as the temperature of a gas in a solid container increases what happens to the pressure exerted by the gas?

Answer:

d d d d d d s d. d d d d d df ff f f. f f f r r ff f f ff d f f f f f f f f f r. ff r f. r

Answer:

The total mass of the atmosphere is  4.508 x 10⁹ kg

Explanation:

Given;

thickness of gas layer, h = 6.8 km

density of Earth's atmosphere, ρ = 1.3 kg/m³

the surface area of Earth is given as 5.10 x 10⁸ km²

Volume of the atmosphere is calculated as;

V = Ah

where;

A is the surface area of Earth

h is the thickness of gas layer

V = (5.10 x 10⁸ km²)(6.8 km)

V = 3.468 x 10⁹ km³

The total mass of the atmosphere is calculated as;

mass = density x volume

m = ρV

m = (1.3 kg/m³)(3.468 x 10⁹ km³)

m = 4.508 x 10⁹ kg

Therefore, the total mass of the atmosphere is 4.508 x 10⁹ kg.

Answer:

210 ft.

Explanation:

Since a square has 4 sides and all sides are equal, just do 210 divided by 4.

Answer:

P=mv

1x450,200=m40

m= 36,255kg

Answer:

Explanation:

B

Answer:

Because humans possess these three types of cones, they are described as trichromats (tri = 3, chroma = color). ... The perception of color is not simply a matter of wavelength detection, as it involves various stages of neuronal processing

Answer: Three forces act significantly on a freely floating helium-

filled balloon: gravity, air resistance (or drag force), and a

buoyant force.

Explanation:

The air pressure on the bottom of the balloon is slightly higher than the air pressure on the top of the balloon (because of the altitude difference). This difference gives rise to the bouyant force. This force competes with gravity as the two main forces acting on the balloon. Every time your feet hit the ground when you are running, the ground hits your feet with an equal and opposite force. Newton’s third law explains how balloons and rocket engines work. When the neck of an inflated balloon is released, the stretched rubber material pushes against the air in the balloon. The air rushes out of the neck of the balloon.

Answer:

motion of an object—even if the object is maintaining a constant speed—still count as acceleration

Explanation:

Answer:

a refractor telescope

Explanation:

Answer:

a. refractor telescope

Answer:

[tex]\frac{y}{L}[/tex] = 0.66

Hence, the fraction of the length of the rod above water = [tex]\frac{y}{L}[/tex] = 0.66

and fraction of the length of the rod submerged in water = 1 - [tex]\frac{y}{L}[/tex] = 1 - 0.66 = 0.34  

Explanation:

Data given:

Density of the rod = 5/9 of the density of the water.

Let's denote density of Water with w

And density of rod with r

So,

r = 5/9 x w

Required:

Fraction of the length of the rod above water.

Let's denote total length of the rod with L

and length of the rod above with = y

Let's denote the density of rod = r

And density of water = w

So, the required is:

Fraction of the length of the rod above water = y/L

y/L = ?

In order to find this, we first need to find out the all type of forces acting upon the rod.

We know that, a body will come to equilibrium if the net torque acting upon a body is zero.

As, we know

F = ma

Density = m/v

m = Density x volume

Volume = Area x length = X ( L-y)

So, let's say X is the area of the cross section of the rod, so the forces acting upon it are:

F = mg

F = (Density x volume) x g

g = gravitational acceleration

F1 = X(L-y) x w x g (Force on the length of the rod submerged in water)

where,

X (L-y) = volume

w = density of water.

Another force acting upon it is:

F = mg

F2 =  X x L x r x g

Now, the torques acting upon the body:

T1 + T2 = 0

F1 ( y + [tex](\frac{L-y}{2})[/tex] ) g sinФ - F2 x ([tex]\frac{L}{2}[/tex]) x gsinФ = 0

plug in the  equations of F1 and F2 into the above equation and after simplification, we get:

[tex](L^{2} - y^{2} ) . w[/tex] = [tex]L^{2}[/tex] . r

where, w is the density of water and r is the density of rod.

As we know that,

r = 5/9 x w

So,

[tex](L^{2} - y^{2} ) . w[/tex] = [tex]L^{2}[/tex] . 5/9 x w

Hence,

[tex](L^{2} - y^{2} )[/tex] = [tex]\frac{5L^{2} }{9}[/tex]

[tex]\frac{L^{2} - y^{2} }{L^{2} }[/tex] = [tex]\frac{5}{9}[/tex]

Taking [tex]L^{2}[/tex] common and solving for [tex]\frac{y}{L}[/tex], we will get

[tex]\frac{y}{L}[/tex] = 0.66

Hence, the fraction of the length of the rod above water = [tex]\frac{y}{L}[/tex] = 0.66

and fraction of the length of the rod submerged in water = 1 - [tex]\frac{y}{L}[/tex] = 1 - 0.66 = 0.34

Answer:

i cant make funny joke

Explanation:

but i can be alive.

wait no, im failing at that currently.

Answer:

0.47m3

Explanation:

Volume = Mass / Density

In this case:

Mass - 1280 kg

Density - 2700kg/m3

1280 / 2700 = 0.4740741m3

When this is rounded off ( 2 d.p ):

0.47 m3

HOPE THIS HELPED

Answer:2000kg

Explanation:

Convert it

Answer:

d = 113.6 m

Explanation:

For this exercise, the first thing we must notice is that the speed of the laser beam in the fiber is constant, so we can use the uniform motion relationships to find the necessary distance

          v = d / t

let's reduce to SI units

         t = 557 ns = 557 10⁻⁹ s

         d = v t

         d = 2.04 10⁸ 557 10⁻⁹

         d = 1.136 102 m

         d = 113.6 m

This is the distance of the fiber for the laser to arrive with the desired delay

Answer:

(Total initial linear momentum = total final linear momentum.)

Momentum = mass × velocity

180×4 + 120×0 = 180×0 + 120×V

(180 ×4)/120 = V

Answer:

11.25m

Explanation:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ = 0 \times 1.5 + \frac{1}{2} \times 10 \times {1.5}^{2} \\ = 5 \times 2.25 \\ = 11.25[/tex]

Answer:Detergent mixes with water to remove dirt and oil from clothes. Water can't remove oil and dirt from clothes. Detergent cleans by causing a chemical reaction with water to force dirt and debris out of clothing. Detergents work with water to loosen the dirt trapped in the material of clothing and clean them away.

Explanation:May i plz have brainlist only if u wanna give me brainlist though have an nice day!

Answer:

centripital acceleration= v^2/r

r = v^2/a

r=31.8×31.8/29

r=34.8703m

Explanation:

the maximum acceleration is obtained with minimum radius.

Answer:

The energy used for the 30-day period is 4878000 kilojoules.

Explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]

[tex]E = 4878000\,kJ[/tex]

The energy used for the 30-day period is 4878000 kilojoules.

Answer:

v = 24.49[m/s]    

Explanation:

We must remember that kinetic energy can be calculated by means of a mathematical expression, which relates kinetic energy to mass and velocity

[tex]E_{kin}=\frac{1}{2}*m*v^{2} \\[/tex]

where:

Ekin = kinetic energy = 12000 [J]

m = mass = 40 [kg]

v = velocity [m/s]

[tex]12000=\frac{1}{2} *40*v^{2}\\24000=40*v^{2}\\600=v^{2}\\v=\sqrt{600}\\v=24.49[m/s][/tex]

Answer:

a) 37.70 m/s

b)710.6 m/s²

Explanation:

Given that ;

Mass of object = 2 kg

Radius of the motion = 2m

Frequency of motion = 3 rev/s

The formula to apply is;

v= 2πrf   where v is linear speed

v = 2×π×2×3 =12π = 37.70 m/s

Centripetal acceleration is given as;

a= 4×π²×r×f²  

a= 4×π²×2×3²

a=710.6 m/s²

Answer:

a is the correct answer hope it will help you

The satellite is moved to a new circular orbit that is 2R from the center of the moon, then the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.

It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.

As given in the problem A satellite of mass m orbits a moon of mass M in a uniform circular motion with a constant tangential speed of v. The gravitational field strength at a distance R from the center of the moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon.

The gravitational field strength is inversely proportional to the square of the distance from the center of the planet.

Thus, the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.

To learn more about gravity here, refer to the link given below ;

brainly.com/question/4014727

#SPJ1

Answer:

4770 N

Explanation:

Momentum is the product of mass and velocity and force is the change in momentum divided by change in time.

Given from the question;

Mass of arrow= 0.53 kg

Velocity of arrow = 63 m/s

Initial velocity of arrow = 0 m/s

Change in time = 0.007 s

Finding momentum after the arrow is released as;

p=m*v

p= 0.53 * 63

p= 33.39 kg*m/s

Force is the change in momentum divided by change in time;

F= 33.39 / 0.007

F= 4770 N

Answer:

Polarization occurs when an electric field distorts the negative cloud of electrons around positive atomic nuclei in a direction opposite the field. Polarization P in its quantitative meaning is the amount of dipole moment p per unit volume V of a polarized material, P = p/V.

Explanation:

Answer:

Polarization occurs when an electric field distorts the negative cloud of electrons around positive atomic nuclei in a direction opposite the field. Polarization( P) in its quantitative meaning is the amount of dipole moment (p) per unit volume V of a polarized material, where P = p/V.

Answer:

The mass of the Planet X is 9.595 x 10²⁴ kg.

Explanation:

mass of the object, m = 0.5 kg

radius of the Planet X, r = 4 x 10⁶ m

weight of the object, W = F = 20 N

let the mass of the Planet  X = mₓ

Apply Newton's gravitational law;

[tex]F = \frac{Gmm_x}{r^2} \\\\m_x = \frac{Fr^2}{Gm} \\\\m_x = \frac{(20)(4\times 10^6)^2}{6.67 \times 10^{-11} \ \times \ 0.5} \\\\m_x = 9.595 \times 10^{24} \ kg[/tex]

Therefore, the mass of the Planet X is 9.595 x 10²⁴ kg.

Answer:

Use the stairs

Explanation:

This is easier because if you go on the stairs you can rest if you get tired but if you go on the inclined plane then the weight of the jugs will make you slower than you already are and you may end up going back down instead of up where you wanna go.

Answer:

77000 J

Explanation:

Formula for the heat energy is;

Q = m•c•Δt

We are given;

mass; m = 2 kg

Change in temperature; Δt = 110 - 10 = 100 °C

From online values, specific heat capacity of copper is; c = 385 J/kg.°C

Thus;

Q = 2 × 100 × 385

Q = 77000 J

Answer:

heat = 20 Kcal

Explanation: