At a restaurant, two burgers and one fries cost 6. 50. What is the cost of six burgers and three fries

Answer:

The .jpeg file is the answer. Others are formulas that I use to solve.

Answer:

2.5 km left

The midpoint is half of 5, which is 2.5, so he'll still have 2.5 km left to complete

Answer:

4.67 mph

Step-by-step explanation:

Speed with no wind = 14 mph

Let wind speed = w mph

Thus;

Speed with wind = 14 + w

Speed against the wind = 14 - w

Now, we are told that against the wind he bikes 10 miles.

Thus, from; time = distance/speed, we have;

Time = 10/(14 - w)

Also, we are told he biked 20 miles with the wind. Thus;

Time = 20/(14 + w)

We are told the times he used in both cases are the same.

Thus;

10/(14 - w) = 20/(14 + w)

Divide both sides by 10 to get;

1/(14 - w) = 2/(14 + w)

Cross multiply to get:

1(14 + w) = 2(14 - w)

14 + w = 28 - 2w

w + 2w = 28 - 14

3w = 14

w = 14/3

w = 4.67 mph

9514 1404 393

Answer:

  2x +2y -8

Step-by-step explanation:

If the equal sides are 'a' and the third side is 'b', then the perimeter is ...

  P = a +a +b = 2a +b

The length of the third side is then ...

  b = P -2a . . . . . . subtract 2a from both sides

Substituting the given expressions, we find ...

  b = (10x +4y -18) -2(4x +y -5)

  b = 10x +4y -18 -8x -2y +10

  b = 2x +2y -8 . . . . the length of the third side

Answer:

[tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] has no relative extrema when the domain is [tex]\mathbb{R} \backslash \lbrace 2 \rbrace[/tex] (the set of all real numbers other than [tex]2[/tex].)

Step-by-step explanation:

Assume that the domain of [tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] is [tex]\mathbb{R} \backslash \lbrace 2 \rbrace[/tex] (the set of all real numbers other than [tex]2[/tex].)

Let [tex]f^{\prime}(x)[/tex] and [tex]f^{\prime\prime}(x)[/tex] denote the first and second derivative of this function at [tex]x[/tex].

Since this domain is an open interval, [tex]x = a[/tex] is a relative extremum of this function if and only if [tex]f^{\prime}(a) = 0[/tex] and [tex]f^{\prime\prime}(a) \ne 0[/tex].

Hence, if it could be shown that [tex]f^{\prime}(x) \ne 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex], one could conclude that it is impossible for [tex]\displaystyle f(x) = \frac{x + 3}{x - 2}[/tex] to have any relative extrema over this domain- regardless of the value of [tex]f^{\prime\prime}(x)[/tex].

[tex]\displaystyle f(x) = \frac{x + 3}{x - 2} = (x + 3) \, (x - 2)^{-1}[/tex].

Apply the product rule and the power rule to find [tex]f^{\prime}(x)[/tex].

[tex]\begin{aligned}f^{\prime}(x) &= \frac{d}{dx} \left[ (x + 3) \, (x - 2)^{-1}\right] \\ &= \left(\frac{d}{dx}\, [(x + 3)]\right)\, (x - 2)^{-1} \\ &\quad\quad (x + 3)\, \left(\frac{d}{dx}\, [(x - 2)^{-1}]\right) \\ &= (x - 2)^{-1} \\ &\quad\quad+ (x + 3) \, \left[(-1)\, (x - 2)^{-2}\, \left(\frac{d}{dx}\, [(x - 2)]\right) \right] \\ &= \frac{1}{x - 2} + \frac{-(x+ 3)}{(x - 2)^{2}} \\ &= \frac{(x - 2) - (x + 3)}{(x - 2)^{2}} = \frac{-5}{(x - 2)^{2}}\end{aligned}[/tex].

In other words, [tex]\displaystyle f^{\prime}(x) = \frac{-5}{(x - 2)^{2}}[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex].

Since the numerator of this fraction is a non-zero constant, [tex]f^{\prime}(x) \ne 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex]. (To be precise, [tex]f^{\prime}(x) < 0[/tex] for all [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace\![/tex].)

Hence, regardless of the value of [tex]f^{\prime\prime}(x)[/tex], the function [tex]f(x)[/tex] would have no relative extrema over the domain [tex]x \in \mathbb{R} \backslash \lbrace 2 \rbrace[/tex].

Answer:[tex]2\sqrt[4]{4}[/tex]

Step-by-step explanation:

[tex]64^{\frac{1}{4} }= \sqrt[4]{64}=\sqrt[4]{(2)(2)(2)(2)(4)}=2\sqrt[4]{4}[/tex]

Answer:

C

Step-by-step explanation:

In the graph given, we can expect the x axis to be horizontal and the y axis to be vertical. This means that the arm span represents y and the height represents x.

Therefore, if a girl on her team is 63 inches tall, we can say that y=x+2, and since height is x, y = 63 + 2 = 65

Answer:

x=7

y=11

z=7

Step-by-step explanation:

x + y + z = 25

y+z= 18

Z= 7

Substitute the third equation into the second

y+z=18

y+7 = 18

y = 18-7

y = 11

Now substitute y=11 and z=7 into the first

x +y+z = 25

x+11+7 = 25

x+18 = 25

x = 25-18

x=7

9514 1404 393

Answer:

  (320 +130π) cm²

Step-by-step explanation:

The perimeter of the base will be the sum of two radii and the arc length of a quarter circle:

  P = 2r +r(π/2) = r(2+π/2)

For a radius of 10 cm, the perimeter of the base is ...

  P = (10 cm)(2+π/2) = (20+5π) cm

The lateral area of the quarter-cylinder is the product of this perimeter and the height:

  LA = Ph = ((20 +5π) cm)(16 cm) = (320 +80π) cm²

__

The total base area is the area of a half-circle of radius 10 cm, so is ...

  BA = 1/2πr² = (1/2)π(10 cm)² = 50π cm²

The total surface area is the sum of the base area and the lateral area:

  SA = BA +LA = (50π +(320 +80π)) cm² = (320 +130π) cm²

Answer:

6 11/12

Step-by-step explanation:

4 1/6 + 2 3/4

Get a common denominator of 12

4 1/6 *2/2  + 2 3/4 *3/3

4 2/12 + 2 9/12

6 11/12

Answer:

The answer is "0.624"

Step-by-step explanation:

[tex]b = 5x\\\\h = x\\\\ l = 10 \\[/tex]

Using formula:

[tex]V = (\frac{1}{2})(b)(h)(l) \\\\[/tex]

   [tex]= \frac{1}{2} \times (5x)\times (x) \times (10)\\\\= 5x\times x \times 5\\\\= 25x^2[/tex]

[tex]\frac{dV}{dt} = 50x \ \frac{dx}{dt} \\\\\text{(where x represents the height in feet and}\ \frac{dv}{dt} = 13\ \frac{ft^3}{min})\\\\\frac{dx}{dt} = (\frac{1}{50})(\frac{1}{x}) \ \frac{dV}{dt}\\\\[/tex]

When the water is 5 inches deep then:

[tex]x = (\frac{5}{12})\ ft\\\\13 =50(\frac{5}{12}) \ \frac{dx}{dt}\\\\13 \times 12 =50(5) \ \frac{dx}{dt}\\\\\frac{13 \times 12}{50 \times 5} = \frac{dx}{dt}\\\\\frac{156}{250} = \frac{dx}{dt}\\\\ \frac{dx}{dt}= 0.624[/tex]

Answer:

AC = 377.19

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp /adj

tan 5 = 33/AC

AC tan 5 = 33

AC = 33/ tan 5

AC = 377.19

Answer:

The right answer is:

(a) -10.67

(b) 0.7986

Step-by-step explanation:

(a)

According to the question,

X                          P(X)                  X.P(X)                 X2.P(X)

12130                  0.002               24.26                 294274

-35                      0.998               -34.93                1222.55      

Now,

[tex]\Sigma x.P(x) = -10.67[/tex]

or,

[tex]\Sigma x^2.P(x) = 295496.35[/tex]

hence,

The mean will be:

[tex]\Sigma x.P(x) = -10.67[/tex]

(b)

According to the question,

n = 12

p = 0.125

q = 1 - p

  = 0.875

Now,

⇒ [tex]P(X=x) = \binom{n}{x} p^x q^{n-x}[/tex]

By substituting the values, we get

⇒ [tex]P(X \geq 1)=1-(\binom{12}{0} 0.125^0. 0.875^{12-0})[/tex]

⇒                  [tex]=1-(1 (0.125^0) (0.875^{12}))[/tex]

⇒                  [tex]=1-(1(1.0)(0.2014))[/tex]

⇒                  [tex]=1-(0.2014)[/tex]

⇒                  [tex]=0.7986[/tex]    

Answer:

Perimeter = 18 + 9pi

Area = 81 - 20.25*pi

Step-by-step explanation:

Perimeter = 9 + 9 + 2(2 pi r)/2     The twos cancel out.

Perimeter = 18 + 9*pi

Area of the square = 9 * 9 = 81 cm^2

Area of the 2 semicircles = 2 * pi * r^2/2

r = d/2

d = 9

r = 9/2 = 4.5

Area of the 2 semicircles = 2 (pi * 4.5^2)/2

Area of the 2 semicircles = 20.25 pi

Area of the blue figure = 81 - 20.25 pi

Answer:

(2, -3) and r = 3.

Step-by-step explanation:

you can also plug this equation in desmos but I guess it's good to know how to do it also:

The equation of a circle is (x-h)^2 + (y-k)^2 = r^2

Now in order to make a perfect square on both sides, we need to do this:

First add 9 to both sides:

x^2 + 6x + 9 + y^2 -4y +4 = 9.

I purposely shifted it to show the perfect square created when you add 9 to both sides. Factor:

(x+3)^2 + y^2 - 4y + 4 = 9.

now the second bolded part is allso a perfect square. Factor:

(x+3)^2 + (y-2)^2 = 9

Based on the equation of a circle, the center must be at (2, -3) and the radius is the square root of 9 which is 3.

:)

Answer:

H0 : μ ≥ 98.6

H1 : μ < 98.6

Step-by-step explanation:

The population mean temperature, μ = 98.6

The null hypothesis takes up the value of the population mean temperature as the initial truth ;

The alternative hypothesis on the other hand is aimed at using a sample size of 109 to establish if the mean temperature is less than the population mean temperature.

The hypothesis ;

Null hypothesis, H0 : μ ≥ 98.6

Alternative hypothesis ; H1 : μ < 98.6

Answer:

Sample space = 36

P(sum of 6) = 5/36

Step-by-step explanation:

Number of faces on a dice = 6

The sample space, for a toss of 2 dice ; (Number of faces)^number of dice

Sample space = 6^2 = 6*6 = 36

Sum of numbers appearing on the dice = 6

The sum of 6 from the roll of two dice has 5 different outcomes ; Hence, required outcome = 5

Total possible outcomes = sample space = 36

Probability, P = required outcome / Total possible outcomes

P = 5 / 36

Probabilities are used to determine the chances of events

The given parameters are:

[tex]n=6[/tex] --- the faces of a six-sided die

[tex]r = 2[/tex] -- the number of dice

(a) The number of sample points

This is calculated as:

[tex]Sample = n^r[/tex]

So, we have:

[tex]Sample = 6^2[/tex]

Evaluate the exponent

[tex]Sample = 36[/tex]

Hence, the number of sample points is 36

(b) The probability that the sum of 6

See attachment for the sample space of the sum of two dice.

From the sample space, there are 5 outcomes where the sum is 6.

So, the probability is:

[tex]Pr = \frac{5}{36}[/tex] --- where 36 represents the number of sample points

Divide 5 by 36

[tex]Pr = 0.1389[/tex]

Hence, the probability that the sum of the numbers appearing on the dice is equal to 6 is 0.1389

Read more about probabilities at:

https://brainly.com/question/10707698

Answer:

25

Step-by-step explanation:

Assuming the equation is f(x) = x³ - 2

Plug in 3 for x

f(3) = 3³-2

= 27-2

=25

Answer:

25!

I hope it's helpful

Answer:

The profit is maximum when x = 40.

Step-by-step explanation:

Cost function, C = 40 x + 300

Revenue function, R = 80 x - 0.5 x^2

The profit function is

[tex]P = R - C\\\\P = 80 x - 0.5 x^2 - 40 x - 300\\\\P = - 0.5 x^2 + 40 x - 300\\\\\frac{dP}{dx} = - x + 40\\\\So, \frac{dP}{dx} = 0\\\\-x + 40 = 0 \\\\x = 40[/tex]

So, the profit is maximum when x = 40 .

Answer:

Lift

Step-by-step explanation:

Finding patterned and relationship between large sets of data can be obtained using the association rule as it finds insights, relationships and trends within sets of data variables. Lift is a parmater of interest whichbus used when performing analysis on association between variables in datasets. The Lift is literally the ratio of confidence to expected confidence. Where, the confidence of association is divided by the expected confidence (benchmark confidence).

...

Calculate Energy Cost by Appliance

Answer:

4

Step-by-step explanation:

We want the cubed root of 64  

(64)^(1/3)  

(4*4*4) ^ (1/3)  

4  

Unless this is 3 * sqrt(64)  

then it would be  

3 sqrt(8*8)  

3 (8)  

24

Answer:

If you want the area of something with the sides 14cm and 7cm then it would be 98 cm.

Step-by-step explanation:

Area = length * width

Area = 14 cm * 7 cm

Area = 98 cm

Answer:

His least score for him in the fourth paper has to be 76.

Step-by-step explanation:

Given that Michael has an average of 68% in his 3 papers but that is below the pass mark of 70%, to determine what must be his least score in the fouth paper to enable him pass the following calculation must be performed:

(70 x 4) - (68 x 3) = X

280 - 204 = X

76 = X

Therefore, his least score for him in the fourth paper has to be 76.

This is the solution to your question.

9514 1404 393

Answer:

  2, 1, -1/2, -1/4, 1/8

Step-by-step explanation:

Use n = 1 through 4:

  [tex]a_{1+1}=\dfrac{(-1)^{1+1}\cdot a_1}{2}\ \Rightarrow\ a_2=\dfrac{1\cdot2}{2}=1\\\\a_3=\dfrac{(-1)^3\cdot 1}{2}=-\dfrac{1}{2}\\\\a_4=\dfrac{(-1)^4\cdot(-\dfrac{1}{2})}{2}=-\dfrac{1}{4}\\\\a_5=\dfrac{(-1)^5\cdot(-\dfrac{1}{4})}{2}=\dfrac{1}{8}[/tex]

The first 5 terms are ...

  2, 1, -1/2, -1/4, 1/8

Answe YEAH BOIIIIII!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!