An 69-kg jogger is heading due east at a speed of 1.6 m/s. A 63-kg jogger is heading 14 ° north of east at a speed of 1.5 m/s. Find (a) the magnitude and (b) the direction of the sum of the momenta of the two joggers. Describe the direction as an angle with respect to due east.

Answers

Answer 1

Answer:

[tex]P=203.3819375kg.m/s\\P\approx203.4kg.m/s[/tex]

[tex]\theta=6.4541\textdegree North East\\\theta\approx6.5\textdegree North East[/tex]

Explanation:

From the question we are told that

Mass of first jogger [tex]M=69kg[/tex]

Speed[tex]v_1=1.6m/s[/tex]

Direction [tex]d= East[/tex]

Mass of 2nd jogger [tex]M=63kg[/tex]

Speed [tex]v_2=1.5m/s[/tex]

Direction [tex]d= 14\textdegree north[/tex]

Generally equation for momentum along the the horizontal is mathematically given as

[tex]P_x=m_1v_1 +m_2v_2cos\theta[/tex]

[tex]P_x=(69)*(1.6) +(63)*(1.5)cos14[/tex]

[tex]P_x=202.0929461kg.m/s[/tex]

Generally equation for momentum along the the vertical is mathematically given as

[tex]P_y=m_2v_2cos\theta[/tex]

[tex]P_x=22.86161913kgm/s[/tex]

a)Generally the magnitude of momentum is mathematically given by

[tex]P=\sqrt{(P_x)^2+(P_y)^2}[/tex]

[tex]P=\sqrt{(202.0929461)^2+(22.86161913)^2}[/tex]

[tex]P=\sqrt{41364.21249}[/tex]

[tex]P=203.3819375kg.m/s[/tex]

[tex]P\approx203.4kg.m/s[/tex]

b) Generally the angle [tex]\theta[/tex] is mathematically given by

[tex]\theta=tan^-^1\frac{py}{px} \\[/tex]

[tex]\theta=tan^-^1\frac{22.86161913}{202.0929461}[/tex]

[tex]\theta=tan^-^1(0.1131242805)[/tex]

[tex]\theta=6.4541\textdegree North East[/tex]


Related Questions

Select ALL of the places you might find DNA evidence.
saliva on gum
blood spatter on the wall
inside a femur bone found in the woods
cells on root of hair found at the scene

Answers

Answer:

Inside a femur bone found in the woods,

saliva of gum

Find the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees.

Answers

Answer:

0

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

 Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

velocity of sound in solid is more than that in liquid.why?​

Answers

Velocity of sound travels faster in solids than in liquids, and faster in liquids than in gases because "the density of solids is higher than that of liquids, meaning that the particles are closer together."

Answer:

Explanation:

Due to the fact that sound is caused by vibrations, it's more noticeable in liquid because the vibrations may cause ripples in the liquid

If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, what is being done? compression work radiation energy creation

Answers

Answer: work

Explanation:

When Jerome swings on a rope and hence this leads to the transfer of energy from the gravitational potential energy to a kinetic energy, this implies that work is being done.

For work to be done, it simply means that one has to transfer energy from one particular form to another form. In this case, the energy was transferred from the gravitational potential energy to a kinetic energy.

Answer:

work

Explanation:

A person runs 15.0 km north then turns around and runs 10.0 Km south. what is his dstance

Answers

Answer:

25km

Explanation:

The person runs 15km Northward

 Turns around and runs 10km southward

The distance is the length of path covered by the person running.

This is given as:

 Distance  = Distance North + Distance South

Distance  = 15km + 10km  = 25km

Answer:

25km

Explanation:

cant explain but ik

A body with mass 2 kg absorbs heat 418.4J when its temperature raises from 293K to 343K . What is the specific heat of the body?

Answers

Answer:

C M (change in T) = heat absorbed      thermal equation for heat gained

C = 418.4 J / (2 kg * 50 deg K) = 4.184 J / kg * deg K     specific heat

Note: 1 gm =.001 kg

So C = .004184J / gm * deg K

Also, 1 J = .239 cal   so in conventional terms

C = .001 cal / gm deg K     (very low, water would be 1 cal / gm deg C

Does someone have hamster name recommendation (girl hamster)

Answers

Explanation:

Lola

Or Jasmine

Or lucy

Or Nightingale

Or Sugarcane

Or Polly

Or Heather

Some names I like!

A student pulls a block across the desk in physics class. He applies 14N of
tension in the string, but friction holds the box back with 4N. His partner
measures the acceleration of the box across the desk to be 2m/s2. What
must the mass of the box be?
100 Pointsss hellppp

Answers

can you please show a picture

A box weighs 1300 N. When a horizontal force of 390 N has applied the box accelerates at 1.3 m/s2. What is the magnitude of the frictional force?

Answers

Answer:

Ffriction = 217.7[N]

Explanation:

First, we must find the mass of the box, we must remember that the weight is defined as the product of the mass by acceleration.

[tex]w=m*g[/tex]

where:

w = weight [N] (units of Newtons)

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]1300=m*9.81\\m=132.51[kg][/tex]

Now we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F sum of forces

m = mass = 132.51[kg]

a = acceleration = 1.3[m/s²]

We must know that the forces that act are the horizontal force that moves the box and the friction force in the negative direction that acts against the movement.

Now replacing:

[tex]390-f_{friction}=132.51*1.3\\390-172.26=f_{friction}\\f_{friction}=217.7[N][/tex]

if an object is projected upwards with an angle 30 to the horizontal and its initial velocity is 20 m/s, its maximum height= ? ( consider g= 10m/s^2 )

Answers

Answer:

[tex]h_m=5 \ m[/tex]

Explanation:

Projectile Motion

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path under the action of gravity.

The maximum height hm is reached when the vertical component of the velocity is 0. It can be calculated as follows:

[tex]\displaystyle h_m=\frac{v_o^2\cdot \sin^2\theta}{2g}[/tex]

Where:

vo = initial speed of the object

θ   = initial launch angle

g   = acceleration of gravity ([tex]10\ m/s^2[/tex])

The object is projected with an angle of θ=30° and an initial speed of vo=20 m/s. The maximum height is:

[tex]\displaystyle h_m=\frac{20^2\cdot \sin^2 30^\circ}{2*10}[/tex]

[tex]\displaystyle h_m=\frac{400\cdot 0.5^2}{20}[/tex]

[tex]\boxed{h_m=5 \ m}[/tex]

4. A toy car travels 60 m during 5.7 s at a constant speed. What is the speed of the toy car?
15.556
13.526
6.116
10.526
None of these is correct.

Answers

Answer: 10.526m/s

Explanation:

The speed of the toy car would be calculated as the distance travelled by the toy card divided by the time taken. This will be:

= Distance travelled / Time taken

= 60/5.7

= 10.526m/s

The speed of the toy car is 10.526 meters per second.

Please help me this is worth allot

Answers

The answer is “a joule”

An object moving at a constant velocity accelerates at a constant rate of 2.5 m/s2 for a distance of 30 m. At the end of the acceleration the object has a velocity of 90 m/s. What was its velocity before accelerating?

Answers

Answer:

The initial velocity is 89.16m/s

Attached is the solution

Explanation:

An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points

Answers

Answer:

d = 4[m]

Explanation:

Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.

[tex]T=F*d[/tex]

where:

T = torque [N*m]

F = force [N]

d = distance [m]

Now replacing in the equation above.

[tex]84=21*d\\\\d= 4[m][/tex]

Hi!! Does anyone know this answer? :D

Answers

Answer:

Im not fully corrrect but I would say C

Explanation:

A body moving in simple harmonic motion has an amplitude of 10cm and a frequency of 100Hz. Find i.mthe period of oscillation, ii. the acceleration at the maximum displacement, iii. the velocity at the centre of motion​

Answers

Explanation:

= 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

When displacement is y, then acceleration, a=−ω2y

Velocity, V=ωr2−y2

Case (a)    When y=5cm=0.05m

a=−(10π)2×0.05=−5π2m/s2

V=10π×(0.05)2−(0.05)2=0

Case (b)    When y=3cm=0.03m

a=−(10π)2×0.03=−3π2m/s2

V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s

Case (c)    When y=0

a=−(10π)2×0=0

V=10π×(0.05)2−02=

hope it helps. pls follow and mark as brainliest

Please help i don't get it.
Which image matches the Topographic Map Shown?
Also, please explain how your answer is the correct answer. Why is your answer correct?

Answers

Answer:

the answer is 4

Explanation:

the picture matches eachother that's why I picked 4

Answer:

devils tower

Explanation:

on the topographic map the circular lines stop at at certain point because the moutain doesnt get any pointyer if you know what that means

in other words if the map continued with the circular lines all the way to the centerit would have been that snowny mountain

A 10.0kg box sits at rest on ramp that has an incline of 20.0° from the horizontal. What is the force of gravity acting on the box?

A. -98.0N

B. 98.0N

C. -92.1N

D. -33.5N

Answers

I think it would be d

Answer:

98.0N

Explanation:

An electromagnetic wave is composed of electrical and magnetic energy.


Please select the best answer from the choices provided

T
F

Answers

Answer:

the answer is T!!

!!!!!!!!

Answer:

true

Explanation:

hope this helps

Janet jumps off a high diving platform with
a horizontal velocity of 2.6 m/s and lands in
the water 1.5 s later.
How far from the base of the platform
does she land? The acceleration of gravity
is 9.8 m/s?
Answer in units of m.

Answers

Answer:

11.025m

Explanation:

In this question there is no vertical velocity,

t= 1.5s

Height of platform=h

From Newton equation

s = ut + 1/2gt^2

But there is no vertical velocity,

Hence,

Then u=0

h = 0 + 1/2 x 9.8 x (1.5)^2

h = 11.025m

Henry designs an experiment to find out why plants without flowers tend to be wind-pollinated and not animal-pollinated. He takes samples from a variety of plants and studies them in the field. He finds that the evidence supports his hypothesis. Which of these was the hypothesis Henry was testing? Choose the correct answer. Nonflowering plants make less pollen than flowering plants. Nonflowering plants lack the structures to attract animal pollinators. Nonflowering plants grow close to the ground and capture fewer pollinators. Nonflowering plants grow close to the ground because they have no pollen grains.

Answers

Answer:

option 2

Explanation:

you are very welcom

Which idea did Ptolemy's model use to explain why the planets appeared to move backward as they moved in their orbits? The planets spun in epicycles. The planets rotated on their axes. The planets revolved around the Sun. The planets were made of different materials.

Answers

Answer:

The planets spun in epicycles.

Explanation:

The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.

Answer:A

Explanation:

What is the same about a particle as gas, liquid, or solid?
A. The speed at which the particles move.
B. The volume that the substance takes up.
C. The chemical composition.
D. The temperature of the substance.

Answers

I am pretty sure the answer is c using process of elimination.

The thing same about a particle as gas, liquid, or solid is its chemical composition.

What are states of matter?

Matter exists in three different states: solid, liquid, and gas. By examining the configuration of their particles, it is possible to understand why they have various qualities. Theoretically, at this temperature, particles move slowly and have the least amount of energy.

Phase refers to the material's actual state. To pay attention to is the word physical. Only physical means can change the state of matter. You can make a physical change if energy is added (by raising the temperature) or subtracted (by freezing things).

The chemical composition of matter same about a particle as gas, liquid or solid.

To learn more about states of matter refer to the link:

brainly.com/question/9402776

 #SPJ5

A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?

Answers

Answer:

Attached is the answer

Explanation:

The car’s velocity after the car has traveled 800 m is 74.83 m/sec.

What is velocity?

When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.

Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.

v² = u² + 2as

v² = 0 + 2*3.5*800

v² = 5600

v = 74.83 m/sec

The car’s velocity after the car has traveled 800 m is 74.83 m/sec.

To learn more about velocity refer to the link

brainly.com/question/18084516  

#SPJ2

aluminum has a density of 270 kg/m3. what volume of aluminum would have a mass of 49.9 kg?

(unit = m^3)

Answers

Answer :

ok so i got
0.184814814814815 m^3 (round to as much as you need to)



Explanation:

To find the volume of an object, divide the mass (49.9) by the density (270) to get you the volume, which would be (0.184814814814815) in this case.

0.184[tex]m^{3}[/tex] is the answer for Acellus students!

If Minnie the Mouse starts moving at 2m/s and increases her velocity to 4m/s because she is being chased, what is heracceleration if the time is 2 seconds?

Answers

Answer:

1m/s²

Explanation:

Given parameters:

Initial velocity  = 2m/s

Final velocity  = 4m/s

Time of chase  = 2s

Unknown:

Acceleration = ?

Solution:

Acceleration is the rate of change of velocity with time;

 A = [tex]\frac{v - u }{t}[/tex]  

A is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

      A  = [tex]\frac{4 - 2}{2}[/tex]   = 1m/s²

In a normal Earth atmosphere, a feather will free fall through the air more slowly than a brick because of what force?
A. Terminal velocity
B. Momentum
C. Weightlessness
D. Air Resistance

Answers

Answer:

Air Resistance

Explanation:

Because air gives a much greater resistance to the falling motion of the feather than it does to the brick.

A 2-kg ball traveling eastward at 5 m/s hits a 5-kg ball moving at 1 m/s eastward. The 2-kg ball bounces west at 3.0 m/s. What is the speed of the 5kg ball?

Answers

Answer:

1.8 m/s

Explanation:

Step one:

given data

m1= 2kg

u1= 5m/s

m2= 5kg

u2= 1m/s

v1= 3m/s

From

m1u1+m2u2= m1v1+m2v2

substitute

2*5+5*1 = 2*3+5*v2

10+5= 6+5v2

15-6= 5v2

9= 5v2

divide both side by 5

v2= 9/5

v2= 1.8 m/s

a) Las siglas M. RU significan

Answers

Answer:

Ver la explicación a continuación.

Explanation:

En física estas siglas significan movimiento rectilíneo uniforme, es decir es el tipo de movimiento donde la velocidad es constante. La velocidad no cambia con el tiempo.

Este tipo de movimiento se puede describir con la siguiente ecuación.

[tex]x=x_{0}+v*t[/tex]

Donde:

x = posición final [m]

xo = posición inicial [m]

v = velocidad [m/s]

t = tiempo [s]

A horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Answers

Answer:

Fscos63

Explanation:

Given that a horizontal pole is attached to the side of a building. There is a pivot P at the wall and a chain is connected from the end of the pole to a point higher up the wall. There is a tension force F in the chain. What is the moment of the force F about the pivot P?

Taking the moment from the pivot point P, that means the moment at point p = 0

Then, if we consider the weight mg of the pole, according to the principle of equilibrium : sum of the upward forces equal to the sum of the downward forces.

Therefore, mg = Fsinø ....... (1)

Also, taking moment at point P

Let the length of the pole = s

The length of the weight of the pole = 1/2 S

Fscosø = mgs/2

The distance s will cancel out

2Fcosø = mg ...... (3)

Substitute mg in equation 1 into equation 3

2fcosø = fsinø

F will cancel out

Tanø = 2

Ø = tan^-1(2)

Ø = 63.4 degree

The moment of force F about pivot point P will be

Moment = force × distance

Moment = Fcos63 × S

Moment = Fscos63

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