An element is highly conductive, highly reactive, soft, and lustrous. The element most likely belongs to which group?(1 point)

transition metals
noble gases
metalloids
alkali metals

Answer:

cant see picture

Explanation:

Answer:

please add picture so i can help you

Explanation:

KE = (0.5) m v²

given that : v = speed of the bottle in each case = 4 m/s when m = 0.125 kg

KE = (0.5) m v² = (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg KE = (0.5) m v² = (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg KE = (0.5) m v² = (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg KE = (0.5) m v² = (0.5) (0.500) (4)² = 4 J

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg

Answer:

c

Explanation:

Answer:

The spring constant is approximately 2.84 N/m

Explanation:

The height of the building, h = 828 m

The mass of the billionaire that has an office on the top floor, m = 120 kg

Gravitational potential energy, P.E. = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

The gravitational potential energy of the billionaire at the top floor is therefore;

P.E. of billionaire at top floor = 120 kg × 9.81 m/s² × 828 m  = 974,721.6 J

The elastic potential energy of the spring, [tex]P.E._{spring}[/tex] is given as follows;

[tex]P.E._{spring} = \dfrac{1}{2} \cdot k \cdot h^2[/tex]

Where;

k = The spring constant of the spring in N/m

h = The extension of the spring = The height of the building = 828 m

Given that the energy of the spring is conserved, we have;

[tex]P.E._{spring}[/tex] = P.E. of billionaire = 974,721.6 J

Plugging in the values gives;

[tex]P.E._{spring} = 974,721.6 \ J = \dfrac{1}{2} \times k \times (828 \ m)^2[/tex]

Therefore;

2*974,721.6/(828^2)

[tex]k = \dfrac{2 \times 974,721.6 \ J}{(828 \ m)^2} \approx 2.84 \ N/m[/tex]

The spring constant, k ≈ 2.84 N/m.

Answer:

yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!

Explanation:

Answer:

television,radios, microwave ovens, telephone system and computer

Answer:

Increasing

Explanation:

I Hope it Helps

we call it as well as 100 . so easey

Answer:

10 squared

Explanation:

10 squared

In Depth:

Let have a square that has a side length of 10.

A square four sides are equal and if we find the area of a squared, our formula is

[tex] {s}^{2} [/tex]

Our in this instance,

[tex] {10}^{2} [/tex]

or we call it

[tex]10 \: \: squared[/tex]

Answer:

An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.

or maybe god:)))(

Answer:

The diagram assigned B

explanation:

Check the direction of the two vectors, their resultant must be in the same direction.

Answer:

photosynthesis is the process by which green leaves prepare their food in the presence of sunlight,air and water

Answer:

They transform energy

Explanation:

thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy

Explanation:

→ Volume of cone = πr² × h/3

Here,

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ Volume of cone = 4780.28 cm³

Answer:

4,778.4 is correct

Explanation:

Answer:

Use the formula ∆H = m x s x ∆T to solve.

Explanation:

Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.

Answer:

Covalent bond.

Explanation:

There are 4 main types of bonds:

Covalent, ionic, metallic, and hydrogen.

Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.

Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities

Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.

Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.

Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)

So we can see that:

The elements are not metals, so we can discard metallic bond.

For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.

Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.

we can conclude that the bond will be a covalent bond.

At the ball's highest point, it has no vertical velocity, so the 6 m/s is purely horizontal. A projectile's horizontal velocity does not change, which means the ball was initially thrown with speed v such that

v cos(53°) = 6 m/s   ==>   v = (6 m/s) sec(53°) ≈ 9.97 m/s

The player shoots the ball from a height of 2.0 m, so that the ball's horizontal and vertical positions, respectively x and y, at time t are

x = (9.97 m/s) cos(53°) t = (6 m/s) t

y = 2.0 m + (9.97 m/s) sin(53°) t - 1/2 gt ²

Find the times t for which the ball reaches a height of 3.00 m:

3.00 m = 2.0 m + (9.97 m/s) sin(53°) t - 1/2 gt ²

==>   t ≈ 0.137 s   or   t ≈ 1.49 s

The second time is the one we care about, because it's the one for which the ball would be falling into the basket.

Now find the distance x traveled by the ball after this time:

x = (6 m/s) (1.49 s) ≈ 8.93 m

Answer:

New force = 0.063 N

Explanation:

Given that,

The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]

The formula for the electric force is:

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂

Put all the values,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]

So, the new force is 0.063 N.

Answer:

The force becomes 0.0315 N.

Explanation:

Force, F = 4.2 x 10^-2 N

When the distance is doubled, a charge is tripled, Let the force is F'.

The force between the two charges is

[tex]F = \frac{K qq'}{r^2}\\[/tex]

when, q' = 3 q' and r is 2 r so

[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

Answer:

sodium

Explanation:

it is highly reactive metal.

Answer:

aluminium

Explanation:

In a period , as we go from left to right in a periodic table, atomic number increases .

Differentiating electrons enters into same shell hence the effective nuclear charge decreases .

Hence atomic radius decreases along period.

Conculsion:

Aluminium is the element which has greater atomic radius and sulphur has smaller atomic radius.

Answer:

a. X: Slower in gases than liquids Y: Faster in solids than gases Z: Velocity depends on medium.

Explanation:

Speed of sound is fastest in solids. Sound waves travel more quickly in solid, than of liquid and gases. Sound waves travel most slowest in gases. Speed of sound varies significantly and it depends upon medium it is travelling through.  In more rigid medium sounds velocity will be faster.

Answer:

The time required is 0.45 s.

Explanation:

Height, h = 1 m

initial velocity, u = m/s

Let the time is t.

Use second equation of motion

[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]

Answer:

A certain source of 12V with an internal resistance 1colomb is connected to 5colomb external resistance what is the current

Answer:

Correct option is C it decreases by a factor of 2

Answer: A - it increases by a factor of 4

Explanation:

Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.

"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.

You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.

If we plug in 4V for V, we now have:

4V = I*R

Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.

Answer:

- Decreasing the resistance

- Using a shorter length

- Using a smaller area wire

Explanation:

Formula for conductance in wires is;

G = 1/R

Where;

G is conductance

R is resistance

This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.

Thus, to increase the conductance, we have to decrease the resistance.

Resistance here has a formula of;

R = ρL/A

Where;

ρ is resistivity

L is length of wire

A is area

Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.

Answer:

False.

Explanation:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.

Answer:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE