Answer:
n=6 u=28/3
Step-by-step explanation:
system of equations
The number of used books sold will be 7 and that of the new book will be 9.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
Given
Number of used books = u
Number of new books = v
In the first case;
12u + 4n = 136
In the second case;
28u + 4n = 248
By both equations,
u = 7 and n = 9
So the number of used books is 7 and the new is 9.
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Find the value of x that will make L||M.
6x + 8
4x + 2
X =[?]
Answer:
6x+8+4x+2=180
so!! 10x+10=180
10x=170
x=17
Answer:
[tex]x=17[/tex]
Step-by-step explanation:
The two angles labelled [tex]6x+8[/tex] and [tex]4x+2[/tex] are co-interior angles. When two parallel lines are cut by a traversal, co-interior angles are supplementary, meaning they add up to 180 degrees. Therefore, if line L is parallel to line M, [tex]6x+8[/tex] and [tex]4x+2[/tex] must be supplementary:
[tex]6x+8+4x+2=180[/tex]
Combine like terms:
[tex]10x+10=180[/tex]
Subtract 10 from both sides:
[tex]10x=170[/tex]
Divide both sides by 10:
[tex]x=\frac{170}{10}=\boxed{17}[/tex]
Conjugate/Rational Number?
Please include a detailed explanation so I can learn to do it by myself, Thank you!
Answer:
1) [tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]
2) [tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]
3) [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]
4) [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]
5) [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]
Step-by-step explanation:
The rationalization of the denominator of the surds are found as follows;
1) [tex]\dfrac{2}{\sqrt{5} }[/tex]
[tex]\dfrac{2}{\sqrt{5} } \times \dfrac{\sqrt{5} }{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]
[tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]
2) [tex]-\dfrac{5}{\sqrt{3} }[/tex]
[tex]-\dfrac{5}{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]
[tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]
3) [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} }[/tex]
[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } \times \dfrac{ \sqrt{10} }{\sqrt{10} } = \dfrac{\sqrt{20} + \sqrt{50} }{10 } = \dfrac{2\cdot \sqrt{5} + 5 \cdot \sqrt{2} }{10} = \dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]
[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]
4) [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} }[/tex]
[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \dfrac{3 \cdot \sqrt{3}+\sqrt{6} }{3 } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]
[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]
5) [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }[/tex]
[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} } = \dfrac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} } = \dfrac{\sqrt{15} -\sqrt{6} }{5 - 2} = \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]
[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]
6) [tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} }[/tex]
[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} = \dfrac{\sqrt{21} + \sqrt{35}}{{3} + {5}} = \dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]
[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} =\dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]
Please help me! I cant figure this out
AB is the same as A multiplied by B. In order to get this value, we need to figure out the value of A and B.
We have two equations here:
a + 5b = 2b + 13
a = 3b - 5
The second equation already has A isolated. So, we can take that equation and plug in the value for A. Doing so will allow us to solve for B.
(3b - 5) + 5b = 2b + 13
8b - 5 = 2b + 13
6b - 5 = 13
6b = 18
b = 3
Now that we know B, we can use our equation that isolated A.
a = 3(3) - 5
a = 9 - 5
a = 4
Therefore, a = 4 and b = 3, and ab = 12.
Hope this helps!
Which system of linear inequalities is graphed?
Answer:
The first one.
Step-by-step explanation:
Graph lines as if the inequalities were equal signs.
X = -3 is a vertical line at x = -3, because it's less than we shade to the left. All numbers less than -3 are to the left. The line is dashed because there is no equal to. Only less than. The line is not included in the solution set.
y = -x - 1 is a line with a y-intercept of -1 and a slope of -1. All values that are less that y are below the line. Because it's less than or equal to the line is solid.
Answer:
A
Step-by-step explanation:
The vertical line is dotted at -3 and shaded to the left
x < -3
This gives us two choices left
A and C
The other line has a y intercept at -1 and is solid and shaded to the left
It is of the form
y ≤ mx+1
We know the slope is negative since is goes down from left to right
The only Choice is A
Helpppp
Graph the quadratic function y 9x Ox 140. What are the solutions of the quadratic equation 0 - 0 - 6x
140?
Answer:
Answer:bf
Step-by-step explanation:
i need helpppppp it’s urgentttttt!!!!
compare the slopes and y intercepts of the graphs of the equations in the linear system 8x + 4y =12 and 3y = -6x -15 to determine whether the system has one solution no solutions or infinitely many solutions explain
Answer:
No solutions
Step-by-step explanation:
Convert both equations into y = mx + b form, where m is the slope and b is the y intercept.
8x + 4y = 12
4y = -8x + 12
y = -2x + 3
Rearrange the other equation:
3y = -6x - 15
y = -2x - 5
So, both equations have a slope of -2. But, one has a y intercept of 3 and the other has a y intercept of -5.
Because the lines have the same slope but different y intercepts, the lines are parallel.
Parallel lines have no solutions, because they will never intersect.
So, the system has no solutions.
help on this question please! also if you can kindly explain it would be very much appreciated!!
Answer:
D. 50°
Step-by-step explanation:
We know that there are 3 line segments that are forming the angles. Based on that, we can safely say that each line segment is 180°. Given that, we can find the other 2 interior angles of the triangle. We know that one of the exterior angles is 90° so that interior angle also has to be 90° because both angles have to sum to 180. The 2nd exterior angle that we know is 140, so 180-140 = 40°. Since we know the other 2 angles of the triangle now and we know that all the angles of a triangle must sum to 180°, we add 90 and 40 to get 130 and then subtract that from 180 to get 50°. That would look something like this: 180-(90+40) = 180 - 130 = 50°. Hope this helps!
Answer
The measure of p is 50 degrees.
Explanation
You can see that p is located in a triangle.
The interior angles of a triangle always add up to 180 degrees.
So, to solve this problem, you can find the other interior angles, then subtract those from 180 to find p.
The exterior angles are 140 and 90 degrees. To find the measure of the interior angles, you subtract them from 180, (because the exterior angles and interior angles add up to 180).
The measure of the interior angles are 40 and 90 degrees; 180-140=40 and 180-90=90.
Now you can subtract the measure of the two interior angles from 180 to find p; 180-40-90=50.
I'm not sure how to answer this!!
Answer:
I think it's a
Step-by-step explanation:
hsjshbwibs hshhsvsu hshsbsbus
Question 2 of 10
Which of the following can you determine, when you use deduction and start
from a given set of rules and conditions?
A. None of these
B. What may be true
C. What may be false
D. What must be true
SUBMIT
Good Afternoon. I hope you’re well:) I need to understand how to go about solving this without a calculator, please. Thank you so much and have a blessed day!
Answer:
Step-by-step explanation:
Being able to do this requires that you understand what is being asked and that you understand domain. This is a piecewise function, made up of 4 different parts, and each part has a domain different from every other part. Now look at the solutions. We are given coordinates, x and y. So this is how this problem is done.
In a. the coordinate is (-1, 1), right? x = -1 here, so the equation that we "pick" (I'll explain that in a sec) has to have a domain where -1 will fall. The first part of this piecewise has a domain of less than or equal to -11. Is -1 less than or equal to -11? No, it is not. -1 is greater than -11, so the equation we "pick" to use will not be this one. Look at the next piece of the function and note its domain. This domain is that x is greater than -11 and less than 5. Does -1 fit in that domain? Is -1 included in that spread of numbers? Yes it is, so that is the equation we will use. By use I mean that we will plug in -1 for x and see if y = 1 (that number comes from the coordinate (-1, 1) where y = 1). The equation is y = x + 2 and plugging in -1 for x:
y = -1 + 2 so
y = 1 and this point is on the piecewise. Let's do one more example so you can see how it looks when it DOESN'T work out, ok?
Look at b. The coordinate is (-2, -10). x = -2, so the same domain, same equation: x + 2. We plug in -2 for x to find y:
y = -2 + 2 so
y = 0. 0 does not equal -10, so this point is not on that graph.
The key here is picking the equation whose domain includes your x value and evaluating the equation at that value of x to find y.
If m angle PQR = 141", find each measure.
Answer:
x=6
pqs=82
sqr=59
Step-by-step explanation:
13x + 4 + 10x - 1 = 141
23x + 3= 141
23x = 136
x = 136/23 = 6
~~~~~~~~~~~~~~~
pqs = 13x + 4 = 13(6) + 4 = 78+4 = 82
sqr = 10x - 1 = 10(6)-1 = 60 - 1 = 59
Answer:
x = 6
Angle PQS is 82
Angle SQR is 59
Step-by-step explanation:
13x + 4 + 10x - 1 = 141
Group like terms : 23x + 3 = 141
Subtract 3 from both sides to get 23x = 138
Divide both sides by 23 to get x = 6
Angle PQS: Plug 6 into x for 13x + 4 = 13 (6) + 4 = 82
Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59
Work out the mean for the data set below:
603,607
X + 1 by X is polymer or not, polymer means ,write its degrees?
If x=3 ,y=4 than what is the value?
PLEASE HELP ASAP 30 POINTS
Answer:
I don't know how to do please let me I will try solve the question
Scarlett made a profit of $250.00 with her mobile car wash company
Not enough information to solve..... Please make your question more clear
Doanh nghiệp bán trả góp 1 bất động sản có giá thanh toán là 32.000trđ . Thu điều cả vốn lẫn lãi trong 10 năm với lãi suất trả chậm là 10% / năm . Xác định số vốn phải thu ở năm thứ 6 ?
Answer:
Step-by-step explanation:
Can someone help me with this math homework please!
Answer:
(-3,-6) and (-3,2)
Step-by-step explanation:
A line with an undefined slope is vertical. In this case it must have x coordinates equal to -3
I only need the answer
Answer:
1
Step-by-step explanation:
The given equation of the function is y = -a·(x - h)² + 1
The positive constants of the equation = a, and h
The points the function crosses the x-axis = 2, and 4
Where the function crosses the x-axis, y = 0, and x = 2, and 4, therefore, when x = 2, we have;
y = 0 = -a·(2 - h)² + 1
When x = 4, we have;
0 = -a·(4 - h)² + 1
-a·(2 - h)² + 1 = -a·(4 - h)² + 1
-a·(2 - h)² = -a·(4 - h)²
(2 - h)² = (4 - h)²
±(2 - h) = +#±(4 - h)
When
(2 - h) is negative, and (4 - h) is positive, but the same magnitude, we have';
-(2 - h) = +(4 - h)
2·h = 4 + 2 = 6
h = 3
0 = -a·(4 - h)² + 1 = -a·(4 - 3)² + 1 = -a + 1
Therefore, a = 1
Which number line plots the integers –6, –2, and 5?
A number line going from negative 6 to positive 6. Points are at negative 6, negative 5, negative 2.
A number line going from negative 6 to positive 6. Points are at 2, 5, 6.
A number line going from negative 6 to positive 6. Points are at negative 5, 2, 6.
A number line going from negative 6 to positive 6. Points are at negative 6, negative 2, 5.
Answer:
Một trục số đi từ âm 6 đến dương 6. Các điểm ở âm 6, âm 2, 5.
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Mọi người giúp em với
Answer:
bka bla bla bla sorry I newbie
in a shipment of 10,000 headlights, 5% are defective. what is the ratio of defective headlights to non-defective headlights
Answer:
19:1
Step-by-step explanation:
There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1
The ratio of defective headlights to non-defective headlights will be 19:1.
What is the percentage?The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.
In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.
There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.
The ratio will be calculated as below:-
Ratio = 9500:500
Ratio = 19:1
Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.
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which one is the correct answer
Answer:
B.
Step-by-step explanation:
2x - 31 = - 2x - 314x = 0x = 0Other equations don't have any value of x.
Answer:
[tex]2x-31=-2x-31[/tex]Because if you see.. The component of x will get canceled in each of the other 3 options.. ( 2x - 2x) which means no solution.. In option B.. 2x + 2x will give 4x..= 31-31 = 0..
-------------------------
Hope it helps...
Have a great day!!
What is the equation of this circle?
Answer:
(x-3)^2+y^2=8
Step-by-step explanation:
I'm going to go ahead and assume the center is (3,0). The radius can be found by computing the distance from the center, (3,0), to a point on the circle, (5,-2).
The distance between two points is calculated by doing sqrt((distance between x's)^2+(distance between y's)^2).
The distance between our x's is 2.
The distance between our y's is 2.
The square of each then is 4 and 4 respectively.
So we have the distance is sqrt(4+4)=sqrt(8).
The radius is sqrt(8).
The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and r is radius.
If r=sqrt(8), then r^2=8.
(h,k)=(3,0)
(x-h)^2+(y-k)^2=r^2
(x-3)^2+(y-0)^2=8
(x-3)^2+y^2=8
Please help! The answer isn’t 36!
Find the value of the expression:
Answer:
3.6
Step-by-step explanation:
Hi there!
We are given this expression:
.6√36 (.6*√36)
And we want to find the value of it
.6 can be re-written as 0.6
In that case,
0.6*√36
First, simplify what's under the radical: √36, which is equal to 6 (6*6=36)
The expression then becomes:
0.6*6
Multiply those numbers together
0.6*6=3.6
Hope this helps!
Which values of a and b in the exponential function y = a times b Superscript x would result in the following graph? On a coordinate plane, a curve approaches the x-axis in quadrant 3 and then decreases down through (0, negative 3) to quadrant 4. a. a = -3, b = 2 c. a = 3, b = 2 b. a = -1, b = 3 d. a = 2, b = -3 Please select the best answer from the choices provided A B C D
Answer:
[tex]a =-3[/tex] [tex]b =2[/tex]
Step-by-step explanation:
Given
[tex]y = ab^x[/tex]
[tex](x_1,y_1) = (0,-3)[/tex]
Required
Find a and b
Substitute [tex](x_1,y_1) = (0,-3)[/tex] for x and y in [tex]y = ab^x[/tex]
[tex]-3 = ab^0[/tex]
[tex]-3 = a * 1[/tex]
[tex]-3 = a[/tex]
Rewrite as:
[tex]a =-3[/tex]
The above implies that (a) is correct;
Hence:
[tex]a =-3[/tex] [tex]b =2[/tex]
So, the equation is:
[tex]y = -3(2)^x[/tex]
Answer: a=-3 b=2
Step-by-step explanation:
1. Take a look at the steps below for solving the
equation 4(3 - 2x) = -20.
Step 1: 4(3 - 2x) = -20
Step 2: 12 - 8x = -20
Step 3: 12-8x - 12 = -20 - 12
Step 4: - 8x + 0 = -32
Step 5:
- 8x = -32
1
Step 6. - 8x
-1
8
8
Step 7:
x = 4
1
= -32
Which property justifies the work between ...
A. Step 1 and Step 2?
B. Step 2 and Step 3?
C. Step 3 and Step 4?
D. Step 4 and Step 5?
E. Step 5 and Step 6?
F. Step 6 and Step 7?
Answer:
x= 1
Step-by-step explanation:
Work is shown in the picture
please help!!!!!!!!!!!
sin pi/3 __ __ pi/6 = 1/2(sin pi/2 + sin pi/6)
I think I’m just supposed to fill in the blank? (question off of a p e x) please give explanation!
Notice that
• π/2 = π/3 + π/6
• π/6 = π/3 - π/6
Recall the angle sum identities for sine:
sin(x + y) = sin(x) cos(y) + cos(x) sin(y)
sin(x - y) = sin(x) cos(y) - cos(x) sin(y)
By adding these together, we get
sin(x + y) + sin(x - y) = 2 sin(x) cos(y)
==> sin(x) cos(y) = 1/2 (sin(x + y) + sin(x - y))
Now take x = π/3 and y = π/6 :
sin(π/3) cos(π/6) = 1/2 (sin(π/2) + sin(π/6))
So the blank should be filled with cos.
