Answer:
Based on your understanding of the ideas of external consistency and fruitfulness, which of the following statements best describes the relevance of these ideas to the acceptance of hypotheses?
2. A fruitful hypothesis is considered stronger because fruitful hypotheses promote scientific progress by revealing new avenues of research and analysis
Which of the following scenarios best demonstrates the idea of fruitfulness?
4. Ordinantly, quantum mechanics is used to describe the behavior of bodies that are so smal that they cannot be seen under an optical microscope, while the theories of classical physics we used to analyze the behavior of large-scale bodies.
Step-by-step explanation:
Someone PLease help me
Using the product of the means equals the product of the extremes, solve for x, to the nearest tenth. 4:9=x:6
Cross multiply:
4 x 6 = 9x
24 = 9x
Divide both sides by 9
X = 24/9
X = 2.7 ( rounded to the nearest tenth)
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 : Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective. Using the data, construct the 80% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that [tex]n = 1067, \pi = \frac{74}{1067} = 0.069[/tex]
80% confidence level
So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079[/tex]
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
If a rectangle has an area of 48 cm², what would be the area of a similar rectangle if
the dimensions are doubled?
A) 2304 cm^2
B) 192 cm^2
C)96 cm^2
D)216 cm^2
Can someone seriously help me!!!!!
Answer:
Step-by-step explanation:
This should help I hope
what is a easier way to solve fractions
Answer: hewo, there! I hope I Made it easier to Understand
the first method is to equally divide the top and bottom of the fraction by whole numbers larger than 1 until you cannot go any further. As an example, let's take the fraction 24/108: Divide each number by 2 to get 12/54. Divide by 2 again to get 6/27
Step-by-step explanation:
To work out a fraction of a number, all you need to do is divide that number by the denominator of the fraction, then multiply your result by the numerator of the fraction
Hope this helps you!!
Have a great day!!!
HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
50%
- Animals
Home
Economics -
20%
30%
- Farm Mechanics
There were 2500 entries at the county fair. The circle graph tells what types of entries were made.
How many were Farm Mechanics entries?
Answer:
750 were Farm Mechanics.
Step-by-step explanation:
30% of 2500 is 750.
Hope this helps
choose the expression that represents the fraction as a product of a whole number and a unit fraction 4/10
Answer:
69
Step-by-step explanation:
trust me
Represent the greatest common factor of 36 and 8 using the distributive property
36 + 8 =
0 4x(9+2)
O2 x (18+4)
O 8x (5+2)
0 11 x (3+1)
An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blends of gasoline:
88.5 98.8 89.6 92.2 92.7 91.8 91.0 91.0 94.7 88.3 90.4 83.4 87.9 88.4 87.5 90.9 84.3
90.4 91.6 91.0 93.0 92.6 87.8 89.9 90.1 91.2 90.7 88.2 94.4 93.7 88.3 91.8 89.0 90.6
88.6 88.5 90.4 96.5 89.2 89.7 89.8 92.2 88.3 93.3 91.2 84.3 92.3 92.2 91.6 87.7 94.2
87.4 91.2 93.2 88.9 90.3 91.1 85.3 91.1 86.7 88.6 89.8 90.0 86.7 90.1 90.5 94.2 88.7
92.7 91.5 93.4 89.3 100.3 90.8 92.7 93.3 89.9 96.1 91.1 87.6 90.1 89.3 86.7
Required:
Construct a stem-and-leaf display for these data. Calculate the median and quartiles of these data.
Answer:
[tex]Median = 90.4[/tex]
[tex]Q_1 = 88.6[/tex]
[tex]Q_3 = 92.2[/tex]
Step-by-step explanation:
Given
The above data
Required
- A stem and leaf display
- The median
- The quartiles
First, determine the range of the data
[tex]Smallest = 83.4[/tex]
[tex]Highest = 100.3[/tex]
Next, group each dataset base on common whole numbers.
So, we have:
[tex]83.4[/tex]
[tex]84.3\ 84.3[/tex]
[tex]85.3[/tex]
[tex]86.7\ 86.7\ 86.7[/tex]
[tex]87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9[/tex]
[tex]88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9[/tex]
[tex]89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9[/tex]
[tex]90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9[/tex]
[tex]91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8[/tex]
[tex]92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7[/tex]
[tex]93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7[/tex]
[tex]94.2\ 94.2\ 94.4\ 94.7[/tex]
[tex]96.1\ 96.5[/tex]
[tex]98.8[/tex]
[tex]100.3[/tex]
Next, we construct the stem and leaf plot.
The whole numbers will be the stem while the decimal parts will be the leaf.
So, we have:
[tex]\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}[/tex]
[tex]\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}[/tex]
From the above plot,
[tex]n = 83[/tex]
The median is calculated as:
[tex]Median = \frac{n+1}{2}th[/tex]
[tex]Median = \frac{83+1}{2}th[/tex]
[tex]Median = \frac{84}{2}th[/tex]
[tex]Median = 42nd[/tex]
i.e. the median is at the 42nd position.
From the above stem and leaf plot.
The 42nd position is at stem 90 and the leaf .4
So the median is:
[tex]Median = 90.4[/tex]
The lower quartile (Q) is calculated as:
[tex]Q_1 = \frac{n+1}{4}th[/tex]
[tex]Q_1 = \frac{83+1}{4}th[/tex]
[tex]Q_1 = \frac{84}{4}th[/tex]
[tex]Q_1 = 21st[/tex]
i.e. the lower quartile is at the 21st position.
From the above stem and leaf plot.
The 42nd position is at stem 88 and the leaf .6
So the lower quartile is:
[tex]Q_1 = 88.6[/tex]
The upper quartile (Q3) is calculated as:
[tex]Q_3 = 3 * \frac{n+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{83+1}{4}th[/tex]
[tex]Q_3 = 3 * \frac{84}{4}th[/tex]
[tex]Q_3 = 3 * 21th[/tex]
[tex]Q_3 = 63rd[/tex]
i.e. the upper quartile is at the 63rd position.
From the above stem and leaf plot.
The 63rd position is at stem 92 and the leaf .2
So the upper quartile is:
[tex]Q_3 = 92.2[/tex]
How can you isolate the variable in this equation? x + 6 = 13 A Add 6 to 13. B Add 6 to both sides. C Subtract x from both sides. D Subtract 6 from both sides.
Answer:
the answer is D, im doiing the flocab rn
Step-by-step explanation:
What is sec 0 when cot 0 = -4/2?
Answer:
[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]
Step-by-step explanation:
[tex]Cot0=-4\sqrt{2}[/tex]
[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]
[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]
[tex]=\frac{4\sqrt{66} }{32}[/tex]
[tex]=\frac{\sqrt{66} }{8}[/tex]
--------------------
hope it helps...
have a great day!!
Suzanne collected data on the weight of her classmates. She found that the range of the data she collected was 17
Which of the following BEST explains what a range of 17 indicates?
A
The average distance of each point from the mean is 17.
.
B
The distance between the minimum and the maximum is 17.
С
The distance between the lower quartile to the upper quartile is 17.
D
The distance between the mean and the median in a skewed data set is 17
Answer:
the answer is A.
Step-by-step explanation:
Meatball subs used to cost $5.40 at Mike's Sub Shop, but he just increased the price by $0.54.
How much do subs cost now?
Answer:
Step-by-step explanation: $5.40 + $0.54 now equals $5.94
Sin 0= 8/17 determine the value of tan?
Answer:
tan theta = 8/15
Step-by-step explanation:
Sin is equal to opposite over hypotenuse. So it means that the side opposite from theta is 8, and the hypotenuse is 17.
To find the value of the adjacent side from theta, use the Pythagorean Theorem.
a^2 + b^2 = c^2
8^2 + b^2 = 17^2
64 + b^2 = 289
Subtract 64.
b^2 = 225
Take the square root.
b = 15.
So that means:
the side opposite from theta is 8,
the side adjacent from theta is 15,
the hypotenuse is 17.
Now we take tan, opposite over adjacent, and use the values from the triangle.
tan = opposite / adjacent
tan = 8/15.
Mrs Mills buys 4 packs of treats for her cats, Fluff and tigger
she gives Fluff 1/6 of a pack each day
She gives tigger 1/5 of a pack each day
for how many complete days will the 4 packs of treats last
Answer: 10 days
Step-by-step explanation:
1/6 + 1/5 = 5/30 + 6/30 = 11/30 (total for the day)
4 / (11/30) = 10.90909091 (divide the total amount of packages by the daily total)
So 10 complete days.
Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.
Answer:
t
Step-by-step explanation:
A circle can be circumscribed about the given quadrilateral, the answer is: A. True.
We know that,
To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.
Opposite angles of a circumscribed polygon are supplementary.
Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.
Learn more about circumscribed polygon on:
brainly.com/question/1423054
#SPJ7
hey I need help with my coordinates
Ok send the picture so I can help you.
Answer:
what is the question? I can help
Step-by-step explanation:
I need to know the answer!
Answer:
As it says he is incorrect.
Step-by-step explanation:
To start, if you were to multiply something such as 5*1, then you would get the same number. Another example would be 8*0. Anything multiplied by 0 IS zero. He does give some valid answers, but there are also ones with smaller numbers. That is why Jackson is incorrect.
Convert 400 meters (m) to feet (ft). Round your answer to two decimal places. (1 metre = 3.28084 feet)
Answer:
1m----------3.28084ft
400m---------xft
x=(400*3.28084)/1
x=1,312.33 ft
Step-by-step explanation:
Rosalind made 969 donuts and put 8 donuts into each box. How many boxes of donuts were made
Answer:
121 donuts in each box
Step-by-step explanation:
969 divided by 8 = 121.125
(Ignore the remainder)
Step by step solution:
We know that there are 969 doughnuts, and there are 8 doughnuts per box. What we need to find out is how many boxes of doughnuts were made.
Step 1:
Set up an equation for Number of doughnuts (969) / Number of doughnuts per box (8) = Number of boxes made (x), which would look like this:
969/8 = x
Step 2:
Doing this, we can get 121.125, which leaves us with
121.125 = x
121.125 = 121.125
Which gives us the answer of 121.125, which we can shorten to 121, as the decimal is not necessary.
Checking our answer:
We can check our answer simply be rewording our 1st equation to solve for the number of doughnuts made. This would give us the equation Number of doughnuts per box (8) * Number of boxes made (121.125) = x. Solving this equation would look like
8 * 121.125 = x
969 = x
969 = 969
Answer: By completing the steps above we get 121, and we can check our work by rewording the problem to solve for the number of Doughnuts. Good Luck!
Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?
Answer:
8x^2 - 26x - 10
Step-by-step explanation:
3(6x2 + 3x - 5 ) = 18x^2 + 9 -15
5(2x2 + 7x - 1) = 10x^2 + 35 - 5
18^2 - 10x^2 = 8x^2
9x - 35x = - 26x
-15 -(-5) = -10
final answer = 8x^2 - 26x - 10
A small country emits 130,000 kilotons of carbon dioxide per year. In
a recent global agreement, the country agreed to cut its carbon
emissions by 3.1% per year for the next 10 years. In the first year of the
agreement, the country will keep its emissions at 130,000 kilotons and
the emissions will decrease 3.1% in each successive year. How many
total kilotons of carbon dioxide would the country emit over the course
of the 10 year period, to the nearest whole number?
Answer:1132858
Step-by-step explanation:
The total carbon dioxide the country emit over the course of the 10 year period would be 1,132,858 kilotons.
What is rate of decrease?
The rate of decrease is a constant amount of deduction from a fixed or primary amount.
Here, the carbon dioxide emits by the country per year is 130,000 kilotons.
The rate of decrease of the carbon dioxide emission per year would be 3.1%.
In the 1st year, the carbon dioxide emission = 130,000 kilotons.
In the 2nd year, the carbon dioxide emission = 130,000 × (100-3.1)/ 100 kilotons = 125,970 kilotons.
In the 3rd year, the carbon dioxide emission = 125,970 × (100-3.1)/ 100 kilotons = 122,064.93 kilotons.
In the 4th year, the carbon dioxide emission = 122,064.93 × (100-3.1)/ 100 kilotons = 118,280.92 kilotons.
In the 5th year, the carbon dioxide emission = 118,280.92 × (100-3.1)/ 100 kilotons = 114,614.21 kilotons.
In the 6th year, the carbon dioxide emission = 114,614.21 × (100-3.1)/ 100 kilotons = 111,061.17 kilotons.
In the 7th year, the carbon dioxide emission = 111,061.17 × (100-3.1)/ 100 kilotons = 107,618.27 kilotons.
In the 8th year, the carbon dioxide emission = 107,618.27 × (100-3.1)/ 100 kilotons = 104,282.1 kilotons.
In the 9th year, the carbon dioxide emission = 104,282.1 × (100-3.1)/ 100 kilotons = 101,049.35 kilotons.
In the 10th year, the carbon dioxide emission = 101,049.35 × (100-3.1)/ 100 kilotons = 97,916.82 kilotons.
Hence, total carbon dioxide emission by that country over 10 years = (130,000 + 125,970 + 122,064.93 + 118,280.92 + 114,614.21 + 111,061.17 + 107,618.27 + 104,282.1 + 101,049.35 + 97,916.82) kilotons = 1,132,857.77 kilotons ≈ 1,132,858 kilotons.
Learn more about rate of decrease here: https://brainly.com/question/14163915
#SPJ2
14. On Monday, a work group eats at Ava's café,
where a lunch special is $8 and a dessert is
$2. The total is $108. On Friday, the group
eats at Bo's café, where a lunch special Is
$6 and a dessert is $3. The total is $90. Each
time, the group orders the same number of
lunches and the same number of desserts.
How many lunches and desserts are
ordered?
what the x and y value.
Answer:
no. who eat lunch special = 12
no. who eat dessert = 6
Step-by-step explanation:
Let x = no. who eat lunch special
y = no. who eat dessert
(1) 8x + 2y = 108 (2) 6x + 3y = 90
Divide thru by 2 Divide thru by 3
4x + y = 54 2x + y = 30
-2x - y = -30
2x = 24
x = 12 2(12) + y = 30
24 + y = 30
y = 6
Help ASAP
What is the highest common factor of 180 and 168
Answer:
Its 12
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
make a factor tree, find the product of the prime factors, it will be 12.
what its 600+600 pls help
Answer:
1200 hope this helps you;)
Answer:
1200 lol
Step-by-step explanation:
What is the shape of
its bases?
A. Circle
B. Heptagon
C. Rectangle
D. Triangle
Answer:
C. Rectangle
Step-by-step explanation:
Hope it helps you in your learning process.
If a team of minors drill a hole 50.4 m into a rock formation and drill at a steady rate of 2.8 m/min. how long does it take to drill the hole
Answer:
t = 18 minutes.
Step-by-step explanation:
We can find the time by using the following kinematic equation:
[tex] y_{f} - y_{0} = v_{0}t + \frac{1}{2}at^{2} [/tex]
[tex] \Delta y = v_{0}t + \frac{1}{2}at^{2} [/tex]
Where:
Δy: is the difference between the initial and the final height = 50.4 m
t: is the time
a: is the acceleration
v₀: is the velocity of the drill = 2.8 m/min
Since the speed of perforation is constant, the acceleration is zero so:
[tex]\Delta y = v_{0}t[/tex]
Then, by solving the above equation for "t" we have:
[tex] t = \frac{\Delta y}{v_{0}} = \frac{50.4 m}{2.8 m/min} = 18 min [/tex]
Therefore, it takes 18 minutes to drill the hole.
I hope it helps you!
Let's say you have a 4 gallon and a 10 gallon pailHow can you measure exactly 2 gallons of water?
You can fill the 10 gallon pail all the way up. After that, you can pour the water from the 10 gallon pail, into the 4 gallon pail 2 times. That will leave you with 2 gallons in the 10 gallon pail.
Determine the amplitude or period as requested. Period of y = - 1/3 * sin 2x
Answer:
[tex]Period = \pi[/tex]
Step-by-step explanation:
Given
[tex]y = -\frac{1}{3} * \sin(2x)[/tex]
Required
The period
A sine function is represented as:
[tex]y =A \sin(Bx + C) + D[/tex]
Where
[tex]Period = \frac{2\pi}{B}[/tex]
By comparing:
[tex]y =A \sin(Bx + C) + D[/tex] and [tex]y = -\frac{1}{3} * \sin(2x)[/tex]
[tex]B = 2[/tex]
So, we have:
[tex]Period = \frac{2\pi}{2}[/tex]
[tex]Period = \pi[/tex]
Hence, the period of the function is [tex]\pi[/tex]
