Assume that processor refers to an object that provides a void method named process that takes no arguments. As it happens, the process method may throw one of several exceptions. Write some code that invokes the process method provided by the object associated with processor and arrange matters so that your code causes any exception thrown by process to be ignored. Hint: use the catch (Exception ex) and do nothing under the catch clause.

Answers

Answer 1

Answer:

Following are the code to the given question:

try//defining a try block

{

processor.process();//defining an object processor that calls process method

}

catch(Exception e)//defining a catch block

{

}

Explanation:

In this question, the 'Try' and 'catch' block is used in which both the keywords are used to represent exceptions managed during runtime due to information or code errors. This try box was its code block which includes errors. A message queue catches the block errors and examines these.

In the try block, a method "process" is used which is create the object processor that calls the method.


Related Questions

The part (or statement) of a recursive function that decides whether the recursive loop is terminated is called: (Select all that apply)

Answers

Answer:

The base case

Explanation:

Required

The part that determines the termination of a recursion

This part of a recursion is referred to as the base case.

Take for instance, the following:

factorial(int n) {

   if (n < = 1) {         return 1; }

   else {             return n*factorial(n-1);    }  }

The base case of the above is     if (n < = 1) {         return 1; }

Because the recursion will continue to be executed until the condition is true i.e. n less than or equals 1

anyone know how to translate this 1100111111110100000110 pls n ty!4!:$;

Answers

Answer:

1100111111110100000110 = �

Binary -> UTF-16

3,407,110 in decimal form

Additionally, it also translates to the color green in hexadecimal.

Not really sure what you are trying to translate this in to though.

yeah sure no problem that says
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