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complete the square too rewrite the following equation. Identify the centers and radius of the circle. You must show l work and calculations too receive full credit.
x2+2x+y2+4y=20

Answers

Answer 1

Given the equation `x² + 2x + y² + 4y = 20`, complete the square to rewrite it and identify the centers and radius of the circle. The answer to the question is
Completing the square:
[x^2 + 2x + y^2 + 4y = 20\]\[x^2 + 2x + 1 - 1 + y^2 + 4y + 4 - 4 = 20\]\[(x + 1)^2 + (y + 2)^2 = 25\]
This equation is in the standard form of a circle, that is:
[(x - h)^2 + (y - k)^2 = r^2\]
where `(h, k)` is the center of the circle and `r` is its radius.
The equation of the given circle is \[(x + 1)^2 + (y + 2)^2 = 5^2\].
Therefore, the center of the circle is `(-1, -2)` and its radius is `5`.

We are given the equation x² + 2x + y² + 4y = 20 and we need to complete the square to rewrite the equation and identify the center and radius of the circle. We know that the standard form of a circle is (x - h)² + (y - k)² = r².
To transform the equation into the standard form of the circle, we need to complete the square. We can complete the square by adding and subtracting (1 + 4) on the left-hand side of the equation, which is equal to adding and subtracting 5 (5 is half of the coefficient of y) on the right-hand side of the equation.
This gives us:(x² + 2x + 1) - 1 + (y² + 4y + 4) - 4 = 20 + 5 - 5(x + 1)² + (y + 2)² = 25
This simplifies to:(x + 1)² + (y + 2)² = 5², which is in the standard form of a circle.
Therefore, the center of the circle is (-1, -2) and its radius is 5.

In conclusion, we have found that the equation of the given circle is (x + 1)² + (y + 2)² = 5². We have also found that the center of the circle is (-1, -2) an;

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C4 plants are named so because they utilize a four-carbon molecule, oxaloacetate, as their first carbon molecule. C4 plants are special types of plants that have evolved to use a highly efficient carbon fixation pathway in order to maintain their photosynthetic rates in hot, arid environments where water is scarce.

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A thermometer is an instrument used to measure the average kinetic energy in a substance.

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Determine the pH of the resulting solution when the following two solutions are mixed: 20.0 mL of 0.20 M HC2H2O2 and 20.0 mL of 0.10 M NaOH. The value of Ka for HC2H2O2 is 1.8 x 10-5.

Answers

The pH of the resulting solution when 20.0 mL of 0.20 M HC₂H₂O₂and 20.0 mL of 0.10 M NaOH are mixed is 3.07.

Neutralization is a chemical reaction in which acid and base react to form salt and water. Hydrogen (H⁺) ions and hydroxide (OH⁻ ions) react with each other to form water.

The strong acid and strong base neutralization have a pH value of 7.

The balanced equation for the reaction is:

HC₂H₂O₂ + NaOH → NaC₂H₃O₂ + H₂O

Moles of HC₂H₂O₂= concentration × volume = 0.20 M × 0.020 L = 0.004 mol

Moles of NaOH = concentration × volume = 0.10 M × 0.020 L = 0.002 mol

Since HC₂H₂O₂ is a weak acid, it will partially dissociate in water according to the equation:

HC₂H₂O₂ ⇌ H⁺ + C₂H₂O₂⁻

Initial:

HC₂H₂O₂: 0.004 M

H⁺: 0 M

C₂H₂O₂⁻: 0 M

Change:

HC₂H₂O₂: -x M

H⁺: +x M

C₂H₂O₂⁻: +x M

Equilibrium:

HC₂H₂O₂: 0.004 - x M

H⁺: x M

C₂H₂O₂⁻: x M

Ka = [H⁺][ C₂H₂O₂⁻] / [HC₂H₂O₂]

1.8 x 10⁻⁵ = x × x / (0.004 - x)

Since x is small compared to 0.004, so 0.004 - x = 0.004:

1.8 x 10⁻⁵= x² / 0.004

x² = 1.8 x 10⁻⁵ × 0.004

x² = 7.2 x 10⁻⁸

x = 8.49 x 10⁻⁴ M = [H⁺]

pH = -log( 8.49 x 10⁻⁴)

pH = 3.07

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