Answer the following questions using 125 words or more:

Write about the similarity of the original comic to the enlargement. How similar are they and how can you tell? What would cause differences in the two pictures? If you drew another comic using a grid, is there anything you would do differently?
What would happen if you reduced the comic's size rather than enlarged it? Would the process be the same? What would you do differently?

Link to video 2min https://media-release.glynlyon.com/g_mat08_ccss_2016/4/media/html5/anm_scale_drawing_comic_project/media/video.mp4

hopefully this answer can help you to answer the next question.

Answer:

j+2

Step-by-step explanation:

combine like terms

3k - 3k = 0

8j - 7j = 1j or j

6 - 4 = 2

put it all together

j + 2

Answer:

j + 2

Step-by-step explanation:

= 8j - 3k + 6 - 7j + 3k - 4

= 8j - 7j - 3k + 3k + 6 - 4

=j + 2

Answer from Gauth math

1.4

2.3

3.7

solution 1

2+2+=4

solution 2

3

Let's do

[tex]\\ \sf\longmapsto 2sin^260cos60tan^245[/tex]

[tex]\\ \sf\longmapsto 2\left(\dfrac{\sqrt{3}}{2}\right)^2\times \dfrac{1}{2}\times (1)^2[/tex]

[tex]\\ \sf\longmapsto 2\times \dfrac{(\sqrt{3})^2}{2^2}\times \dfrac{1}{2}\times 1[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{2}\times \dfrac{1}{4}[/tex]

[tex]\\ \sf\longmapsto \dfrac{3}{4}[/tex]

Trigonometric values

[tex]\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}[/tex]

Answer:

Step-by-step explanation:

The supplement of the exterior angle is 180 - 75 = 105

In a cyclic quadrilateral (a four sides figure where all the vertices touch the circumference of a circle), the opposite angles are supplementary. Therefore <a = 180 - 105 = 75

But I think you already knew that.

Answer:

y=(5/6)x-6

Step-by-step explanation:

The slope intercept form of a line is y=mx+c. The equation of the line will be y=(5/6)x-6

Answer:

26

Step-by-step explanation:

Given: Lines J and H are parallel lines. O intersects both lines equally.

Since two angles equal 180, that will be what  (4y + 12) and 64 will be equal to.

(4y + 12) + 64 = 180

76 + 4y = 180

-76          -76

-------------------

    4y = 104

      y = 26

x and y is both 26 because they are vertical angles.

Hope this helped.

Answer: 90 points

Step-by-step explanation:

Team A's score = 72 points

Team B's score = 125% of A's

= 90 points

please click thanks and mark brainliest if you like :)

Answer:

Step-by-step explanation:

¾*90=67.5

180-67.5=112.5°

Answer:

60°

Step-by-step explanation:

You can see the explanation in the picture

Answer:

x = 59/10, z = 237/70, and y = -121/70

Step-by-step explanation:

Answer:

we have to add (-b) to get (a)

Step-by-step explanation:

a+b+(-b)=a

a+b-b=a

a=a

Hence verified.

Hope this helps you. Have a nice day^_^

Answer:

The 3rd one, 10.5+(-7.5)+12

Step-by-step explanation:

If something is +(-), the answer is minus.

So therefore 10.5-7.5+12 would be our answer

Which is equivalent to the original expression

Hope this helps!

Answer:

20 books

Step-by-step explanation:

35/1.75

20

Answer:

-3

Step-by-step explanation:

-8 - x =-5

Answer:

100/360

Step-by-step explanation:

A circle is 360 degrees

100/360

10/36

5/18

Answer:6

Step-by-step explanation: The rules of exponential says (a^x)^y=a^xy.

Therefore you will multiply 1/4 with 4 to get an exponent of 1. So the answer is 6^1 which is also written as 6

[tex]\\ \sf\longmapsto x+14+x=32[/tex]

[tex]\\ \sf\longmapsto 2x+14=32[/tex]

[tex]\\ \sf\longmapsto 2x=32-14[/tex]

[tex]\\ \sf\longmapsto 2x=18[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{18}{2}[/tex]

[tex]\\ \sf\longmapsto x=9[/tex]

This problem can be a bit confusing, so let's break it down:

First, let's take the area of the square (A = b · h):

A = 15 · 15

A = 225 cm²

Now comes the confusing part:

We can tell that the non-shaded area is 1/4 of a circle, so, if we take 1/4 of the area of a circle, we can subtract its area from the area of the square:

A = πr²

A = 15²π

A = 225π

1/4 A = 225π / 4

New Area = 56.25π

Or... about 176.7

Since we have both of the areas, all we have to do is subtract:

225 - 176.7 =

48.3.

Your final answer is 48.3 cm²

Answer:

c) 12/15 = 4/5

Step-by-step explanation:

imagine we mirror the triangle up, so that Z is on top.

then you can clearly see that 6 is cos(X) times r (and r is then 7.5).

XY is sin(X)×7.5

and again, 7.5 is r (the line making the X angle).

so, the cosine ratio of X is

6 = cos(X)×7.5

cos(X) = 6/7.5 or then 12/15. or simplified 4/5.

Answer:

320 minutes (5 hours and 20 minutes).

Step-by-step explanation:

2 hours and 17 minutes = 137 minutes

137 + 84 + 99 = 320

Therefore, they will spend 320 minutes (5 hours and 20 minutes) watching movies.

Answer: the answer to this is 3x-2

Step-by-step explanation:

Answer:

Step-by-step explanation:

i don't understand this language but i think you want to simplify  it.

[tex]\frac{3x-3\sqrt{x} -3}{x+\sqrt{x} -2} -\frac{\sqrt{x} +1}{\sqrt{x} +2} +\frac{\sqrt{x} -2}{1-\sqrt{x} } \\=\frac{3x-3\sqrt{x} -3}{x+2\sqrt{x} -\sqrt{x} -2} -\frac{\sqrt{x} +1}{\sqrt{x} +2} -\frac{\sqrt{x} -2}{\sqrt{x} -1} \\=\frac{3x-3\sqrt{x} -3}{\sqrt{x} (\sqrt{x} +2)-1(\sqrt{x} +2)} -\frac{(\sqrt{x} +1)(\sqrt{x} -1)+(\sqrt{x} +2)(\sqrt{x} -2)}{(\sqrt{x} +2)(\sqrt{x} -1)} \\=\frac{3x-3\sqrt{x} -3}{(\sqrt{x} +2)(\sqrt{x} -1)} -\frac{(x-1)+(x-2)}{(\sqrt{x} +2)(\sqrt{x} -1)} \\[/tex]

[tex]=\frac{3x-3\sqrt{x} -3-2x+3}{(\sqrt{x} +2)(\sqrt{x} -1)} \\=\frac{x-3\sqrt{x} }{(\sqrt{x} +2)(\sqrt{x} -1)}[/tex]

If x is the number 0.222…, then 10x = 2.222…. Subtracting x from 10x eliminates the fractional part, so that

10x - x = 2.222… - 0.222…

==>   9x = 2

and solving for x gives x = 2/9.

Answer:

y = - [tex]\frac{1}{4}[/tex] x - 1

Step-by-step explanation:

Assuming you require the equation of the line

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - [tex]\frac{1}{4}[/tex] , then

y = - [tex]\frac{1}{4}[/tex] x + c ← is the partial equation

To find c substitute (12, - 4) into the partial equation

- 4 = - 3 + c ⇒ c = - 4 + 3 = - 1

y = - [tex]\frac{1}{4}[/tex] x - 1 ← equation of line

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Annual interest rate (i)= 0.055

Initial investment (PV)= $10,000

Number of years (n)= 7

To calculate the future value (FV), we need to use the following formula (except in d):

FV= PV*(1+i)^n

a.

Semiannual interest rate= 0.055/2= 0.0275

Number of semesters= 7*2= 14

FV= 10,000*(1.0275^14)

FV= $14,619.94

b.

Quarterly rate= 0.055/4= 0.01375

Number of quarters= 7*4= 28

FV= 10,000*(1.01375^28)

FV= $14,657.65

c.

Monthly interest rate= 0.055/12= 0.0045833

Number of months= 7*12= 84

FV= 10,000*(1.0045833^84)

FV= $14,683.18

d.

To calculate the future value using continuous compounding, we need to use the following formula:

FV= PV*e^(n*i)

FV= 10,000*e^(7*0.055)

FV= $14,696.14

Answer:

F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)

Step-by-step explanation:

The minimum value of the curve = (1.9, -5.7),

The maximum value = (0, 2)

The point the function crosses the x-axis (the x-intercept) = (-0.7, 0), (0.76, 0), and (2.5, 0)

The point the function crosses the y-axis (the y-intercept) = (0, 2)

The given points can be plotted using MS Excel, from which we have;

F(x) is less than 0 over the interval from x = -∞, to x = -0.7, and the interval from x = 0.76 to x = 2.5

The correct option is therefore, F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)

Answer:

A. F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5).

Step-by-step explanation: