B
13 ft.
5 ft.
A
C
12 ft.
Find the value of Cos (B) =

Answer:

the operating characteristics have been solved below

Step-by-step explanation:

we have an average of 10 minutes per customers

μ = mean service rate = 60/10 = 6 customers in one hr

the average number of customers that are waiting in line

mean arrival λ = 2.5

μ = 6

[tex]Lq = \frac{2.5^{2} }{6(6-2.5)} \\[/tex]

= 6.25/21

= 0.2976

we calculate the average number of customers that are in the system

[tex]L=Lq+\frac{2.5}{6}[/tex]

= 0.2976+0.4167

= 0.7143

we find the average time that a customer spends in waiting

[tex]Wq=\frac{0.2976}{2.5}[/tex]

= 0.1190 hours

when converted to minutes = 0.1190*60 = 7.1424 minutes

[tex]0.1190+\frac{1}{6}[/tex]

=0.2857

probability that arriving customers would wait for the service

= 2.5÷6 = 0.4167

Answer:

p=c(1+r)^t so the population will be 4679.43424 or rounded to 4679

Step-by-step explanation:

p=c(1+r)^t

p=4,000(1+.04)^t

p=4,000(1.04)^t

p=4,000(1.04)^4

p=4679.43424

p= the population you are solving for

c= the initial amount of the population

(1+r)= the rate of change

t= the period of time

The exponential equation that represents the population of the town in terms of the number of years : [tex]p=4000 (1+0.4)^{t}[/tex]

An exponential equation is an equation with exponents where the exponent (or) a part of the exponent is a variable.

It is similar to the amount received after investing a certain amount compounded annually.

Given,

Initial population = 4000

Rate of increase = 4%

Let current population be p.

Let number of years passed be t.

The exponential equation will be: [tex]p=4000 (1+0.4)^{t}[/tex]

(The population of the town has grown exponentially. This means that:

Initial population = 4000

Population in year I = 4000 + 4% of 4000 = 4000(1 + 0.4)

Population in year II = 4000 + 4% of 4000(1 + 0.4) = 4000(1 + 0.4)(1+0.4)

and this goes on.)

Learn more about exponential equation here

https://brainly.com/question/23729449

#SPJ2

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

[tex] {3}^{2} = 9[/tex]

8 is a multiple of 4, and 9 is more than 8.

[tex] {11}^{2} = 121[/tex]

120 is a multiple of 4 and 121 is one more than it.

[tex] {25}^{2} = 625[/tex]

624 is a multiple of 4 and 625 is one more than it.

[tex] {37}^{2} = 1369[/tex]

1368 is a multiple of 4 and 1369 is one more than 1368.

[tex] {131}^{2} = 17161[/tex]

17160 is a multiple of 4.

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

Answer:

False

Step-by-step explanation:

Each f(x) increases by 8 therefore this equation is a linear function. If you where to graph it would be a straight line

Hope this helped :)

Answer:

False

Step-by-step explanation:

The slope is the same between all pounts which means the function is linear.

Hope this helps!

Answer:

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Step-by-step explanation:

Given

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]

Required

Solve

Start with the bracket

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]

Evaluate all exponents

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]

Evaluate all products

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]

[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]

Answer:

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Step-by-step explanation:

Marla scored 70% on her last unit exam in her statistics class.

This means that in her statistics class, Marla got 70% of her test correct.

When Marla took the SAT exam, she scored at the 70th percentile in mathematics.

This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.

Explain the difference in these two scores.

The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.

Answer:

No, a quadrilateral with the given vertices is not  an isosceles trapezoid.

Step-by-step explanation:

We are given that

A(3,3), B(5,3), C(8,1), D(1,1)

Slope formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]

Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]

Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]

Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]

Slope of AB=Slope of CD

When slopes of two lines are equal then the lines are parallel.

Therefore, AB is parallel to CD.

When one pair of quadrilateral is parallel then the  quadrilateral is trapezoid.

[tex]\implies [/tex]ABCD is a trapezoid.

Distance formula:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]

Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units

Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]

Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]

Length of AD is not equal to length of BC.

Hence, trapezoid is not an isosceles trapezoid.

Answer:

554 executives should be surveyed.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation of 3 hours.

This means that [tex]\sigma = 3[/tex]

The 95% level of confidence is to be used. How many executives should be surveyed?

n executives should be surveyed, and n is found with [tex]M = 0.25[/tex]. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.25 = 1.96\frac{3}{\sqrt{n}}[/tex]

[tex]0.25\sqrt{n} = 1.96*3[/tex]

[tex]\sqrt{n} = \frac{1.96*3}{0.25}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*3}{0.25})^2[/tex]

[tex]n = 553.2[/tex]

Rounding up:

554 executives should be surveyed.

Answer:

y = 5x + 1

Step-by-step explanation:

Given the coordinate points (0,1) and (5,0)

First, get the slope

Slope m =(0-1)/5-0

m = -1/5

Since the required line is perpendicular, then the required slope is;

M = -1/(-1/5)

M = 5

Since 1the y intecept id (0,1) i.e. 1

Required equation is y = mx+b

y = 5x + 1

This gives the required equation

Note that the coordinate (0,1) was used instead os (0,0)

Answer:

ya the equation divides y as a function of x

Answer:

$3.22 per square feet

Step-by-step explanation:

To solve, I usually set up an equation:

sq ft  = 12 1/2 = 1

 $        40.21     x

Then, use cross multiplication.

(12 1/2)x=40.21

Divide both sides by 12 1/2 or 12.5

x = 3.2168

Round to the hundredths place [because we're dealing with money]

$3.22

I hope this helps!

Answer:

3.22 per sq ft

Step-by-step explanation:

Take the total cost and divide by the amount of tiles

40.21 / 12.5

3.2168 per sq ft

Rounding to the nearest cent

3.22 per sq ft

Answer:

113.1 =VOLUME , 4/3 X 3.14 (3) ^3 = 113.1

Answer:

350

Step-by-step explanation:

400- 80 ( 20% discount)

=320+30(loss)

=350

Answer:

The numerical values of the circumference and area of the circle are equal.

Answer:

$10

Step-by-step explanation:

5 toys = $1

Zach wants 50 of these

50 ÷ 5 = 10

10 x 1 = 10

= $10

Answer:

10 dollars

Step-by-step explanation:

We can use a ratio to solve

5 rings     50 rings

----------  = --------------

1 dollar         x dollars

Using cross products

5*x = 1 * 50

5x = 50

Divide by 5

5x/5 = 50/5

x = 10

Answer:

z(max) =  2996.13  $

x₁  = 968      x₂  =  430       ( quantities of regular and Decaf coffee respectevely)

Total quantity of BN = 898 pounds

Total quantity of CM =  500 pounds

Step-by-step explanation:

Cost of the beans

Brazilian natural   =  Price market + 10 %    =  0.47 + 0.047  

BN  Cost   = 0.517 $/lb

Clombian Mild      =  Price market + 10 %    =  0.62  +  0.062

CM Cost   =  0.682  $/lb

Composition of the coffee blend

Regular coffee     0.75 BN  +  0.25 CM

De Caf   coffee     0.40 BN + 0.60  CM

PRICES

Regular Roman  =  3.60  $

Decaf                   =  4.40  $

Production costs:

Regular Roman  =  0.80  $/lb

Decaf                   =  1.05  $/lb

Packaging costs:   0.25  $/Lb       both

Profit  =  Price  -  cost

Profit  of regular coffee  =  3.60 - 0.80 - 0.25 -Cost of bean

for regular coffee cost of BN + CM

BN   is :   0.75*BN cost  = 0.75*0.517  =  0.38775       and

CM  is : 0.25*0.682   =   0.1705

Profit  of regular coffee  =  1.99175  $

Profit for Decaf coffee  =  4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)

Profit for Decaf coffee  =  4.4  - 1.30 - 0.616

Profit for Decaf coffee  =  2.484  $

Let´s call  x₁  pounds of regular coffee   and  x₂   pounds of Decaf coffee then:

 Objective Function is:  

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

Availability of beans for 1000 pounds of Regular coffee means:

750 pounds of BN  +  250 pounds of CM

Availability of beans for 500 pounds of Decaf coffee means

200 pounds of BN  +   300 pounds of CM

Then   750 + 200  =  900 pounds of BN

And     250 + 300 =  550  pounds of CM

Availability of beans for 1000 pounds of Decaf  coffee correspond to

0.75 *x₁  +  0.40*x₂  ≤ 900

Availability of beans for 500 pounds of Regular  coffee correspond to

0.25*x₁  +  0.60*x₂  ≤ 500

Then the model is:

z  =  1.99175*x₁  +  2.484*x₂      to maximize

Subject to:

0.75 *x₁  +  0.40*x₂  ≤ 900

0.25*x₁  +  0.60*x₂  ≤ 500

General constraints  x₁ ≥ 0      x₂ ≥   0  both integers

After 6 iterations optimal solution  ( maximum z) is

z(max) =  2996.13  $

x₁  = 968      x₂  =  430  

x₁   and  x₂  are quantities of  Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild

we proceed as follows

Regular coffee is :  0.75*968 =   726 pounds of BN

Decaf coffee is :      0.40*430 =   172  pounds of BN

Total quantity of BN = 898 pounds

Regular coffee is :  0.25*968   =  242 pounds of CM

Decaf coffee is :  0.6*430  =  258 pounds of CM

Total quantity of CM =  500 pounds

Answer:

AB IS THE ANSWER !!!!!!!!!!

Answer: AB

Step-by-step explanation:

Hi! I don't know if you need help anymore ,but here you go!

Because BC=ED, I asume that AE=AB

Answer:

10 hours

Step-by-step explanation:

ok so we know he is getting payed $20 + $7 every hour so what i would do is keep the multiply the 7 till you get 70 so thats 7x10=70 and 70+20=90 so he worked for 10 hours last week :)  i hope this helps, i tried my best to explain it

Answer:

56.5 degrees

Step-by-step explanation:

Because complementary angles are when their sum is 90, you get the equation:

P + Q = 90

Since Q is 33.5,

P + 33.5 = 90

Subtracting 33.5 from both sides,

P = 56.5

Answer:

[tex] \large{ \tt{❀ \: m \: \angle \: NML= m \: \angle \:QML + m \: \angle \: NMQ}}[/tex]

[tex] \large{ \tt{⤇m \: \angle \:NML= 115 \degree + 28 \degree }}[/tex]

[tex] \boxed{ \large{ \tt{⤇ \: m \: \angle \:NML = 143 \degree }}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

division is right i hope you understand

9514 1404 393

Answer:

  Multiplication

Step-by-step explanation:

The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.

Jaylene got back ...

  90% × $20 = $18

Answer:

is 22

Step-by-step explanation:

Answer:

It doesn't have a slope?

Step-by-step explanation:

Knowing that the slope equation is y2-y1/x2-x1

9-4       5

----- = ------   = 0

4-4       0

this means that the slope is 0...

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

Answer:

Discrete random variable.

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

10-3=7+2=9

4×9=36

36 is the answer

Answer:

58.80

Step-by-step explanation:

84 x .7(70%) =58.80

Answer:

v=-6 or 4

Step-by-step explanation:

Answer:

the answer would be 5

Step-by-step explanation:

have to do the question multiply add and divide to find your answer

Answer:

6x + y

Step-by-step explanation:

6x + 3y/3​

6x + y

Answer:

6x + y

Step-by-step explanation:

6x + 3y / 3

cancel 3y by 3

6x + y

Answer:

[tex]31y^{3} -28y^{2}[/tex]+35y

Step-by-step explanation: