The universe is made of a lot of galaxies. The likely explanation for a galaxy having more than one nucleus is that the galaxy must have swallowed several smaller galaxies that were its neighbors.
There are some reason behind the theory that the eating up of a galaxy is by another galaxy. The galaxy is said to have a powerful past due to the fact that a lot of smaller galaxies were eaten up.The universe is known to have a very largest galaxy called the giant elliptical galaxy that is made up of about a trillion stars.
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A block of mass =4.20 kg slides along a horizontal table with velocity 0=3.50 m/s . At =0 , it hits a spring with spring constant =26.00 N/m and it also begins to experience a friction force. The coefficient of friction is given by =0.250 . How far has the spring compressed by the time the block first momentarily comes to rest? Assume the positive direction is to the right.
The distance in which the spring is compressed is 1.065 m.
The given parameters;
mass of the block, m = 4.2 kgvelocity of the block, v = 3.5 m/sspring constant, k = 26 N/mcoefficient of friction, μ = 0.25Apply the principle of conservation of energy to determine the distance in which the spring is compressed.
[tex]K.E = W + U\\\\\frac{1}{2} mv^2 = \mu Fx \ + \ \frac{1}{2} kx^2\\\\\frac{1}{2}(4.2)(3.5)^2 = 0.25(4.2 \times 9.8)(x) \ + \frac{1}{2} (26)(x^2)\\\\25.725 = 10.29x \ + \ 13x^2\\\\13x^2 + 10.29x - 25.725 = 0\\\\[/tex]
solve the quadratic equation using formula method;
a = 13, b = 10.29, c = -25.725
[tex]x = \frac{-b \ \ +/- \ \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-(10.29) \ \ +/- \ \sqrt{(10.29)^2 \ - \ 4(13\times 25.725)} }{2(13)} \\\\x = 1.065 \ m, \ \ or \ -1.86 \ m[/tex]
choose positive distance, x = 1.065 m.
Thus, the distance in which the spring is compressed is 1.065 m.
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A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
plz make me brainliest
The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?
The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The variation of the volume is: ΔV = 7.67 cm³
Pressure is defined by the relationship between force and area.
P = F / A
The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.
PV = nR T
Where P is pressure, V is volume, and T is temperature.
Let's write this equation for two points assuming that the temperature has not changed.
P₀ V₀ = P₁ V₁
V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex] (1)
The subscript "o" is used for the start point and the subscript "1" for the end point.
The pressure in a barometer is:
P = ρ g y
They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.
The volume of the cylinder is
V = π r² y
Let's calculate the initial volume.
V₀ = π 1 9
V₀ = 28.27 cm³
We substitute in equation 1.
V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]
V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]
Let's calculate.
V₁ = [tex]\frac{75}{59} \ 27.27[/tex]
V₁ = 35.94 cm³
The volume to be incremented is
ΔV = V₁ - V₀
ΔV = 35.94 - 28.27
ΔV = 7.67 cm³
Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:
The change of the volume is: ΔV = 7.67 cm³
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I need help in question 7, a and b.
Answer:
The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)
Explanation:
if you have 3 moles of iron, how many grams of iron do you have?
Answer:
55.84 look at periodic table
so 55.84*3= 167.52gFe
Se aplican dos fuerzas concurrentes a un objeto de 4N a la derecha y 5N a la izquierda. ¿Hacia donde se movió y con cuanta fuerza?
The forces move strongly towards the left by 1N
Given the following
Force towards the right = 4N
Force towards the left = 5N
Note that the force acting towards the left is negative, hence the force acting towards the left is -5N
Take the sum of force
Resultant force = -5N + 4N
Resultant force = -1N
This shows that the forces move strongly towards the left by 1N
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Historia de baloncesto internacional resumen
Answer:
?
Explanation:
5 a
What causes the pressure of air at the Earth's surface?
Answer:
Atmospheric pressure is caused by the gravitational attraction of the planet on the atmospheric gases above the surface and is a function of the mass of the planet, the radius of the surface, and the amount and composition of the gases and their vertical distribution in the atmosphere
Explanation:
1.How did earthquakes affect the rise and progress of the civilization in America and the Pacific islands?
2. What should you do when a natural disaster like earthquake occurs in your place?
3. Among the three types of waves, what is the most destructive? Why?
Please po pasagot
Based on geographical analysis, the earthquakes affect the rise and progress of the civilization in America and the Pacific islands by causing slope failures, liquefaction, and tsunami.
The effect of earthquakes in America and the Pacific Islands has caused people displacement as buildings collapsed, and water from nearby oceans caused the destruction of physical properties.
For safety reasons, when a natural disaster like an earthquake occurs in your place, you are expected to stay away from buildings if you're outside.
Similarly, if you are in a car, you should stop and pull over.
If you are in bed during the earthquake, wrap your head and neck with a pillow while turning your head upside.
Also, avoid doorways or windows if you are inside.
Considering the three types of waves, the most destructive wave is known as surface waves.
Surface waves have the most potent vibrations and can travel through any earth surface, whether air or water.
Other types of waves include Transverse waves and Longitudinal waves.
Hence, in this case, it is concluded that the effect of earthquakes is negative on human society, and waves can be destructive.
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Name any three things that cause soil pollution
Answer:
garbage , polluted water dam, unexpected dust particle
which wave has a higher frequency and why?
Explanation:
the figure in the left side has higher frequency.
because it has more nos. of wave in 1sec.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Evonne does not have a lot of time to work out during the week. She wonders if she spent half a day on the weekend getting is as many different types of exercise as possible if that would help. What is the BEST advice for Evonne?
A.
She has the right idea since variety is more important than intensity.
B.
She can do that, but should have a clear goal in mind to define her exercise.
C.
She should only focus on one type of exercise since she can do it once a week.
D.
She would be better off fitting in 15-20 minutes of exercise several times a week.
PLEASE NO LINKS
She would be better off fitting in 15-20 minutes of exercise several times a week. This t is the BEST advice for Evonne.
What are the benefits of regular exercise?Regular physical activity and exercise have many positive health effects that are difficult to deny. Everyone, regardless of age, sex, or physical ability, benefits from exercise.
Exercise can assist sustain weight loss or prevent excessive weight gain. Calorie burn occurs during physical exertion. You burn more calories when you engage in more vigorous exercise.
Numerous health issues and concerns, such as stroke, the metabolic syndrome, high blood pressure, and type 2 diabetes, can be prevented or managed with regular exercise. It can also help with cognitive improvement and reduce the danger of dying from any cause.
Exercise helps your circulatory system function more effectively and distributes oxygen and nutrients to your tissues. Additionally, you have greater energy to complete daily tasks as your heart and lung health improves.
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A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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a block weighing (Fg) 500 N is resting on a steel table ( us=0.74) the minimum force start this block moving is?
The minimum force required to start this block moving is 370 N.
The given parameters;
weight of the block, W = 500 Ncoefficient of static friction, [tex]\mu_s[/tex] = 0.74The minimum force required to start this block moving is calculated as follows;
[tex]F= \mu_s F_n[/tex]
where;
[tex]F_n[/tex] is the normal force on the block which is equal to the weight of the block
[tex]F= \mu_s F_n \\\\F= \mu_s W\\\\F = 0.74 \times 500 \\\\F= 370 \ N[/tex]
Thus, the minimum force required to start this block moving is 370 N.
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a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
the force needed to accelerated it at 2.0m/s^2 ?
Answer:
750 Newton
Explanation:
force=mass(acceleration)
Calculate torque using angular momentum
Answer:
The equation net τ=ΔLΔt net τ = Δ L Δ t gives the relationship between torque and the angular momentum produced.
plss helpp:((
(i'll mark as brainliest if u answer)
Answer:
Seriously Your Question Is Kinda Tremendous
Explanation:
I'll Head Is Boiling From Question That Keeps Popping Up My Head, Someone Might Give You A Positive Hand
Virtual image formed by concave mirror
Answer:
yes
Explanation:
because it is a diverging mirror
easy one - giving brainly if correct.
Gas.
HOPE YOU GET 100!
What is the mass, in kilograms, of a large dog that weighs 441 newtons?
Answer:
441 Newtons equals 44.97 kilograms.
Guys plz i need those answers as soon as possible
9) a) formula = h(ρ)g by default g=9.8m/s²
Pressure = 2×1000×9.8 = 19600Pa
b)
If you double the pressure of a constant amount of gas at a constant temperature, what happens to the volume
Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.
Explanation:
A bob attached to a string of length L = 1.25 m, initially found at the equilibrium
position, is given an initial velocity v = 0.8 m/s. The maximum displacement angle,
Omax, is: (Take g=10 m/s)
17
3.2
13
10.2
6.4
Clear selection
A hoh attached to a string of length 2 m is displaced by an angle of 8º and then
The maximum displacement angle of the bob is 13⁰.
The given parameters;
Length of the pendulum, L = 1.25 mInitial velocity of the bob, v = 0.8 m/sThe maximum displacement of the bob is calculated by applying the principle of conservation of energy;
[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m[/tex]
The maximum displacement angle is calculated as follows;
[tex]cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0[/tex]
Thus, the maximum displacement angle of the bob is 13⁰.
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A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Gravitational Potential Energy of an object is calculated by formula ~
[tex] \large\boxed{\sf P = mgh}[/tex]
where,
m = mass of the object = 3500 kgg = Acceleration due to gravity = 12 m/s²h = height attained by the object = 4 mNow, let's calculate its potential energy ~
[tex]3500 \times 10 \times 4[/tex][tex]140000 \: \: joules[/tex][tex]140 \: \: kj[/tex]Answer:
Potential Energy of an object is calculated by formula:
Potential Energy (P.E)=m×g×hWhere,
m=mass of bodyg=acceleration due to gravityh=height from the earth surfaceNow, let's solve the question.
Given,
mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²Now,
We know that,
Potential Energy (P.E)=mgh
[tex] = 3500 \times 10 \times 4[/tex]
[tex] = 3500 0\times 4[/tex]
[tex] =140000 joules [/tex]
[tex]\mathfrak{\blue{DisneyPrincess29}}[/tex]
A catamaran with a mass of 5.44×10^3 kg is moving at 12 knots. How much work is required to increase the speed to 16 knots? (One knot = 0.51 m/s.)
show all steps
The work that is required to increase the speed to 16 knots is 14,176.47 Joules
If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;
5.44×10^3 kg = 12 knots
For an increased speed to 16knots, we will have:
x = 16knots
Divide both expressions
[tex]\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\[/tex]
To get the required work done, we will divide the mass by the speed of one knot to have:
[tex]w=\frac{7230}{0.51}\\w= 14,176.47Joules[/tex]
Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules
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7. A bus covers a certain distance in 60 minutes if it runs at a speed of 60 km/hr.
What must be the speed of the bus in order to reduce the time of journey by 40
minutes?
Answer:
90 Km/h
Explanation:
60 mins is 1 hr
so in an hour bus covers 60 Km
so new speed:
d/t
(60km/40mins)*60mins/h
90Km/h
2. What are the challenges of wind energy that causes decrease in the electrical production?
3. Give two solutions:
1. Modification in the structure of the turbine
2. Modification in the function of the turbine.
4. You must estimate the cost in each solution, and which one is more affordable and efficient for the municipality to go for.
5. You must make sure that there is minimal energy loss.
Levelized production cost is a big challenge in the production of wind energy.
The main challenge in the production of wind energy is the high production cost. It has to minimize the Levelized Production Cost (LPC) which is the ratio between energy production cost and economic lifetime. This problem can be solved by doing modification in the structure of the turbine as well as we must ensure minimal energy loss.
The modification in the structure can produce more electrical energy and reduce the energy loss also provides more profit to the company so we can conclude that levelized production cost is a big challenge in the production of wind energy.
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Acceration is a change in motion over time:
True False
how have astronomers interpreted the unexpectedly fast rotation of galaxies
Answer:
There must be a lot of dark matter that can be felt but not seen
The astronomers interpreted the unexpectedly fast rotation of galaxies that there must be a large quantity of dark energy whose gravity is detectable yet invisible.
What is a galaxy?Any system of stars plus interstellar material that makes up the cosmos is referred to as a galaxy. Such assemblages are common, and many of them are so massive that they hold tens of trillions of stars.
A vast variety of galaxies, from dim, hazy dwarf objects to spectacular spiral-shaped giants, have been created by nature. Almost all galaxies seem to have formed shortly after the universe started, and they are everywhere in space, even at the farthest limits of the universe that can be seen by the most advanced telescopes.
The majority of galaxies are found in clusters, many of which are further organized into clusters that span hundreds of billions of light-years.
Since there are almost empty spaces between these so-called super clusters, the universe's overall structure resembles a network of sheets or chains of galaxies.
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