsFN1

The μs can be calculated as

μs = a / √L² - a² x d / L

μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95

μs = 0.945 / √2.91225 x 0.89 / 1.95

μs = 0.2522

Thus, the coefficient of static friction between feet and ground is 0.2522.

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The final velocity of the cannonball-cart system is less than the initial velocity of the cannonball and the system will move in the direction of the cannonball ( V < v_b ).

The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.

Mathematically, the law of conservation of linear momentum is given as;

Pi = Pf

where;

m₁u₁ + m₂u₂ = v ( m₁ + m₂ )

where;

since the cart is initially at rest, the initial velocity of the cart = 0

m₁u₁ + 0 = v ( m₁ + m₂ )

m₁u₁ = v ( m₁ + m₂ )

v = ( m₁u₁ ) / ( m₁ + m₂ )

given initial velocity of the cannon ball = v_b

The final velocity of the cannonball-cart system is calculated as follows;

V = ( m₁v_b ) / ( m₁ + m₂ )

Hence, V < v_b

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The mass-to-light ratio for a globular cluster is equal to 137.7 kg/lsun

To measure the mass-to-light ratio of a globular cluster, we first determine the total mass of the cluster. Since the cluster has 105 stars, and the average mass of a star in the cluster is 1 m-sun, therefore, the total mass of the cluster is 10^5 * 1 msun = 10^5 msun.

Now, we convert the luminosity of the cluster from solar units to kilograms. The luminosity of the cluster is given as 10^6 lsun, which is equal to 10^6 * 3.828 x 10^26 W.

Using the equation, [tex]E = mc^2[/tex], we can convert this energy to mass:

[tex]mass = (luminosity * time) / (c^2)[/tex]

where, c is the speed of light (3 x 10^8 m/s) and time is the amount of time over which the luminosity is measured (here, time is equal to 1 second).

Substituting the values in above equation, we find that the mass of the cluster in kilograms is approximately 1.45 x 10^31 kg.

To determine the mass-to-light ratio, divide the total mass of the cluster (in kilograms) by its luminosity (in solar units):

mass-to-light ratio = (total mass of cluster in kg) / (luminosity in solar units)

Substituting the values in above equation, we find that the mass-to-light ratio for this globular cluster is approximately:

1.45 x 10^31 kg / 10^6 lsun = 137.7 kg/lsun.

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I think it is "energy cannot be destroyed but it can change forms".

If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.

The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.

The equation of the Doppler effect is

f₀ = [(v ± v₀)/(v ± vs)] × fs

Where

Note:

When an object producing sound is moving away from us, the frequency of the sound we heard changed.

Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).

With the Doppler's effect, we get

f₀ = [(v+0) / (v+vs)] × fs

f₀/fs = v/(v+vs)

v < v+vs

f₀ < fs

The frequency of sound we heard is lower that the actual frequency.

The wavelength is inversely proportional to the frequency. It is described in the equation:

λ = c/f

It means that the lower the frequency, the longer the wavelength.

Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.

Here is the group of answer choices:

(a) Band width

(b) Doppler's effect

(c) Sound refraction

(d) Vibrations

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Answer:

18447 J

Explanation:

To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.

We can use the following equation to calculate the internal energy of steam at a given temperature:

U = m * Cp * (T - T_b) + m * L

Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.

Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.

First, we need to convert the temperature from degrees Celsius to kelvins:

T = 177°C + 273 = 450 K

Then, we can calculate the mass of the steam:

m = 1.2 moles * 18 g/mol = 21.6 g

Substituting these values into the equation for internal energy, we get:

U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg

Solving for the internal energy, we get:

U = 18,447 J

Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.

The fraction of its final impact speed is 1/√2.

Impact speed is the speed of the vehicle at the time of impact or collision.

The rock has lost half of its gravitational potential energy, its kinetic energy at the halfway point is half of its kinetic energy at impact.

As we know kinetic energy is directly proportional to mass (m) and velocity square (v²),

KE ∝ v²

KE = (1/2)mv²

then K.E at halfway point is equal to 1/2 x K.E,

Then,

The K.E at impact, then the rock’s speed at the halfway point its speed at impact will be 1/√2 its impact speed.

Therefore option D is the correct answer, the fraction of its final impact speed is 1/√2.

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The centripetal force needed to keep the fly from sleeping will be zero point 0.00176 Newton in magnitude.

The mass of the fly is 2 gram and it is selling itself on a phonograph turntable.

The fly is at a distance of 4 cm away from the center of the phonograph turntable and when the turntable is turned on and retreats with 45 Revolution per minute the centripetal force that would be working on the fly will be given by,

F = Mw²R

Where,

M is mass of the fly,

w is the angular speed of the fly and,

R is the radius of the turnable.

Putting all the values,

F = 0.002×(4.7)²×0.04

F = 0.00176N.

So, a centripetal force of magnitude 0.00176 Newton will be required in order to keep the fly from slipping.

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Complete question- A fly of mass 2.00 g is sunning itself on a phonograph turntable at a location that is 4.00 cm from the center. When the turntable is turned on and rotates at 45.0 rev/min, calculate the centripetal force needed to keep the fly from slipping?

Whenever the gases are heated at a fixed volume, no outside work is done as well as the heat energy given is simply used to make the gas more energetic internally.

The specific heat under constant pressure for an ideal gas, Cp, is higher than Cv.This is due to the fact that when the gas' temperature rises while the pressure stays constant, the gas must perform some finite work on its surroundings.

When the goal value and the specification's average are equal, Cpk equals Cp.Never can Cpk go above Cp.With the creation of descriptive statistic displays and histograms, Cp and Cpk can both be determined.

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A heat engine, symbolized by a circle in this illustration, uses some of the heat transfer to produce work.

The most effective heat engine that is theoretically possible—i.e., any machine that can transform thermal energy (heating) into mechanical energy—is the Carnot engine (work).The heat and cold reservoirs are the names given to the hot and cold items. Only the hot temperatures' absolute values affect efficiency. A portion of the heat QH that is extracted from the high-temperature source TH in the case of a heat engine is transformed into work. The ratio of net work completed to heat absorbed throughout one full cycle is known as a heat engine's thermal efficiency.

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D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.

A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.

The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.

Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.

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Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.

Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.

Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.

Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.

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If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .

it is given that a 5Ω resistor is connected between points X and Y ;

the magnetic field (B) = 0.5 ;

length of wire (l) [tex]=[/tex] 2 ;

velocity of the wire loop (v) = 3 m/s ;

the potential difference will be induced because charge separation on the vertical hand wire of wire loop.

Points X and Y are the same as the top and bottom of left wire.

The EMF(potential difference) induced in wire is given by

EMF = B*l*v

substituting the values ,

we get  

= (0.5)(2)(3) = 3V

Therefore , the induced potential difference between points X and Y is 3V .

The given question is incomplete , the complete question is

A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.

Determine the potential difference induced between points X and Y.

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Where the exercise here is to name the disorder, note that:

It should be mentioned that medication (such as antidepressants or benzodiazepines) and/or counseling may be used to treat a panic disorder such as cognitive-behavioral therapy.

A suitable course of treatment for dissociative disorders may involve counseling (such as cognitive-behavioral therapy, trauma-focused therapy, or psychodynamic therapy) and/or medication.

The focus of psychodynamic therapy is on unconscious processes as they show in the client's current behavior. Client self-awareness and knowledge of the effect of the past on present behavior are the aims of psychodynamic therapy.

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The centripetal acceleration of the mass m when it is at the lowest position is 10 m/s². The correct option is A.

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.

A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's trajectory.

The equation of projectile motion is:

[tex]V = \sqrt{2gh}\\\\\\V = \sqrt{2 \times 10 \times \dfrac{1}{2} } \\\\V = \sqrt{20}[/tex]

a² = v² / l  = 20 / 2 = 10 m/s²

Therefore, the correct option is A, 10 m/s².

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The question is incomplete. Your most probably complete question is given below:

The centripetal acceleration of the mass m when it is at the lowest position is:

10 m/s²

5 m/s²

20 m/s²

25 m/s²

The experimental procedures that will allow the students to determine both of these relationships is option E:

The formula  F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.

By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.

Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.

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Answer: 16 Pounds.

To figure out how much YOU would weigh on the moon, take your weight and divide it by 6. So, if you weighed 100 pounds on Earth, you would weigh only about 16 pounds on the moon.

The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D

We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.

We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.

With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.

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The force of gravity acting on the 23 Kg object in the diagram is 225.4 N

The force of gravity is defined as follow:

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Force of gravity = 23 Kg × 9.8 m/s²

Force of gravity = 225.4 N

Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N

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Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.

Step 2: Calculate the ratio after eliminating any constant values.

Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.

PV= nRT

However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.

T = PV/nR

The ideal gas law equivalency is used to compute the final temperature in the next two issues.

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The two level portions in the graph represented phase changes.

What are phase changes?

The transition of matter from one state (solid, liquid, gas, or plasma) to another is referred to as a phase change.  These changes also take place when the pressure on the system varies, as well as when the system receives enough energy or loses enough energy.

The slope of the line dividing two phases is determined by the relative densities of the two phases. The solid-liquid line, for instance, slopes up and to the right if the liquid is less dense than the solid, whereas up and to the left if the liquid is denser than the solid.

Therefore the two level portions in the graph represented phase changes.

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