blank = blank x 0.1 + 8 x blank

Answer:

[tex]2 \sqrt[3]{3} [/tex]

Step-by-step explanation:

[tex]24 {}^{ \frac{1}{3} } [/tex]

[tex] \sqrt[3]{24} [/tex]

[tex] \sqrt[3]{8 \times 3} [/tex]

[tex] \sqrt[3]{8} \times \sqrt[3]{3} [/tex]

[tex] \sqrt[3]{2 {}^{3} } \times \sqrt[3]{3} [/tex]

[tex]2 \times \sqrt[3]{3} [/tex]

[tex]2 \sqrt[3]{3} [/tex]

Answer:

Separating the variables , using equality symbol , drawing boundary line in XY plane , shading the area are the four steps in graphing linear inequalities

Step-by-step explanation:

Mathematical expressions known as linear inequalities compare two expressions using the inequality symbol. The expression may be either a numerical or an algebraic expression, or it may be both.

Step 1: Always start by separating the variable y from the left side of the inequality.

Step 2: The equality symbol should be used in place of the inequality symbol

Step 3: Draw the boundary line from step 2 in the XY plane.

Step 4: The last step is to partially or completely shade the border line.

Separating the variables , using equality symbol , drawing boundary line in XY plane , shading the area are the four steps in graphing linear inequalities

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Question 1

Since the x-coordinates are the same, the line is vertical. Therefore, the slope is undefined.

Question 2

Since the y-coordinates are the same, the line is horizontal. Therefore, the slope is zero.

You can occasionally start by isolating and replacing a variable that is squared in both equations if you're required to solve a system of equations without a starting linear equation.

If there isn't a linear equation to begin with, you can pick out and use a squared variable in both equations.

Start by dividing both sides of the supplied nonlinear equation by the variable's coefficient, for instance.

After you've done that and isolated a variable, carry on with the problem-solving by adding that variable to the other equation.

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Answer: It indicates that the quadratic has a repeated real number solution.

Step-by-step explanation:

Answer:

$23.55

Step-by-step explanation:

First we will need to determine the total amount of sales Ryan and Carlos made. To do that we will multiply the amount of products sold by the product cost.

$2.75 x 12 = $33

Now we need to deduct the cost of supplies they need to pay back from their profits.

$33- $9.45= $23.55

Now we are left with Ryan and Carlos' total profit, which is $23.55

The heights of both trees at the time when they have an equal height are equal to 4 inches and 48 inches respectively.

In order to graphically solve the system of equations, we would first of all write a system of equations that models the situation. Additionally, we would assign variables to the height of Tree A t years after being planted and height of Tree B t years after being planted, and then translate the word problem into algebraic equation as follows:

Therefore, translating the word problem into algebraic equation, we have the following:

A = 32 + 4t

B = 16 + 8t

On a graph, we would plot the height of Tree A on the x-axis while height of Tree B would be plotted on the y-axis of the cartesian coordinate.

By critically observing the graph, the point of intersection which gives a solution to the system of equations include the following:

Height of Tree A, A = 4 inches.

Height of Tree B, B = 48 inches.

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Answer:

43x+3x+17y

Step-by-step explanation:

because 43x+17y+3x=43x+17y+3x

This is 224's prime factorization. This is the method of repeated division, and the prime factorization of 224 is 2 2 2 2 7.

Image for number 2. Show that the prime factorization of 220 is the same when 220 is multiplied by 2 times 110 or 10 times 22. What numbers might possibly be in the next form when numbers? Give two or three responses.

Therefore, 22 51 111, where 2, 5, and 11, can be expressed as 220's prime factorization.

220 has three prime factors, which are 22; 51; and 111. Here, the pair does not contain the prime factor 5. Consequently, 220 is not a square perfectly.

Consequently, the first ten multiples of 220 are as follows: 220, 440, 660, 880, 1100, 1320, 1540, 1760, 1980, and 2200.

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The graph of f(x)=|x| and m(x)=|x+1| is 1 unit left translation

From the question, we have the following function that can be used in our computation:

f(x) = |x|

m(x) = |x + 1|

First, we have the transformation to be:

From f(x) = |x| to m(x) = |x + 1|

This means the function is translated left by 1 unit

So, we can conclude that

The graph function is translated left by 1 unit

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Answer:

find p (A or ),given that A and B are independent

Using the rate, the number of book Mason reads per month is 2 books.

Mason read 4 books in 2 months. Mason reads at a constant rate. The number of books he reads each month can be calculated as follows;

The number of books he reads is at a constant rate. The rate formula can be used to find the number of book Mason read each month.

rate = number of books read / number of month

Therefore,

number of books read = 4 books

number of month = 2 month

Hence,

rate  = 4 / 2

rate = 2 books per month

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Answer:

30 tadpoles

Step-by-step explanation:

the 3 part of the ratio relates to the number of swans, that is 18 , then

18 ÷ 3 = 6 ← value of 1 part of the ratio

Then

number of tadpoles = 5 × 6 = 30

Answer:

A

Step-by-step explanation:

Fill in X and Y for each of the equations until you find one that fits

The equation of the line y=2x+3 passes through the (1,4) point only.
The line gave y=2x+3.

In order to check whether the line passes through the points the following steps are:

A) (1,4)

Here x=1 , y=4.

We will put these values in the line y=2x+3.

4= 2(1)+3

4=4
As L.H.S=R.H.S, therefore this point (1,4) passes through the line.

B) (-1,4)

Here x=-1 , y=4.

We will put these values in the line y=2x+3.

4= 2(-1)+3

4= -2+3
4 [tex]\neq[/tex] 1
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (1,4) does not pass through the line.

C) (2,3)

Here x=2 , y=3.

We will put these values in the line y=2x+3.

3= 2(2)+3

3= 4+3
3 [tex]\neq[/tex] 7
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (2,3) does not pass through the line.

D) (3,2)

Here x=3 , y=2.

We will put these values in the line y=2x+3.

2= 2(3)+3

2= 6+3
2 [tex]\neq[/tex] 9
As L.H.S  [tex]\neq[/tex]R.H.S, therefore this point (3,2) does not pass through the line.

Only (1,4) point passes through the line.

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The common denominator of the complex fraction is (1/a - 1/b)/(1/a + 1/b) is a²b² which is option D.

The provided complex fraction is  (1/a - 1/b)/(1/a + 1/b).

Now, to find the common denominator,

Solving this complex fraction.

First multiplying each component of every bracket to every component of the other bracket,

= 1/a² + 1/ab - 1/ab - 1/b²

Now, simplifying the equation,

= 1/a² + 1/b²

= (a²+b²)/a²b²

The denominator is the lower part of the fraction.

Hence, the common denominator of the complex fraction is a²b².

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Complete question - What is the common denominator of 1/a + 1/b in the complex fraction (1/a - 1/b)/(1/a + 1/b)?

A)a2 b2

B)a – b

C)a + b

D)ab

The area of this rectangular walk is 390[tex]ft^{2}[/tex]

A rectangle is a closed two-dimensional figure with four sides. The opposite sides of a rectangle are equal and parallel to each other and all the angles of a rectangle are equal to 90°.

The width of the walk is constant and is 2ft, length of the walk is determined by the part of the rectangular yard.

Area of walk = 3 x 27 +3x27 + 3 x 38 + 3 x 38 which is 390[tex]ft^{2}[/tex]

In conclusion the area of the walk is 390[tex]ft^{2}[/tex]

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Answer:

[tex]f(h(x)) = ( \sqrt{x} - 3)^{2} + 4[/tex]

[tex]f(h(x)) = (x - 9) + 4[/tex]

[tex]f(h(x)) = x - 5[/tex]

Step-by-step explanation:

h(x) became x for function of f(x)

The comparison of the terms are:

From the question, we have the following equation:

-4x + 11 = -10x + 17

The variable terms are terms that have the variable x represented

In this case, the variable terms are

Left-hand side = -4x

Right-hand side = -10x

When -4x and -10 are compared, we can conclude that

-4x is greater than -10x

From the question, we have the following equation:

-4x + 11 = -10x + 17

The constant terms are terms that do not have the variable x represented

In this case, the constant terms are

Left-hand side = 11

Right-hand side = 17

When 11 and 17 are compared, we can conclude that

11 is less than 17

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Factor the expression using the GCF 24y+88x

24y+88x

GCF is 8:

8(3y + 11x)

Using the par value method, the journal entry to record the treasury stock transaction is as follows:

Debit Treasury Stock $2,350

Debit Paid-in Capital in Excess of Par Value $1,880

Credit Cash $4,230

Treasury stock transactions can be recorded using the cost or the par value methods.

When the cost method is used, the Treasury Stock account is debited or credited with the cost (cash price paid or received).

When the par value method is used, the difference between the cash price or cost and the par value is recorded in the Paid-in Capital in Excess of the Par Value account.

The Treasury Stock account is then credited or debited with the par value.

Treasury Stock $2,350 (470 x $5) Paid-in Capital in Excess of Par Value $1,880 (470 x $9 - $5) Cash $4,230 (470 x $9)

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Journalize the treasury stock transaction using the par value method.

The linear equations that represent the relationships in the question order are;

A linear equation is an equation of the form; y = m·x + c

The slope of the line is found as follows;

(-5 - (-21))/(-1 - (-5)) = 4

The equation is y - (-5) = 4·(x - (-1)) = 4·x + 4

y = 4·x + 4 - 5 = 4·x - 1

The y-intercept is (0, 4), the x-intercept is (4, 0)

The slope is therefore; (0 - 4)/(4 - 0) = -1

The equation is therefore; y - 0 = -1 × (x - 4) = -x + 4

The y-intercept is (0, -1), the x-intercept is (4, 0)

The slope is therefore; (0 - (-1))/(4 - 0) = 1/4

The equation is therefore; y - 0 = (1/4) × (x - 4) = x/4 - 4/4 =

The slope of the line is; [tex]\dfrac{-3\frac{3}{4} - \left(-\frac{3}{4}\right) }{4-1} = -1[/tex]

y - (-3/4) = -1 × (x - 1) = -x + 1

y = -x + 1 - (3/4) = -x + 1/4

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Assuming [tex]\overline{BC}[/tex] is a diameter, minor arc [tex]AB[/tex] has a measure of [tex]180^{\circ}-108^{\circ}=72^{\circ}[/tex].

Using the inscribed angle theorem, [tex]36=x+3 \implies x=\boxed{33}[/tex].

Answer: 4/3

Step-by-step explanation:

The reciprocal of a/b is b/a.

Answer: false

Step-by-step explanation:

if the expected grade was 100 but passing was 80 then she couldn't have passes with a 48

Two triangles are congruent if they satisfy SSS or ASA or SAS or AAS or RHS criteria.

What is the meaning of congruent triangles?

If two triangles have both the same shape and the same size then it is said that the two triangles are congruent. In other words, two triangles are congruent if they are copies of each other.

We can prove that two triangles are congruent if they satisfy any one of the following criteria:-

SSS (side side side ):- If three sides of one triangle are equal to the corresponding three sides of the other triangle.

SAS ( side angle side ):- If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle.

ASA ( angle side angle ):- If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle.

AAS ( angle angle side ):- If two angles and a none included side of a triangle are equal to the corresponding angles and side of another triangle.

RHS (right hypotenuse side ):- If the hypotenuse and one side of the right triangle are equal to the corresponding side and the hypotenuse of another triangle.

Hence, two triangles are congruent if they satisfy any one of the criteria of congruence (SSS, ASA, SAS, AAS or RHS).

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The coordinates of the point after the two reflections are (0.3,-7/10).

A reflection is a mapping from an isometric hyperplane with a set of fixed points acting as the reflection's axis or plane from a Euclidean space to itself. A figure's reflection creates its mirror image of that figure in the plane or axis of the reflection.

Given that, the point (-0.3, 7/10) is reflected over the y-axis and then over the x-axis respectively.

The coordinates of the point after the reflection in the y-axis are:
(0.3, 7/10)

Now, the coordinates of the point after the reflection in the x-axis are:
(0.3, -7/10)

Hence, the coordinates of the point after the two reflections are (0.3,-7/10).

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The graph of the inequality is plotted using the below points.

Graph:

In math, graph show you information as a visual image or picture.

Given,

Here we need to find the graph of the given inequality.

To graph an inequality:

To graph the related boundary line. We have to replace the <, >, ≤ or ≥ sign in the inequality with = to find the equation of the boundary line.

Now, we have to identify at least one ordered pair on either side of the boundary line and substitute those (x, y) values into the inequality.

Then shade the region that contains the ordered pairs that make the inequality a true statement.

Here if points on the boundary line are solutions, then use a solid line for drawing the boundary line. This will happen for ≤ or ≥ inequalities.

Where as if points on the boundary line are not solutions, then use a dotted line for the boundary line. This will happen for < or > inequalities.

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The reasons put into the correct order to justify solving the inequality:

-2(x + 6) < 3(x + 1) - Given

-2x - 12 < 3x + 3 - Distributive Property

-2x < 3x + 15 - Addition Property of Order

-5x < 15 - Subtraction Property of Order

x > 3 - Division Property of Order

Check how to solve:

-2(x + 6) < 3(x + 1)

Open the parenthesis

-2x - 12 < 3x + 3

Add 12 to both sides

-2x - 12 + 12 < 3x + 3 + 12

-2x < 3x + 15

Subtract 3x from both sides

-2x - 3x < 3x + 15 - 3x

- 5x < 15

divide both sides by -5

x > 3

Therefore, the solution to the given inequality -2(x + 6) < 3(x + 1) is x > 3.

The properties mentioned above are properties of inequalities and hold for all situations of inequalities as given.

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Answer:

Answer:

[tex]8\sqrt{11}[/tex]

Step-by-step explanation:

Given:

[tex]x+\dfrac{1}{x}=\sqrt{11}[/tex]

Sum of two squares

[tex]\boxed{a^2+b^2=(a+b)^2-2ab}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^2+\dfrac{1}{x^2}&=\left(x+\dfrac{1}{x}\right)^2-2x\left(\dfrac{1}{x}\right)\\\\&=\left(\sqrt{11}\right)^2-2\\\\&=11-2\\\\&=9\end{aligned}[/tex]

Sum of two cubes

[tex]\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}[/tex]

[tex]\textsf{Let}\; a = x[/tex]

[tex]\textsf{Let}\; b = \dfrac{1}{x}[/tex]

Therefore:

[tex]\begin{aligned}x^3+\dfrac{1}{x^3}&=\left(x+\dfrac{1}{x}\right)\left(x^2-x\left(\dfrac{1}{x}\right)+\left(\dfrac{1}{x}\right)^2\right)\\\\ &=\left(x+\dfrac{1}{x}\right)\left(x^2-1+\dfrac{1}{x^2}\right)\\\\&=\left(x+\dfrac{1}{x}\right)\left(x^2+\dfrac{1}{x^2}-1\right)\\\\&=\sqrt{11}\left(9-1\right)\\\\&=8\sqrt{11}\end{aligned}[/tex]