An ideal horizontal spring-mass system is set into motion. At an instant when the mass passes through its equilibrium position: The potential energy in the spring is at its _____. The kinetic energy of the mass is at its ______. The magnitude of net force acting on the mass is at its ______.

Answer:

the potential energy is zero, and the kinetic energy must be maximum

    F = 0

Explanation:

In this exercise you are asked to complete the sentences of a simple harmonic movement of a mass-spring system.

In this system mechanical energy is conserved

at the most extreme point the carousel potential energy is

          K_e = ½ k x²

the kinetic energy is zero for that stopped.

At the equilibrium point

the spring elongation is x = 0 so the potential energy is zero

and the kinetic energy must be maximum since total energy of the system is conserved

the spring force is

             F =- k x

as in the equilibrium position x = 0 this implies that the force is also zero

             F = 0

In this exercise we have to use the knowledge of force to calculate the energy of a spring, in this way we find that:

The potential energy in the spring is at its [tex]K_e = 1/2 k x^2[/tex]. The kinetic energy of the mass is at its zero . The magnitude of net force acting on the mass is at its Zero.

In this system mechanical energy is conserved,  at the most extreme point the carousel potential energy is:

       [tex]K_e = 1/2 k x^2[/tex]

The kinetic energy is zero for that stopped or when at the equilibrium point, so:

the spring force is:

          [tex]F =- k x\\F=0[/tex]

See more about force at brainly.com/question/26115859