Analyze the reasons why a dropping mercury electrode is better as
compared to a conventional electrode.

The nuclear fusion results in the liberation of large amount of energy by the conversion of mass to energy. Thus, option B is correct.

The nuclear fusion has been a type of nuclear reaction in which the reaction of the two nuclei results in the nuclei with mass smaller than the reactants. In nuclear reactions, there has been the liberation of large amount of energy.

The energy released in the nuclear fusion has been formed by the conversion of the mass. Since, the formed product has nuclei with the mass smaller than the reactants, the remaining mass of the reactants has been converted to the energy.

Thus, in nuclear fusion, the energy released has been produced from the conversion of mass to energy. Thus, option B is correct.

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Answer:

it will be no.A genotype

Answer:

a. 13.0g/L is the concentration of SO2Cl2 after 3.00h

b. FALSE

Explanation:

The first order reaction follows the equation:

ln[SO2Cl2] = -kt + ln[SO2Cl2]₀

Where [] is the concentration after time t, k is rate constant = 1.42x10⁻⁴s⁻¹

[]₀ is initial concentration:

a. []₀ = 75.6g/1.25L = 60.48g/L

t in seconds: 3h * (3600s / 1h) = 10800s

Replacing:

ln[SO2Cl2] = -1.42x10⁻⁴s⁻¹*10800s + ln[60.48g/L]₀

ln[SO2Cl2] = 2.5687

[SO2Cl2] = 13.0g/L is the concentration of SO2Cl2 after 3.00h

b. The rate constant of a reaction remains constant if temeprature remains constant.

Answer:

[tex]N _{2} H _{3} {}^{3 + } [/tex]

Answer:

the answer is 4 hope this helps

Answer:

B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺

Explanation:

Let's consider Arrhenius acid-base theory:

Boric acid, B(OH)₃ reacts with water according to the following equation.

B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺

As we can see, boric acid releases H⁺ in aqueous media. Thus, it is an acid.

The question is incomplete, the complete question is;

When sulfur loses one electron, it becomes a particularly stable, half-filled p subshell. The removal of this first electron requires less energy than the removal of an electron from phosphorus, which is initially a half-filled p subshell. This signifies that the first ionization energy of sulfur is larger than the first ionization energy of phosphorus. the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus. the second ionization energy of sulfur is smaller than the first ionization energy of phosphorus. the second ionization energy of phosphorus is larger than the second ionization energy of sulfur.

Answer:

the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus

Explanation:

Let us look back at the electronic configuration of each of the atoms;

Sulphur; [Ne] 3s² 3p⁴

Phosphorus; [Ne] 3s² 3p³

We can easily see that phosphorus has an exactly filled half filled 3p sublevel. This partially filled orbital has a great deal of stability associated with it.

On the other hand, sulphur can attain this stability that results from a half filled orbital by loosing one of its p electrons. The energy required for this process is much lower than the energy required to remove an electron from an already half filled 3p orbital of the phosphorus atom.

Hence, the first ionization energy of sulfur is smaller than the first ionization energy of phosphorus.

Answer:

CF4

Molecular geometry- tetrahedral

Electron geometry- tetrahedral

NF3

-molecular geometry - trigonal pyramidal

Electron geometry - tetrahedral

OF2

Molecular geometry - bent

Molecular geometry - tetrahedral

H2S

Molecular geometry- bent

Electron geometry - tetrahedral

Explanation:

According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electron pairs on the valence shell of the central atom in the molecule.

For all the compounds listed, the central atom has four points of electron density. This correspond to a tetrahedra electron pair geometry. The presence of lone pairs on the central atom of OF2,NF3 and H2S accounts for the departure of the observed molecular geometry from the geometry and idealized bond angle predicted on the basis of the VSEPR theory.

Answer:

1.806 × 10²⁴ atoms

Explanation:

To obtain the number of atoms a substance contain, we have to multiply the number of moles in that substance (n) by Avogadro's number, which is 6.02 × 10²³.

According to this question, a sample of carbon tetrachloride (CCl4) contains 3 moles of the substance. The number of atoms in CCl4 is calculated thus:

number of atoms = 3 × 6.02 × 10²³

number of atoms = 18.06 × 10²³

number of atoms = 1.806 × 10²⁴ atoms.

Answer:

D

Explanation:

pH=-log(x)

x=0.001M,pH=3

x=0.01M,pH=2

x=0.1M,pH=1

x=1M,pH=0

Highest pH is for option D

Answer:

D.

Explanation:

The highest pH is D because

0.01 M HCL => 2

0.1 M HCL => 1

1 M HCL => 0

0.001 M HCL => 3

so the answer is D.

Answer:

22/7 × [tex]10^{2}[/tex]

Explanation:

The area of a circle can be found out using π[tex]r^{2}[/tex]. Since r is the radius so if they multiply, they will give you an area of a square then multiply by 22/7 since it is a circle.

The surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.

A Tambourine has circular shape, and the area of the Tambourine can be determined by applying formula for area of a circle as shown below;

A = πr²

where;

r  = ¹/₂D

r = ¹/₂ x 10 in

r = 5 in

A = π(5)²

A = 25π in²

A = 78.54 in²

Thus, the surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.

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Answer:

b. 0.3 mol/L is the closest.

Explanation:

A molar solution of a substance contains 1 mole per liter of solution

So if we have 2 moles in 6 liters the there are 2/6 =1/3 of a mole in 1 liter.

Answer:

Option A. 107 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 150 mL

Initial pressure (P₁) = 500 mmHg

Final pressure (P₂) = 700 mmHg

Temperature = constant

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

500 × 150 = 700 × V₂

75000 = 700 × V₂

Divide both side by 700

V₂ = 75000 / 700

V₂ = 107 mL

Therefore, the final volume of the gas is 107 mL.

Answer: 54 molecules of water will be formed in the reaction.

Explanation:

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation, the balanced equation follows:

[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]

We are given:

Molecules of [tex]C_8H_{18}[/tex] = 6

Molecules of [tex]O_2[/tex] = 75

By the stoichiometry of the reaction:

If 2 molecules of [tex]C_8H_{18}[/tex] produces 18 molecules of water

So, 6 molecules of [tex]C_8H_{18}[/tex] will produce = [tex]\frac{18}{2}\times 6=54[/tex] molecules of water

Hence, 54 molecules of water will be formed in the reaction.

Answer:

Suppose that you add 29.2 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.78 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound

Explanation:

The mass of nonvolatile solute added is ---- 29.2g

The mass of solvent benzene is ---- 0.250kg = 250g

The Kf value of benzene is ---- 5.12^oC/m.

Depression in the freezing point of the solution is --- 2.78^oC.

What is the molar mass of the unknown solute?

[tex]The depression in freezing point = Kf * molality of the solution\\molality of the solution = \frac{mass of solute}{molar mass of solute}*\frac{1}{mass of solvent in kg}[/tex]

Substitute the given values in this formula to get the molar mass of unknown solvent:

[tex]molality=\frac{29.2g}{M} * \frac{1}{0.250kg} \\depression in freezing point:\\2.78^oC=5.12^oC/m * \frac{29.2g}{M} * \frac{1}{0.250kg} \\\\=>M=5.12^oC/m * \frac{29.2g}{2.78^oC} * \frac{1}{0.250g} \\\\\\=>M=215.1g/mol[/tex]

Hence, the molar mass of unknown solute is --- 215g/mol.

Answer:

46.525 u

Explanation:

From the question given above, the following data were obtained:

Isotope A (⁴⁶Ti)

Abundance (A%) = 77.100%

Mass of A = 45.95263 u

Isotope B (⁴⁸Ti):

Abundance (B%) = 17.100%

Mass of B = 47.94795 u

Isotope C (⁵⁰Ti):

Abundance (C%) = 5.800%

Mass of C = 49.94479 u

Average atomic mass =?

The average atomic mass of titanium can be obtained as follow:

Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

= [(45.95263 × 77.1)/100] + [(47.94795 × 17.1)/100] + [(49.94479 × 5.8)/100]

= 35.429 + 8.199 + 2.897

= 46.525 u

Therefore, the average atomic mass of titanium is 46.525 u

Answer:

mixture

Explanation:

an example of one is a salad you can separate the ingredients

Answer: The pH of the resulting solution will be 3.001

Explanation:

Molarity is calculated by using the equation:

[tex]\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}[/tex]          ......(1)

We are given:

Moles of NaOH = 0.0224 moles

Molarity of nitrous acid = 0.475 M

Molarity of sodium nitrite = 0.302 M

Volume of solution = 150 mL = 0.150 L          (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

[tex]\text{Moles of nitrous acid}=(0.475mol/L\times 0.150L)=0.07125mol[/tex]

[tex]\text{Moles of sodium nitrite}=(0.302mol/L\times 0.150L)=0.0453mol[/tex]

The chemical equation for the reaction of nitrous acid and NaOH follows:

                   [tex]HNO_2+NaOH\rightleftharpoons NaNO_2+H_2O[/tex]

I:                0.07125     0.0224     0.0453

C:             -0.0224     -0.0224   +0.0224

E:              0.04885         -          0.0677

The power of the acid dissociation constant is the negative logarithm of the acid dissociation constant. The equation used is:

[tex]pK_a=-\log K_a[/tex]        ......(2)

We know:

[tex]K_a[/tex] for nitrous acid = [tex]7.2\times 10^{-4}[/tex]

Using equation 2:

[tex]pK_a=-\log (7.2\times 10^{-4})=3.143[/tex]

To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:

[tex]pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}}[/tex]         .......(3)

Given values:

[tex][NaNO_2]=\frac{0.0677}{0.150}[/tex]

[tex][HNO_2]=\frac{0.04885}{0.150}[/tex]

[tex]pK_a=3.143[/tex]

Putting values in equation 3. we get:

[tex]pH=3.143-\log \frac{(0.0677/0.150)}{(0.04885/0.150)}\\\\pH=3.143-0.142\\\\pH=3.001[/tex]

Hence, the pH of the resulting solution will be 3.001

Answer:

317 mL.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 250 mL

Initial temperature (T₁) = 373.15 K

Final temperature (T₂) = 473.15 K

Pressure = Constant

Final volume (V₂) =?

The final volume of the air sample can be obtained by using the Charles' law equation as illustrated below:

V₁/T₁ = V₂/T₂

250 / 373.15 = V₂ / 473.15

Cross multiply

373.15 × V₂ = 250 × 473.15

373.15 × V₂ = 118287.5

Divide both side by 373.15

V₂ = 118287.5 / 373.15

V₂ = 317 mL

Therefore, the final volume of the air sample is 317 mL

Answer:

263 K

Explanation:

Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

In this case:

We input the data:

And solve for T₁:

Answer:

Carbon (i) : quaternary carbon

Carbon (ii) : secondary carbon

Carbon (iii) : tertiary carbon

Carbon (iv) : secondary carbon

Explanation:

Carbons can be classified into 4 categories:

(1) Primary carbon [tex](1^o)[/tex]: These are the atoms where the carbon atom is attached to one other carbon atom.

(2) Secondary carbon [tex](2^o)[/tex]: These are the atoms where the carbon atom is attached to two other carbon atoms.

(3) Tertiary carbon [tex](3^o)[/tex]: These are the atoms where the carbon atom is attached to three other carbon atoms.

(4) Quaternary carbon [tex](4^o)[/tex]: These are the atoms where the carbon atom is attached to four other carbon atoms.

In the given structure:

Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.

Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.

Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.

Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.

Answer:

C8H16 (Ethylcyclohexane).

Explanation:

From the given information:

Compound A is an alkene because it interacts with 1 unit of hydrogen across a palladium catalyst.

Also, we are given another hint that:

Compound A needs 4 equivalence of H2 to hydrogenate under circumstances that decrease aromatic rings, indicating that it is a phenyl substituted alkene.

Compound A with formula C8H8 reacts instantly with KMnO4 to produce CO2, as well as carboxylic acid, points out that Compound acts as a terminal alkene.

Therefore, we can opine that compound A is a terminal phenyl substituted alkene whose formula = C8H8 (Styrene)

The diagrammatic expression of the compound can be seen below.

However, in the presence of the palladium catalyst, the reduction of Compound A with 4 units of hydrogen produces Compound B: C8H16 (Ethylcyclohexane).

The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?

a. 16mm Hg

b. 24mm Hg  

c. 20mm Hg  

d. 12mm Hg

Answer: The vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.

Explanation:

Given: Mass of sucrose = 171 g

Mass of water = 1 L = 1000 g

Vapor pressure of water = 24 mm Hg

As moles is the mass of substance divided by its molar mass. Hence, moles of water (molar mass = 18.02 g) is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1000 g}{18.02 g/mol}\\= 55.49 mol[/tex]

Similarly, moles of sucrose (molar mass = 342 g/mol) is as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{171 g}{342 g/mol}\\= 0.5 mol[/tex]

Total moles = 55.49 + 0.5 mol = 55.99 mol

Mole fraction of water is as follows.

[tex]Mole fraction = \frac{moles of water}{total moles}\\= \frac{55.49}{55.99}\\= 0.99[/tex]

Formula used to calculate vapor pressure of the solution is as follows.

[tex]P_{i} = P^{o}_{i} \times \chi_{i}[/tex]

where,

[tex]P_{i}[/tex] = vapor pressure of component i over the solution

[tex]P^{o}_{i}[/tex] = vapor pressure of pure component i

[tex]\chi_{i}[/tex] = mole fraction of i

Substitute the values into above formula to calculate vapor pressure of water as follows.

[tex]P_{i} = P^{o}_{i} \times \chi_{i}\\= 24 mm Hg \times 0.99\\= 23.76 \\or 24 mm Hg\\[/tex]

Thus, we can conclude that the vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.

Answer:

C₆H₁₀NO

Explanation:

In order to arrive at a molecular formula we have to make some assumptions and they are

Assuming there is one ( 1 ) N and one ( 1 ) O that is present in the said molecule

Total mass =   29.998

next step: subtract the total mass from 112.0499 = 82.501

next : assume the presence of 6 carbon atoms in said molecule

Total mass =  6 * 12 = 72

Mass of Hydrogens = 82.501 - 72 = 10.501

∴ number of hydrogens = 10.501 / 1.0078  ≈ 10

Hence Total mass = 29.998 + 82.501  ≈ 112.0499

Finally Molecular formula = C₆H₁₀NO

Answer:

true because the bonds cannot be broken down

Answer:

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

100 mg/mL?

a. 25

b. 30

c.50

d. 60

Explanation:

if mali po I'm so sorry

About 60 tablets of 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing 100 mg/mL.

To calculate the number of tablets needed, we can use the following formula:

Number of tablets = (Desired total mass of metronidazole) / (Mass of one tablet)

The desired total mass of metronidazole in the suspension is given as 100 mg/mL × 150 mL = 15000 mg.

Since each tablet contains 250 mg of metronidazole, we can calculate the number of tablets as:

Number of tablets = 15000 mg / 250 mg = 60 tablets

Therefore, the correct answer is d. 60 tablets.

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#SPJ 2

Answer:

There are [tex]9[/tex] electrons in this atom.

Explanation:

Electron configuration of this atom: [tex]1s^2\, 2s^2\, 2p^5[/tex].

The electron orbitals of an atom are denoted as [tex]1s[/tex], [tex]2s[/tex], [tex]2p[/tex], [tex]3s[/tex], [tex]3p[/tex], etc. At any given time, an electron in this atom is located in exactly one orbital.

The electron configuration of an atom gives the number of electrons in each orbitals of this atom.

For example, in this atom, the superscript "[tex]2[/tex]" on the right of "[tex]1s[/tex]" means that there are two electrons in the [tex]1s\![/tex] orbital of this atom. Hence, [tex]1s^2\, 2s^2\, 2p^5[/tex] would translate to:

Hence, there would be [tex]2 + 2 + 5 = 9[/tex] electrons in total in this atom.

Answer: It's used in chemistry to measure the concentration of chemical solutions.

Explanation:

Beer's Law is used in chemistry to measure the concentration of chemical solutions, to analyze oxidation, and to measure polymer degradation.

The law also describes the attenuation of radiation through the Earth's atmosphere