An opposition paragraph in an Argumentative Essay identifies and defends against ideas or arguments that might go against your argument (as a defense). True or false​

Given:

Consider the given equation is:

[tex](2\cdot 2^2)^x=64[/tex]

To find:

The value of x.

Solution:

We have,

[tex](2\cdot 2^2)^x=64[/tex]

It can be written as:

[tex](2\cdot 4)^x=8\times 8[/tex]

[tex]8^x=8^2[/tex]

On comparing the exponents of both sides, we get

[tex]x=2[/tex]

Therefore, the value of x is 2.

Answer:

Step-by-step explanation:

The period of a trig function tells you how much space is taken up by one "up-down-up" of the graph, which is a revolution. Because half of this graph takes place in a span of 2π, then the whole graph will span 4π.

Answer:

12, 120,012

Step-by-step explanation:

Hello!

9x + 4 + x = 54 <=>

<=> 9x + x + 4 = 54 <=>

<=> 10x + 4 = 54 <=>

<=> 10x = 54 - 4 <=>

<=> 10x = 50 <=>

<=> x = 50 : 10 <=>

<=> x = 5 => 9 × 5 + 4 + 5 = 54

Good luck! :)

Answer:

x = 5

Step-by-step explanation:

First, combine like terms. Like terms are terms with the same variables as well as same amount of said variables:

9x + x + 4 = 54

(9x + x) + 4 = 54

10x + 4 = 54

Next, isolate the variable, x. Note the equal sign, what you do to one side, you do tot he other. Do the opposite of PEMDAS.

PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

-

First, subtract 4 from both sides of the equation:

10x + 4 (-4) = 54 (-4)

10x = 54 - 4

10x = 50

Next, divide 10 from both sides of the equation:

(10x)/10 = (50)/10

x = 50/10 = 5

x = 5 is your answer.

~

Answer:

Since both terms are perfect squares, factor using the difference of squares formula,  

a ^2 − b ^2 = ( a + b ) ( a − b )

where  

a = y

and  

b = 6  

( y + 6 ) ( y − 6 )

═══════ღ❦ღ══╮

[tex]\boxed{ \sf{Answer}} [/tex]

↦ First find the value of x

[tex]27x = 45263514282 \\ x = \frac{45263514282}{27} \\ x = 1676426454.89[/tex]

↦ Now, find the value of 200x

[tex]x = 1676426454.89 \\ 200x = 200 \times 1676426454.89 \\ 200x = 335285290978[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Given that,

→ 27x = 45263514282

Then we have,

To find the required value of 200x.

Before that,

find the required value of x.

→ 27x = 45263514282

→ x = 45263514282/27

→ [x = 1676426454.89]

Now we can,

Solve for the value of 200x.

→ 200x

→ 200 × (x)

→ 200 × (1676426454.89)

→ 335285290978

Hence, 200x is 335285290978.

Answer:

Capacity of the rectangular tank in litres is 165.75l

Step-by-step explanation:

Volume of the tank

[tex] = lbh[/tex]

[tex] = 85 \times 65 \times 30[/tex]

[tex] = 165750 {cm}^{3} [/tex]

Capacity of the tank

[tex] = 165750ml[/tex]

[tex] = 165.75l[/tex]

1cm = 2m

=> 1cm = 200cm

2.5cm = 2.5 × 200cm = 500 cm = 5m

So, the length of window is 500cm or 5m.

Answer: The ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]

Step-by-step explanation:

We are given:

UV = 56 units

VT = 33 units

UT = 65 units

∠V = 90°

Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.

[tex]\cos \theta=\frac{\text{base}}{\text{hypotenuse}}[/tex]

Base of the triangle is UV and the hypotenuse of the triangle is TU

Putting values in above equation, we get:

[tex]\cos \theta=\frac{UV}{TU}=\frac{56}{65}[/tex]

Hence, the ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]

Answer:

The answer is 180 - 65

Step-by-step explanation:

We got 180, because that is the number of degree's in a line

so 180 - 65 is 115 degrees, that's your answer :)

Answer:

Answer:

Radius of the circular garden

= 210 sq

=105m

Radius of the region covering the garden and the path =105m+7m

=112m

Area of the region between two concentric circles

with radius of outer circle R, and inner circle r =π(R sq−r sq)

Hence, the area of the path

=π(112sq−105 sq)= 7/22

(12544−11025)

= 33418/7

=4774m sq

HOPE THIS WILL HELP YOU MATE

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

[tex](a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x[/tex]

[tex](b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)[/tex]

[tex](c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x[/tex]

[tex](d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x[/tex]

Thus, all the identities are correct.

A. Not an identity

B. An identity

C. Not an identity

D. An identity

To check whether each expression is an identity, we need to verify if the equation holds true for all values of the variable x. If it is true for all values of x, then it is an identity. Let's check each option:

A. [tex]\((\sin x + \cos x)^2 = 1 + \sin 2x\)[/tex]

To check if this is an identity, let's expand the left-hand side (LHS):

[tex]\((\sin x + \cos x)^2 = \sin^2 x + 2\sin x \cos x + \cos^2 x\)[/tex]

Now, we can use the trigonometric identity [tex]\(\sin^2 x + \cos^2 x = 1\)[/tex] to simplify the LHS:

[tex]\(\sin^2 x + 2\sin x \cos x + \cos^2 x = 1 + 2\sin x \cos x\)[/tex]

The simplified LHS is not equal to the right-hand side (RHS) 1 + sin 2x since it is missing the sin 2x term. Therefore, option A is not an identity.

B. [tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

To check if this is an identity, we can use the double-angle identity for sine:[tex]\(\sin 2\theta = 2\sin \theta \cos \theta\)[/tex]

Let [tex]\(2\theta = 6x\)[/tex], which means [tex]\(\theta = 3x\):[/tex]

[tex]\(\sin 6x = 2 \sin 3x \cos 3x\)[/tex]

The equation holds true with the double-angle identity, so option B is an identity.

C. [tex]\(\frac{\sin 3x}{\sin x \cos x} = 4\cos x - \sec x\)[/tex]

To check if this is an identity, we can simplify the right-hand side (RHS) using trigonometric identities.

Recall that [tex]\(\sec x = \frac{1}{\cos x}\):[/tex]

[tex]\(4\cos x - \sec x = 4\cos x - \frac{1}{\cos x} = \frac{4\cos^2 x - 1}{\cos x}\)[/tex]

Now, using the double-angle identity for sine, [tex]\(\sin 2\theta = 2\sin \theta \cos \theta\),[/tex] let [tex]\(\theta = x\):[/tex]

[tex]\(\sin 2x = 2\sin x \cos x\)[/tex]

Multiply both sides by 2: [tex]\(2\sin x \cos x = \sin 2x\)[/tex]

Now, the left-hand side (LHS) becomes:

[tex]\(\frac{\sin 3x}{\sin x \cos x} = \frac{\sin 2x}{\sin x \cos x}\)[/tex]

Using the double-angle identity for sine again, let [tex]\(2\theta = 2x\):[/tex]

[tex]\(\frac{\sin 2x}{\sin x \cos x} = \frac{2\sin x \cos x}{\sin x \cos x} = 2\)[/tex]

So, the LHS is 2, which is not equal to the RHS [tex]\(\frac{4\cos^2 x - 1}{\cos x}\)[/tex]. Therefore, option C is not an identity.

D. [tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \tan x\)[/tex]

To check if this is an identity, we can use the sum-to-product trigonometric identities:

[tex]\(\sin A - \sin B = 2\sin \frac{A-B}{2} \cos \frac{A+B}{2}\)\(\cos A + \cos B = 2\cos \frac{A+B}{2} \cos \frac{A-B}{2}\)[/tex]

Let A = 3x and B = x:

[tex]\(\sin 3x - \sin x = 2\sin x \cos 2x\)\(\cos 3x + \cos x = 2\cos 2x \cos x\)[/tex]

Now, we can rewrite the expression:

[tex]\(\frac{\sin 3x - \sin x}{\cos 3x + \cos x} = \frac{2\sin x \cos 2x}{2\cos 2x \cos x} = \frac{\sin x}{\cos x} = \tan x\)[/tex]

The equation holds true, so option D is an identity.

To know more about identity:

https://brainly.com/question/28974915

#SPJ3

The correct answer is to drag The Plus sign (+)

This has to do with the use of symbols to denote mathematical equations such as addition, subtraction, etc.

Hence, we can see that the correct position to put the operator on the image to result in a binomial is to drag the plus sign (+) so that the equations can be solved,.

Read more about operators here:

https://brainly.com/question/25974538

#SPJ2

Answer:.

Step-by-step explanation:

Answer:

First exercise

a) 1/8=0.125

b) 5$

c) y = 0.125 * x - 5

Second exercise

a) 0.11 $/KWh

b) no flat fee

c) y = 0.11 * x

Step-by-step explanation:

(See the pictures)

Answer:

b

Step-by-step explanation:

Answer: B (option 3)

Step-by-step explanation:

When you multiply [tex]\sqrt{b}[/tex] by itself, the two square roots cancel our, giving you just b.

Answer:

[tex]y = \frac{1}{2} x + \frac{1}{2} [/tex]

Step-by-step explanation:

choose 2 points to find slope

(1,1) (-3,-1)

[tex]m = \frac{ - 1 - 1}{ - 3 - 1} = \frac{1}{2} [/tex]

y-y1 = m(x-x1)

y-1 = 1/2( x-1)

y = 1/2x + 1/2

guessing

y= 1/2x + 1/2

did y2 - y1/ x2-x1

which gave

-3

-6

also it passed through the y axis at +1/2

Answer:

A.............

Step-by-step explanation:

. ..........

Answer:

C. (3,3)

Step-by-step explanation:

When These equations are both graphed the solution for these equations when they intersect is (-3,3)

Answer:

First answer choice: [tex]y=\sqrt{x}[/tex] shifted right 6 units and down 2 units.

Step-by-step explanation:

Graph

Answer:

p = T - a - b

Step-by-step explanation:

T = a + p + b

p = T - a - b

Answer:

69 miles/hour

Step-by-step explanation:

Average speed = Total distance travelled / Total time taken

Distance travelled = 3,518 miles

Time taken = 51 hours

Average speed = Total distance travelled / Total time taken

= 3,518 miles / 51 hours

= 68.980392156862

Approximately,

Average speed = 69 miles/hour

Answer: 69 miles/hour

Step-by-step explanation:

Answer:

[tex]JL=54[/tex]

Step-by-step explanation:

We are given that K is the midpoint of JL. Using this information, we want to find JL.

By the definition of midpoint, this means that:

[tex]JK=KL[/tex]

Substitute them for their equations:

[tex]8x+11=14x-1[/tex]

Solve for x. Subtract 8x from both sides:

[tex]11=6x-1[/tex]

Add 1 to both sides:

[tex]6x=12[/tex]

And divide both sides by 6. Hence:

[tex]x=2[/tex]

JL is the sum of JK and KL. Hence:

[tex]JK+KL=JL[/tex]

Since JK = KL, substitute either one for the other:

[tex]JK+(JK)=2JK=JL[/tex]

Substitute JK for its equation:

[tex]2(8x+11)=JL[/tex]

Since we know that x = 2:

[tex]2(8(2)+11)=2(16+11)=2(27)=54=JL[/tex]

Thus:

[tex]JL=54[/tex]

Answer:

using Pythagoras' theorem c²=a²+b²

the diagonal is the hypotenuse of one of the triangles formed

let x represent one side of the square

√48²=x²+x²

√48²=2x²

48=2x²

48/2=2x²/2

24=x²

√24=√x²

4.8989794855663561=x

~4.90

Area of the square=side x side

4.90x4.90

24.01units²

Answer:

The slope is 9.

Step-by-step explanation:

Answer:

Slope = 9

Step-by-step explanation:

Slope intercept form is y = mx +b (where m is slope and b is y intercept).

Here, m= 9 (slope) and b=0 (y intercept)

Answer:

7 nickels, 5 quarters, 3 dimes

Step-by-step explanation:

7 nickels= 35 cents

5 quarters= $1.25

3 dimes= 30 cents

35+ 1.25+ 30= $1.90

Hope this helps!

Plz mark Brainliest if u can :)

Answer of this question

Answer:

the side XY

Step-by-step explanation:

we know 2 angles in a triangle. but are 45 degrees.

that means the third angle Z is 180-45-45 = 90 degrees.

the side opposite of the largest angle is the longest side.

opposite of Z is the side XY.

Answer:

4560

Step-by-step explanation:

Answer:

A √202km

Step-by-step explanation:

x²=11²-9²

x²=121-81

x²=202

√x²=√202

x=√202

Step-by-step explanation:

Hey there!

The equation is: 2x + 3y -12=0 (i)

From the given equation;

Slope (m) = (-coeff.of X)/(coeff.of y)

m = -2/3

Now; Let the missing component be "a".

The equation also can be written in;

The equation also can be written in;(y-8) = -2/3(x-a) (using one point formula)

3y - 24 = -2x + 2a

2x +3y -2a -24 = 0………(ii)

Since both equation are made from same coordinates, equating equation (i) and (ii).

2x + 3y -12= 2x +3y -2a -24

Cancel like terms,

-2a - 24 = -12

or, -2a = 12

or, a = -6.

Therefore, the missing value is -6.

Check:

Putting the value "a" in equation (ii).

2x + 3y -2(-6) -24 = 0

or, 2x+3y -12 = 0 (which is equal to equation (i).

Hope it helps!