Answer:
Explanation:
I think it's insects. All the rest have some sort of spinal structure. They are classified as vertebrates (meaning they have a spinal structure).
Answer:
Mammals
Explanation:
Mammals are the odd ones out because they do not lay eggs. Unlike amphibians, fish, birds, reptiles, and insects, which do lay eggs.
In the Vector Addition Lab, the following data was collected for determining the displacement from the door of the Physics classroom to another location in the building: 2 m, West; 14.0 m, South; 25.0 m, East; 11.0 m, North; and 2 m, West. The magnitude of the resultant displacement from the physics classroom to the assigned location is closest to ___ meters. (Round to the nearest integer.)
Answer:
21 m
Explanation:
Since the displacement from the door is 2 m West, we have our vector as -2i. The vector representing 14.0 m South is -14.0j. The vector representing 25.0 m East is 25.0i. The vector representing 11.0 m North is 11.0j. And, the vector representing 2.0 m West is -2.0i.
So, to get our position vector at the other location, we add all the vectors together.
So, r = -2i + (-14.0j) + 25.0i + 11.0j - 2i
= -4i + 25.0i - 14.0j + 11.0j
= 21.0i -3j m
Now, if we assume the position vector for the door is at the origin, we have r₀ = 0i + 0j m
So, our displacement from the door is r - r₀ = 21.0i - 3.0j - (0i + 0j) = 21.0i - 3.0j
So, the magnitude of the resultant displacement |r - r₀| = √(21.0² + 3.0²)
= 3.0√(7.0² + 1)
= 3.0√(49 + 1)
= 3.0√50
= 3.0 × 7.0711
= 21.2
≅ 21 m to the nearest integer
A motor has an internal resistance of 12.1 Ω. The motor is in a circuit with a current of
4.0 Amps
What is the voltage?
Answer:
Explanation:
V = I * R
V = 4 * 12.1 = 48.4 v
The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to raise the temperature of 0.900 kg of this sea water from 10 °C up to its boiling point. Also mention the equation to be used. *
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).
Choose the incorrect statement about the proton: Group of answer choices The proton has the atomic mass of 1 amu The proton has the same charge as the neutron. The proton has greater mass than an electron The proton and the neutron have approximately the same atomic mass
Answer:
The proton has the same charge as the neutron.
Explanation:
Because the proton has a positive charge whereas the neutron has no charge at all.
PLSSSSS HELPPPPP
Consider the potential energy diagram shown below. This graph shows the chemical potential energy in a reaction system over time. The y-axis is potential energy in kilojoules. The x-axis is the reaction progress, or time.
The far left part of the curve is horizontal and has an energy value of 50 kJ. The curve then rises to a peak of 250 kJ before falling to a horizontal region at 200 kJ.
Does this graph represent an endothermic or an exothermic reaction? Explain your answer.
What is the enthalpy change, ΔH, for this reaction? Show your work.
What is the activation energy, Ea, for this reaction? Show your work.
In a particular chemical reaction, the energy of the reactants is 30 kJ and the energy of the products is 5 kJ. The maximum energy of the system is 40 kJ.
Sketch a potential energy diagram for this reaction. Make sure to label the energy of the reactants, the energy of the products, the activation energy, and the enthalpy change for the reaction.
What is the activation energy for this reaction?
What is the enthalpy change for this reaction?
Is this reaction endothermic or exothermic? Explain your answer in two ways: first, using the energy values, and second, by referring to the shape of the graph.
The coating on the head of a match is highly flammable. When it burns, it releases a great deal of energy. However, before the match can burn, it must gain a small amount of energy from a spark. That spark is typically produced by striking (rubbing) the match head against a rough surface. Sketch and describe a potential energy diagram that represents the striking and burning of the match. Remember to label the diagram with the energy changes that occur. Your answer must include the potential energy diagram and a written description. (Note: you do not have to use actual energy values.)
Answer:
A. Endothermic reaction.
B. +150KJ.
C. 250KJ.
Explanation:
A. The graph represents endothermic reaction because the heat of the product is higher than the heat of the reactant.
B. Determination of the enthalpy change, ΔH for the reaction. This can be obtained as follow:
Heat of reactant (Hr) = 50KJ
Heat of product (Hp) = 200KJ
Enthalphy change (ΔH) =..?
Enthalphy change = Heat of product – Heat of reactant.
ΔH = Hp – Hr
ΔH = 200 – 50
ΔH = +150KJ
Therefore, the enthalphy change for the reaction is +150KJ
C. The activation energy for the reaction is the energy at the peak of the diagram.
From the diagram, the activation energy is 250KJ.
how can you account for the differences in the entropies of combination of methyl propane (-1465J/mol K) and butane (1465J/mol K)
Explanation:
The change in entropy is a measure of temperature. When the temperature of a compound or a system increases, there will be more randomness in the system.
The boiling point is directly related to the number of carbon atoms but is indirectly proportional to the branching in a hydrocarbon.
Butane and methyl propane, both have 4 carbon atoms.
But, butane has 4 carbon atoms in a straight chain while methyl propane has 3 carbon atoms in a straight chain and 1 methyl substituent which makes it a branched hydrocarbon.
Thus, the boiling point of methyl propane will be less than the butane. Likewise, the pattern in entropies will be seen.
A meterstick is placed on a pivot point of 42.5cm and a 45g mass is hung at the 20cm mark. When released the meterstick remains in static equilibrium. What is the mass of the meterstick
A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by the wall?
A. The ball experiences more force than the wall.
B. The ball experiences less force than the wall.
The ball and the wall experience the same force.
D. The ball experiences half the force of the wall.
Reset
Next
Answer:
The ball and the wall experience the same force.
Explanation:
According to the third law of Newton, which states that "for every action, there is an equal and opposite reaction", this means that when an object 1 acts on object 2 with a certain force, object 2 also acts on object 1 with the same magnitude of force but in an opposite direction.
According to this question, a ball hits a wall with a certain force. This means that the wall will react on the ball with the same force magnitude, but in an opposite manner. Hence, the ball and the wall experience the same force.
Calcalculate potential energy given to a potato sack having a mass of 2 kg as I raise it to a height of 450 CM
Answer:
8.829 Joules
Explanation:
The potential energy of an object, is the energy it posses (the energy stored within the object) by virtue of its relative elevation or height, position, state, or arrangement
The potential energy of an object raised to a given height, P.E. = m·g·h
Where;
m = The mass of the object
g = The acceleration due to gravity, a constant ≈ 9.81 m/s²
h = The present height of the object
For the potato sack having a mass, m = 2 kg, and raised to a height, h = 450 cm = 0.45 m, we have;
The potential energy given to the potato sack, by raising its height, P.E. is given as follows;
P.E. = 2 kg × 9.81 m/s² × 0.45 m = 8.829 Joules
The potential energy given to the potato sack, P.E. = 8.829 Joules
Amelia is doing an experiment in which she is
going to burn various solid chemicals to see the
colors of flames they produce. For this laboratory
experiment, what types of safety precautions
should she take?
tie hair back
leave open flame unattended to get a drink
only burn the amount of chemicals as
directed by the lab procedure
put out the flame with water from the eyewash
station
Answer:
tie hair back
only burn the amount of chemicals as
directed by the lab procedure
Explanation:
The correct safety precautions for Amelia to take from the options would be to tie her hair back and to only burn the amount of chemicals recommended by the lab procedure.
With her hair left flowing freely, Amelia runs the risk of the hair catching flame while trying to burn the chemicals according to the procedure. Hence, tying her hair up into one neat bunch will limit the risk of it catching fire while working in the lab.
Also, burning less or more than the amount of chemicals recommended by the procedure may be dangerous or hinder Amelia from getting the right result.
Answer:
1,3
Explanation:
just did it
PLEASE HELP WITH THIS QUESTION
What of Newton's 3 laws is represented in this picture?
Answer:
The first law states that an object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force. Mathematically, this is equivalent to saying that if The second law states that the rate of change of momentum of a body over time is directly proportional to the force applied, and occurs in the same direction as the applied force. the net force on an object is zero, then the velocity of the object is constant. The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction
Explanation:
A test car and its driver, with a combined mass of 600 kg, are moving along a straight,horizontal track when a malfunction causes the tires to stop rotating. The car skids to a halt with constant acceleration, leaving skid marks on the road during the whole time it skids. Which two of the following measurements, taken together, would allow engineers to find the total mechanical energy dissipated during the skid?
A. The length of the skid marks
B. The contact area of each tire with the track.
C. The coefficent of static frction between the tires and the track.
D. The coefficent of static frction between the tires and the track.
Answer:
The two of the following measurements, when taken together, would allow engineers to find the total mechanical energy dissipated during the skid
B. The contact area of each tire with the track.
C. The co-efficent of static friction between the tires and the track.
D. The co-efficent of static friction between the tires and the track.
Explanation:
A piece of iron has a mass of 30 g and its volume is 6.2 cm3. What is its density?
Answer:
Density = 4.84 g/cm³
Explanation:
Given the following data;
Mass = 30 g
Volume = 6.2 cm³
To find the density of the piece of iron;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Substituting into the equation, we have;
[tex]Density = \frac{30}{6.2}[/tex]
Density = 4.84 g/cm³
You hear the dishwasher with a loudness of 40 dB and a siren outside
with a loudness of 60 dB. How much greater is the amplitude of the
siren's sound than the amplitude of the dishwasher's sound?
Answer:
The ratio of the amplitudes of siren to dishwasher is 10.
Explanation:
loudness of dishwasher = 40 dB
loudness of siren = 60 dB
let the intensity of dishwasher is I an the intensity of siren is I'.
Use the formula of intensity and decibels.
[tex]dB = 10 log\frac{I}{I_o}\\\\40=10 log\frac{I}{I_o}\\\\4 = log\frac{I}{I_o}\\\\I = 10000 I_o[/tex]
And
[tex]60=10 log\frac{I'}{I_o}\\\\60 = log\frac{I'}{I_o}\\\\I' = 1000000 I_o[/tex]
The intensity if proportional to the amplitude.
[tex]\frac{A'}{A}=\sqrt\frac{1000000}{10000}\\\\\frac{A'}{A}= 10[/tex]
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutionsAt what rate is the flywheel spinning when the power comes back on(in rpm)
Complete Question
A flywheel in a motor is spinning at 510 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75.0 cm . The power is off for 40.0 s , and during this time the flywheel slows down uniformly due to friction in its axle bearings. During the time the power is off, the flywheel makes 210 complete revolutions. At what rate is the flywheel spinning when the power comes back on(in rpm)? How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on, and how many revolutions would the wheel have made during this time?
Answer:
[tex]\theta=274rev[/tex]
Explanation:
From the question we are told that:
Angular velocity [tex]\omega=510rpm[/tex]
Mass [tex]m=40.kg[/tex]
Diameter d [tex]75=>0.75m[/tex]
Off Time [tex]t=40.0s[/tex]
Oscillation at Power off [tex]N=210[/tex]
Generally the equation for Angular displacement is mathematically given by
[tex]\theta_{\infty}=\frac{w+w_0}{t}t[/tex]
[tex]w=\frac{2*\theta_{\infty}}{t}-w_0[/tex]
[tex]w=\frac{28210}{40*(\frac{1}{60})}-510[/tex]
[tex]w=120rpm[/tex]
Generally the equation for Time to come to rest is mathematically given by
[tex]t=(\frac{\omega_0}{\omega_0-\omega})t[/tex]
[tex]t=(\frac{510}{510-120rpm})(40.0)(\frac{1}{60})[/tex]
[tex]t=0.87min[/tex]
Therefore Angular displacement is
[tex]\theta =(\frac{120+510}{2})0.87[/tex]
[tex]\theta=274rev[/tex]
A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2. The acceleration of the plane is 4.9
What is the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline?
Answer in units of N.
Answer:
Explanation:
What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:
w = mg so
w = (4.04)(9.8) and
w = 4.0 × 10¹ N
The magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
The given parameter are:
mass M = 4.04 kg
Angle of inclination = 30 degree
Acceleration due to gravity = 9.8 m/s^s
To calculate the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the plane, The force will be the weight of the block which is equal to the normal reaction.
Normal N = mgcosФ
N = 4.04 x 9.8 x cos30
N = 34.28 Newtons
At all point in the plane, the magnitude of the perpendicular force that the block exerts on the surface of the plane will be the same.
Therefore, the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
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A positively charged rod is brought close to a neutral metal sphere. Explain what
happens to the charges in the neutral sphere as the rod comes close, touches the
sphere, and then moves away. Is the metal sphere still neutral at the end of this
encounter?
Answer:
No, the metal sphere becomes positively charged because electrons are transferred from the sphere to the rod.
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscillations. What can we say, about these springlike bonds when the charge is first, furthest away and second, closest to the source charge
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source when Furthest away the bond with charge will be less effective
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of the rectangle. How would you find the electric potential?
Answer:
With the help of formula.
Explanation:
We can calculate the electric potential of any point through the formula of electric potential which is given below.
Electric potential = Coulomb constant x charge/ distance of separation.
Symbolically it can be written as, V = k q/ r where
V = electric potential
k = Coulomb constant
q = charge
r = distance of separation
If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.
What is the amount of change in an object's momentum equal to?
A.
The amount of mass applied to the object over a certain amount of time
B.
The amount of force applied to the object over a certain amount of time
C.
The amount of acceleration applied to the object over a certain amount of time
D.
The amount of energy applied to the object over a certain amount of time
answer:
Explanation:
the impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it. The impulse-momentum theorem is logically equivalent to Newton's second law of motion (the force law).
According to the impulse-momentum theorem, the amount of change in an object's momentum equal to the amount of force applied to the object over a certain amount of time. So, option B.
According to the impulse-momentum theorem, the impulse that is applied to an item is equal to the change in momentum.
It shows how an object's change in momentum depends on both the strength and duration of the applied forces.
Impulse is defined as the force acting for a short interval of time.
Impulse = F x t
The momentum of the object,
P = mv
So, the rate of change of momentum,
dP/dt = d(mv)/dt
dP/dt = mdv/t
dP/dt = ma = Force
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Which variable is represented by the following symbol? λ
a. Wavelength
b. Amplitude
c. Frequency
d. Velocity
Answer:
A
Explanation:
Wavelength is represented by lambda
Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
Why is using the same cutting and knife for both
cooked and uncooked food not a drisable?
Answer:
It spreads diseases.
Explanation:
But when cooked food is kept on the place where uncooked meat or food was kept the germs spread to the cooked food also and as the cooked food cannot be washed it harms us as we directly consume it.
A car has a kinetic energy of 103kJ.
The speed of the car is 13.1 m/s.
Calculate the mass of the car.
Give your answer to 2 significant figures.
Answer: 1200kg
Explanation:
KE = (1/2)mv^2
103kJ = 103000J
103000J = (1/2) * m * (13.1m/s)^2
Solve for m
A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,
The kinetic energy of the car = 1/2 × mass × velocity
103000 =0.5 × mass × (13.1) ²
The mass of the car = 1200 Kilogram
Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
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please helpppp... thank u ❤️
Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
if a car is taken from the garage driven for 100km before returning to the garage after 2 hours what is it average speed?
Answer:
50km/h
Explanation:
Average Speed = Distance/Time
100km/2h = 50km/h
A 75kg hockey player is skating across the ice at a speed of 6.0m/s. What is the magnitude of the average force required to stop the player in 0.65s?
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
What 3 things does the force of gravity depend on?
Answer:
Size of an object, and the distance between the objects.
When the mass of an object increases the force of gravity increases as well.
Explanation:
The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.
I just... I don't know man I suck at physics :(
A tour guide shouts across a canyon. At a temperature of 20 °C, her echo is heard 2.00 s later. How wide is the canyon?
The answer is 340 m I just don't know how to get that....
Explanation:
Sound travels from the tour guide to the other of the canyon and then back, thus hearing the echo. The time of 2.0 s represents the time it takes the sound to make a round trip, therefore it takes 1.0 s for the tour guide's voice to reach the other side of the canyon. At 20°C, the speed of sound is 343 m/s therefore the width of the canyon is
[tex]x = vt = (343\:m/s)(1.0\:s) = 343\:m[/tex]
The canyon in the given question is 340 m wide.
What is echo?Echo is a reflection of sound that comes to the listener after the direct sound, but with a delay. The delay is inversely proportional to the separation between the source and the listener of the reflecting surface.
To hear the echo, the following conditions must be met:
There must be a minimum of 17 meters between the sound source and the reflecting surface, and there must be at least 0.1 seconds between the original sound and its echo.
Given parameters:
When a tour guide shouts across a canyon, her echo is heard 2.00 s later. That means, in two seconds the sound goes to other wall of canyon and reflected back.
At a temperature of 20 °C, velocity of sound is 340 m/s.
So, the wide is the canyon be = velocity of sound × time/2
= 340 m/s ×2 s/2s = 340 m.
Hence, the wide is the canyon be 340 m.
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