Based on this data, are "being in high school" and "GPA above 3.0" independent events? Yes, P(high school ∩ GPA above 3.0) = P(high school) ⋅ P(GPA above 3.0) No, P(high school ∩ GPA above 3.0) = P(high school) ⋅ P(GPA above 3.0) Yes, P(high school ∩ GPA above 3.0) ≠ P(high school) ⋅ P(GPA above 3.0) No, P(high school ∩ GPA above 3.0) ≠ P(high school) ⋅ P(GPA above 3.0)

Answers

Answer 1

Answer:

No, P(high school | GPA above 3.0) ≠ P(high school)

Step-by-step explanation:

Given

See attachment for table

Required

Determine if High school and GPA above 3.0 are independent

Let

[tex]H \to[/tex] High school

[tex]G \to[/tex] GPA above 3.0

For both events to be independent, the following must be true

[tex]P(H\ |\ G) = P(H)[/tex]

From the table:

[tex]P(H) = \frac{H}{Total}[/tex]

[tex]P(H) = \frac{60}{100} = 0.60[/tex]

[tex]P(H | G) = \frac{H\ n\ G}{G}[/tex]

[tex]P(H | G) = \frac{14}{40} = 0.35[/tex]

The test for independence is as follows:

[tex]P(H\ |\ G) = P(H)[/tex]

By comparison

[tex]P(H\ |\ G) \ne P(H)[/tex]

i.e.

[tex]0.35 \ne 0.60[/tex]

Hence, both events are not independent

Based On This Data, Are "being In High School" And "GPA Above 3.0" Independent Events? Yes, P(high School

Related Questions

solve y+1/2-2y-1/2=4​

Answers

Answer:

y+1/2-2y-1/2=4​

y-2y=4

-y=4

y=-4

Let  me know if this helps!

Please help me
A person starts walking from home and walks: 6 miles East 6 miles Southeast 3 miles South 5 miles Southwest 2 miles East This person has walked a total of 22Correct miles Find the total displacement vector for this walk: If this person walked straight home, they'd have to walk miles

Answers

Answer:

1) The total displacement vector is ((16 + √2)/2, -(6+11·√2)/2)

2) The number of miles they'd have to walk is approximately 13.856 miles

Step-by-step explanation:

1) The distance, direction, and location of the path of the walk the person takes,  are listed as follows;

Start location, (0, 0)

6 miles East walk to location, (6, 0)

6 miles Southeast to location, (6 + 3·√2, -3·√2)

3 miles South to location, (6 + 3·√2, -3·√2 - 3)

5 miles Southwest to location, (6 + 3·√2 - 2.5·√2, -3·√2 - 3 - 2.5·√2)

2 miles East to location, (6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2)

(6 + 3·√2 - 2.5·√2 + 2, -3·√2 - 3 - 2.5·√2) = ((16 + √2)/2, -(6+11·√2)/2)

Therefore the destination coordinates is ((16 + √2)/2, -(6+11·√2)/2)

The total displacement vector, [tex]\underset{d}{\rightarrow}[/tex] = ((16 + √2)/2, -(6+11·√2)/2)

d =  (16 + √2)/2)·i - (6+11·√2)/2)·j

2) If the person walked straight home, the number of miles they'd have to walk, [tex]\left | \underset{d}{\rightarrow} \right |[/tex], is given as follows;

[tex]\left | \underset{d}{\rightarrow} \right | = \sqrt{\left(\dfrac{16 +\sqrt{2} }{2} \right)^2 + \left(-\dfrac{6 + 11 \cdot \sqrt{2} }{2} \right)^2 } = \sqrt{134 + 41 \cdot \sqrt{2} }[/tex]

Therefore;

If the person walked straight home, the number of miles they'd have to walk [tex]\left | \underset{d}{\rightarrow} \right | \approx 13.856 \ miles[/tex]

Find the volume of each figure. Round your answers to the nearest tenth, if necessary​

Answers

Answer:

1.92

hopefully this answer can help you to answer the next question.

answer all of the following please.​

Answers

Answer:

Front = 30

Back = 30

Right = 30

Left = 30

Bottom = 25

Top = 16

Total = 161

Let me know if this helps!

The temperature on a winter was -23 °F. The temerature rise by 5 °F when the sun came up. When the sun set again, the temperature dropped by. 7°F. Write and evaluate an exspression to find the temperature after the sun set.

Answers

Answer:

-25

Step-by-step explanation:

First, add 5 to -23 since the temperature is getting hotter.

so -23 +5= -18

Second, minus the answer by 7 since the temperature is now falling down after the sunset.

so -18 -7 = -25

or...

this step can be simplified as:

-23 +5 -7 =. -25

find the distance of gap d

Answers

Answer:

[tex]\displaystyle d \approx 15.8768[/tex]

Step-by-step explanation:

We want to find the distance of d or AB.

From the right triangle with a 35° angle, we know that:

[tex]\displaystyle \tan 35^\circ = \frac{50}{PB}[/tex]

And from the right triangle with a 42° angle, we know that:

[tex]\displaystyle \tan 42^\circ = \frac{50}{PA}[/tex]

AB is PA subtracted from PB. Thus:

[tex]\displaystyle d = AB = PB - PA[/tex]

From the first two equations, solve for PB and PA:

[tex]\displaystyle \frac{1}{\tan 35^\circ } = \frac{PB}{50} \Rightarrow PB = \frac{50}{\tan 35^\circ}[/tex]

And:

[tex]\displaystyle \frac{1}{\tan 42^\circ } = \frac{PA}{50} \Rightarrow PA = \frac{50}{\tan 42^\circ}[/tex]

Therefore:

[tex]\displaystyle d = AB = \frac{50}{\tan 35^\circ} - \frac{50}{\tan 42^\circ}[/tex]

Using a calculator:

[tex]\displaystyle d= AB \approx 15.8768[/tex]

There is a $30 fee to rent a tool from the local hardware store plus $6 per day. If Joe rents a jackhammer for 5 days, what is his total bill? The correct function for this situation is f(x) = 30x + 6.
O False
O True

Answers

The answer is false because the 30 and 6 would be in each other’s place

Please hurry I will mark you brainliest

Answers

Answer:

q = 1/4

Step-by-step explanation:

-5/4 - (-1/4) = -1

-1/(q-1/2) = 4

-1 = 4(q-1/2)

-1 = 4q - 2

1 = 4q

q = 1/4

a. IfA= {a, b} and B = {p, q, r}, find A x B and B x A using tree diagram.​

Answers

Answer:

Step-by-step explanation:

You tried to get every semi truck to honk but only 7 did what fraction if semi trucks you saw honked

Answers

Answer:

I am so lost but if it's how many honk out of how many you saw I would assume 7/7

A boat goes 24 miles at a constant speed in 4 hours against a river current. It takes the boat 3 hours to go the same distance at the same speed with the current of the river. What is the speed of the boat and what is the current of the river?

Boat speed: Speed of Current:

Answers

Answer: 7 miles/h and 1 miles/h

Step-by-step explanation:

With the speed of current = x + 1

Against the speed of current = x - 1

ATQ

4(x-1) = 3(x+1)

4x-4 = 3x+3

4x - 3x = 3+4

x = 7

Speed of boat = 7miles/h

Current of river = 1 miles/h

please click thanks and mark brainliest if you like :)

Answer:

Hello,

Boat speed=7 miles/h

Current speed = 1 mile/h

Step-by-step explanation:

I am going to try to explain.

Let say V the speed of the boot (V like vitesse in french)

Let say v the speed of the current.

distance=24 miles

[tex]\left\{\begin{array}{ccc}V-v&=&\dfrac{24}{4} \\V+v&=&\dfrac{24}{3} \\\end{array}\right.\\\\\left\{\begin{array}{ccc}V-v&=&6 \\V+v&=&8 \\\end{array}\right.\\\\Adding\ the\ 2\ equations\ and\ substracting\ them \\\\\\\left\{\begin{array}{ccc}2V&=&14 \\2v&=&2 \\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}V&=&7 \\v&=&1 \\\end{array}\right.\\\\[/tex]

Boat speed=7 miles/h

Current speed = 1 mile/h

The present age of Madison's Mother is 3 time that of Madison. After 6 1/4 years, the sum of their age will be 53 3/4 years. Find their present ages. (Estimate to the nearest whole number)

Answers

Answer: [tex]10, 31\ \text{years}[/tex]

Step-by-step explanation:

Given

The present age of Madison's Mother is three time that of Madison

Suppose the Present age of Madison is [tex]x[/tex], so age of her mother is [tex]3x[/tex]

After [tex]6\dfrac{1}{4}\ \text{years}[/tex], the sum of their age will be [tex]53\dfrac{3}{4}\ \text{years}[/tex]

[tex]\therefore (x+6\dfrac{1}{4})+(3x+6\dfrac{1}{4})=53\dfrac{3}{4}\\\\\Rightarrow 4x+2\times \dfrac{25}{4}=\dfrac{53\times 4+3}{4}\\\\\Rightarrow 4x+\dfrac{50}{4}=\dfrac{215}{4}\\\\\Rightarrow 4x=\dfrac{215-50}{4}\\\\\Rightarrow x=\dfrac{165}{16}\\\\\Rightarrow x= 10.31\approx 10[/tex]

Madison mother's age [tex]3x=30.93\approx 31\ \text{years}[/tex]

Find the area of the triangle.​

Answers

Answer:

B

Step-by-step explanation:

area=1/2×32×6.1=16×6.1=97.6 yd²

Answer:

Choice B. 97.6 yd^2

Step-by-step explanation:

B×W×.5= A

Simplify this expression.






I need u again pls

Answers

Answer:

The answer is the Second Option

Step-by-step explanation:

Answer:

the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)

Step-by-step explanation:

plz help!! will mark brainliest!!

Answers

Answer:

correct me if I'm but i think the net cash flow is 3,790 because 2,040 a month income and 1,750 a month for other stuff. 2,040+1,750=3,790

Step-by-step explanation:

Use the points slope formula..

Answers

Answer:

y = -5/14 -13/7

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (1 - -4)/(-8 - 6)

    = (1+4)/(-8-6)

   = 5/-14

   =-5/14

Point slope form is

y-y1 = m(x-x1)

y - -4 = -5/14(x-6)

y+4 = -5/14(x-6)

We want the equation in slope intercept form y = mx+b

Distribute

y+4 = -5/14x + 15/7

Subtract 4 from each side

y+4 -4= -5/14x + 15/7-4

y = -5/14x +15/7 - 28/7

y = -5/14 -13/7

The length, breadth and thickness of a brick is 18 cm, 8 cm, and 5 cm respectively. Find the area of the widest part of the brick. Also find the volume of the brick.​

Answers

Answer:

area = 8 × 18 = 144 cm^2

volume 8×18×5 = 720cm^3

Find the value of x in Circle O.

Answers

Answer:

x=8

Step-by-step explanation:

x^2+15^2=17^2, x=sqrt(64)=8

Change 400cm into mm​

Answers

Answer:

4,000mm

Step-by-step explanation:

I tryed my best

Answer:

mate...

cm to mm is by multiplying 10

400 * 10 = 4000mm

brainliest l m a o

pls help graph of function​

Answers

Answer:

i: -1.3

ii: 1.3

Step-by-step explanation:

You literally have it.

I hope this helps!

pls ❤ and give brainliest pls

A right rectangular prism is 5 inches long, 12 inches wide, and 8 inches tall. The diagonal of the base is 13 inches.
The area of the cross section that is perpendicular to the base and created by a plane that slices the prism through the diagonals of the base and its opposite face is
square inches.

Answers

Answer:

Step-by-step explanation:

The cross-section is an 8”×13” rectangle.

Area = 104 square inches

For what values of k does the equation (2k + 1)x^2 + 2x = 10x – 6 have two
real and equal roots?

Answers

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

In this question, we use the concept of the solution of a quadratic equation to solve it, considering that a quadratic equation in the format:

[tex]ax^2 + bx + c = 0[/tex]

has two equal solutions if [tex]\Delta = b^2 - 4ac[/tex] is 0.

------------------------------------

In this question:

The equation is:

[tex](2k+1)x^2 + 2x = 10x - 6[/tex]

Placing in the correct format:

[tex](2k+1)x^2 + 2x - 10x + 6 = 0[/tex]

[tex](2k+1)x^2 - 8x + 6 = 0[/tex]

Thus, the coefficients are: [tex]a = 2k + 1, b = -8, c = 6[/tex]

------------------------------------

Delta:

We want it to be positive, so:

[tex]\Delta = b^2 - 4ac[/tex]

[tex]\Delta = 0[/tex]

[tex]b^2 - 4ac = 0[/tex]

[tex](-8)^2 - 4(2k+1)(6) = 0[/tex]

[tex]64 - 48k - 24 = 0[/tex]

[tex]-48k + 40 = 0[/tex]

[tex]-48k = -40[/tex]

[tex]48k = 40[/tex]

[tex]k = \frac{40}{48}[/tex]

[tex]k = \frac{5}{6}[/tex]

The equation has two real and equal roots for [tex]k = \frac{5}{6}[/tex]

A similar question is found at https://brainly.com/question/12144265

BRAINLIEST Which equation could be solved using this application of the quadratic formula?



A.
x2 + 1 = 2x − 3
B.
x2 – 2x − 1 = 3
C.
x2 + 2x − 1 = 3
D.
x2 + 2x − 1 = -3

Answers

The quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

What is the quadratic formula?

A standard quadratic equation of the form ax² + bx + c = 0, can be solved using the quadratic formula, which is given as:

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

How to solve the question?

In the question, we are asked for the quadratic equation, which could be solved using this application of the quadratic formula:

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

To find the quadratic equation for which we use the quadratic formula

[tex]x = \frac{-2\pm\sqrt{2^2-4(1)(-4)} }{2(1)}[/tex]

we compare this equation with the standard quadratic formula,

[tex]x = \frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

to get a = 1, b = 2, and c = -4, to get the standard quadratic equation, ax² + bx + c = 0, as (1)x² + (2)x + (-4) = 0, or x² + 2x - 4 = 0.

Now, we convert the given options in the standard form to check for the correct choice:

A. x² + 1 = 2x - 3 ⇒ x² - 2x + 4 = 0, which is not the correct choice.B . x² - 2x - 1 = 3 ⇒ x² - 2x - 4 = 0, which is not the correct choice.C. x² + 2x - 1 = 3 ⇒ x² + 2x - 4 = 0, which is the correct choice.D. x² + 2x - 1 = -3 ⇒ x² + 2x + 2 = 0, which is not the correct choice.

Thus, the quadratic equation that could be solved using the given application of the quadratic formula is x² + 2x - 1 = 3, which in standard form is x² + 2x - 4 = 0. Hence, option C is the right choice.

Learn more about the quadratic formula at

https://brainly.com/question/1214333

#SPJ2



** I NEED HELP PLEASE AND THANK YOU***

Instructions : X,Y,and Z are midpoints. Find the length of each segment.​

Answers

Answer:

MZ = 10

ZO = 10

MO = 20

XZ = 9

YZ = 7

Step-by-step explanation:

Triangles are all the same, proportionally.

X is midpoint of 14, so 7

Y for 18, so 9

Triangle with 10 is 7, 9, 10

Full triangle is double at 14, 18, MO

Since angle N is same angle, MO is double 10, so 20

Z is midpoint, so both halves are 10

Because of midpoints, XZ and YZ with 10 form same triangle as half triangle at 9, 7, and 10 respectively.

Find the multiples of 7 which is greater than 56 but less than 77

Answers

Answer:

63,70

Step-by-step explanation:

7 x 8 = 56

7 x 11 = 77

multiples of 7 and 9, 7 x 10

63 and 70

7×9 = 63

7×10 = 70

Answered by Gauthmath must click thanks and mark brainliest

Ferris started to bike the 4 1/3 miles to school. After 3/5 mile, he stoppedto talk to a friend. How mush farther did he have to go to get to school?

Answers

Answer:

3 11/15 miles

Step-by-step explanation:

4 1/3 - 3/5

4 5/15 - 9/15

3 20/15 - 9/15

3 11/15 miles

what is the value of the smallest of five consecutive integers if the least minus twice the greates equals -3

A. -9
B. -5
C. -3
D. 5

Answers

Answer: (b)

Step-by-step explanation:

Given

There are five consecutive integers and the least minus twice the greatest equals to -3

Suppose [tex]x,x+1,x+2,x+3,x+4[/tex] are the five consecutive integers

According to the question

[tex]\Rightarrow x-2(x+4)=-3\\\Rightarrow x-2x-8=-3\\\Rightarrow -x=8-3\\\Rightarrow x=-5[/tex]

option (b) is correct.

pls help in question no 10. a)​

Answers

Answer:

He should sell it at the cost of 11,115.7895 Rs

Explanation:

Find original price:

100% - 5% = 95% = 9600

Let x be the original price.

Thus (95/100)x = 9600
x = (9600 x 100)/95
x = 960000/95
x = 10105.2632

Find the price in order to gain 10%.

x • 110% = 10105.2632 x 110/100 = 11,115.7895

Rectangle ABCD is similar to rectangle JKLM. AB = 12, BC = 8, CD = 12, DA = 8, and JK = 15. What is the scale factor from JKLM to ABCD? Reduce all answers.

Answers

Answer:

4/5 or 0.8

Step-by-step explanation:

this problem description is not very precise. it leaves out the definition what corners or sides of JKLM correspond to corners and sides of ABCD.

I assume J and K correlate to A and B, and JK is a long side of JKLM.

so, we are going from JKLM to ABCD.

that means we are going from larger to smaller (as JK = 15 and therefore larger than AB = 12).

what is the scale factor to go from 15 to 12 ?

15 × x = 12

x = 12/15 = 4/5 or 0.8

PLSSSS HELP ME WHOEVER ANSWERS CORRECTLY GETS BRAINLIEST!!!!
1. How would we name the polynomial below? Think about degree and number of terms.
x^4 + 3x^2 - x


2. Simplify by adding
(x + 4) + (2x + 7)


3. Multiply
3x^2(5x^3)


4. Divide
8x^3y^5 / 4x^2y^3

Answers

Answer:

This is what you asked me just now.

Step-by-step explanation:

Other Questions
Which of the following should informed citizen follow in order to fulfill his/her civic responsibilities find the supplement of 158 degrees and 17 minutes Many freeways have service (or logo) signs that give information on attractions, camping, lodging, food, and gas services prior to off-ramps. These signs typically do not provide information on distances. An article reported that in one investigation, six sites along interstate highways where service signs are posted were selected. For each site, crash data was obtained for a three-year period before distance information was added to the service signs and for a one-year period afterward. The number of crashes per year before and after the sign changes were as follows.Before 13 22 65 123 56 63After 14 21 43 84 75 721. The article included the statement "A paired t-test was performed to determine whether there was any change in the mean number of crashes before and after the addition of distance information on the signs." Carry out such a test. (Note: The relevant normal probability plot shows a substantial linear pattern.)a. State and test the appropriate hypotheses. (Use = 0.05.)b. Calculate the test statistic and P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.)t = _____p-value = _____c. State the conclusion in the problem context.A. Fail to reject H0. The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.B. Reject H0. The data suggests a significant mean difference in the average number of accidents after information was added to road signs.C. Fail to reject H0. The data suggests a significant mean difference in the average number of accidents after information was added to road signs.D. Reject H0. The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.2. 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