please show me step by step how to simplify this equation​

Answer:

Step-by-step explanation:

I assume that you mean y = x²/(x²+1), not y = x²/x²+1.

x²+1 = 0

x² = -1

x = ±√(-1) = ±i

deleted: deleted by user

Answer:

1716 ways

Step-by-step explanation:

Given that :

Number of entrants = 13

The number of ways of attaining first, second and third position :

The number of ways of attaining first ; only 1 person can be first ;

Using permutation :

nPr = n! ÷(n-r)!

13P1 = 13! ÷ 12! = 13

Second position :

We have 12 entrants left :

nPr = n! ÷(n-r)!

12P1 = 12! ÷ 11! = 12

Third position :

We have 11 entrants left :

nPr = n! ÷(n-r)!

11P1 = 11! ÷ 10! = 11

Hence, Number of ways = (13 * 12 * 11) = 1716 ways

9514 1404 393

Answer:

  $500

Step-by-step explanation:

Bruno's fraction of the total contribution was ...

  Bruno / Total = $20/($25 +20 +35) = 20/80 = 1/4

Then Bruno's share of the earnings is this same fraction, so is ...

  (1/4) × ($2000) = $500

Answer:

Step-by-step explanation:

[tex]2(x-2)^2=8(7+y)\\2(x-2)^2=56+8y \Rightarrow y={1\over{8}}[2(x-2)^2-56]={1\over{4}}(x-2)^2-7\\finally\\y={1\over{4}}(x-2)^2-7\\let ~change~x~and~y\\x={1\over{4}}(y-2)^2-7\\x+7={1\over{4}}(y-2)^2\\4(x+7)=(y-2)^2\\y-2=\pm\sqrt{4(x+7)}\\\\y=2\pm\sqrt{4x+28}[/tex]

Answer:

y = 26.3x² - 116.9x + 109.6

Step-by-step explanation:

Given the data ;

Year Period Users (Millions)

2004 1 1

2005 2 5

2006 3 11

2007 4 58

2008 5 145

2009 6 359

2010 7 607

2011 8 846

A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :

y = Ax² + Bx + C

y = 26.3x² - 116.9x + 109.6

Answer:

[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}][/tex]

when:

[tex]|x|<\frac{1}{2}[/tex]

Step-by-step explanation:

In order to solve this problem, we must begin by splitting the function into its partial fractions, so we must first factor the denominator.

[tex]\frac{x+6}{2x^2-9x+5}=\frac{x+6}{(2x+1)(x-5)}[/tex]

Next, we can build our partial fractions, like this:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]

we can then add the two fraction on the right to get:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A(x-5)+B(2x+1)}{(2x+1)(x-5)}[/tex]

Since we need this equation to be equivalent, we can get rid of the denominators and set the numerators equal to each other, so we get:

[tex]x+6=A(x-5)+B(2x+1)[/tex]

and expand:

[tex]x+6=Ax-5A+2Bx+B[/tex]

we can now group the terms so we get:

[tex]x+6=Ax+2Bx-5A+B[/tex]

[tex]x+6=(Ax+2Bx)+(-5A+B)[/tex]

and factor:

[tex]x+6=(A+2B)x+(-5A+B)[/tex]

so we can now build a system of equations:

A+2B=1

-5A+B=6

and solve simultaneously, this one can be solved by substitution, so we get>

A=1-2B

-5(1-2B)+B=6

-5+10B+B=6

11B=11

B=1

A=1-2(1)

A=-1

So we can use these values to build our partial fractions:

[tex]\frac{x+6}{(2x+1)(x-5)}=\frac{A}{2x+1}+\frac{B}{x-5}[/tex]

[tex]\frac{x+6}{(2x+1)(x-5)}=-\frac{1}{2x+1}+\frac{1}{x-5}[/tex]

and we can now use the partial fractions to build our series. Let's start with the first fraction:

[tex]-\frac{1}{2x+1}[/tex]

We can rewrite this fraction as:

[tex]-\frac{1}{1-(-2x)}[/tex]

We can now use the following rule to build our power fraction:

[tex]\sum_{n=0}^{\infty} ar^{n} = \frac{a}{1-r}[/tex]

when |r|<1

in this case a=1 and r=-2x so:

[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2x)^n[/tex]

or

[tex]-\frac{1}{1-(-2x)}=-\sum_{n=0}^{\infty} (-2)^{n} x^{n}[/tex]

for: |-2x|<1

or: [tex] |x|<\frac{1}{2} [/tex]

Next, we can work with the second fraction:

[tex]\frac{1}{x-5}[/tex]

On which we can factor a -5 out so we get:

[tex]-\frac{1}{5(1-\frac{x}{5})}[/tex]

In this case: a=-1/5 and r=x/5

so our series will look like this:

[tex]-\frac{1}{5(1-\frac{x}{5})}=-\frac{1}{5}\sum_{n=0}^{\infty} (\frac{x}{5})^n[/tex]

Which can be simplified to:

[tex]-\frac{1}{5(1-\frac{x}{5})}=-\sum_{n=0}^{\infty} \frac{x^n}{5^(n+1)}[/tex]

when:

[tex]|\frac{x}{5}|<1[/tex]

or

|x|<5

So we can now put all the series together to get:

[tex]\frac{x+6}{2x^2-9x+5}=-\sum_{n=0}^{\infty} [(-2)^{n}x^{n} + \frac{x^{n}}{5^{n+1}}}[/tex]

when:

[tex]|x|<\frac{1}{2}[/tex]

We use the smallest interval of convergence for x since that's the one the whole series will be defined for.

9514 1404 393

Answer:

  1,222,200

Step-by-step explanation:

A search using a computer program found ...

  5432 × 225 = 1,222,200

__

1000 mod 225 = 100

4 × 225 = 900

This suggests that if we have some number of thousands whose digits total 9, that we will have the number of interest. Of course, we can add 200 to some number of thousands with a digit total of 7. The smallest such digit total will be had with the number 1222 using the specified digits {0, 1, 2}. This gives rise to the result above: 1222×1000 +200 = 1,222,200. It also explains why moving the 1 to the right will also give a multiple of 225.

9514 1404 393

Answer:

  (c)  f(t)=21,000(0.85)^t

Step-by-step explanation:

Each year, the value is multiplied by 1-15% = 85% = 0.85. This is correctly shown in the function ...

  f(t)=21,000(0.85)^t

Step-by-step explanation:

21.

22.

23.

hope it helps

Answer:

21. (x+7)(x+3)

22. (x-7)(x+3)

23. 12

Step-by-step explanation:

X^2+10x+21

(X+7)(x+3)

(We know that 7*3 is equal to 21 and that 7+3= 10)

Now try the same thing for 22.

(X-7)(X+5)

(-7*5= -35 . and -7+5=-2)

23. Use SPOE to get like terms to one side:

-7x=-84

Then use DPOE to find the value of X

x=12

Answer: hello your question was poorly written but i was able to the get missing parts online which enabled me resolve your question

answer:

a) a = 0.1096

b) 1.89 watts

Step-by-step explanation:

Std of output voltage = 0.25 volt

H0 : μ = 5 volts

Ha : μ ≠ 5 volts

n = 16

a) Acceptance region = 4.9 ≤ X ≤ 5.1  

Determine the value of a

value of a = 0.0548 + 0.0548

                 = 0.1096

attached below is the reaming solution

note : a is a type 1 error

b) power of test

True mean output voltage = 5.1 volts

P = - 1.89 watts

power cant be negative hence the power of the test  = 1.89 watts

Answer:

A

=

w

l

d

=

w

2

+

l

2

Solving for

d

d

=

l

2

+

(

A

l

)

2

=

11

2

+

(

110

11

)

2

≈

14.86607

The length of the diagonal of the rectangle is 14.9 units.

A diagonal is the longest line that divides a plane shape into two halves.

To calculate the diagonal of the rectangle, we use Pythagoras theorem.

Formula:

Where:

make w the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Finally, to calculate the diagonal of the rectangle, we use the formula below

Given:

Substitute these values into equation 3

Hence, the length of the diagonal of the rectangle is 14.9 units.

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Answer:

10

Step-by-step explanation:

10-7 do it yourself and don't vheat

Answer:

x = 20

Step-by-step explanation:

 3x -10 = 2x +10

x = 20

Step-by-step explanation:

always Pythagoras with the coordinate differences as sides and the distance the Hypotenuse.

c² = (2/3 - 5/3)² + (-10/9 - -7/9)² = (-3/3)² + (-10/9 + 7/9)² =

= (-1)² + (-3/9)² = 1 + (-1/3)² = 1 + 1/9 = 10/9

c = sqrt(10)/3

Answer:

Step-by-step explanation:

Point 1  ([tex]\frac{2}{3}[/tex] , [tex]\frac{-10}{9}[/tex])   in the form (x1,y1)

Point 2 ( [tex]\frac{5}{3}[/tex] , [tex]\frac{-7}{9}[/tex])  in the form (x2,y2)

use the distance formula

dist = sqrt[ (x2-x1)^2 + (y2-y1)^2 ]

dist = sqrt [ [tex]\frac{5}{3}[/tex] -[tex]\frac{2}{3}[/tex])^2 + (  [tex]\frac{-7}{9}[/tex] - ( [tex]\frac{-10}{9}[/tex] ) )^2 ]

dist = sqrt [ ([tex]\frac{3}{3}[/tex])^2 + ([tex]\frac{3}{9}[/tex])^2 ]

dist = sqrt [  1 + ([tex]\frac{1}{3}[/tex])^2 ]

dist = sqrt [  [tex]\frac{9}{9}[/tex] + [tex]\frac{1}{9}[/tex] ]

dist = [tex]\sqrt{\frac{10}{9} }[/tex]

dist = [tex]\sqrt{10}[/tex] *[tex]\sqrt{\frac{1}{9} }[/tex]

dist = [tex]\sqrt{10}[/tex]  * [tex]\frac{1}{3}[/tex]

dist = [tex]\frac{\sqrt{10} }{3}[/tex]

carry on learning

Answer:

- 850

3

Step-by-step explanation:

650 - 700 - 800

650 - 1500

- 850

25 - 45 + 23

- 20 + 23

3

Answer:

3cm/s

Step-by-step explanation:

Area of a square is expressed as:

A = L²

Rate of change of area is expressed as:

dA/dt = dA/dL•dL/dt

Given that

dA/dt = 24cm²/s

L = 4cm

Required

dL/dt

Since dA/dl = 2L

dA/dl = 2(4)

dA/dl = 8cm

Subatitute the given values into the formula

24 = 8 dL/dt

dL/dt = 24/8

dL/dt = 3cm/s

Answer:

68 i think..........

Step-by-step explanation:

(⌒_⌒;)

Answer:

16. false

17. True

18. True

19. True

20. false

Step-by-step explanation:

16. all terms are expressions of weather - except for cold snow. "snowfall" would be the weather condition. "snow" itself is the accumulated mass of snowflakes on the ground.

17. that is simply true. there is nothing really to explain.

18. the same as 17. that is the definition of weather.

19. yes, that is part of the explanation of the difference between weather and climate.

20. South North is NOT a direction. it kind of contradicts itself. and what is between South and North ? East and West. so, even from that perspective it is not clear.

overall, what kind of math question is that ? that is more for geography, Earth science, or meteorology or something like this.

Answer:

I think the choose (B)

5x/x + 3/x

Answer:

I thinkchoose no.3

5x+3

5x+3x

Answer:

The function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Step-by-step explanation:

Firstly, we integrate the function by algebraic substitution:

[tex]\int {x^{2}\cdot e^{2\cdot x^{3}}} \, dx[/tex] (1)

If [tex]u = 2\cdot x^{3}[/tex] and [tex]du = 6\cdot x^{2} dx[/tex], then:

[tex]\int {e^{2\cdot x^{3}}\cdot x^{2}} \, dx[/tex]

[tex]\frac{1}{6}\int {e^{u}} \, du[/tex]

[tex]f(u) = \frac{1}{6}\cdot e^{u} + C[/tex]

[tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} + C[/tex]

Where [tex]C[/tex] is the integration constant.

If [tex]x = 0[/tex] and [tex]f(0) = 0[/tex], then the integration constant is:

[tex]\frac{1}{6}\cdot e^{2\cdot 0^{3}} + C= 0[/tex]

[tex]C = -\frac{1}{6}[/tex]

Hence, the function that passes through (0, 0) is [tex]f(x) = \frac{1}{6}\cdot e^{2\cdot x^{3}} - \frac{1}{6}[/tex].

Answer:

ACF

Step-by-step explanation:

angles must be equal since the triangles are similar

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. The statement that are correct are x=35, y = 55, and z =90.

Two figures are known as similar figures if there the corresponding angles are equal and the corresponding sider is in ratio. It is denoted by the symbol "~".

Given the ΔPQR is similar to ΔSTU, therefore, the statements that are correct about the two triangles are,

∠P = ∠S = x = 35°

∠Q = ∠T = y

∠R = ∠U = z = 55°

Since the sum of all the angles of a triangle is equal to 180°. For ΔPQR we can write,

∠P + ∠Q + ∠R = 180°

°35 + y + 55° = 180°

y = 180° - 55° - 35°

y = 90°

Hence, the statement that are correct are x=35, y = 55, and z =90.

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Answer:

cube(v=l×l×l)

cylinder (v= πr^2h)

cone(v=1/3πr^2h)

rectangular prism (v= area of base×lenght)

pyramid (v=1/3×area of base×h)

Step-by-step explanation:

Cube:-a^3

Cuboid:-lbh

Cylinder :-pi r^2h

Cone:-1/3pi r^2h

Answer:

0.0498

Step-by-step explanation:

In this question,

x~exponential

we have

mean = 1/λ = 8

from here we cross multiply, when we do

such that

λ = 1/8

probability of x functioning in 8 months

= e^-λx

= e^-1/8x12

= e^-1.5

= 0.2231

i got this value through the use of a scientific calculator

then the probability that these two are greater than 12

= 0.2231²

= 0.04977

= approximately 0.0498

therefore the probability that both components are functioning in 12 months is 0.0498

Answer:

1) any number that is greater than ten is considered an integer bigger than ten: for example, 11, 12, 100, 1000000, etc.

2) any number that is smaller than ten is considered an integer smaller than ten: for example, 9, 8, 7, -100, -100000, etc.

3) any number that is bigger than zero is considered an integer bigger than ten: for example, 1, 2, 10, 100, 100000, etc.

4) any number that is smaller than zero is considered an integer smaller than zero: for example, -1, -2, -3, -10, -100000, etc.

Step-by-step explanation:

An integer is any whole number

Answer:

Step-by-step explanation:

integer bigger than 10 is 11

integer smaller than 10 is 9

integer greater than 0 is 1.

integer smaller than 0 is -1.

Answer:

1-g

2-b

3-a

4-i

5-f

6-e

7-d

8-c

Answer:

Step-by-step explanation:

A circumcircle can be referred to as a circumscribed circle to a triangle. The steps to follow is stated below:

i. Since the triangle is equilateral, draw the triangle with sides 6.5 cm

ii. Bisect any of its two sides. The two bisecting lines would intersect at center, O, of the triangle.

iii. With the center and either radius  OA, OB or OC, draw a circumscribed circle to the triangle.

The construction is attached to this answer for clarifications.

Answer:

[tex]f(h(xc)) = 2xc-4[/tex]

Step-by-step explanation:

Given

[tex]f(x) = x - 7[/tex]

[tex]h(x) = 2x + 3[/tex]

Required

[tex]f(h(xc))[/tex]

First, calculate h(xc)

If [tex]h(x) = 2x + 3[/tex]

Then

[tex]h(xc) = 2xc + 3[/tex]

Solving further:

[tex]f(x) = x - 7[/tex]

Substitute h(xc) for x

[tex]f(h(xc)) = h(xc) - 7[/tex]

Substitute [tex]h(xc) = 2xc + 3[/tex]

[tex]f(h(xc)) = 2xc + 3 - 7[/tex]

[tex]f(h(xc)) = 2xc-4[/tex]

Answer:

Third Choice - The graph of g(x) is the graph of f(x) compressed vertically by a factor of 3

Step-by-step explanation:

x^2 is the the parent function, so it opens up with a normal compression.

Any number > (greater than) 1 as a coefficient of x will lead to a vertical compression (narrower parabola), while any number < (less than) 1 as a coefficient of x will lead to a vertical stretch (wider parabola).

So, 3x^2 would have to have to be a compressed parabola.

I hope this helps!

Answer:

The graph of g(x) is the graph of f(x) stretched vertically by a factor of 3.

Step-by-step explanation:

A vertical stretch or shrink of a function, kf(x), results from multiplying the entire function by a constant, k.

In this case, g(x) equals 3 times f(x). If k > 1, then the graph will be stretched vertically (along the direction of the y-axis) by a factor of k.

So, the graph of g(x) is the graph of f(x) stretched vertically by a factor of 3.

Answer:1

Step-by-step explanation:2

2

The value of a when the function f(x) = 3|xl is written in the standard form of an absolute value function is 3.

An absolute function is defined as a function which consists of an algebraic expression that is within absolute value symbols.

Here,

The standard form of the absolute value function is written by,

f(x) = a|x|

Given that,

f(x) = 3|x|

Comparing this with the standard form, we get,

a|x| = 3|x|

Therefore, a = 3

Hence,

The value of a when the function f(x) = 3|xl is written in the standard form of an absolute value function is 3.

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Answer:

350

Step-by-step explanation:

400- 80 ( 20% discount)

=320+30(loss)

=350