Answer:
shift of 6 units left
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
f(x) = 3 | x + 6 | + 9
Represents a horizontal shift of the parent function 6 units left
match the absolute value functions with their vertices
A student survey was conducted at a major university. Data were collected from a random sample of 206 undergraduate students, and the information that was collected included physical characteristics (such as height and handedness), study habits, academic performance and attitudes, and social behaviors. In this exercise we will focus on exploring relationships between some of those variables. The variables are:
Answer:
Students Major
Cheat reporting response
Number of Alcohols taken
Student's Height
Step-by-step explanation:
The Variables are the following:
Categorical variables
1. Major – The student's majors -
Arts & Social Science or STEM
2. Cheat - Response about reporting cheating - Yes or No
Quantitative Variables
3. Alcohol - Number of alcoholic beverages consumed in a typical week
4. Height - Self-reported height (in inches)
What’s the answer? I don’t understand the question and I came to see if you all can help
Answer:
15/2 that is the answer man
The height, h, in metres, of a rocket t seconds after it is launched is approximately modelled by the quadratic relation h = 80t - 16t2. To the nearest second, how long is the rocket in the air?
Answer: 5 s
Step-by-step explanation:
Given
Height of the rocket can be modelled as [tex]h=80-16t^2[/tex]
Rocket will land on earth when it's height becomes 0
[tex]\Rightarrow 80t-16t^2=0\\\Rightarrow t(80-16t)=0\\\\\Rightarrow t=0\ \text{or}\ t=\dfrac{80}{16}=5\ s[/tex]
Neglecting 0 value
Thus, rocket remains in air for 5 s.
A rectangle is 12 feet long and 5 feet wide. If the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in the area of the rectangle? The change in the area of the rectangle is
Answer:
no change in area
Step-by-step explanation:
The original area is
A = 12*5 = 60 ft^2
The new length and width
l = 12 + .25 (12) = 12+3 =15
w = 5 - .2 (5) =5-1 = 4
The new area is
A = l*w =15*4 = 60 ft^2
The area is the same
Help anyone can help me do this question,I will mark brainlest.
Answer:
Answer is in attached image
I hope it help...
How to find a parallel sides of trapezium length 7.3mm and 5.3mm ,and it's height is 5mm calculate the area of a trapezium
Answer:
31.50 mm²
Step-by-step explanation:
A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs
Characteristics of a trapezoid
It has 4 vertices and edges
If both pairs of its opposite sides of a trapezoid are parallel, it becomes a parallelogram
Area of a trapezoid = 1/2 x (sum of the lengths of the parallel sides) x height
1/2 x ( 7.3 + 5.3) x 5 = 31.50 mm²
What should be done so that the expression will have a value of 28?
6 + 2 + 32 × 2
Answer:
6+2+(32×2)
6+2+(64)
8+64
72
difference between 72 and 28
72-28
=44
add 44 to make the value 28
Find out the values of x and y from the following ordered pairs.
(x + y, 2) = (13, 2x – y)
Answer:
(x, y) = (5,8)
Step-by-step explanation:
Comparing the ordered pairs we get, x+y=13 and 2=2x-y. Solving it we will get, x=5 and y=8
Question 4 of 5
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each explicit formula to its corresponding recursive formula.
(8) = 5(5)(1-1)
(n) = 3 +5(n-1)
(3) = 5+3(1-1)
7(n) = 3(5)(n-1)
$(n) = 5 +5(n-1)
f(1) = 5
(*) = 3;(n - 1), for 3
(1) = 5
(n) = f(n-1) +5, for n?
f(1) = 5
f(n) = f(n-1) + 3, for n?
Given:
The recursive formulae.
To find:
The correct explicit formulae for the given recursive formulae.
Solution:
If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:
[tex]f(n)=ar^{n-1}[/tex]
Where, a is the first term and r is the common ratio.
The first recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:
[tex]f(n)=5(3)^{n-1}[/tex]
Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].
If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:
[tex]f(n)=a+(n-1)d[/tex]
Where, a is the first term and d is the common difference.
The second recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:
[tex]f(n)=5+(n-1)5[/tex]
[tex]f(n)=5+5(n-1)[/tex]
Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].
The third recursive formula is:
[tex]f(1)=5[/tex]
[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].
It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:
[tex]f(n)=5+(n-1)3[/tex]
[tex]f(n)=5+3(n-1)[/tex]
Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].
Can someone please help me with this I’m struggling
Answer:
Equation: [tex]70=(x+3)x[/tex]
x = -10 or x = 7
x = 7 (width can't be negative)
x + 3 = 10
Step-by-step explanation:
Represent the width of the rectangle by x. "The length of a rectangle EXCEEDS the width by 3" means the length is 3 LONGER than the width, so the length is represented by the expression x + 3.
Area = (length)(width)
70 = (x + 3)x
Multiply out the right side.
[tex]70=x^2+3x\\x^2+3x-70=0[/tex]
Factor the left side.
[tex](x+10)(x-7)=0[/tex]
Each binomial could equal 0, so
[tex]x+10=0 \text{ or }x-7=0\\x=-10\text{ or }x=7[/tex]
The negative solution does not make sense as the width of a rectangle.
x = 7, making the length, x + 3 = 10
Answer:
Pls mark this as brainiest
Step-by-step explanation:
Area of the rectangle = length x breadth
consider 'x' to be width
therefore length = x+3
area = (x+3)*x
Area = 70 square
x = 7
x+3 = 7+3
= 10
verification
7 x 10
= 70
Question 4(Multiple Choice Worth 4 points)
.
(08.03)Solve the system of equations and choose the correct answer from the list of options.
X + y = -3
y = 2x + 2
a- five over 3, four over 3
b-negative five over 3, negative four over 3
c- negative 3 over 5 negative 3 over 4
D- 3 over 4, 3 over 5
Answer:
Hello,
Answer B (-5/3,-4/3)
Step-by-step explanation:
I am going to use the substitution 's method.
[tex]\left\{\begin{array}{ccc}x+y&=&-3\\y&=&2x+2\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\x+2x+2&=&-3\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\3x&=&-5\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&2*(-\dfrac{5}{3})+2\\\end {array} \right.\\\\\\\boxed{\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&-\dfrac{4}{3}\\\end {array} \right.\\}[/tex]
Find the distance between the
following points using the
Pythagorean theorem: (5, 10)
and (10, 12)
Answer:
[tex]\displaystyle d = \sqrt{29}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]Step-by-step explanation:
*Note:
The distance formula is derived from the Pythagorean Theorem.
Step 1: Define
Identify
Point (5, 10)
Point (10, 12)
Step 2: Find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(10 - 5)^2 + (12 -10)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{5^2 + 2^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{25 + 4}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{29}[/tex]Please help me answer this question.
Answer:
total candy = 54 bags
y=17
x=37
Step-by-step explanation:
5x + 4y = 253
x-y = 20
x = 20+y
5(20+y) + 4y = 253
100 + 9y = 253
9y = 153
y=17
x=37
GIVE FULL STEP BY STEP OF THIS MATHS WORD PROBLEM
Sohanlal is a gardener. He is paid ₹160 daily, find how much money will he
get in the month of September?
Answer:
Step-by-step explanation:
days in september=30
salry paid per day=Rs.160
salary paid in 30 days=160×30=Rs.4800
Answer:
4800
Step-by-step explanation:
In the month of September there are only 30 days. So assuming Sohanlal works the entire month of September we will multiply how much he makes daily which is 160 times the amount of days he works which is 30. this will look like this:
160 × 30 = 4800
6. The right triangles ABC and DEF are
similar. The hypotenuse of AABC
measures 28 cm and the hypotenuse
of A DEF measures 7 cm. If one of the
legs of AABC measures 16 cm, what
does the corresponding leg of ADEF
measure?
F 1 cm
H 12 cm
G 4 cm
J 64 cm
Answer:
G. 4 cm
Step-by-step explanation:
28 divided by 7 equals 4.
So, 16 divided by 4 equals 4, which is the answer.
4 is the multiple that relates AABC to ADEF.
Can you answer this math homework? Please!
Answer:
y + 2.3 = 0.45x
y = 0.45x - 2.3
-2y = 4.2x - 7.8
-2(0.45x - 2.3) = 4.2x - 7.8
-0.90x + 4.6 = 4.2x - 7.8
-0.90x - 4.2x = -7.8 - 4.6
-5.1x = - 12.4
x = -12.4 / -5.1
x = 2.4
y + 2.3 = 0.45x
y = 0.45(2.4) - 2.3
y = 1.08 - 2.3
y = -1.2
solution is : (2.4, - 1.2)
Step-by-step explanation:
Complete the missing parts of the
table for the following function. (picture) please answer all asap
Answer:
x=-1 y = 1/3
x = 1 y = 3
x = 3 y = 27
Step-by-step explanation:
y = 3^x
Let x = -1
y = 3^-1 = 1/3^1 = 1/3
Let x = 1
y = 3^1 = 3
Let x = 3
y = 3^3 = 27
the polygons in each pair are similar. find the missing side length.
Given:
The polygon in the given figure are similar.
To find:
The missing side length.
Solution:
We know that the corresponding sides of similar figures are proportional.
The given polygons are similar, so the their corresponding sides are proportional.
[tex]\dfrac{x}{15}=\dfrac{32}{40}=\dfrac{32}{40}[/tex]
So, the missing values in the equation of proportion are 15, 40, 32 respectively.
On solving the above equation, we get
[tex]\dfrac{x}{15}=\dfrac{4}{5}=\dfrac{4}{5}[/tex]
[tex]\dfrac{x}{15}=\dfrac{4}{5}[/tex]
[tex]x=\dfrac{4}{5}\times 15[/tex]
[tex]x=12[/tex]
Therefore, the value of x is 12.
9. what is the measure of QSR
=======================================================
Explanation:
Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.
We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.
For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A
A+N+T = 180
A+108+34 = 180
A+142 = 180
A = 180-142
A = 38
So angle NAT is 38 degrees.
----------------------------
Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.
We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees
----------------------------
The angles QSR and QST are a linear pair, so they are supplementary
(angle QSR) + (angle QST) = 180
angle QSR = 180 - (angle QST)
angle QSR = 180 - 38
angle QSR = 142 degrees
i need help ASAP please
Answer:
reflection over Y axis
Step-by-step explanation:
Answer:
I believe it is D) a reflection over the Y-axis
Step-by-step explanation
it is going over the Y-axis as if it is a sort of mirror, if it were going over the x-axis it would be flipped upside down, if it was A the shape would be going over the original shape. I don't know how to explain C. (I hope this helped and I hope it was correct lol)
How do you solve this problem?
9514 1404 393
Answer:
-19.2
Step-by-step explanation:
Fill in the given values and do the arithmetic.
[tex]\displaystyle x\ \blacksquare\ y=\frac{x}{y}-xy\\\\4\ \blacksquare\ 5=\frac{4}{5}-4\cdot5=0.8-20\\\\\boxed{4\ \blacksquare\ 5=-19.2}[/tex]
4 raised to power two minus 8u minus 9=0
Answer: u = [tex]\frac{7}{8}[/tex] or 0.875
Step-by-step explanation:
Let us convert this statement to a question
[tex]4^{2}[/tex]-8u-9 = 0
16-8u-9 = 0
-8u = 0+9-16
-8u = -7
u = -7 ÷ -8
u = [tex]\frac{7}{8}[/tex] or 0.875
Dan invests £18790 into his bank account. He receives 5.9% per year simple interest. How
much will Dan have after 2 years? Give your answer to the nearest penny where appropriate.
Answer: £21007.22
Step-by-step explanation:
First, find the interest amount using the formula SI = (P × R × T) / 100.
SI = interest amount P = principle amount = £18790R = interest rate(in percentage) = 5.9T = time(in years) = 2SI = (P × R × T) / 100 = (18790 × 5.9 × 2)/100 = 221722/100 = £2217.22
The total amount = principle amount + interest amount
= £18790 + £2217.22 = £21007.22
Zoe and Hanna share tips in the ratio 3:7
Last week Zoe received £24
How much did Hanna receive last week?
Answer:
56
Step-by-step explanation:
Zoe : hanna
3 7
Zoe got 24
3*8 = 24
so multiply each side by 8
Zoe : hanna
3*8 7*8
24 56
Hanna got 56
what is the formula to calculate VAT percentage
Answer:
Take the gross amount of any sum (items you sell or buy) – that is, the total including any VAT – and divide it by 117.5, if the VAT rate is 17.5 per cent. (If the rate is different, add 100 to the VAT percentage rate and divide by that number.)
Answer:
divide by 117.5 if the rate different, add 100 to the percentage and divide by the number therefore multiply by 100 to get the total
Step-by-step explanation:
the formula to calculate vat percentage
Ben is 4 times as old as Ishaan. 6 years ago, Ben was 6 times as old as Ishaan.
How old is Ishaan now?
Answer:
Ishaan is currently 15 years old.
Step-by-step explanation:
Let B represent Ben's current age and I represent Ishann's current age.
Ben is four times as old as Ishaan. In other words:
[tex]B=4I[/tex]
Six years ago, Ben was six times as old as Ishaan. In other words:
[tex]B-6=6(I-6)[/tex]
Solve for I. Substitute:
[tex](4I)-6=6(I-6)[/tex]
Distribute:
[tex]4I-6=6I-36[/tex]
Subtract 4I from both sides and add 36 to both sides:
[tex]2I=30[/tex]
And divide both sides by two. Hence:
[tex]I=15[/tex]
Ishaan is currently 15 years old.
Answer:
Age of Ishaan = 15 years
Step-by-step explanation:
Let Ishaan's age = x years
Age of Ben = 4 * x = 4x years
6Years ago:
Age of Ishaan = x - 6
Age of Ben = 4x - 6
6 years ago, Ben was 6 times as old as Ishaan
So, Age of Ben = 6 * Ishaan's age
4x - 6 = 6 *(x-6)
4x - 6 = 6x - 36
Add 36 to both sides
4x - 6 + 36 = 6x
4x + 30 = 6x
Subtract '4x' from both sides
30 = 6x - 4x
30 = 2x
2x = 30
Divide both by 2 sides
x = 30/2
x = 15
What type of line is PQ¯¯¯¯¯¯¯¯?
A. median
B. angle bisector
C. side bisector
D. altitude
Answer:
angle bisector
Step-by-step explanation:
Since the line divided the top angle into two equal pieces we call this an angle bisector.
The reliability coefficient of scores in an end of semester examination. If the variance of the exam score is 100. What is the standard error of measurement ?
Answer:
I Will explained you youuuuuu<uuuuuuuuuu
the length of a rectangle is 8 cm longer than its width. find the dimensions of the rectangle if its area is 108cm
!!no links!!
Answer:
[tex]4+2\sqrt{31}\text{ by } -4+2\sqrt{31}[/tex]
Or about 15.136 centimeters by 7.136 centimeters.
Step-by-step explanation:
Recall that the area of a rectangle is given by:
[tex]\displaystyle A = w\ell[/tex]
Where w is the width and l is the length.
We are given that the length is 8 centimeters longer than the width. In other words:
[tex]\ell = w+8[/tex]
And we are also given that the total area is 108 square centimeters.
Thus, substitute:
[tex](108)=w(w+8)[/tex]
Solve for w. Distribute:
[tex]w^2+8w=108[/tex]
Subtract 108 from both sides:
[tex]w^2+8w-108=0[/tex]
Since the equation is not factorable, we can use the quadratic formula:
[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
In this case, a = 1, b = 8, and c = -108. Substitute and evaluate:
[tex]\displaystyle \begin{aligned} w&= \frac{-(8)\pm\sqrt{(8)^2-4(1)(-108)}}{2(1)} \\ \\ &=\frac{-8\pm\sqrt{496}}{2}\\ \\ &=\frac{-8\pm4\sqrt{31}}{2} \\ \\ &=-4 \pm 2\sqrt{31} \end{aligned}[/tex]
So, our two solutions are:
[tex]w=-4+2\sqrt{31} \approx 7.136 \text{ or } w=-4-2\sqrt{31}\approx -15.136[/tex]
Since width cannot be negative, we can eliminate the second solution.
And since the length is eight centimeters longer than the width, the length is:
[tex]\ell =(-4+2\sqrt{31})+8=4+2\sqrt{31}\approx 15.136[/tex]
So, the dimensions of the rectangle are about 15.136 cm by 7.136 cm.
