Below is a regular octadecagon (18 sided polygon).
What is the SUM of its interior angles.
What is the measure of ONE of its interior angles?

Answer:

133 Students

Step-by-step explanation:

Let the number of student in a van=v

Let the number of student in a bus=b

The senior class at Snellville rented and filled 12 vans and 14 buses with 796 students.

Therefore: 12v+14b=796

General High rented and filled 14 vans and 12 buses with 738 students.

Therefore: 14v+12b=738

We solve the two resulting equations simultaneously

12v+14b=796

14v+12b=738

Multiply equation 1 by 12 and equation 2 by 14 to eliminate b

144v+168b=9552

196v+168b=10332

Subtract

-52v=-780

Divide both sides by -52

v=15

We substitute v=15 to obtain b in any of the equations

12v+14b=796

12(15)+14b=796

14b=796-180

14b=616

Divide both sides by 14

b=44

Therefore a bus contains 44 Students and a Van contains 15 students.

Number of Students who would fill 2 buses and 3 vans

=2b+3v

=2(44)+3(15)

=133 Students

Answer:

[tex]k-m=b[/tex]

[tex]b-m=diff[/tex]

Step-by-step explanation:

If there are total of k students in a class, and m of those students are girls, the total amount of boys would be:

[tex]k-m=b[/tex]

(Where k, m, b are variables that represent the total number of students, the amount of girls and the amount of boys respectively)

As the amount of girls subtracted from the total amount would leave you with the amount of boys.

There would be:

[tex]b-m[/tex] more boys than girls.

If there were 10 total students in the class and 3 of those students were girls, lets use our above equations to see if they are correct - and if we get the expected amounts of:

7 boys in the class, and 4 more boys than there are girls.

[tex]k-m=b\\10-3=7\\7=7[/tex]

This is correct, as we expected this amount.

[tex]b-m=diff\\7-3=4[/tex]

The difference between them is 4, so this is correct.

Answer:

[tex]\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)[/tex]

Step-by-step explanation:

The coordinate has the following polar form:

[tex]\vec r = (1, 0^{\circ})[/tex]

The image of the coordinate rotated counterclockwise 60° is:

[tex]\vec s = (1, 60^{\circ})[/tex]

Its equivalent form in rectangular coordinates is:

[tex]\vec s = (1\cdot \cos 60^{\circ}, 1 \cdot \sin 60^{\circ})[/tex]

[tex]\vec s = \left(\frac{1}{2},\frac{\sqrt{3}}{2} \right)[/tex]

[tex]\text{Solve for y:}\\\\2y+2=\frac{3y}{2}\\\\\text{Multiply both sides by 2 to cancel the denominator}\\\\4y+4=3y\\\\\text{Subtract 3y from both sides}\\\\y+4=0\\\\\text{Subtract 4 from both sides}\\\\\boxed{y=-4}[/tex]

Answer:-4

Step-by-step explanation:

2y+2=3y/2

Cross multiply

2(2y+2)=3y

Open bracket

4y+4=3y

Collect like terms

4y-3y=-4

y=-4

Answer:

1 seconds after being thrown, the stone reaches its max height

Step-by-step explanation:

Answer:1 Seconds Is wrong the correct answer is 2

Step-by-step explanation:

Khan said so

PLEASE LIKE AND RATE IF YOU GOT YOUR QUESTION RIGHT!!!

Answer:

A. associative property of addition

Step-by-step explanation:

Associative because you can add or multiply those regardless of how the numbers are grouped.

I hope this helped and have a good rest of your day!

Answer:

Associative Property of Addition

Step-by-step explanation:

This property states that the sum of 3 or more numbers stays the same, no matter how they are grouped.

Hope this helped. Have an awesome day!

Answer:

You don't need experiments to ask people questions

Answer:

13

Step-by-step explanation:

It should just be 104 divided by 8 which equals=13

Answer:

i think ...

Step-by-step explanation:

symmetric distribution  usually be a bell shape distribution .

most likely the median = mean = 60

The required value of 60 could be the median of the distribution. Option B is correct.

The mean of the values is the ratio of the total sum of values to the number of values.

When a dataset is ordered, the median is the value that is exactly in the middle. It is a measure of central tendency that distinguishes between the lowest and top 50% of data.

Here,
The mean of a symmetric distribution is 60.
Since for the symmetric data and rational data, the mean is equal to the median,
So Mean = Median
Median = 60

Thus, the required value of 60 could be the median of the distribution.

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Answer: C electricity

Step-by-step explanation:

It is

Answer:

7/8

Step-by-step explanation:

28/32

Divide the top and bottom by 4

28/4 = 7

32/4 = 8

28/32 = 7/8

Answer:

25%

Step-by-step explanation:

Answer:

22,950 units³

Step-by-step explanation:

All you have to do is:

[tex]\frac{3}{4} *60*15*34=\\45*15*34=\\675*34=\\\\22,950[/tex]

Answer:

$353.28

Step-by-step explanation:

Answer:

645

Step-by-step explanation:

it says 645 were inrolled in the fall

Answer:

Step-by-step explanation:

350-75%=87.5\\so 350-87.5\\=262.5\\$262.5 dolla profit\\

Answer:

Start with making them equal.

1/8 --> 3/24

1/8 --> 3/24

1/3 --> 8/24

Now order them.

1/8, 1/8, 1/3.

Hope this helps ;)

Answer:

  c.  y = 3.25^x

Step-by-step explanation:

At x=1, the value of y is slightly more than 3, so the base must be more than 3. The appropriate choice is ...

  y = 3.25^x

Answer:

Step-by-step explanation:

To determine the PMF of the points that the team receive, we must determine the probabilities of winning each of the games.

Consider the firt game. We know that the probability of not losing is 0.4. Since the team can either lose the game or not, we have that the probability of losing it is 0.6. We are told that given that the team does not lose, the probability of winning or having a tie is the same. Recall that, given events A, B, the conditional probability P(A|B) (which means probability of A given B) is given as

[tex]P(A|B) = \frac{P(A\cap B)}{P(B)}[/tex]

in our case, we have that B:= not losing the game. Consider A:= To win the game, C:= To tie the game. We know that P(A|B)=P(C|B). When the team doesn't lose, then the team either ties or wins, this means that

[tex]P(A|B)+P(C|B) = 1[/tex]

So we get that P(A|B) = P(C|B) = 1/2. Let us find P(A)

[tex]P(A|B) = \frac{P(A\cap B)}{P(B)} = \frac{P(A)}{P(B)}=\frac{1}{2}[/tex]

Then [tex]P(A) = \frac{P(B)}{2} = 0.2[/tex]. By an analogous calculation we have that P(A) = P(C) = 0.2.

We will define the following events: [tex]W_i[/tex] is the event that the team wins the game i, [tex]T_i[/tex] is the event that the team ties the game i and [tex]L_i[/tex] is the event that the team loses the game i. In this notation, we have that

[tex]P(W_1) = P(T_1) = 0.2, P(L_1) = 0.6[/tex]

By reasoning the same way for the second game, we can calculate that

[tex]P(W_2)=P(T_2)=0.35, P(L_2) = 0.3[/tex]

To calculate the PMF we must check all the possible outcomes of the results of both games. Since we can either win (W), tie(T) or lose(L) a game, we will express the outcome as follows TW(3) means that the team ties  the first game and wins the second one, for a total of points. In this way, the possible outcomes are

WW(4), WT(3), WL(2), TW(3), TT(2), TL(1), LW(2), LT(1), LL(0)

We see that the number of possible points are 0,1,2,3,4. Let X be the number of points, to get the pmf of X is to give the probability P(X=k) for k=0,1,2,3,4 explicitly. Note that since each game is independent of each other, to get the probability of one of the outcomes it suffices to multiply the probability of each event. For example we have that [tex]P(WW) = P(W_1)\cdotP(W_2) = 0.07[/tex]

Then, the pmf is given by

[tex]P(X=0) = P(LL) = 0.18[/tex]

[tex]P(X=1)=P(LT)+P(TL) = 0.27[/tex]

[tex]P(X=2)=P(LW)+P(TT)+P(WL) = 0.34[/tex]

[tex]P(X=3)=P(WT)+P(TW) = 0.14[/tex]

[tex]P(X=4)=P(WW)= 0.07[/tex]

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

[tex]5c+7s+12a=2808[/tex]

We also know that the children attendance doubles the adult attendance:

[tex]c=2a[/tex]

The third equation is the seating capacity, which we assume is full:

[tex]c+s+a=387[/tex]

We start by replacing variables in two of the equations:

[tex]c=2a\\\\s=387-c-a=387-2a-a=387-3a[/tex]

Then, we solve the remaining equation for a:

[tex]5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99[/tex]

Then, we solve for the other two equations:

[tex]c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90[/tex]

The attendance was 198 children, 90 students and 99 adults.

Answer:

0.09

because I multiplied...

Answer:

0.09

Step-by-step explanation:

36/ 10 x 25/ 1000 = 18/ 5 x 1/40 = 9/100 = 0.09

Answer:

  Draw perpendicular bisectors of two the sides

Step-by-step explanation:

The point that is the same distance from each of their houses is the point called the "circumcenter." It is the center of the circle that passes through the vertices of the triangle. Then each of the vertices is the same distance from the center.

The circumcenter is the intersection point of the perpendicular bisectors of the sides of the triangle. To find it, the group needs to draw perpendicular bisectors of two of the sides.

Answer:

The answer is C

Step-by-step explanation:

EDGE2020

Answer:

27

Step-by-step explanation:

Input 5 for all x-values.

If that is an equal sign...

1/9*(3^5)

With PEMDAS, exponents are done before multiplication.

1/9*243

= 27

Answer:

Which expression is equivalent to 3 over 175

I would say try - C or D

Answer

the answer is -56

Step-by-step explanation:

Answer:

y = 3x-6

Step-by-step explanation:

y = 3x−5

This is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

m =3

Parallel lines have the same slope

We have the slope m=3 and a point (2,0)

y = mx+b

y = 3x+b

Substituting the point into the equation to solve for b

0 = 3(2)+b

0 = 6+b

b = -6

y = 3x-6

Answer:

y = 3x - 6

Step-by-step explanation:

Parallel lines have the same slope,

So m = 3

y - 0 = 3(x - 2)

y = 3x - 6

Answer:

B. 1/3 multiplied by k=7

Step-by-step explanation:

7 ÷ ⅓ = k

Multiply both sides by ⅓

7 ÷ ⅓ × ⅓ = k × ⅓

7 = k × ⅓

Answer:

A. n = -2

Step-by-step explanation:

A. n = -2

4(-2) + 9 = 1

-8 + 9 = 1

1 = 1

The value of n for which the statement of equation 4n + 9 = 1 holds true is n = -2.

Given an equation:

4n + 9 = 1

There are some given options for the value of n.

It is required to find the value of n, where the statement is true.

A) When n = -2:

4n + 9 = 4(-2) + 9

          = 1

B) When n = 2:

4n + 9 = 4(2) + 9

          = 17

C) When n = 3:

4n + 9 = 4(3) + 9

          = 21

D) When n = 4:

4n + 9 = 4(4) + 9

          = 25

Hence the true statement is when n = -2.

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I don't usually do calculus on Brainly and I'm pretty rusty but this looked interesting.

We have to turn K into the limits of integration on our integrals.

Clearly 0 is the lower limit for all three of x, y and z.

Now we have to incorporate

x+y+z ≤ 1

Let's do the outer integral over x.  It can go the full range from 0 to 1 without violating the constraint.  So the upper limit on the outer integral is 1.

Next integral is over y.  y ≤ 1-x-z.   We haven't worried about z yet; we have to conservatively consider it zero here for the full range of y.  So the upper limit on the middle integration is 1-x, the maximum possible value of y given x.

Similarly the inner integral goes from z=0 to z=1-x-y

We've transformed our integral into the more tractable

[tex]\displaystyle \int_0^1 \int_0^{1-x} \int _0^{1-x-y} (x^2-z^2)dz \; dy \; dx[/tex]

For the inner integral we get to treat x like a constant.

[tex]\displaystyle \int _0^{1-x-y} (x^2-z^2)dz = (x^2z - z^3/3)\bigg|_{z=0}^{z= 1-x-y}=x^2(1-x-y) - (1-x-y)^3/3[/tex]

Let's expand that as a polynomial in y for the next integration,

[tex]= y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3[/tex]

The middle integration is

[tex]\displaystyle \int_0^{1-x} ( y^3/3 +(x-1) y^2 + (2x+1)y -(2x^3+1)/3)dy[/tex]

[tex]= y^4/12 + (x-1)y^3/3+ (2x+1)y^2/2- (2x^3+1)y/3 \bigg|_{y=0}^{y=1-x} [/tex]

[tex]= (1-x)^4/12 + (x-1)(1-x)^3/3+ (2x+1)(1-x)^2/2- (2x^3+1)(1-x)/3[/tex]

Expanding, that's

[tex]=\frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1)[/tex]

so our outer integral is

[tex]\displaystyle \int_0^1 \frac{1}{12}(5 x^4 + 16 x^3 - 36 x^2 + 16 x - 1) dx[/tex]

That one's easy enough that we can skip some steps; we'll integrate and plug in x=1 at the same time for our answer (the x=0 part doesn't contribute).

[tex]= (5/5 + 16/4 - 36/3 + 16/2 - 1)/12[/tex]

[tex]=0[/tex]

That's a surprise. You might want to check it.

Answer: 0