Answer:
k. e. = 1/2 mv^2
100 = 1/2 * m * 5^2
100 = 1/2 * m * 25
m = 100 *2/25
m = 8 kg
hope it helps you
If you find a chemical in the lab and are unsure of
its identity, what is the best way to find out what it
is?
Answer:
C. read the label on the container
Explanation:
What information is found in an SDS? Check all that apply.
A. the identification of the chemical
C. the chemical and physical properties of the substance
D. the first-aid measures to take if an accident occurs involving the chemical
Answer:
C
Explanation:
just did it
Explain five physical and/or chemical properties that you need to consider for the substances before using them as construction materials for buildings
Answer: There are many properties of a metal which is taken into consideration when it is used for construction
Explanation:
The properties can be physical, chemical, et cetera. The physical properties that is considered are:
1. Durability: It can be defined as the property of the material to withstand the atmospheric pressure and other factors.
2. Density: The ratio of mass by volume of a material (homogeneous material) is called as density.
3. Fire resistance: The ability of the material to withstand in fire without changing its size or shape.
4. Weather resistance: The ability of the material to withstand the weather which could be variable round the year.
5.Water absorption: The ability of the material to absorb water and retain it.
The general area of the atom (outside the nucleus) where the e- are located is the — and —
5. CaCO, - CaO+CO,
Reaction Type
Answer:
(a) Decomposition: A substance breaks down to smaller species. [e.g. CaCO3(s) → CaO(s) + CO2(g) Decomposition of limestone to calcium oxide (quicklime) and carbon dioxide on heating.]
what type of heat transfer takes place when you come in contact with a snow flake on a cold day?
Answer:
Conduction
Explanation:
Conduction is how heat transfers through direct contact with objects that are touching. Any time that two objects or substances touch, the hotter object passes heat to the cooler object.
Answer:
Conduction
Explanation:
Conduction is how heat transfers through direct contact with objects that are touching. Any time that two objects or substances touch, the hotter object passes heat to the cooler object.
An object has a mass of 26.94 grams and a volume of 2.568 cubic centimeters. What material is it likely to be
made of?
Substance iron gold silver copper
Density (g/cm) 7.874 19.32 10.49 8.92
a. Silver
c. Iron
b. Gold
d. Copper
Answer:
a) silver
Explanation:
Given data:
Mass of object = 26.94 g
Volume of object = 2.568 cm³
Which subject is this = ?
Solution:
Formula:
d = m/v
by putting values
d = 26.94 g/ 2.568 cm³
d = 10.49 g/cm³
Densities of objects: g/cm³
iron = 7.874
gold = 19.32
silver = 10.49
copper = 8.92
Thus, given object is silver.
Which statements about freshwater sources are true? Check all that apply.
O Only about 3 percent of Earth's water ís fresh water.
O Most of the fresh water on Earth is groundwater.
O About 75 percent of the fresh water on Earth is frozen in ice sheets.
O The largest source of usable fresh water is groundwater.
O More fresh water is in the atmosphere than in rivers and lakes.
Answer:
Explanation:
1 is true
2 is false
3 is true
4 is true
5 is false
That is what I got from researching.
Only about 3% of the water in the Earth is fresh water and about 75 % of the fresh water on Earth is frozen in ice sheets.
• The most vital element present on the Earth is water. All the living beings are dependent on it.
• Water is present in the majority of the Earth, however, of this only 3% of the water is freshwater, the rest is saline and undrinkable.
• Of this 3%, the 75 percent of the freshwater is present in the form of ice and glaciers in the polar region.
• The remaining 24 percent is the groundwater and the rest 1 percent includes the waters of rivers, lakes, and ponds.
• The prime source of usable freshwater is present in the trapped form in the ice and glaciers.
Thus, the correct statements are 1st and 3rd.
To know more about:
https://brainly.com/question/11981746
Why are electromagnetic Waves important society today?
Answer Electromagnetic waves are used to transmit long/short/FM wavelength radio waves, and TV/telephone/wireless signals or energies. They are also responsible for transmitting energy in the form of microwaves, infrared radiation (IR), visible light (VIS), ultraviolet light (UV), X-rays, and gamma rays.
Explanation:
Electromagnetic waves are important in society today because they are used to "transmit long/short/FM wavelength radio waves, and TV/telephone/wireless signals or energies. They are also responsible for transmitting energy in the form of microwaves, infrared radiation (IR), visible light (VIS), ultraviolet light (UV), X-rays, and gamma rays."
Answer these three please! Thank you <3333
(I will give brainliest)
Answer:
Explanation:
21:B 22:B
what is 1/4 of 12 pleas i need help
Answer:
3
Explanation:
It's basically saying what number goes into 12 four times, I think.
5. Describe the effects of photons of light on an electron of the hydrogen atom
Answer:
How do atoms give off light?
Atoms emit light when they are heated or excited at high energy levels. The color of light that is emitted by an atom depends on how much energy the electron releases as it moves down different energy levels. ... It shows the electron moving down energy levels.
Explanation:
What is the percent composition of Phosphorus in Li3PO3
Answer:
you will get 17.983 g of lithium for every 100 g of lithium phosphate.
Explanation:
69.7% is the percent by mass of Lithium in Li[tex]_3[/tex]PO[tex]_3[/tex]. A percent is obtained by multiplying the result by 100.
One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.
99.795g/mol = molar mass of Li[tex]_3[/tex]PO[tex]_3[/tex]
6.94g/mol = molar mass of Li
mass percentage of Li=(molar mass of Li/molar mass of Li[tex]_3[/tex]PO[tex]_3[/tex])× 100
=(6.94/99.7)× 100
=69.7%
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