(a) What is the difference between a compare validator and a range validator?

(b) When would you choose to use one versus the other?

Answer:

Solid state drive

Explanation:

The term solid-state drive is used for the electronic circuitry made entirely from semiconductors. This highlights the fact that the main storage form, in terms of a solid-state drive, is via semiconductors instead of a magnetic media for example a hard disk.  In lieu of a more conventional hard drive, SSD is built to live inside the device. SSDs are usually more resistant to physical shock in comparison to the electro-mechanical drives and it functions quietly and has faster response time. Therefore,  SSD will be best suitable for the Dave.

Answer:

Check the explanation

Explanation:

SDLC

SDLC stands for Software Development Life Cycle

It provides steps for developing a software product

It also checks for the quality and correctness of a software

The main aim of SDLC is to develop a software, which meets a customer requirements

SDLC involves various phases to develop a high-quality product for its end user

Phases of SDLC

           There are seven phases in a software development life cycle as follows,

Requirement Analysis   Feasibility Study   Design    Coding    Testing Deployment      Maintenance

kindly check the attached image below

Requirement analysis

This is the first stage in a SDLC.

In this phase, a detailed and precise requirements are collected from various teams by senior team members

It gives a clear idea of the entire project scope, opportunities and upcoming issues in a project

This phase also involves, planning assurance requirements and analyze risk involved in the project

Here, the timeline to finish the project is finalized

Feasibility Study

In this stage, the SRS document, that is “Software Requirement Specification” document is defined, which includes everything to be designed and developed during the life cycle of a project

Design

In this phase as the name indicates, software and system design documents are prepared, based on the requirement specification document

This enable us to define the whole system architecture

Two types of design documents are prepared in this phase as follows,

High-Level Design

Low-Level Design

Coding

In this phase, the coding of project is done in a selected programming language

Tasks are divided into many units and given to various developers

It is the longest phase in the SDLC

Testing

In this stage, the developed coding is tested by the testing team

The testing team, checks the coding in the user point of view

Installation/Deployment

In this stage, a product is released by the company to the client

Maintenance

Once the product is delivered to the client, the maintenance phase work will start by fixing errors, modifying and enhancing the product.

Employee Payroll System

Requirement analysis

Gather information from various team for requirement

Analyze the number of employees to handle the project

Timeline to finish the project, eg.1 month

Feasibility Study

The system requirements such as how many systems are required

Decide which software to be installed to handle the project.

For example, if we are going to develop the software using C language, then software for that has to be installed

The SRS document has to be prepared

Design

In this the HLD and LLD is prepared, the overall software architecture is prepared

The modules involved in coding are decided

Here the modules can be employee, payroll manager, Employee Log time, account details

The input and output are designed, such as employee name is the input and output is the salary for him, based on working hours

Coding

Here the coding is divided into various sections and given to 2 or more employees

One may code employee detail, one will code working hours of employees and one may code the banking details of employee

Testing

The coding is tested for syntax, declaration, data types and various kinds of error

The testing team will test the coding with various possible values

They may even check with wrong values and analyze the output for that

Installation

Now the software is installed in the client system and the client is calculating the payroll for an employee based on working hours in a month

Maintenance

If any error occurs, the team will clear the issue.

When a new employee joins, then the employee data will added to the database and the database is updated

Also if the client asks for any new features, it will done in this phase.

Explanation:

The most reliable hard drives are those whose most common size is 3.5 inches, their advantages are their storage capacity and their speed and a disadvantage is that they usually make more noise.

For greater speed, it is ideal to opt for two smaller hard disks, since large disks are slower, but are partitioned so that there are no problems with file loss.

For a person who needs to use content creation programs, it is ideal to opt for a hard drive that has reliability.

Answer:

Variety

Explanation:

Answer:

The java program for the given scenario is as follows.

import java.util.*;

//interface with method area

interface ObjectWithTwoParameters

{

double area (double d1, double d2);

}

class RectangleClass implements ObjectWithTwoParameters

{

//overriding area()

public double area (double d1, double d2)

{

return d1*d2;

}

}

class TriangleClass implements ObjectWithTwoParameters

{

//overriding area()

public double area (double d1, double d2)

{

return (d1*d2)/2;

}  

}

class CylinderClass implements ObjectWithTwoParameters

{

public double area (double d1, double d2)

{

return ( 2*3.14*d1*d1 + d2*(2*3.14*d1) );

}

}

public class Test

{

public static void main(String[] args)

{

//area displayed for all three shapes

ObjectWithTwoParameters r = new RectangleClass();

double arear = r.area(2, 3);

System.out.println("Area of rectangle: "+arear);

ObjectWithTwoParameters t = new TriangleClass();

double areat = t.area(4,5);

System.out.println("Area of triangle: "+areat);

ObjectWithTwoParameters c = new CylinderClass();

double areac = c.area(6,7);

System.out.println("Area of cylinder: "+areac);

}

}

OUTPUT

Area of rectangle: 6.0

Area of triangle: 10.0

Area of cylinder: 489.84

Explanation:

1. The program fulfils all the mentioned requirements.

2. The program contains one interface, ObjectWithTwoParameters, three classes which implement that interface, RectangleClass, TriangleClass and CylinderClass, and one demo class, Test, containing the main method.

3. The method in the interface has no access specifier.

4. The overridden methods in the three classes have public access specifier.

5. No additional variables have been declared.

6. The test class having the main() method is declared public.

7. The area of the rectangle, triangle and the cylinder have been computed as per the respective formulae.

8. The interface is similar to a class which can have only declarations of both, variables and methods. No method can be defined inside an interface.

9. The other classes use the methods of the interface by implementing the interface using the keyword, implements.

10. The object is created using the name of the interface as shown.

ObjectWithTwoParameters r = new RectangleClass();

Answer:

public class RectangleArea {

   public static void main(String[] args) {

       Rectangle myRectangle = new Rectangle(15.8, 7.9);

       double calArea = myRectangle.calcArea(15.8, 7.9);

       System.out.println("The area is "+ calArea);

   }

}

class Rectangle{

   private double length;

   private double width;

   //Defined Constructor

   public Rectangle(double length, double width) {

       this.length = length;

       this.width = width;

   }

   public double calcArea(double len, double wi){

       return len* wi;

   }

}

Explanation:

Answer:

I don't remember much on this stuff but I think it was B

Answer:

Check the explanation

Explanation:

Kindly check the attached image for the first step

Note that the -print" statement executes n(n — I)(n — 2) times and the index values for i, j, and k can never be the same.  

Therefore, the algorithm prints out all the possible ways to draw three balls in sequence, without replacement.

Now we need to determine the number of lines this the algorithm print. In this case, we are selecting three different balls randomly from a set of n balls. So, this involves permutation.  

Therefore, the algorithm prints the total  

P(n, 3)  

lines.  

Answer:

Explanation:

Base on the scenario been described in the question, We are 95% confident that the price of a single hard drive with 33 megahertz speed and 386 CPU falls between $3,943 and $4,987

Answer:

The answer is 1646

Explanation:

The original code requires 1024 bytes and is called 70 times ,it requires 7 byte and its size is 132 bytes

1024 + (70*7) + 132 = 1024 + 490 +132

= 1646

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

Answer:

They can communicate over the phone or have meetings describing what is and isn't working for Joe. It's also very important that Darla makes eye contact and is actively listening to effectively handle their customer.

Explanation:

Answer: I would suggest you consider your audience and how you can connect to them. Is your presentation, well, presentable? Is whatever you're presenting reliable and true? Also, no more than 6 lines on each slide. Use colors that contrast and compliment. Images, use images. That pulls whoever you are presenting to more into your presentation.

Explanation:

Answer:

1. Logical

2.=

3.IF

Explanation:

just did the assignment

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

Answer:

can you give more detail

Explanation:

Answer:

Check the explanation

Explanation:

Let the population mean time on task of original website be [tex]\mu_1[/tex] and that of new prototype be [tex]\mu_2[/tex]

Here we are to test

[tex]H_0:\mu_1=\mu_2\;\;against\;\;H_1:\mu_1<\mu_2[/tex]

The data are summarized as follows:

                                                       Sample 1             Sample 2

Sample size                                        n=20                    n=20

Sample mean                                 [tex]\bar{x}_1=243.4[/tex]             [tex]\bar{x}_2=253.4[/tex]

Sample SD                                     s1=130.8901          s2=124.8199

The test statistic is obtained from online calculator as

t=-0.23

The p-value is given by 0.821

As the p-value is more than 0.05, we fail to reject the null hypothesis at 5% level of significance and hence conclude that there is no statistically significant difference between the original website and the prototype developed by the team at 5% level of significance.

Answer:

All the classes are mentioned with code and screenshots. . That class is shown at last.

Explanation:

Solution

Class.Java:

Code

**

* atauthor your_name

* This class denotes Class at the college.

*

*/

public class Class {

  private String className,classID;

  private Professor professor;

  /**

  * atparam className

  * atparam classID

  * atparam professor

  */

  public Class(String className, String classID, Professor professor) {

      this.classID=classID;

      this.className=className;

      this.professor=professor;

  }

     /**

  * at return classID of the class

  */

  public String getClassID() {

      return classID;

  }

    /**

  * Override toString() from Object Class

  */

  public String toString() {    

      return classID+" "+className+" "+professor.getName()+" "+professor.getEducation();        

  }  

}

Person.Java:

Code:

/**

* atauthor your_name

* This class represents Person

*

*/

public class Person {    

  protected String name;  

  /**method to fetch name

  * at return

  */

  public String getName() {

      return name;

  }

  /**method to set name

  * at param name

  */

  public void setName(String name) {

      this.name = name;

  }

Professor.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* at author your_name

*

*This class represents professors

*

*/

public class Professor extends Person{    

  private String professorID, education;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * at param name

  * at param professorID

  * at param education

  */

  public Professor(String name,String professorID,String education) {        

      this.name=name;

      this.professorID=professorID;

      this.education=education;        

  }

  /**

  * at return

  */

  public String getEducation() {

      return this.education;

  }    

  /**

  * at return

  */

  public String getprofessorID() {

      return this.professorID;

  }  

  /** to add classes

  * at param Class

  */

  public void addClass(Class c) {

      classes.add(c);

  }  

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+professorID+" - "+education;

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }      

      return result;

  }

}

}

Student.java:

Code:

import java.util.ArrayList;

import java.util.List;  

/**

* This class represents students

*  at author your_Name

*

*/

public class Student extends Person{    

  private String studentID;

  private List<Class> classes=new ArrayList<Class>();    

  /**

  * atparam name

  * atparam studentID

  */

  public Student(String name,String studentID) {      

      this.name=name;

      this.studentID=studentID;      

  }  

  /**

  * atreturn

  */

  public String getStudentID() {

      return studentID;

  }

     /**

  * atparam c

  */

  public void addClass(Class c) {

      classes.add(c);

  }    

  /**

  * atreturn

  */

  public int getClassCount() {

      return classes.size();

  }

  /**

  * Override toString() from Object Class

  */

  public String toString() {

      String result=this.getName()+" - "+studentID+"\n";

      for(Class c:classes) {

          result+=c.toString()+"\n";

      }    

      return result;

  }  

}

NOTE: Kindly find an attached copy of screenshot of the output, which is a part of the solution to this question

Answer:

See explaination

Explanation:

//ReadFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class ReadFile

{

public static void main(String[] args)

{

int elementsCount=0;

//Create a File class object

File file=null;

Scanner fileScanner=null;

String fileName="sample.txt";

try

{

//Create an instance of File class

file=new File(fileName);

//create a scanner class object

fileScanner=new Scanner(file);

//read file elements until end of file

while (fileScanner.hasNext())

{

double value=fileScanner.nextInt();

elementsCount++;

}

//print smallest value

System.out.println(elementsCount+" data values are read");

}

//Catch the exception if file not found

catch (FileNotFoundException e)

{

System.out.println("File Not Found");

}

}

}

Sample output:

sample.txt

10

20

30

40

50

output:

5 data values are read

Answer:

[tex]5909? \times \frac{?}{?} 10100010 {?}^{?} 00010.222 {?}^{2} [/tex]

Answer:

C = (3P+1) % 27

so when P will be max 26,when P is 26 the (3P+1) = 79. And 79/27 = 2 so let's give name n = 2.

Now doing reverse process

We get ,

P = ((27*n)+C-1)/3

Where n can be 0,1,2

So substituting value of n one by one and the C=7(corresponding index of h)

For n= 0,we get P=2, corresponding char is 'c'

For n=1,we get P=11, corresponding char is 'l'

For n=2,we get P= 20, corresponding cahr is 'u'.

So beside 'c',the system will generate 'h' for 'l' and 'u' also.

Answer:

How was the Aswan high dam had an adverse effect on human health? It created new ecosystems in which diseases such as malaria flourished. An environmental challenge facing the Great Man Made River is that pumping water near the coast. ... Water scarcity makes it impossible to grow enough food for the population.

Explanation:

Answer:

Explanation:

The solution code is written in Python 3.

Firstly, we need to import math module (Line 1).

Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).

We can test the function using a sample list (Line 20) and we shall get 4.509249752822894

If we pass an empty list, a ZeroDivisionError exception will be raised.

Answer:

You should name it honest and sincere intention

Explanation:

That is a good name for what you are going to talk about in your slideshow.

Answer:

Bits

Explanation:

Step-by-step Explanation:

SIS stands for: The Student Information System (SIS).

This system (a secure, web-based accessible by students, parents and staff) supports all aspects of a student’s educational experience, and other information. Examples are academic programs, test grades, health information, scheduling, etc.

It is difficult to convince top management to commit funds to develop and implement SIS, this can be due to a thousand reasons.

The obvious is that the management don't see the need for it. They would rather have students go through the educational process the same way they did. Perhaps, they just don't trust the whole process, they feel more in-charge while using a manual process.

Answer: (a). 11.3137

(b). 22.849

Explanation:

Provided below is a step by step analysis to solving this problem

(a)

clc;close all;clear all;

a=2;x=3.5;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('2^3.5 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

2^3.5 from tailor series=11.3137 after adding n=15 terms

disp('2^3.5 using calculator =11.3137085');

Command window:

2^3.5 from tailor series=11.3137 after adding n=15 terms

2^3.5 using calculator =11.3137085

(b)

clc;close all;clear all;

a=6.3;x=1.7;

E=10;n=0;k=1;sn1=0;

while E >0.000001

cn=((log(a))^n)*(x^n)/factorial(n);

sn=sn1+cn;

E=abs((sn-sn1)/sn1);

sn1=sn;

n=n+1;

k=k+1;

end

fprintf('6.3^1.7 from tailor series=%6.4f after adding n=%d terms\n',sn,n);

disp('6.3^1.7 using calculator =22.84961748');

Command window:

6.3^1.7 from tailor series=22.8496 after adding n=16 terms

6.3^1.7 using calculator =22.84961748

cheers i hope this helped !!!