Answer:
to sell and to buy
Explanation:
measurement is a comparison between unknown quantity with a known quantity
what is work - energy theorem ??
The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.
This idea is expressed in the following equation:
is the total work done
is the change in kinetic energy
is the final kinetic energy
is the initial kinetic energy
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When you put water in the ice tray in the freezer, water becomes ice. Ice is more ordered than water. Is this a violation of Second Law of Thermodynamics
Answer:
No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.
Explanation:
A car is accelerating at 6 m/s2. How long would it take the car to go 12 m/s faster?
Answer:
2 seconds
Explanation:
Each second, it increases its speed by 6 m/s, so it will take 2 seconds for the speed to increase by 12 m/s.
An object is launched at a 60 degree angle with an initial velocity of 100
m/s. What is the objects height? How long is the object in the air? What is
the objects's range (distance)? *
PLS HELP QUICK LOL
Answer:
Explanation:
The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:
[tex]v^2=v_0^2+2a[/tex]Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:
[tex]v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}[/tex]
And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:
[tex]0=(90)^2+2(-9.8)[/tex]Δx
[tex]0=8000-20[/tex]Δx and
-8000 = -20Δx so
Δx = 400 m
Now for the time it was in the air...we will use the simple equation
[tex]v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9[/tex]
So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:
Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.
[tex]v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}[/tex]
And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:
Δx = [tex]50(9)+\frac{1}{2}(0)(9)^2[/tex]
Δx = 500 m
A mountain climber at the peak ha ___________ energy.
A.gravitational potential
B. Elastic potential
C.Kinetic
find the final velocity of the initial velocity of 8m/s with an acceleration of 7 m/s2 over 3 second interval
Please find attached photograph for your answer. Hope it helps! Please do comment.
How do we know how much
gravitational force objects have?
Answer:
With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.
Explanation:
i hope this helps
If it takes Tanya 9.4 hours to get to her cousin's house while driving an average of 40 mph, how far away does her
cousin live?
Answer:
376 miles
Explanation:
speed = distance / time
therefore distance = speed * time
distance = 40 miles/hr * 9.4 hr
then
distance = 375 miles
10. What is a rule for determining the mass?
Answer:
Mass number is the sum of the protons and neutrons in the atomic nucleus.
The mass number (A) is the sum of the atomic number (Z), which is the number of protons, and the number of neutrons (N) in the atomic nucleus of an isotope of an element. A=Z+N
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Question:-
Convert 4cm to m
Solution:-
Lets do
First note down the below formula
[tex]\boxed{\sf 1m=10^{2}cm}[/tex]
Then
[tex]\boxed{\sf 1cm=10^{-2}cm}[/tex]
Now we are given 4cm
So convert
[tex]\\ \sf\longmapsto 4\times 10^{-2}m[/tex]
If we simplify to decimal
[tex]\\ \sf\longmapsto 4cm=0.04m[/tex]
Hence done .
Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?
Average Velocity=Total Distance/Total Time
[tex]\\ \sf\longmapsto \dfrac{2.5}{9.1}[/tex]
[tex]\\ \sf\longmapsto 0.3m/s[/tex]
What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a
velocity of 3 m/s?
What’s the answer
Answer:
kinetic energy = 1/2mv²
k.E =1/2 X 0.5 X 3²
k.e = 9/4
K.E = 2.25j
Every mass exerts a gravitational force on every other mass.
a. True
b. False
Answer:
A
Explanation:
newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses
Convert the following in to SI units without changing its values
A. 4000 g
b. 2.4 km
A. The S.I unit of mass is kg . therefore we have to convert 4000g into kg from gram
i.e 4000g = 4 kg
B. The S.I unit of length is meter. so we have to convert 2.4 km into meters,
i.e 2.4 km = 2400 m
#A
[tex]\boxed{\sf 1kg=1000g}[/tex]
[tex]\\ \sf\longmapsto 4000[/tex]
[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]
[tex]\\ \sf\longmapsto 4kg[/tex]
#B
[tex]\boxed{\sf 1km=1000m}[/tex]
[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]
[tex]\\ \sf\longmapsto 2400m[/tex]
A car traveling at 90 m/s can stop in a distance of 110 m. What is the magnitude of the cars acceleration as it slows down?
I think I have already answer this question. Anyways please do let me know whether it is useful or not
If you are given force and time, you can determine power if you can know
(a) watts
(b) energy
(c) distance
Answer:
joules/energy.
Explanation:
power is defined as the rate of work. Hence power=work/time, then you obtain Watts.
Work is the product of force and displacement.
Write any three condition required for nuclear fussion that are found in the sun.
Answer:
High pressure squeezes the hydrogen atoms together. They must be within 1x10-15 meters of each other to fuse. The sun uses its mass and the force of gravity to squeeze hydrogen atoms together in its core. We must squeeze hydrogen atoms together by using intense magnetic fields, powerful lasers or ion beams.
explain 3points to be taken into consideration while measuring the length of a body
Answer:
Y T and v
Explanation:
I NEED THE ANSWER TO PASS SO I CAN GET MY PHONE BACK HELPPPPPPPPPPPPPP
Answer:
it would be c.
Explanation:
starts at zero and isn't a straight shot up
2. Determine the units of the quantity described by each of the following
combinations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)
We have that the unit of the quantities are described
a.kg (m/s) (1/s)=Newton
b. (kg/s) (m/s^2)=Newton
c. (kg/s) (m/s)^2=Newton
d. (kg/s) (m/s)=Newton
From the question we are give the units
a.kg (m/s) (1/s)
b. (kg/s) (m/s^2)
c. (kg/s) (m/s)^2
d. (kg/s) (m/s)
a)
Generally
kg (m/s) (1/s) is Represented as Newton
Where Newton is the unit Force and Weight
b)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
c)
kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
d)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
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a car is traveling north. can its acceleration vector ever Point South? explain
When a car is traveling north, its acceleration vector can point south when it is slowing down.
A vector quantity has both magnitude and direction. The direction of a vector is always shown by the direction to which the arrow points.
If the car is travelling north, the direction of the acceleration vector will continue to point northwards.
However, when the car slows down, the direction of the accelerating vector will now point southwards.
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show that Newton's first law is the special case of Newton's second law of motion
Please find attached photograph for your answer. Please do comment whether it is useful or not.
Identify the parts of the body based on the medical terminology given:
1. mr. heart describes pain that is midline, superior to the chest but inferior to the chin.
2. miss triangle says that she has a ‘tweak’ that is superior to the waist, inferior to the breast bone, lateral to the umbilicus on the left side of the body on the anterior surface.
3. mr. square states that he has pulled a muscle, inferior to the buttocks, superior to the knee, medial to the right side of the body on the posterior surface.
4. miss circle complains of a sharp pain inferior to her ears, superior to the scapula at midline on the posterior side of her body.
5. mr. x says that he has numbness and tingling on the anterior side of his left arm, distal to the wrist.
6. mrs. diamond describes a throbbing pain on the posterior side of her body, inferior to her shoulder blades and superior to her waist.
7. miss arrow states that she has had a pain on the left side of her body, superior to her neck and inferior to her forehead, lateral to her nose.
8. mr. teardrop says that he has been bitten by a spider lateral to his umbilicus on the anterior aspect of his body, superior to his hip on the right side of his body.
9. miss eight describes a burning sensation on the posterior side of her body, lateral to the spine on the left side of the body inferior to the shoulder blade, inferior to the waist but anterior to the knee.
10. mr. four shows you a deep wound on the anterior side of his body, medial to the left hip, lateral to the umbilicus, inferior to the collarbone and anterior to the waist.
Answer:
1. Right hypochondriac region (upper, right).
2. Epigastric region (upper, middle).
3. Left hypochondriac region (upper, left).
4. Right lumbar region (middle, right).
5. Umbilical region (centre).
6. Left lumbar region (middle, left).
7. Right iliac region (lower, right).
8. Hypogastric region (lower, middle).
9. Left iliac region (lower, left).
Explanation:
1. Right hypochondriac region (upper, right)- Liver, gallbladder, right kidney, small intestine.
2. Epigastric region (upper, middle)- stomach, liver, pancreas, duodenum, spleen, adrenal glands
3. Left hypochondriac region (upper, left)- Spleen, colon, left kidney, pancreas
4. Right lumbar region (middle, right)- Gallbladder, liver, right colon
5. Umbilical region (centre)- Umbilicus, parts of the small intestine, duodenum
6. Left lumbar region (middle, left)- Descending colon and left kidney
7. Right iliac region (lower, right)- Appendix and cecum
8. Hypogastric region (lower, middle)- Bladder, reproductive organs, sigmoid colon
9. Left iliac region (lower, left)- Descending and sigmoid colon.
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Bobo, the clown, wants to set the world record for the furthest range traveled by a clown shot out of a cannon. Write a sentence describing the cannon that Bobo would need to use to accomplish this feat. Be sure to include the necessary initial velocity and the required angle of the cannon. Score: 0 / 1
In the human cannonball act makes use of of a special type of "cannon" that more safely ejects a person who acts as the "cannonball"
The world record for the longest flight by a human cannonball is approximately 194 feet and therefore the human cannon catapult that Bobo would need is one that would be able to propel him with an initial velocity of more than 120 kilometer per hour (more than the speed of the current record holder) with the cannon directed at an angle 45 degrees above the horizonal
The reason the values given above are correct is as follows:
The world record of the furthest range of the human cannonball is 193 ft. 8.8 inches. The maximum claim for the furthest range of a human cannonball is 200 ft. 4 in. Therefore, to safely set the world record would be to reach a range of 194 feet
The speed with which the world record was accomplished (120 km/jhr) should be expected to be exceeded given, horizontal speed in free fall motion is constant (decreasing in the presence of drag), and the conditions are likely to be more or less similar
In order to reach the furthest range, R, at the possible speed, the angle of inclination of the "cannon" required is 45°, according to the range formula, which is given as follows;
[tex]Range, \ R = \dfrac{v^2 \times sin(2\cdot \theta)}{g}[/tex]
The maximum range is given where θ = 45, such that sin(2·θ) = sin(90°) = 1
A further range than the world record van be obtained using the above values
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In Physics what's does cos and sin stand for?
Answer:
Sin = Sine
Cos = Cosine
Explanation:
Sin(θ) = Opposite/Hypotenuse
Cos(θ) = Adjacent/Hypotenuse
Add these two velocity vectors to find the magnitude of their resultant vector.
5.8 meters/seconds + 1.2 meters/seconds
The magnitude of their resultant vector is 4.6 meters/seconds
Since we are to add the velocity vectors in order to find the magnitude of their resultant vector.
Hence:
Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)
Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds
Resultant vector magnitude 4.6 meters/seconds
Inconclusion The magnitude of their resultant vector is 4.6 meters/seconds
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The microwave portion of the spectrum has wavelengths ranging from 1 mm to 1 m. Find the corresponding frequencies. g
Answer:
f = c / y where y is the wavelength
f1 = 3 *10E8 m/s / .001 m = 3 * 10E11 / s
f2 = 3 * 10E8 m/s / 1 m = 3 * 10E8 / s
1. Calculate the height of tree, 250 m away that produces
an image 1.5cm high
in a
pin-hole camera of width 30 cm.
Answer:
Explanation:
1.5/30 = x/250
x = 12.5 m
Select the correct answer.
Calculate the force of gravity on a 1–kilogram box located at a point 1.3 × 107 meters from the center of Earth. (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)
A.
2.36 newtons
B.
3.58 newtons
C.
4.87 newtons
D.
8.95 newtons
Answer:
A. 2.36 Newtons
Explanation:
F = GmM/d²
F = 6.673 x 10⁻¹¹(1)(5.98 x 10²⁴) / (1.3 x 10⁷)²
F = 2.36121...
Very poor question design.
mass of box... 1 significant digit
distance... 2 significant digits
mass of earth... 3 significant digits
value of G... 4 significant digits
Answer precision to 3 significant digits is not justifiable
A vehicle starts from rest and travels 50 m in 5 s. What is its acceleration?
