an employee is paid $9.00 per hour plus a 10% differential for evening shifts. in one workweek, he worked 24 hours on day shift and 24 hours in evening shift. calculate the gross wages for the week.

a. 482.80
b. 475.20
c. 491.40
d. 472.00​

Answer:

43.4 yd

Step-by-step explanation:

[tex]45^{2}[/tex]-[tex]12^{2}[/tex]

2025-144=1881

[tex]\sqrt{1881}[/tex]

43.37049

43.4

48..................

Answer:

Perimeter is (8x + 4) units.

Step-by-step explanation:

[tex]{ \sf{perimeter = side + side + side}} \\ { \sf{p = (2x + 1) + (7x - 2) + (5 - x)}} \\ { \sf{p = (2x + 7x - x) + (1 - 2 + 5)}} \\ { \sf{p = 8x + 4}}[/tex]

Answer:

[tex]5. \: \: 8 + 5(7) = 8 + 35 = 43[/tex]

I hope I helped you^_^

Answer:

TR = 23

Step-by-step explanation:

first we have to find TS, so we subtract 16 from 4 to get 12. then we can add 12 and 11 to get TR

The Sequence:

1 , 1+2 , 1+2+3 , 1+2+3+4, ...

here, every term is an AP. finding the general formula for the sum of the elements of each term is:

Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex]        [where x = number of term, a = first term and d = common difference]

here, the first term is always 1 and so is the common difference.

Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]

Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]

which is the formula for a general term in our series

now, we need to find the sum of the first n terms of this series

[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]

[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]

in this formula, for the first term, it's just an AP from x = 1 to x = n

for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

in this AP (first term), the first term and the common difference is 1 as well

[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]

[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]

[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]

[tex]\frac{n(n+1)(n+2)}{6}[/tex]

which is the sum of n terms of the given sequence

Answer:

5d = 30

Step-by-step explanation:

1. first you need to add 5 to both sides

   d-4+5 = 2+5

2. then you need to combine like terms

   d+1 = 7

3. after that you have to multiply both sides by 5

   5(d+1) = 7(5)

4. simplify

   5d + 5 = 35

         -5     -5

   5d = 30

Answer:

10 inches

Step-by-step explanation:

radius = 5 inches

Diameter = radius x 2 = 5 x 2 = 10 inches

Answer:

C

Step-by-step explanation:

Squaring is multiplying a number by itself

Examples:

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

etc.

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

hope it helps, appreciate if you can give brainliests

Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

Notice that a number is only divisible by 5 if it ends in 5 or 0.

Only using this, we will find that the number is 49,999

Suppose we wanted the sum of the digits to end in 5, then we could have something like:

23

2 + 3 = 5

if we add 1, we get:

23 + 1 = 24

2 + 4 = 6

This will happen always.

instead, if we use a 0 as the last digit of the sum, we get:

For example, the simplest one:

19

we have:

1 + 9 = 10

10 is divisible by 5.

if we add 1, we get:

19 + 1 = 20

2 + 0 = 2

2 is not divisible by 5.

We have a  problem again, but this time you can see that the whole structure of the number does change. So we should keep trying with ones and nines.

Now we need to modify our number to the point we get n + 1 to be divisible by 5.

if we add a 9 to the right side of our number, we get:

199

1 + 9 + 9 = 19

clearly, not divisible by 5.

Here we need to add a 1 at the left side to make it divisible by one, so we get:

1199

1 + 9 + 1 + 9 = 20

this is divisible by 5.

now let's add 1:

1,199 + 1 = 1,200

1 + 2 = 3

3 is not divisible by 5.

Now, if you look at the two numbers we used, we can see that:

for 19, the sum of the digits + 1 gave us a 2.

for 1,199, the sum of the digits +1 gave us a 3.

then just let's add two ones and two nines.

We will get:

11,119,999

adding the digits:

1 + 1 + 1 + 1 + 9 +9 +9 +9 = 40

is divisible by 5.

Adding one to our number, we can get:

11,119,999 + 1= 11,120,000

Adding the digits:

1 + 1 + 1 + 2 + 0 + 0+ 0+ 0 = 5

divisible by 5.

Now, we can group the ones together, so instead of the number 11,119,999

we can have 49,999, which is way smaller.

Adding the digits, we get:

4 + 9 + 9 + 9 + 9 = 40

And adding one to our number, we get:

49,999 + 1 = 50,000

Adding the digits:

5 + 0 + 0 +0 + 0 = 5

So we found the smallest number n such that the sum of the digits of n is divisible by 5, and the sum of the digits of n + 1 is also divisible by 5.

If you want to learn more, you can read:

https://brainly.com/question/21416852

Answer:

wheres the file or question?

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

Learn more about reflection;

https://brainly.com/question/12950057

#SPJ2

Answer:

here's the answer to your question

Answer:

153*10^3

Step-by-step explanation:

I assumed the first exponential number as 1

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{(3.4 \times 10^4)(4.5 \times 10^3)}}\\\huge\boxed{\mathsf{\rightarrow 3.4\times10^4 \times 4.5 \times 10^3}}[/tex]

[tex]\huge\boxed{\mathsf{10^4}}\\\huge\boxed{= 10\times10\times10\times10}\\\huge\boxed{= 100\times100}\\\huge\boxed{= 10,000}\\\\\\\huge\boxed{\mathsf{10^3}}\\\huge\boxed{=10\times10\times10}\\\huge\boxed{= 100\times10}\\\huge\boxed{= 1,000}[/tex]

[tex]\huge\boxed{\rightarrow\mathsf{3.4\times \bold{10,000} \times 4.5 \times \bold{1,000}}}}[/tex]

[tex]\huge\boxed{\mathsf{3.4\times10,000}}\\\huge\boxed{= 34,000}\\\\\\\huge\boxed{\mathsf{4.5\times1,000}}\\\huge\boxed{{= 4,500}}}[/tex]

[tex]\huge\boxed{\mathsf{\rightarrow\bf 34,000\times4,500}}\\\huge\boxed{\rightarrow\mathsf{ORIGINAL \ ANSWER: \frak {153,000,000}}}}[/tex]

[tex]\huge\boxed{\textsf{Your answer: }\mathsf{153\times10^6}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

The correct choice is option B. (5, 2)

Step-by-step explanation:

The rotation rule of 180° is = (x ,y) -> ( -x , -y) .

Coordinates of C before the rotation are ( -5 , -2) so according to the rule above they will now be = C'( 5 , 2 ) .

Therefore, the ordered pair for C' is (5, 2) after the 180 degrees rotation.

Answer:

17/30 (0.56)

Step-by-step explanation:

18/20-4/12

Reduce the fraction with 2 and 4: 9/10-1/3

Write all numerators above the least commmon denominator 30: 27-10/30

Subtract: 27-10/30 = 17/30

Answer:

This will plot as an upward  "V" with the vertex at x = 4/3, y = 5

Step-by-step explanation:

The absolute value will mean that y can only be positive. y will be at a minimin when the absolute value is zero. To determine that find the x that makes it zero, so

-3x + 4 = 0

-3x = -4

x = 4/3

which makes y = 5 (the minimin)

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).

Answer:

semoga jawapan ini dapat membantu

Make the unknown numerator be x and unkown denominotor be y

We have :  7 - [tex]\frac{x}{y}[/tex] = 6[tex]\frac{4}{5}[/tex]

            =>       [tex]\frac{x}{y}[/tex] = 7 - 6[tex]\frac{4}{5}[/tex]

                       [tex]\frac{x}{y}[/tex] = [tex]\frac{1}{5}[/tex]

So we need to fill in the box : [tex]\frac{1}{5}[/tex]

If the answer is helpful, Brainliest please!

Answer:

Step-by-step explanation:

x-intercept(s):  

( − 4 , 0 ) , ( 6 , 0 )

y-intercept(s):  

( 0 , − 24 )

Answer:1 and 2

Step-by-step explanation:right on edge

Answer:

y-intercept is (0, -8)

Step-by-step explanation:

[tex]y = {x}^{2} + 2x - 8[/tex]

At y-intercept, x is zero

substitute x as zero:

[tex]y = {(0)}^{2} + 2(0) - 8 \\ y = 0 + 0 - 8 \\ y = - 8[/tex]

I believe this is the expression:

[tex] \displaystyle \large \boxed{ - 8 {y}^{2} }[/tex]

Since we want to evaluate it when y = -2, simply substitute y = -2 in the expression.

[tex] \displaystyle \large{ - 8 {( - 2)}^{2} }[/tex]

Any negative number squared will result in positive, refer below:

[tex] \displaystyle \large{ {( - a)}^{2} = {a}^{2} } \\ \displaystyle \large{ {( - 2)}^{2} = {2}^{2} } \longrightarrow \boxed{4} \\ [/tex]

Hence,

[tex] \displaystyle \large{ - 8(4) = - 8 \times 4} \\ \displaystyle \large \boxed{ -32}[/tex]

Answer:

-32

Step-by-step explanation:

Replace the variable y with -2 in the expression giving -8(-2)^2

Then, square -2 giving us (positive) 4

Lastly, multiply -8 with 4 and get -32 as our answer

(Hopefully this helped you! Feel free to ask again if you need more help. Tell me if the solution is unclear to you)

Answer:

hahaaaaaaaaaaaaaaaaa

Step-by-step explanation:

Answer:

IF the signs ARE same the result is a POSITIVE, if the signs are NOT the same the result is NEGATIVE

Step-by-step explanation: