Answer:
Variables are used to represent an unknown quantity in a mathematical expression.
Step-by-step explanation:
Variables are used to represent an unknown quantity in a mathematical expression.For example : x + 2 = 4, here x is the variable.We can denote variable by any alphabet i.e, a,b,c,d etc.What is the tangent of 0?
Answer: Tis 0
Step-by-step explanation:
4. The average salary for public school teachers for a specific year was reported to be $39,385. A random sample of 50 public school teachers in a particular state had a mean of $41,680, and the population standard deviation is $5975. Is there sufficient evidence at the a _ 0.05 level to conclude that the mean salary differs from $39,385
Answer:
The p-value of the test is 0.0066 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean salary differs from $39,385
Step-by-step explanation:
The average salary for public school teachers for a specific year was reported to be $39,385. Test if the mean salary differs from $39,385
At the null hypothesis, we test if the mean is of $39,385, that is:
[tex]H_0: \mu = 39385[/tex]
At the alternative hypothesis, we test if the mean differs from this, that is:
[tex]H_1: \mu \neq 39385[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
39385 is tested at the null hypothesis:
This means that [tex]\mu = 39385[/tex]
A random sample of 50 public school teachers in a particular state had a mean of $41,680, and the population standard deviation is $5975.
This means that [tex]n = 50, X = 41680, \sigma = 5975[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{41680 - 39385}{\frac{5975}{\sqrt{50}}}[/tex]
[tex]z = 2.72[/tex]
P-value of the test and decision:
The p-value of the test is the probability that the sample mean differs from 39385 by at least 2295, which is P(|Z| > 2.72), which is 2 multiplied by the p-value of Z = -2.72.
Looking at the z-table, Z = -2.72 has a p-value of 0.0033
2*0.0033 = 0.0066
The p-value of the test is 0.0066 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean salary differs from $39,385
In parallelogram ABCD, line AC is congruent to line BD. Is ABCD a rectangle?
A. Yes
B. No
C. Cannot be determined
9514 1404 393
Answer:
A. yes
Step-by-step explanation:
The diagonals of a rectangle are congruent and bisect each other.
The diagonals of a parallelogram bisect each other. If they are also congruent, then the parallelogram is a rectangle.
Answer:
Yes.
Step-by-step explanation:
Press option yes
What are the values of x for which the denominator is equal to zero for y=(x+3)/(x^2+4x)
9514 1404 393
Answer:
-4, 0
Step-by-step explanation:
The denominator is x^2+4x. This is zero when ...
x^2 +4x = 0
x(x +4) = 0
The zero product rule tells you the product is zero when the factors are zero.
x = 0
x +4 = 0 ⇒ x = -4
The denominator is zero for x=0 and x=-4.
The accompanying data are lengths (inches) of bears. Find the percentile corresponding to 61.0 in.
(Round to the nearest whole number as needed.)
Bear Lengths
36.0 37.0 39.5 40.0 40.5 43.0 44.0 45.5 45.5 46.5 48.0 48.00 49.0 50.0 51.5 52.5 53.0 53.5 54.0 57.3 57.5 58.0 58.5 59.0 59.5 60.0 61.0 61.0 61.0 61.5 62.0 62.5 63.0 63.0 63.5 64.0 64.0 64.0 64.5 65.0 66.0 67.5 67.5 68.5 70.0 70.5 71.5 72.0 72.5 72.5 72.5 73.5 74.5 77.5
Answer:
52nd percentile
Step-by-step explanation:
The sorted data :
36.0, 37.0, 39.5, 40.0, 40.5, 43.0, 44.0, 45.5, 45.5, 46.5, 48.0, 48.00, 49.0, 50.0, 51.5, 52.5, 53.0, 53.5, 54.0, 57.3, 57.5, 58.0, 58.5, 59.0, 59.5, 60.0, 61.0, 61.0, 61.0, 61.5, 62.0, 62.5, 63.0, 63.0, 63.5, 64.0, 64.0, 64.0, 64.5, 65.0, 66.0, 67.5, 67.5, 68.5, 70.0, 70.5, 71.5, 72.0, 72.5, 72.5, 72.5, 73.5, 74.5, 77.5
The total size of the data = 54
The value 61.0 occurs in position ; 27th, 28th and 29th
Taking the position average :
(27+28+29)/3 = 84/3 = 28th position
This means the percentile score of 61 is :
(Position average / total size) * 100%
(28/54) * 100%
0.5185185 * 100%
= 51.85%
This means that 61 inch length falls in the 52nd percentile
ASAP!!!!!!!!! Please show process!!! Using law of sines!!!!!!!! Thank you so much
Answer:
the answers are on the picture but the numbers may be rounded
if triangle TAN has vertices T(0, 2), A(-1,3), and N(-2,-4), which of the following coordinates is N' of the dilation from the origin using the scale factor 3?
Answer:
(-6,-12)
Step-by-step explanation:
A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.
[tex] - 2 \times 3 = - 6[/tex]
[tex] - 4 \times 3 = - 12[/tex]
So our new coordinates is
(-6,-12)
Answer:
(-6,-12)
Step-by-step explanation:
A dilation makes a figure gets bigger so just multiply 3 to point N to find N prime.
So our new coordinates is
(-6,-12)
Step-by-step explanation:
If BC = 8.3, CD - 6,7, and AD = 11.6, find AB to the nearest tenth.
Answer:
ab=14.4
Step-by-step explanation:
This is going to be tricky to explain over text, so try to bear with me :) You have the information given above. Let's start with just ad = 11.6 for now. since these are variables, it can also be understood be understood as a times d= 11.6. Knowing this, we can figure out that d = 11.6/a, when you divide both sides by a. You now have d, so plug (11.6/a) into cd=6.7. You have to do the same thing you did last time, except this time you are aiming to get c by itself. So, multiply both sides by a/11.6 and you get c = (6.7a)/ 11.6. Guess what, you know c now! so you put (6.7a)/11.6 in for c in the equation given to you earlier, bc =8.3. The math gets a bit messy here, but you basically solve for b here, which, when you crunch the numbers down, ends up being ~14.3705 divided by a. You are looking for ab, so just multiply both sides by a, and round to the nearest tenth so that you have ab= 14.4
Express the function as the sum of a power series by first using partial fractions. f(x)=x+62x2−9x−5
Answer:
[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}][/tex]
when:
[tex]|x|<\frac{1}{2}[/tex]
Step-by-step explanation:
In order to solve this problem, we must begin by splitting the function into its partial fractions, so we must first factor the denominator.
[tex]\frac{x+6}{2x^2-9x+5}=\frac{x+6}{(2x+1)(x-5)}[/tex]
Next, we can build our partial fractions, like this:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]
we can then add the two fraction on the right to get:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A(x-5)+B(2x+1)}{(2x+1)(x-5)}[/tex]
Since we need this equation to be equivalent, we can get rid of the denominators and set the numerators equal to each other, so we get:
[tex]x+6=A(x-5)+B(2x+1)[/tex]
and expand:
[tex]x+6=Ax-5A+2Bx+B[/tex]
we can now group the terms so we get:
[tex]x+6=Ax+2Bx-5A+B[/tex]
[tex]x+6=(Ax+2Bx)+(-5A+B)[/tex]
and factor:
[tex]x+6=(A+2B)x+(-5A+B)[/tex]
so we can now build a system of equations:
A+2B=1
-5A+B=6
and solve simultaneously, this one can be solved by substitution, so we get>
A=1-2B
-5(1-2B)+B=6
-5+10B+B=6
11B=11
B=1
A=1-2(1)
A=-1
So we can use these values to build our partial fractions:
[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]
[tex]\frac{x+6}{(2x+1)(x-5)}=-\frac{1}{2x+1}+\frac{1}{x-5}[/tex]
and we can now use the partial fractions to build our series. Let's start with the first fraction:
[tex]-\frac{1}{2x+1}[/tex]
We can rewrite this fraction as:
[tex]-\frac{1}{1-(-2x)}[/tex]
We can now use the following rule to build our power fraction:
[tex]\sum_{n=0}^{\infty} ar^{n} = \frac{a}{1-r}[/tex]
when |r|<1
in this case a=1 and r=-2x so:
[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2x)^n[/tex]
or
[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2)^{n} x^{n}[/tex]
for: |-2x|<1
or: [tex] |x|<\frac{1}{2} [/tex]
Next, we can work with the second fraction:
[tex]\frac{1}{x-5}[/tex]
On which we can factor a -5 out so we get:
[tex]-\frac{1}{5(1-\frac{x}{5})}[/tex]
In this case: a=-1/5 and r=x/5
so our series will look like this:
[tex]-\frac{1}{5(1-\frac{x}{5})}=-\frac{1}{5}\sum_{n=0}^{\infty} (\frac{x}{5})^n[/tex]
Which can be simplified to:
[tex]-\frac{1}{5(1-\frac{x}{5})}=-\sum_{n=0}^{\infty} \frac{x^n}{5^(n+1)}[/tex]
when:
[tex]|\frac{x}{5}|<1[/tex]
or
|x|<5
So we can now put all the series together to get:
[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}}[/tex]
when:
[tex]|x|<\frac{1}{2}[/tex]
We use the smallest interval of convergence for x since that's the one the whole series will be defined for.
In the word PARADISE,how many pairs are there which have as many letters between them in the word as in the alphabet?
Answer:
three
P A R
A R A D
A D I S E
P Q R
A B C D
A B C D E
There are three such pairs of letters.
A ball is thrown into the air with an upward velocity of 24 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 24t + 7. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?
Answer:
Step-by-step explanation:
Since you have this categorized under college math, I'm going to go out on a limb here and assume you're in calculus. We will solve using the position function and its first derivative (velocity) to solve. Remember that at an object's max height, the velocity is 0.
If the position function is
[tex]s(t)=-16t^2+24t+7[/tex] the first derivative, velocity, is
v(t) = -32t + 24. Set this equal to 0 to find the time when the object is at its max height:
0 = -32t + 24 and
-24 = -32t so
t = .75 seconds. Now we can plug that time into the position function to find where it is at that time. This "where" will be the max height:
s(.75) = [tex]-16(.75)^2+24(.75)+7[/tex] so
s(.75) = 16 feet
Bindi is buying pet food with a coupon for 20% off. The original price of the bag of food is $39.
Which answer gives the best estimate for the price after the discount?
$48
$19
$34
$32
data in the bar graph to solve the following problems. Choose the letter of the correl answer.
Distance from Churh (meters)
250
210
190
200
175
150
150
100
50
C. 25m
1. How much farther does Paolo walk thạnIgpher? Joshua
Topher
A. 20m
B. 15 m
C. 10m
D. 5m
2. How much farther does Joshua walk than Lucas?
A. 15m
B. 20m
D. 30m
3. How much farther does Topher than Lucas?
A. 50m
B. 40m
C. 30m
D. 20m
4. If you combine Paolo's and Lucas' distance from the church and compare it against the combined
distance walked by Joshua and Topher, which combined distance is farther
from the church?
A. Joshua and Topher
C. Joshua and Paolo
B. Paolo and Lucas
D. Topher and Lucas
5. Find the average distance of the houses of the 4 friends from the church?
A. 181
B. 191
C. 180
Answer:
The answer is below
Step-by-step explanation:
The bar chart to the question is attached below.
The distance traveled by Paolo = 210 m, The distance traveled by Lucas = 150 m, The distance traveled by Jashua = 175 m, The distance traveled by Topher = 190 m
1) The farther distance walk by Paolo = The distance traveled by Paolo - The distance traveled by Topher = 210 m - 190 m = 20 m
2) The farther distance walk by Jasha = The distance traveled by Jashua - The distance traveled by Lucas = 175 m - 150 m = 25 m
3) The farther distance walk by Topher = The distance traveled by Topher - The distance traveled by Lucas = 190 m - 150 m = 40 m
4) Combined distance of Paolo's and Lucas = 210 m + 150 m = 360 m
Combined distance of Jashua and Topher = 175 m + 190 m = 365 m
Therefore the Combined distance of Jashua and Topher is more
5) Average distance = (210 + 150 + 175 + 190)/4 = 181.25 m
Solve for the following equation for x. l x/4 + 3 l < 6
Answer:
this is the answer I got! i don't know if it helps, but I hope it does
Will give brainliest answer, there has to be two answers to give one of you the brainliest
Answer:
C
Step-by-step explanation:
[tex] ({8}^{ { - 9})^{ \frac{ - x}{9} } } [/tex]
when putting a power to another power, then these two powers are multiplied.
so, -9 × (-x/9) = (-9 × -x) / 9 = 9x/9 = x
so, this reduces to the original
[tex] {8}^{x} [/tex]
and therefore C is the right answer.
A canning factory turns out 568 tins of jam on a certain day. How many tins will be produced in 297 working days?
Sumas y restas
W+y=9
3W-y=11
Answer:
w = 5
y = 4
Step-by-step explanation:
w + y = 9
3w - y = 11 ( + )
________
4w + 0 = 20
4w = 20
w = 20 / 4
w = 5
Substitute w = 5 in eq. w + y = 9,
w + y = 9
5 + y = 9
y = 9 - 5
y = 4
The Cougar Swim Club acquired some Speedo Fastskin bodysuits and decided to test them out. A number of the club's fastest swimmers performed a 50m freestyle swim in a regular spandex bodysuit and in a Speedo Fastskin suit. The table below summarizes their times in seconds.Swimmer Spandex Speedo Fastskin1 31.1 29.12 28.9 30.43 31.4 32.04 34.9 31.75 27.7 28.26 36.7 32.97 33.3 28.68 30.8 26.2Perform a t-test for dependent means to determine if there is a difference between the regular spandex suit and the Fastskin bodysuit in terms of performance.t = _____df = _____Critical value of t = _____ (use alpha = 0.05)Would you reject the null hypothesis?
Answer:
T = 2.215
df = 7
Critical value = 2.364
Fail to reject the null
Step-by-step explanation:
Swimmer __Spandex __Speedo Fastskin__ d
1 __________31.1 _______29.1 __ 2
2_________ 28.9 ______30.4 __ -1.5
3_________ 31.4 ______ 32.0 __ - 0.6
4_________ 34.9 ______31.7 __ 3.2
5 _________27.7 ______28.2 __ - 0.5
6_________ 36.7 _____ 32.9 ___ 3.8
7 _________ 33.3 _____28.6 ___ 4.7
8_________ 30.8 _____26.2 ___ 4.6
The mean difference = Σd / n
2, - 1.5, - 0.6, 3.2, - 0.5, 3.8, 4.7, 4.6
μd = Σd / n = 15.7 / 8 = 1.9625
Sd = standard deviation of difference = 2.5065 (using calculator)
H0 : μd = 0
H1 : μd ≠ 0
The test statistic:
T = μd / (Sd/√n)
T = 1.9625 / (2.5065/√8)
T = 2.2145574
The degree of freedom, df = n - 1 = 8 - 1 = 7
Using a Pvalue calculator :
α = 0.05
Critical value, Tcritical = 2.364 (T distribution table)
Since Test statistic < Critical value
we fail to reject H0 ;
I need help with question 9
9514 1404 393
Answer:
a) yes
b) see attached
c) see discussion
d) neither
e) increasing (2,5); decreasing (-2, 2)
Step-by-step explanation:
a) The graph passes the vertical line test, so is the graph of a function.
__
b) A table of values is attached
__
c) Generally, this sort of function would be defined piecewise:
[tex]\displaystyle f(x)=\begin{cases}-\dfrac{1}{2}x+1&\text{for }-2\le x<2\\2x-4&\text{for }2\le x \le5\end{cases}[/tex]
In the attachment, we have shown the use of the "maximum" function to define it. The effect is the same.
__
d) The function has no symmetry about the origin or the y-axis, so is neither odd nor even.
__
e) The function is increasing where the line has positive slope, on the interval (2, 5). The function is decreasing where the line has negative slope, on the interval (-2, 2).
Which of the following expressions has a Value of 6.18???
Answer:
B. -21.012÷ -3.4
its yr correct ans.
hope it helps
stay safe healthy and happy.determine the 2nd and 3rd terms of a geometric sequence of which T1 =5 and T4=40
Answer:
Second term of this sequence: [tex]10[/tex].
Third term of this sequence: [tex]20[/tex].
Step-by-step explanation:
The first step is to find the common ratio of this sequence.
In a geometric sequence, multiply one term by the common ratio to find an expression for the next term. Let [tex]r[/tex] denote the common ratio of this sequence. For this sequence:
The first term of this sequence is [tex]5[/tex]. Multiply the first term by the common ratio to find an expression for the third term: [tex]5\, r[/tex].Multiply the second term by the common ratio to find an expression for the fourth term: [tex]5\, r^{2}[/tex].Similarly, an expression for the the fourth term would be: [tex]5\, r^{3}[/tex].However, the question states that the value of the fourth term is [tex]40[/tex]. In other words, [tex]5\, r^{3} = 40[/tex].
Solve this equation for [tex]r[/tex]:
[tex]r^{3} = 8[/tex].
[tex]r = 2[/tex].
(Since the power of [tex]r[/tex] is non-even in the equation, there's no need to consider the sign of [tex]r\![/tex] when taking the cube root.)
Substitute [tex]r = 2[/tex] into the expression for the second term and the third term to find their values:
Second term: [tex]5\, r = 10[/tex].Third term: [tex]5\, r^{2} = 20[/tex].i’ll give brainliest to the right answer
Answer:
First one , 0.0000805
Step-by-step explanation:
With negative exponents the decimal is moved to the left the amount of the exponent. The spaces are filled with zeros.
With positive exponents the opposite occurs. The decimal moves to the right.
I am Your Crush boy you have never seen a boy like me if you will see me you will fall in my love. come zom Id- 6622308635 pas- 6UC3yE
Answer:
I don't know the answer to ur question. LOL
Answer:
stop being desperate
nobody is gonna fall in love with some desperate weirdo
(3k + 5)(2k2 – 5k – 3)
SOLVE PLS!! ILL MARK BRAINILEST!!
Answer:
73.3333....
Step-by-step explanation:
please mark me brainliest
Answer:
a: t=13.6 cm
b: h=12.9 mm
Step-by-step explanation:
Hi there!
Let's start with a
in a, we are given a right triangle (notice the right angle), the length of the hypotenuse (the side OPPOSITE from the right angle) as 18 cm, one acute angle given as 41° and the length of one of the legs (the legs are the sides that make up the right angle) as t
We're asked to use the primary trigonometric ratios
Those ratios are:
Sine, which is opposite/hypotenuse
Cosine, which is adjacent/hypotenuse
Tangent, which is opposite/adjacent
We will be basing the ratio off of the 41° angle, so let's find out which sides will be which in reference to that angle
The opposite side will be the other leg, the unmarked side
The adjacent side will be t
The hypotenuse will be the side marked as 18 cm
So let's use cos(41) in this case
cos(41)=t/18
Plug cos(41) into your calculator, and remember to have the calculator in degree mode
cos(41)≈0.8 (rounded to the nearest tenth)
0.8=t/18
multiply both sides by 18
13.6 cm=t
It's already rounded to the nearest tenth :)
b.
We are given a right triangle, and the lengths of the legs as h and 9 mm, as well as one acute angle as 35°
We'll be basing our ratio off of the 35 degree angle, so let's find which sides will be which in reference to that angle
The opposite side will be the leg marked as 9 mm
The adjacent side will be the leg marked as h
The hypotenuse will be the unmarked side
Since we are given the lengths of the opposite and the adjacent, let's use tan(35)
tan(35)=9/h
Plug tan(35) into your calculator, and remember to have it in degree mode
tan(35)≈0.7
0.7=9/h
multiply both sides by h
0.7h=9
divide both sides by 0.7
h=12.9 mm (rounded to the nearest tenth)
Hope this helps!
A.109
B.87
C.98
D.69
Answer:
hey what's
Step-by-step explanation:
a question wow okay the answer is
Find the volume of the box. The box shows the length is 6 feet, the width is 5 feet, and the height is 3 feet. The volume of the box is blank cubic feet. The solution is
Answer:
[tex]90[/tex] [tex]ft^3[/tex]
Step-by-step explanation:
----------------------------------------
The formula to find the volume of a rectangular prism is [tex]V=lwh[/tex]
Let's substitute the number for the length, width, and height now.
[tex]V=(6)(5)(3)[/tex]
[tex]V=(30)(3)[/tex]
[tex]V=90[/tex]
--------------------
Hope this is helpful.
what term can you add to
[tex] \frac{5}{6} x - 4[/tex]
to make it equivalent to
[tex] \frac{1}{2} x - 4[/tex]
9514 1404 393
Answer:
-1/3x
Step-by-step explanation:
We want to find the term 'a' such that ...
(5/6x -4) + a = (1/2x -4)
Add 4-1/2x to both sides.
(5/6 -1/2)x -4 +4 +a = 0
(5/6 -3/6)x + a = 0 . . . . . . express the fractions using a common denominator
1/3x + a = 0 . . . . . . . . . . simplify the difference
a = -1/3x . . . . . . . . . . .subtract 1/3x
The term you can add to make the desired equivalent is -1/3x.
Calculate the number of ways to form a set of three distinct items such that no two of the selected items are in the same row or same column
Answer:
1200
Explanation:
Order does not matter, if we said xyz order, it would still not make a difference if it was zyx or yzx hence we use the combination formula:
nCr = n! / r! * (n - r)!
where n= total number of items
r= number of items chosen at a time
Combinations are used when the order of events do not matter in calculating the outcome.
We calculate using the formula:
(30×20×12)÷3!=1200
There are therefore 1200 ways for the three distinct items to not be in same row or column
Of the at-home games, what proportion of games were wins? (Note: Some answers are rounded to two decimal places
Answer:
0.33
Step-by-step explanation:
See comment for complete question
Given
[tex]H = 60\%[/tex]
[tex]W=25\%[/tex]
[tex]HW = 20\%[/tex] --- at-home wins
Required
The proportion of at-home games that were wins
This proportion is represented as:
[tex]Pr = HW : H[/tex]
Substitute values for HW and H
[tex]Pr = 20\% : 60\%[/tex]
Divide by 20%
[tex]Pr = 1 : 3[/tex]
Express as fraction
[tex]Pr = 1 /3[/tex]
[tex]Pr = 0.33[/tex]
