Answer:
8.3 g
Explanation:
Step 1: Write the balanced equation
H₃PO₄ + 3 NH₃ ⇒ (NH₄)₃PO₄
Step 2: Calculate the moles corresponding to 5.5 g of H₃PO₄
The molar mass of H₃PO₄ is 97.99 g/mol.
5.5 g × 1 mol/97.99 g = 0.056 mol
Step 3: Calculate the moles of (NH₄)₃PO₄ produced
The molar ratio of H₃PO₄ to (NH₄)₃PO₄is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.056 mol = 0.056 mol.
Step 4: Calculate the mass corresponding to 0.056 moles of (NH₄)₃PO₄
The molar mass of (NH₄)₃PO₄ is 149.09 g/mol.
0.056 mol × 149.09 g/mol = 8.3 g
Rank the following series of molecules or ions in order of decreasing bond energy using their bond order to predict relative magnitude: chlorine: Cl2, sulfur: S2, phosphorus: P2.
Answer:
P2>S2>Cl2 is the order of bond energy of the given molecules.
Explanation:
The bonding in each molecule is shown below:
Thus, between each P-atom, there exists a triple bond.
Between two S-atoms there exists a double bond.
Between two chlorine atoms, there exists a single bond.
As the number of bonds increases between the given atoms, then bond energy required to break the bonds also increases.
Thus, the bond order is shown below:
[tex]P_2>S_2>Cl_2[/tex].
What type of energy does a skier stopped at the top of a hill have because of
his or her position?
A. Kinetic energy
B. Gravitational potential energy
C. Heat energy
D. Chemical energy
Answer:
B
Explanation:
Compound X has a molar mass of 266.64 g/mol and the following composition: aluminum 20.24% chlorine 79.76% Write the molecular formula of X
Answer:
Explanation:
Assume we have 100g of this substance. That means we would have 20.24g of Cl and 79.76g of Al. Now we can find how many moles of each we have:
[tex]\frac{79.76 \:g}{35.45 \: g/mol}[/tex] = 2.25 mol of chlorine
[tex]\frac{20.24 \: g}{26.98 \: g/mol}[/tex] = 0.750 mol of Al.
To form a integer ratio, do 2.25/0.75 = 2.99999 ~= 3.
So the ratio is essentially Al : Cl => 1 : 3. To the compound is possibly [tex]AlCl_3[/tex].
However, it says it has a molar mass of 266.64 g/mol, and since AlCl3 has a molar mass of 133.32, it must be [tex]Al_2Cl_6[/tex].
Actually this molecule isn't exactly AlCl3 (which is ionic). Al2Cl6 forms a banana bond where Cl acts as a hapto-2 ligand. But that's a bit advanced. All you need to know is X = Al2Cl6
The molecular formula of the compound is Al₂Cl₆
To solve the question given above, we'll begin by obtaining the empirical formula of the compound. This can be obtained as follow:
Aluminum (Al) = 20.24%
Chlorine (Cl) = 79.76%
Empirical formula =?Al = 20.24%
Cl = 79.76%
Divide by their molar mass
Al = 20.24 / 27 = 0.75
Cl = 79.76 / 35.5 = 2.25
Divide by the smallest
Al = 0.75 / 0.75 = 1
Cl = 2.25 / 0.75 = 3
Thus, the empirical formula of the compound is AlCl₃
Finally, we shall determine the the molecular formula of the compound.
Molar mass of compound = 266.64 g/mol
Empirical formula = AlCl₃
Molecular formula =? Molecular formula = [AlCl₃]ₙ = molar mass of compound[AlCl₃]ₙ = 266.64
[27 + (3×35.5)]n = 266.64
[27 + 106.5]n = 266.64
133.5n = 266.64
Divide both side by 133.5
n = 266.64 / 133.5
n = 2Molecular formula = [AlCl₃]ₙ
Molecular formula = [AlCl₃]₂
Molecular formula = Al₂Cl₆Therefore, the molecular formula of the compound is Al₂Cl₆
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Melanie has completed the analysis of her data for the reaction of KMnO4 with malonic acid and data for a reaction of KMnO4 with tartaric acid. She compared the activation energies, Ea, she calculated for the two reactions and found the Ea for the malonic acid reaction to be greater than the Ea for the tartaric acid reaction.
Required:
What does this mean about the magnitude of the rate constant, k, and the rate of the reaction?
Answer:
See explanation
Explanation:
The relationship between the activation energy and rate of reaction is best captured by the Arrhenius equation;
k= Ae^-Ea/RT
Where;
k= rate constant
A= pre-exponential factor
Ea=activation energy
R= gas constant
T= temperature
We can see from the foregoing that, as the activation energy increases, the rate of reaction decreases and vice versa. reactions that have a very high activation energy are markedly slow.
Since the activation energy for the malonic acid reaction is found to be greater than the activation energy for the tartaric acid reaction, then the rate of the malonic acid reaction(k) will be slower than that of the tartaric acid reaction.
The study of chemistry and bonds is called chemistry. There are two types of elements metal and nonmetals.
The correct answer is mentioned below.
What is the Arrhenius equation?The relationship between the activation energy and rate of reaction is best captured by the Arrhenius equationThe equation is as follows:-
[tex]k= Ae^{-Ea/RT[/tex] Where;
k= rate constantA= pre-exponential factorEa=activation energyR= gas constantT= temperatureWe can see from the foregoing that, as the activation energy increases, the rate of reaction decreases and vice versa. reactions that have very high activation energy are markedly slow. Since the activation energy for the malonic acid reaction is found to be greater than the activation energy for the tartaric acid reaction, then the rate of the malonic acid reaction(k) will be slower than that of the tartaric acid reaction.
Hence, the correct answer is mentioned above.
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Anyone can help me out please?!
For consumption of each gram of reactant released=37.9 kJ/g
Therefore, for consumption of 4kg of reactant heat released=37.9x4 kJ/g
What is the molality of a glucose solution prepared by dissolving 16.7 g of glucose, C6H12O6, in 133.6 g of water
Answer:
0.696 m
Explanation:
We'll begin by calculating the number of mole in 16.7 g of C₆H₁₂O₆. This can be obtained as follow:
Mass of C₆H₁₂O₆ = 16.7 g
Molar mass of C₆H₁₂O₆ = (6×12) + (12×1) + (6×16)
= 72 + 12 + 96
= 180 g/mol
Mole of C₆H₁₂O₆ =?
Mole = mass / molar mass
Mole of C₆H₁₂O₆ = 16.7 / 180
Mole of C₆H₁₂O₆ = 0.093 mole
Next, we shall convert 133.6 g of water to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
133.6 g = 133.6 g × 1 Kg / 1000 g
133.6 g = 0.1336 Kg
Thus, 133.6 g is equivalent to 0.1336 Kg.
Finally, we shall determine the molality of the solution. This can be obtained as illustrated below:
Mole of C₆H₁₂O₆ = 0.093 mole
Mass of water = 0.1336 Kg
Molality =?
Molality = mole / mass of water (in Kg)
Molality = 0.093 / 0.1336
Molality = 0.696 m
Therefore, the molality of the solution is 0.696 m
A sample of a compound is analyzed and found to contain 0.420 g nitrogen, 0.480g oxygen, 0.540 g carbon and 0.135 g hydrogen. What is the empirical formula of the compound? a. C2H5NO b. CH3NO c. C3H9N2O2 d. C4HN3O4 e. C4H13N3O3
Answer:
c. C3H9N2O2
Explanation:
The empirical formula of a compound is defined as the simplest whole number ratio of atoms present in a molecule. To solve this question we need to convert the mass of each atom to moles. With the moles we can find the ratio as follows:
Moles N -Molar mass: 14.01g/mol-
0.420g N * (1mol/14.01g) = 0.0300 moles N
Moles O -Molar mass: 16g/mol-
0.480g O * (1mol/16g) = 0.0300 moles O
Moles C -Molar mass: 12.01g/mol-
0.540g C * (1mol/12.01g) = 0.0450 moles C
Moles H -Molar mass: 1.0g/mol-
0.135g H * (1mol/1g) = 0.135moles H
Dividing in the moles of N (Lower number of moles) the ratio of atoms is:
N = 0.0300 moles N / 0.0300 moles N = 1
O = 0.0300 moles O / 0.0300 moles N = 1
C = 0.0450 moles C / 0.0300 moles N = 1.5
H = 0.135 moles H / 0.0300 moles N = 4.5
As the empirical formula requires whole numbers, multiplying each ratio twice:
N = 2, O = 2, C = 3 and H = 9
And the empirical formula is:
c. C3H9N2O2
If 13.50 mL of an aluminum chloride solution is needed to reach the equivalence point with 10.00 mL of 0.109 M silver nitrate solution, determine the molarity of the aluminum chloride solution.
Answer:
If 13.50 mL of an aluminum chloride solution is needed to reach the equivalence point with 10.00 mL of 0.109 M silver nitrate solution, determine the molarity of the aluminum chloride solution.
Explanation:
The balanced chemical equation of the reaction is:
[tex]AlCl_3(aq)+3AgNO_3(aq)->3AgCl(s)+Al(NO_3)_3(aq)[/tex]
So, one mole of aluminum chloride reacts with three moles of silver nitrate.
At the equivalence point,
the number of moles of each reactant must be equal.
The number of moles = molarity x volume in L.
Number of moles of AlCl3 = volume x molarity
=0.0135Lx Molarity
The number of moles of AgNO3 = 3 x 0.010Lx 0.109M
Thus,
0.0135Lx Molarity = 3 x 0.010Lx 0.109M
Molarity of AlCl3 :
[tex]Molarity of Alcl_3=3 x 0.010Lx 0.109M/0.0135\\=0.242M[/tex]
Answer is : 0.242M.
Write the net ionic equation for the reaction that occurs when equal volumes of 0.546 M aqueous acetylsalicylic acid (aspirin) and sodium acetate are mixed. It is not necessary to include states such as (aq) or (s).
Answer:
[tex]C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:
[tex]C_9H_8O_4+NaC_2H_3O_2\rightarrow C_2H_4O_2+NaC_9H_7O_4[/tex]
Whereas acetic acid and sodium acetylsalicylate are formed. Now, we write the complete ionic equation whereby sodium acetate and sodium acetylsalicylate are ionized because they are salts yet neither aspirin nor acetic acid are ionized as they are weak acids:
[tex]C_9H_8O_4+Na^++C_2H_3O_2^-\rightarrow C_2H_4O_2+Na^++C_9H_7O_4^-[/tex]
Finally, for the net ionic equation we cancel out the sodium spectator ions to obtain:
[tex]C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-[/tex]
Regards!
Jane performed the following trials in an experiment.
Trial 1: Heat 80.0 grams of water at 15.0 °C to a final temperature of 65.0 °C.
Trial 2: Heat 80.0 grams of water at 10.0 °C to a final temperature of 65.0 °C.
Which statement is true about the experiments?
The same amount of heat is absorbed in both the experiments because the mass is same.
The same amount of heat is absorbed in both the experiments because the final temperature is same.
The heat absorbed in Trial 2 is about 1,240 J greater than the heat absorbed in Trial 1.
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
Answer:
The heat absorbed in Trial 2 is about 1,240 J greater than the heat absorbed in Trial 1.
The heat absorbed in Trial 2 is about 1,674 J greater than the heat absorbed in Trial 1.
The amount of heat absorbed or released by a substance can be calculated using the formula Q = mcΔT, where Q represents heat, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the mass (m) is the same in both trials, but the initial and final temperatures (ΔT) differ. By comparing the values of ΔT in both trials, we can determine the difference in the amount of heat absorbed.
In Trial 1, the initial temperature is 15.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 15.0 = 50.0 °C.
In Trial 2, the initial temperature is 10.0 °C and the final temperature is 65.0 °C, resulting in a ΔT of 65.0 - 10.0 = 55.0 °C.
Since the specific heat capacity of water is approximately 4.18 J/g°C, we can calculate the difference in heat absorbed:
ΔQ = mcΔT = (80.0 g)(4.18 J/g°C)(55.0 °C - 50.0 °C) = 1,674 J
Therefore, the heat absorbed in Trial 2 is approximately 1,674 J greater than the heat absorbed in Trial 1.
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How much energy is released when 31.0 g of water freezes? The heat of fusion for water is 6.02 kJ/mol.
Express your answer in kilojoules to three significant figures.
Answer:
The molar heat of fusion for a given substance basically tells you how much heat is required to melt one mole of that substance at its melting point from two angles.
Explanation:
:)
The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. Decide, in each case, whether or not an insoluble precipitate is formed.
a. K2S and NH4Cl
b. CaCl2 and NH4CO3
c. Li2S and MnBr2
d. Ba(NO3)2 and Ag2SO4
e. RbCO3 and NaCl
Answer:
a) [tex]K_{2} S[/tex] and [tex]NH_{4} Cl[/tex] :
There are no insoluble precipitate forms.
b) [tex]Ca Cl_{2}[/tex] and [tex](NH_{4} )_{2} Co_{3}[/tex] :
There are the insoluble precipitates of [tex]CaCo_{3}[/tex] forms.
c) [tex]Li_{2}S[/tex] and [tex]MnBr_{2}[/tex] :
There are the insoluble precipitates of [tex]MnS[/tex] forms.
d) [tex]Ba(No_{3} )_{2}[/tex] and [tex]Ag_{2} So_{4}[/tex] :
As [tex]Ag_{2} So_{4}[/tex] is insoluble, therefore no precipitate forms.
e) [tex]Rb_{2}Co_{3}[/tex] and [tex]NaCl[/tex]:
There are no insoluble precipitates forms.
Explanation:
a)
Solubility rule suggests:- [tex]K_{2} S[/tex] ⇒ soluble, [tex]NH_{4} Cl[/tex] ⇒ soluble.
KCl ⇒ soluble, [tex](NH_{4})_{2} S[/tex] ⇒ soluble.
There are no insoluble precipitate forms.
b)
Solubility rule suggests:- [tex]Ca Cl_{2}[/tex] ⇒ soluble, [tex](NH_{4} )_{2} Co_{3}[/tex] ⇒ soluble.
[tex]CaCo_{3}[/tex] ⇒ insoluble, [tex]NH_{4} Cl[/tex] ⇒ soluble.
There are the insoluble precipitates of [tex]CaCo_{3}[/tex] forms.
c)
Solubility rule suggests:- [tex]Li_{2}S[/tex] ⇒ soluble, [tex]MnBr_{2}[/tex] ⇒ soluble.
[tex]LiBr[/tex] ⇒ soluble, [tex]MnS[/tex] ⇒ insoluble.
There are the insoluble precipitates of [tex]MnS[/tex] forms.
d)
Solubility rule suggests:- [tex]Ba(No_{3} )_{2}[/tex] ⇒ soluble, [tex]Ag_{2} So_{4}[/tex] ⇒insoluble.
As [tex]Ag_{2} So_{4}[/tex] is insoluble, therefore no precipitate forms.
e)
Solubility rule suggests:- [tex]Rb_{2}Co_{3}[/tex] ⇒ soluble, [tex]NaCl[/tex] ⇒ soluble.
[tex]RbCl[/tex] ⇒ soluble, [tex]Na_{2} Co_{3}[/tex] ⇒ soluble.
There are no insoluble precipitates forms.
A dehydration reaction starting with 3.0 g cyclohexanol produces 1.9 g cyclohexene. Calculate the theoretical yield for this reaction. Report your answer with two significant figures.
Answer:
77%
Explanation:
First we convert 3.0 g of cyclohexanol (C₆H₁₂O) to moles, using its molar mass:
Molar mass of C₆H₁₂O = 100.158 g/mol3.0 g ÷ 100.158 g/mol = 0.030 molThen we convert 1.9 g of cyclohexene (C₆H₁₀) to moles, using its molar mass:
Molar mass of C₆H₁₀ = 82.143 g/mol1.9 g ÷ 82.143 g/mol = 0.023 molFinally we calculate the theoretical yield:
0.023 mol / 0.030 mol * 100% = 77%The second law of thermodynamics requires that spontaneous processes generate entropy, either in the system or in the surroundings. What is the thermodynamic driving force for dissolving a solid in a liquid if it is an endothermic process (which reduces the entropy of the surroundings)
Answer:
See explanation
Explanation:
Truly, the second law of thermodynamics requires that spontaneous processes generate entropy, either in the system or in the surroundings.
When a solid is dissolved in a liquid, the solid dissociates into ions. These ions increases the number of particles and hence the entropy of the system thereby making the process spontaneous.
Hence, the dissolution of a substance via an endothermic process is spontaneous because of increase in the number of particles which in turn increases the entropy of the system.
What is the mass of a piece of iron if its density is 1.98 g/mL and its volume is 2.45 mL?
0.80 g
4.858
1.248
5.998
2.71 g
Answer:
4.858 g
Explanation:
Start with the formula
density = [tex]\frac{mass}{volume}[/tex]
density = 1.98 g/mL
volume = 2.45 mL
mass = ??
rearrange the formula to solve for mass
(density) x (volume) = mass
Add in the substitutes and solve for mass
1.98 g/mL x 2.45 mL = 4.858 g
Complete the table by assigning variable or fixed to the shape and volume of solids, liquids, and gases.
You are currently in a labeling module. Turn off browse mode or quick nav, Tab to items, Space or Enter to pick up, Tab to move, Space or Enter to drop.
Shape Volume
solids
liquids
gases
Answer Bank
Fixed or variable
The properties of solids, liquids and gases regarding their shapes and volumes are:
Shape Volume
Solids Fixed Fixed
Liquids Variable Fixed
Gases Variable Variable
Solids have strong attraction forces between their molecules. Thus, the molecules are closely packed with little movement. As a consequence, both shape and volume are fixed.
In liquids, attraction and repulsion forces are similar. They have a little more movement than the solid state. Then, they do have a fixed volume but they adopt the shape of the container.
Gases have very weak attraction forces between their molecules. They move very freely and expand trying to occupy as much volume as possible. So, they have a variable volume and shape (adopt the shape of the container).
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Gold’s natural state has a definite shape and a definite volume. What is gold’s natural state
If Gold's natural state has a definite shape and a definite volume, then its natural state is solid.
Identify each of the following properties as more typical of organic or inorganic compound
a. contains Li and F
b. is a gas at room temperature
c. contains covalent bonds
d. produces ion in water
this is the difference between organic and inorganic if this doesn't help you can research more on it
Please help thank you
Answer:
[tex]K=1.7x10^{-3}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:
[tex]K=\frac{[NO]^2}{[N_2][O_2]}[/tex]
Next, we plug in the given concentrations on the data table to obtain:
[tex]K=\frac{(0.034)^2}{(0.69)(0.98)}\\\\K=1.7x10^{-3}[/tex]
Regards!
The numerical value of 0.001 is written with the prefix:
Answer:
Milli, m.
Explanation:
Hey there!
In this case, according to the given information, it turns out possible for us to answer to this question by bearing to mind the attached file whereas the most common prefixes and their factors are shown both in standard and scientific notation.
In such a way, we will be able to infer that the prefix related to the numerical value of 0.001 is milli, m, for example 1 mm which is 0.001 m.
Regards!
here is the question
Answer:
1. Nitrate ions, NaNO3 - Sodium nitrate.
2. Sulphide ions, K2S - Potassium sulphide.
3. Sulphate ions, CaSO4 - Calcium sulphate.
4. Hydrogensulphite ions, NaHSO3 - Sodium hydrogensulphite.
5. Carbonate ions, CaCO3 - Calcium carbonate.
6. Hydrogencarbonate ions, KHCO3 - Potassium hydrogencarbonate.
7. Phosphite ions, PH3 - Hydrogen phosphite.
8. Nitride ions, NH3 - Hydrogen nitride ( ammonia ).
9. Ethanoate ions, CH3COONa - Sodium ethanoate.
10. Methanoate ions, HCOONa - Sodium methanoate.
11. Fluoride ions, HF - Hydrogen fluoride.
12. Chloride ions, KCl - Potassium chloride.
13. Bromide ions, HBr - Hydrogen bromide.
14. Iodide ions, NaI - Sodium iodide.
15. Phosphate ions, K3PO3 - potassium phosphate.
What is the relationship (formula) and proportionality
between frequency, and wavelength?
Answer:
Frequency and wavelength are inversely proportional. c=f⋅λ (The speed of light is directly proportional to f and λ)
How do I balance this equation? ?KClO3 → ?KCl + ?O2(g) and what type of reaction is it?
Explanation:
the reaction is a decomposition reaction since potassium hypochlorite is decomposed into potassium chloride and oxygen
In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 grams. If the % composition of the acetanilide impurity in the sample is 6.3 %, what is the minimum amount in mL of solvent (water) required for the recrystallization
This question is incomplete, the complete question is;
In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 grams. If the % composition of the acetanilide impurity in the sample is 6.3 %, what is the minimum amount in mL of solvent (water) required for the recrystallization
Compound Solubility in water at 25°C Solubility in water at 100°C
Benzoic Acid 0.34 g/100mL 5.6 g/100mL
Acetanilide 0.53 g/100mL 5.5 g/100mL
Answer:
The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL
Explanation:
Given the data in the question;
mass of sample = 5 g
percentage composition of the acetanilide impurity = 6.3%
mass of the acetanilide in impure sample will be;
⇒ 6.3% × 5 g = 0.315 g
Mass of benzoic acid in impure sample;
⇒ 5 g - 0.315 g = 4.685 g
now, solubility in water at 100°C for benzoic acid = 5.6 g/100mL
hence 4.685 g of benzoic acid is soluble in x mL
x = [ 100 mL × 4.685 g ] / 5.6 g
x = 83.66 ≈ 84 mL
Also, solubility in water at 100°C for acetanilide = 5.5 g/100mL
hence 0.315 g of benzoic acid is soluble in x mL
x = [ 100 mL × 0.315 g ] / 5.5 g
x = 5.727 ≈ 6 mL
So, the minimum amount in mL of solvent (water) required for the recrystallization will be;
⇒ 85 mL + 6 mL = 91 mL
The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL
Find the oxidation number of:
A. sulfur in S032-
B. nickel in NiO2
c. iron in Fe(OH)2
Answer:
A. 4+.
B. 4+
C. 2+.
Explanation:
Hey there!
In this case, according to the given substances, it turns out possible for us to find the oxidation number of each element by applying the concept of charge balance in all of them as shown below:
A. sulfur in S032- : overall charge is 2- and the oxidation number of oxygen is 2-, thus:
[tex]x-6=-2\\\\x=6-2\\\\x=4+[/tex]
B. nickel in NiO2 : overall charge is 0 and the oxidation number of oxygen is 2-, thus:
[tex]x-4=0\\\\x=4+[/tex]
C. iron in Fe(OH)2: overall charge is 0 and the oxidation state of the OH ion is 1-, thus:
[tex]x-2=0\\\\x=2+[/tex]
Regards!
Please help answering 46)
Answer:
CO2 is a trigonal planar.
For each of the scenarios, determine if the ionic strength of the solution would increase, decrease, or not change.
a. If a solution of HNO3 were added to a solution of KOH , the ionic strength of the KOH solution would:_________
1. Increase
2. Decrease
3. Not change
b. If a dilute solution of KOH were added to a solution of CaCl2 (Ca(OH)2 (s) is formed), the ionic strength would:
1. Increase
2. Decrease
3. Not change
Answer:
Increase
Decrease
Explanation:While in solution, ionic substances produce ions. The ions in solution determine the conductivity of the solution.
The ionic strength of a solution shows the concentration of ions in a given solution. The more the number of ions in the solution, the greater the ionic strength of the solution and vice versa.
When HNO3 is added to a solution of KOH, the number of ions in the solution increases and so does the ionic strength of the solution.
When KOH is added to a solution of CaCl2 then Ca(OH)2 is formed. The formation of a solid precipitate decreases the concentration of ions in solution as well as the ionic strength of the solution.
The standard enthalpies of combustion of fumaric acid and maleic acid (to form carbon dioxide and water) are - 1336.0 kJ moJ-1 and - 1359.2 kJ moJ-1, respectively. Calculate the enthalpy of the following isomerization process:
maleic acid ----> fumaric acid
Answer:
Explanation:
maleic acid ⇒ fumaric acid
ΔHreaction = ΔHproduct - ΔHreactant
ΔHproduct = -1336.0 kJ mol⁻¹
ΔHreactant = - 1359.2 kJ mol⁻¹.
ΔHreaction = -1336.0 kJ mol⁻¹ - ( - 1359.2 kJ mol⁻¹.)
= 1359.2 kJ mol⁻¹ -1336.0 kJ mol⁻¹
= 23.2 kJ mol⁻¹ .
Enthalpy of isomerization from maleic to fumaric acid is 23.2 kJ per mol.
A gas at 273K temperature has a pressure of 590 MM Hg. What will be the pressure if you change the temperature to 273K? 
Explanation:
here's the answer to your question
What is the volume of 1.5 moles of gas at STP ?
0 9.02 L
0 20.0 L
0 33.6 L
0 22.4L
The volume of 1.5 moles of gas at STP is 33.6 L.
Volume of the gas at STPThe volume of the gas at STP is calculated as follows;
I mole of gas at STP = 22.4 L
1.5 moles of the gas at STP = ?
= 1.5 moles x 22.4 L/mole
= 33.6 L
Thus, the volume of 1.5 moles of gas at STP is 33.6 L.
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