Answer the following questions by choosing whether the first situation is less, equally, or more likely to happen than the second.

PART A


The probability of a chance event is 0.32, is likely to happen when compared to 1/3

Answers

Answer 1

Answer:

probably g

Step-by-step explanation:


Related Questions

what is a easier way to solve fractions ​

Answers

Answer: hewo, there! I hope I Made it easier to Understand

the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27

Step-by-step explanation:

To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction

Hope this helps you!!

Have a great day!!!

Pleeeeeeeaaase answer quick. With explanation. Will give 40 points

Answers

Answer:

See attached

Step-by-step explanation:

Review the picture

A sweater costs $25. The store marks up the price by 85%. What is the selling price of the sweater?

Answers

21.25 because $25x85%=21.25

What are some of the applications for exponential functions?
Designing identification tags
Conversion of measurements
Assigning phone numbers
Finding perimeter
Determining the number of subsets in a given set

Answers

Answer:

Option B and D are correct

Step-by-step explanation:

Exponential functions are really useful in the real world situation. They can be used to solve following

a) Population Models

b) Determination of area and perimeters

c) Determine time related things such as half life, time of happening of an event etc.

d) Useful for solving financial problems such as computing investments etc.

Hence, option B and D

How many odd numbers are between 10 and 50?

Answers

Answer:

There are 20 odd numbers between 10 and 50

Step-by-step explanation:

Here are all the odd numbers! Hope this helps!

11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49

Pls help me if u can

Answers

Answer:

523.33 cm³

Step-by-step explanation:

Formula of volume of sphere

[tex] = \frac{4}{3} \pi {r}^{3} [/tex]

The volume of the sphere

[tex] = \frac{4}{3} \times 3.14 \times {5}^{3} [/tex]

[tex] = \frac{1570}{3} [/tex]

[tex] = 523.3333333...[/tex]

= 523.33 cm³ (rounded to the nearest hundredth)

Suzanne collected data on the weight of her classmates. She found that the range of the data she collected was 17
Which of the following BEST explains what a range of 17 indicates?
A
The average distance of each point from the mean is 17.
.
B
The distance between the minimum and the maximum is 17.
С
The distance between the lower quartile to the upper quartile is 17.
D
The distance between the mean and the median in a skewed data set is 17

Answers

Answer:

the answer is A.

Step-by-step explanation:

1. Find (f(g(2)) for f(x)= 3x² and g(x)= 5 - x.

Answers

Answer: 27

Step-by-step explanation:

PLSS HELP ASAP!!
13 points when answered:) Thank you!!

Answers

Answer:

The wright answer is A

Step-by-step explanation:

[tex] \sqrt{20} = 4.47 \\ \frac{14}{3} = 4.67 \\ 4.47 < 4.5 < 4.67[/tex]

HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

50%
- Animals
Home
Economics -
20%
30%
- Farm Mechanics
There were 2500 entries at the county fair. The circle graph tells what types of entries were made.
How many were Farm Mechanics entries?

Answers

180 is the answer pls don’t get mad if i get it wrong

Answer:

750 were Farm Mechanics.

Step-by-step explanation:

30% of 2500 is 750.

Hope this helps

Represent the greatest common factor of 36 and 8 using the distributive property
36 + 8 =
0 4x(9+2)
O2 x (18+4)
O 8x (5+2)
0 11 x (3+1)

Answers

36/4= 9, 8/4= 2 a is correct

36/2=18, 8/2= 4 b is correct however wrong because it is the simplest distribution

36/8= 4.5, 8/8= 1 c is incorrect

36/11= 3.27, 8/11= .73 d is incorrect.

Answer is 4x(9+2)

14. On Monday, a work group eats at Ava's café,
where a lunch special is $8 and a dessert is
$2. The total is $108. On Friday, the group
eats at Bo's café, where a lunch special Is
$6 and a dessert is $3. The total is $90. Each
time, the group orders the same number of
lunches and the same number of desserts.
How many lunches and desserts are
ordered?
what the x and y value.

Answers

Answer:

no. who eat lunch special = 12

no. who eat dessert = 6

Step-by-step explanation:

Let x = no. who eat lunch special

y = no. who eat dessert

(1)    8x + 2y = 108             (2)    6x + 3y = 90

 Divide thru by 2                         Divide thru by 3

      4x + y = 54                          2x + y = 30

     -2x - y = -30

       2x = 24

         x = 12                               2(12) + y = 30

                                                    24 + y = 30

                                                            y = 6

                                                 

Sin 0= 8/17 determine the value of tan?

Answers

Answer:

tan theta = 8/15

Step-by-step explanation:

Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.

To find the value of the adjacent side from theta, use the Pythagorean Theorem.

a^2 + b^2 = c^2

8^2 + b^2 = 17^2

64 + b^2 = 289

Subtract 64.

b^2 = 225

Take the square root.

b = 15.

So that means:

the side opposite from theta is 8,

the side adjacent from theta is 15,

the hypotenuse is 17.

Now we take tan, opposite over adjacent, and use the values from the triangle.

tan = opposite / adjacent

tan = 8/15.

Mrs Mills buys 4 packs of treats for her cats, Fluff and tigger
she gives Fluff 1/6 of a pack each day
She gives tigger 1/5 of a pack each day
for how many complete days will the 4 packs of treats last

Answers

Answer: 10 days

Step-by-step explanation:

1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)

4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)

So 10 complete days.

Someone PLease help me

Answers

I’m pretty sure the answer is the last one. Playing football and soccer combined. If you look really closely you can see playing the piano takes up 1/4 of Brad’s time. And if you combine football and soccer you get about 1/4. Hope this helps

What is sec 0 when cot 0 = -4/2?

Answers

Answer:

[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]

Step-by-step explanation:

[tex]Cot0=-4\sqrt{2}[/tex]

[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]

[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]

[tex]=\frac{4\sqrt{66} }{32}[/tex]

[tex]=\frac{\sqrt{66} }{8}[/tex]

--------------------

hope it helps...

have a great day!!

Helpppppppppppppppppppp

Answers

Answer:

95°

Step-by-step explanation:

95°

They are vertical angles.

Answer:

95 degree write it fast jakakkaoaoa

Can someone help? I hate math so much lol I don’t understand

Answers

Answer:

±6

Step-by-step explanation:

Given the mathematical expression;

√36 < √42 < √49

But, √36 = 6 * 6 = 6²

√49 = 7 * 7 = 7²

Simplifying further, we would substitute the new values respectively;

±[6] < √42 < ±[7]

Therefore, evaluating √36 is equal to ±6.

Rosalind made 969 donuts and put 8 donuts into each box. How many boxes of donuts were made

Answers

Answer:

121 donuts in each box

Step-by-step explanation:

969 divided by 8 = 121.125

(Ignore the remainder)

Step by step solution:

We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.

Step 1:

Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:

969/8 = x

Step 2:

Doing this, we can get 121.125, which leaves us with

121.125 = x

121.125 = 121.125

Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.

Checking our answer:

We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like

8 * 121.125 = x

969 = x

969 = 969

Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!

hey I need help with my coordinates ​

Answers

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

Using the product of the means equals the product of the extremes, solve for x, to the nearest tenth. 4:9=x:6​

Answers

Cross multiply:

4 x 6 = 9x

24 = 9x

Divide both sides by 9

X = 24/9

X = 2.7 ( rounded to the nearest tenth)

Find the surface area of the prism.
2 in.
2 in.
6 in.

Answers

Answer:

56 m^2

Explanation: L=2, H=2, W=2, d = 6.63324958 m, TSA = 56 m^2, LSA = 48 m^2, TSA = 4 m^2, BSA = 4 m^2, V = 24 m^3

The management of KSmall Industries is considering a new method of assembling a computer. The current assembling method requires a mean time of 66 minutes with a standard deviation of 3.0 minutes. Using the new method, the mean assembly time for a random sample of 24 computers was 61 minutes.
a. Using the 0.10 level of significance, can we conclude that the assembly time using the new method is faster?
b. What is the probability of a Type II error? (Round "Critical values" to 2 decimal places and round your final answer to 4 decimal places.)

Answers

Answer:

Part a:

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)=  0.6628

Step-by-step explanation:

The null and alternate hypothesis are

H0: μ1 ≥ μ2   against the claim Ha: μ1 < μ2

This is left tailed test

The critical region for this test at 0.10 ∝ is z < ± 1.28

The test statistic

z= x1-x2/ s/√n

z= 66-61/ 3/√24

z= 5/0.61238

z= 8.16486

Since the calculated z= 8.1649 falls in the critical region  z < ± 1.28 we reject H0 and conclude that the assembly time using the new method is faster.

Part b:

P (Type II Error)  = P ( accept H0/ H0 is false)

z ( ∝)= X-u/s/√n

1.28= X-61/0.61238

X= 61.7838

So I will incorrectly fail to reject the null as long as a draw a sample mean that greater than 61.7838

 The probability of a Type II error is given by

P (z> 61.7838-66/24)

P (z>- 0.42161)

From the tables

P (z>- 0.42161)=  0.6628

If a rectangle has an area of 48 cm², what would be the area of a similar rectangle if
the dimensions are doubled?
A) 2304 cm^2
B) 192 cm^2
C)96 cm^2
D)216 cm^2

Answers

Answer is
B)192cm^2
Step by step exploration

You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir

Answers

Answer:

a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.

b- The test statistic is given as

[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]

Step-by-step explanation:

a-

This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.

b-

The F-Value is given as

[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]

Here MSA is given as

[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]

Here

I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]

Similarly MSAB is given as

[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]

Here

I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type i

By putting these values and simplifying, equation becomes:

[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]

This is further simplified as

[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]

The numerator can be written as

[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]

what is the midpoint of a segment with endpoints at (-4,-8) and (8,10)

Answers

Answer: Midpoint: (2, 1)

Step-by-step explanation:

Midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)

(-4 + 8)/2 = 2

(-8 + 10)/2 = 1

Answer: (2, 1)

!NO LINKS, NO FILES!

please :)

Answers

area is base x height
12 x 6 = 72
the area is 72 in^2

Answer:

the area is 72

Step-by-step explanation:

Find the area of the composite figure.
9 ft
4 ft
6 ft

Answers

92 square feet is the answer

Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.

Answers

Answer:

t

Step-by-step explanation:

A circle can be circumscribed about the given quadrilateral, the answer is: A. True.

We know that,

To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.

Opposite angles of a circumscribed polygon are supplementary.

Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.

Learn more about circumscribed polygon on:

brainly.com/question/1423054

#SPJ7

The most expensive type of life insurance is

O limited-payment life insurance

O term insurance

O endowment life insurance

O whole-life insurance

Answers

Whole life insurance I think
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