Answer:
0.4 meters per second I believe
You have three flowers. You give
each a different amount of
water. What is one of the
possible controlled variables?
Answer:
flowers
Explanation:
flowers cannot change
show that Newton's first law is the special case of Newton's second law of motion
Please find attached photograph for your answer. Please do comment whether it is useful or not.
Convert 4 centimeters to meters using dimensional analysis and scientific notation. Please go step by step as I am having difficulty with this subject.
Answer:
[tex]thank \: you[/tex]
Define measurement What problems might me face it measurement systems were not established? (1+2=3)
Answer:
The process of comparing unknown quantities with known quantities is called measurement .If it measurement system were not established ,then there may create lots of problem such as: unequal measure ,anyone can get more ,or anyone can get less mass ,so on .
What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a
velocity of 3 m/s?
What’s the answer
Answer:
kinetic energy = 1/2mv²
k.E =1/2 X 0.5 X 3²
k.e = 9/4
K.E = 2.25j
A car traveling at 90 m/s can stop in a distance of 110 m. What is the magnitude of the cars acceleration as it slows down?
I think I have already answer this question. Anyways please do let me know whether it is useful or not
When you put water in the ice tray in the freezer, water becomes ice. Ice is more ordered than water. Is this a violation of Second Law of Thermodynamics
Answer:
No because the heat that moved out of the water to make ice caused an even greater disorder in the environment around it.
Explanation:
What phase of matter has the highest energy?
Answer:
plasma is the state with the highest energy level.
Any two importance of measurement
Answer:
to sell and to buy
Explanation:
measurement is a comparison between unknown quantity with a known quantity
A wheel of mass 4kg is pulled up a plane inclined at 30° to the horizontal by a force of 45N applied to the axle and parallel to the plane. If the wheel has a radius of 0.5m and the moment of inertia 0.5kgm?, calculate the translational velocity acquired after travelling 12m up the plane, assuming the wheel is initially at rest (6 marks)
Answer:
v = 10 m/s
Explanation:
Let's assume the wheel does not slip as it accelerates.
Energy theory is more straightforward than kinematics in my opinion.
Work done on the wheel
W = Fd = 45(12) = 540 J
Some is converted to potential energy
PE = mgh = 4(9.8)12sin30 = 235.2 J
As there is no friction mentioned, the remainder is kinetic energy
KE = 540 - 235.2 = 304.8 J
KE = ½mv² + ½Iω²
ω = v/R
KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²
v = √(2KE / (m + I/R²))
v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6
v = 10.07968...
What is the displacement of a car traveling 14 km North on I985 then 20 km South on I985?
Displacement = (14-20) Km = -6 Km
The displacement of a car is -6 Km South
Bella makes the 2.5m distance to her food bowl in 9.1 seconds. What is her average velocity?
Average Velocity=Total Distance/Total Time
[tex]\\ \sf\longmapsto \dfrac{2.5}{9.1}[/tex]
[tex]\\ \sf\longmapsto 0.3m/s[/tex]
What type of light does this light bulb produce most (i.e. at what wavelength does the spectrum have maximum intensity)?
Hint: Refer to the image of the electromagnetic spectrum at the beginning of the assignment.
Infrared light
Red visible light
Violet visible light
Ultraviolet light
Answer:
infrared light
Explanation:
infrared light
I NEED THE ANSWER TO PASS SO I CAN GET MY PHONE BACK HELPPPPPPPPPPPPPP
Answer:
it would be c.
Explanation:
starts at zero and isn't a straight shot up
Convert the following in to SI units without changing its values
a. 4000 g
b. 2.4 km
Plz help. I will make you a brailyest and 10,000 $
Answer:
4000g
Thank You
Hope it helps
Answer:
a 4 kg
b 2400 meter
Explanation:
International system of units Sl
the units are
kelvin for temperatures
meter for distance
Ampere for electric current
Second for time
Kg for mass
...etc
How do we know how much
gravitational force objects have?
Answer:
With a force of 1 Newton, an object weighing 100 grams is dragged towards the planet's center. On Earth, an item with a mass of 100 grams has a gravitational pull of only 1%, or about kg.
Explanation:
i hope this helps
A rocket blasts off and accelerates upward from rest with a rate of 15.4 m/s2. Calculate the
distance it will rise in 22 seconds.
NEED HELP!!
From question we have,
Inital velocity(u) = 0Accleration(a) = 15.4 m/s²Time taken(t) = 22 secNow, from the second equation of motion;
s = ut + ½at² { where s = distance covered }Just put all the values provided in the question, in this equation;
s = ut + ½at²s = (0 × 22) + ½ × 15.4 × 22 × 22s = 15.4 × 11 × 22s = 15.4 × 242s = 3726.8 mTherefore, distance it will rise in 22 seconds will be 3726.8m
Convert the following in to SI units without changing its values
A. 4000 g
b. 2.4 km
A. The S.I unit of mass is kg . therefore we have to convert 4000g into kg from gram
i.e 4000g = 4 kg
B. The S.I unit of length is meter. so we have to convert 2.4 km into meters,
i.e 2.4 km = 2400 m
#A
[tex]\boxed{\sf 1kg=1000g}[/tex]
[tex]\\ \sf\longmapsto 4000[/tex]
[tex]\\ \sf\longmapsto \dfrac{4000}{1000}[/tex]
[tex]\\ \sf\longmapsto 4kg[/tex]
#B
[tex]\boxed{\sf 1km=1000m}[/tex]
[tex]\\ \sf\longmapsto 2.4km=2.4(1000)[/tex]
[tex]\\ \sf\longmapsto 2400m[/tex]
A car is accelerating at 6 m/s2. How long would it take the car to go 12 m/s faster?
Answer:
2 seconds
Explanation:
Each second, it increases its speed by 6 m/s, so it will take 2 seconds for the speed to increase by 12 m/s.
Add these two velocity vectors to find the magnitude of their resultant vector.
5.8 meters/seconds + 1.2 meters/seconds
The magnitude of their resultant vector is 4.6 meters/seconds
Since we are to add the velocity vectors in order to find the magnitude of their resultant vector.
Hence:
Resultant vector magnitude=5.8 meters/seconds + (1.2 meters/seconds)
Resultant vector magnitude=5.8 meters/seconds-1.2 meters/seconds
Resultant vector magnitude 4.6 meters/seconds
Inconclusion The magnitude of their resultant vector is 4.6 meters/seconds
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What is difference between simple microscope and compound microscope
Answer:
simple microscope - a codenser lens is not required I simple microscopes .
compound microscope- the condenser lens is embedded in compound microscopes for adjusting the intensity of the light to magnify the object.
Explanation:
hope this helps you
mrk me brainiliest
Write any three condition required for nuclear fussion that are found in the sun.
Answer:
High pressure squeezes the hydrogen atoms together. They must be within 1x10-15 meters of each other to fuse. The sun uses its mass and the force of gravity to squeeze hydrogen atoms together in its core. We must squeeze hydrogen atoms together by using intense magnetic fields, powerful lasers or ion beams.
explain 3points to be taken into consideration while measuring the length of a body
Answer:
Y T and v
Explanation:
Bobo, the clown, wants to set the world record for the furthest range traveled by a clown shot out of a cannon. Write a sentence describing the cannon that Bobo would need to use to accomplish this feat. Be sure to include the necessary initial velocity and the required angle of the cannon. Score: 0 / 1
In the human cannonball act makes use of of a special type of "cannon" that more safely ejects a person who acts as the "cannonball"
The world record for the longest flight by a human cannonball is approximately 194 feet and therefore the human cannon catapult that Bobo would need is one that would be able to propel him with an initial velocity of more than 120 kilometer per hour (more than the speed of the current record holder) with the cannon directed at an angle 45 degrees above the horizonal
The reason the values given above are correct is as follows:
The world record of the furthest range of the human cannonball is 193 ft. 8.8 inches. The maximum claim for the furthest range of a human cannonball is 200 ft. 4 in. Therefore, to safely set the world record would be to reach a range of 194 feet
The speed with which the world record was accomplished (120 km/jhr) should be expected to be exceeded given, horizontal speed in free fall motion is constant (decreasing in the presence of drag), and the conditions are likely to be more or less similar
In order to reach the furthest range, R, at the possible speed, the angle of inclination of the "cannon" required is 45°, according to the range formula, which is given as follows;
[tex]Range, \ R = \dfrac{v^2 \times sin(2\cdot \theta)}{g}[/tex]
The maximum range is given where θ = 45, such that sin(2·θ) = sin(90°) = 1
A further range than the world record van be obtained using the above values
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A man walks his dog on a very straight path in a park. He can walk back and forth as slow or fast as he wants to, but he has to stay on the path. Which of the following statements is correct for an arbitrary time interval?
a. His average speed can be greater than the magnitude of his average velocity.
b. His average speed can be less than the magnitude of his average velocity.
c. Since he is walking along a straight path, his average acceleration must be zero.
d. His average velocity must be zero.
Answer:
a. His average speed can be greater than the magnitude of his average velocity.
Explanation:
As speed is distance traveled over time traveled, this is always greater than zero if he has moved at all.
velocity is displacement over time traveled. As the man is allowed to return to the point of origin, his velocity at some point might be zero while his speed is positive.
2. Determine the units of the quantity described by each of the following
combinations of units:
a. kg (m/s) (1/s)
b. (kg/s) (m/s)
c. (kg/s) (m/s)
d. (kg/s) (m/s)
We have that the unit of the quantities are described
a.kg (m/s) (1/s)=Newton
b. (kg/s) (m/s^2)=Newton
c. (kg/s) (m/s)^2=Newton
d. (kg/s) (m/s)=Newton
From the question we are give the units
a.kg (m/s) (1/s)
b. (kg/s) (m/s^2)
c. (kg/s) (m/s)^2
d. (kg/s) (m/s)
a)
Generally
kg (m/s) (1/s) is Represented as Newton
Where Newton is the unit Force and Weight
b)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
c)
kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
d)
Generally
(kg/s) (m/s) is the unit representation of Newton
Therefore
Newton
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The following are dimensions of various physical parameters that will be discussed later on in the text. Here [L], [T], and [M] denote, respectively, dimensions of length, time, and mass.
Dimension Dimension
Distance (x) [L] Acceleration (a) [L]/[T]2
Time (t) [T] Force (F) [M][L]/[T]2
Mass (m) [M] Energy (E) [M][L]2/[T]2
Speed (v) [L]/[T]
Which of the following equations are dimensionally correct?
a. F = ma
b. x = 2 at2
c. E = 1/2 max
d. E = max
e. F = ?Fx/m
Dimentional analysis is very important in physics, because it allows finding errors in equations. We find that the following true equations
a) F= m a
b) x = 2 a t²
c) E = [tex]\frac{1}{2} }\ m \ a \ x[/tex]
d) E = m a x
The fundamental units in mechanics are;
the length [L] whose unit is the meter
The time [T] that has the second as a unit
The mass [M] with fundamental unit the kilogram (kg)
all other quantities are derived from these three fundamental units, for example velocity is
v = x / t
we replace the units
[v] = [L] / [T]
so the units of velocity are the distance between time.
This exercise uses the units of various quantities and asks to find if the equations are dimensionally correct.
Let's substitute the units in each expression
a) F = m a
[M] [L] / [[T] ² = [M] [L] / [T] ²
the two sides of the expression are equal therefore the equation is correct
b) x = 2 a t²
scalar quantities have no units
[L] = [L] / [T] ² [T] ²
[L] = [L]
the two sides are equal, therefore the equation is correct
c) E = ½ m a x
[M] [L] ² [T] ² = [M] [L] [T] ² [L]
[M] [L] ² [T] ² = [M] [L] ² [T] ²
the two sides are equal the equation is correct
d) E = m a x
since scalar quantities have no units, this expression is equivalent to the expression in part c, therefore it is correct
e) F = F x / m
[M] [L] / [T] ² = [M] [L] / [T] ² [L] / [M]
[M] [L] / [T] ² = [L] ² / [T] ²
the two sides are different so the equation is false
In the dimensional analysis we find that expressions are true a, b, c, d and we see that the expression e is false
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An object is launched at a 60 degree angle with an initial velocity of 100
m/s. What is the objects height? How long is the object in the air? What is
the objects's range (distance)? *
PLS HELP QUICK LOL
Answer:
Explanation:
The first question asks for the object's height. That is a y-dimension thing so we will use the one-dimensional formula:
[tex]v^2=v_0^2+2a[/tex]Δx and we are looking for delta x, which is the displacement of the object (here, the height since displacement in the y-dimension is height). Before we do that, though, we need to know the initial upwards velocity, which is found in:
[tex]v_{0y}=100sin(60)\\v_{0y}=90\frac{m}{s}[/tex]
And we also have to know from previous physics experience that the final velocity of an object at its max height is 0. Filling in:
[tex]0=(90)^2+2(-9.8)[/tex]Δx
[tex]0=8000-20[/tex]Δx and
-8000 = -20Δx so
Δx = 400 m
Now for the time it was in the air...we will use the simple equation
[tex]v=v_0+at\\0=90-9.8t\\-90=-9.8t\\t=9[/tex]
So the object is in the air for 9 seconds. Now we go to the other dimension, the x-dimension, to find out how far it goes horizontally. We will use the equation:
Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] but first we have to find the horizontal velocity, which is NOT the same as the upwards velocity.
[tex]v_{0x}=100cos(60)\\v_{0x}=50\frac{m}{s}[/tex]
And another thing we need to know prior to solving problems like this is that the acceleration in the x-dimension is ALWAYS 0. Filling in the equation:
Δx = [tex]50(9)+\frac{1}{2}(0)(9)^2[/tex]
Δx = 500 m
If it takes Tanya 9.4 hours to get to her cousin's house while driving an average of 40 mph, how far away does her
cousin live?
Answer:
376 miles
Explanation:
speed = distance / time
therefore distance = speed * time
distance = 40 miles/hr * 9.4 hr
then
distance = 375 miles
Identify the parts of the body based on the medical terminology given:
1. mr. heart describes pain that is midline, superior to the chest but inferior to the chin.
2. miss triangle says that she has a ‘tweak’ that is superior to the waist, inferior to the breast bone, lateral to the umbilicus on the left side of the body on the anterior surface.
3. mr. square states that he has pulled a muscle, inferior to the buttocks, superior to the knee, medial to the right side of the body on the posterior surface.
4. miss circle complains of a sharp pain inferior to her ears, superior to the scapula at midline on the posterior side of her body.
5. mr. x says that he has numbness and tingling on the anterior side of his left arm, distal to the wrist.
6. mrs. diamond describes a throbbing pain on the posterior side of her body, inferior to her shoulder blades and superior to her waist.
7. miss arrow states that she has had a pain on the left side of her body, superior to her neck and inferior to her forehead, lateral to her nose.
8. mr. teardrop says that he has been bitten by a spider lateral to his umbilicus on the anterior aspect of his body, superior to his hip on the right side of his body.
9. miss eight describes a burning sensation on the posterior side of her body, lateral to the spine on the left side of the body inferior to the shoulder blade, inferior to the waist but anterior to the knee.
10. mr. four shows you a deep wound on the anterior side of his body, medial to the left hip, lateral to the umbilicus, inferior to the collarbone and anterior to the waist.
Answer:
1. Right hypochondriac region (upper, right).
2. Epigastric region (upper, middle).
3. Left hypochondriac region (upper, left).
4. Right lumbar region (middle, right).
5. Umbilical region (centre).
6. Left lumbar region (middle, left).
7. Right iliac region (lower, right).
8. Hypogastric region (lower, middle).
9. Left iliac region (lower, left).
Explanation:
1. Right hypochondriac region (upper, right)- Liver, gallbladder, right kidney, small intestine.
2. Epigastric region (upper, middle)- stomach, liver, pancreas, duodenum, spleen, adrenal glands
3. Left hypochondriac region (upper, left)- Spleen, colon, left kidney, pancreas
4. Right lumbar region (middle, right)- Gallbladder, liver, right colon
5. Umbilical region (centre)- Umbilicus, parts of the small intestine, duodenum
6. Left lumbar region (middle, left)- Descending colon and left kidney
7. Right iliac region (lower, right)- Appendix and cecum
8. Hypogastric region (lower, middle)- Bladder, reproductive organs, sigmoid colon
9. Left iliac region (lower, left)- Descending and sigmoid colon.
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