Answer:
Parallel circuit
Explanation:
A parallel circuit has a direct current allowing it to go back and forth making it have more pathways and loops. if one light bulb goes out the pathways will allow the electricity to still flow inti the other light bulbs.
Problem 3 (a) Assuming the human body (skin temperature 34◦C) to behave like an ideal thermal radiator, find the wavelength where the intensity from the body is a maximum. In what region of the electromagnetic spectrum is radiation with this wavelength? (b) Making whatever (reasonable) assumptions you may need, estimate the power radiated by a typical person isolated from the surroundings. (c) Estimate the radiation power absorbed by a person in a room in which the temperature is 20◦C.
Answer:
Explanation:
a )
We shall apply Wein's displacement law
λm x T = b where λm is wavelength of radiation having maximum intensity
T is absolute temperature of body , and b is a constant
b = 2898 μm-K
T = 273 + 34 = 307 K
λm x 307 = 2898
λm = 9.44 μm
= 9440 nm
It is infrared radiation .
b )
We shall apply Stefan's law of radiation.
E = σA T⁴
E is emitted radiation by body acting as black body , A is surface area , T is absolute temperature of body
σ = 5.67 x 10⁻⁸ J / m²T⁴
Surface area of a typical man's body A = 1.9 m²
T = 273 + 34 = 307 K
Assuming human body as black body
E = 5.67 x 10⁻⁸ x 1.9 x 307⁴ J/s
= 9.57 x 10² J/s
= 957 W .
c )
Radiation absorbed
E = 5.67 x 10⁻⁸ x 1.9 x ( 273 + 20 )⁴ J/s
= 794 W .
Three point charges are fixed in place in a right triangle, as shown in the figure.
What is the magnitude of the electric force on the +1.00-C charge due to the other two charges?
What angle does the force make with the -x-axis? A positive angle is counterclockwise from the -x-axis.
For the three-point charges fixed in a right triangle, we have:
1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. The force does an angle of 21.68° with the x-axis.
1. Magnitude of the electric forceFirst, let's denote the charges as is shown in the picture below:
q₁: is the charge 1 = +0.800 μC = +0.800x10⁻⁶ Cq₂: is the charge 2 = +1.00 μC = +1.00x10⁻⁶ Cq₃: is the charge 3 = -0.600 μC = -0.600x10⁻⁶ C
The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:
[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex] (1)
Where:
[tex]\Sigma\vec{F}_{x}[/tex]: is the sum of the forces acting on the x-axis[tex]\Sigma\vec{F}_{y}[/tex]: is the sum of the forces acting on the y-axisWe can calculate the electrical forces with Coulomb's law:
[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]
Where:
K is the Coulomb's constant = 9.00x10⁹ Nm²/C² q₁ and q₂ are the chargesd is the distance between the charges
Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])
The forces in the x-component are given by:
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex] (2)
Where:
θ: is the angle of the force F₂₁ with the x-axisd₁₂ = z = 9.60 cm = 0.0960 m d₂₃ = xWe can calculate the angle θ with the following trigonometric function:
[tex]sin(\theta) = \frac{y}{z}[/tex]
[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]
To find the distance x (d₂₃), we need to use Pythagoras:
[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]
After entering θ and x (d₂₃) into equation 2, we have:
[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]
[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]
Hence, the x-component of the force is -1.66 N.
Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])
The only force acting on the y-axis is the y-component of the force F₂₁, so:
[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]
The minus sign is because the vector is pointing in the negative y-direction (see the picture below).
[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]
Hence, the y-component of the force is -0.66 N.
Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):
[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]
Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. Direction of the force with the x-axisAccording to the picture below, the angle of the force with respect to the x-axis is given by:
[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]
[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]
Therefore, the force does an angle of 21.68° with the x-axis.
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Determine the position of a train moving at 45 m/s after 5 minutes.
The train has covered 13,500 meters of track.
We don't know its position, because we don't know where it started from, and we don't know how straight the track is.
Which statement can be supported by using a position-time grap
O A negative slope results when an individual is moving away
O A horizontal line on the graph means the individual is moving
O A positive slope results when an individual is moving away fr
O The speed of an individual cannot be determined from this ty
Answer:
A negative slope results when an individual is moving away
Explanation:
At the bottom of a mine shaft, the air
pressure is 138,000 Pa. How deep is
the mine?
(Unit = m)
1 atm = 101300 Pa
Pair = 1.29 kg/m3
Plz help
Answer:2900
Explanation:
I think
A rocket blasts off from the Earth's surface. During the initial phase of flight, the engine of the rocket burns fuel at a rate α, which creates thrust by expelling exhaust gas downward with velocity β relative to the velocity of the rocket. The thrust from the engine provides an additional upward force on the rocket of magnitude αβ. By Newton's 2nd Law, the equation governing the motion of the rocket while the rocket is burning fuel is
Answer:
αβ = Ma
Explanation:
By Newton's 2nd Law, the equation governing the motion of the rocket while the rocket is burning fuel is
αβ = Ma where α = rocket's fuel burning rate, β = relative to the velocity of the rocket, M = instantaneous mass of the rocket and a = acceleration of rocket.
What happens when a mixture is formed?
Answer:
Explanation:
A mixture can usually be separated back into its original components. Some examples of mixtures are a tossed salad, salt water and a mixed bag of M&M's candy.
what scale ranks minerals from softest to hardest
Answer: Mohs Scale
Explanation: Mohs Scale of Hardness
hope this helped!!!!!!!!!!!
Newton's first Law implies that an object at rest will remain at rest unlss a net force acts on it / TRUE or FALSE?
Answer:
True
Explanation:
If an object is at rest it will stay at rest unless a force acts on it.
A 20.0 newton force is used to push a 2.00 kilogram cart a distance of 5.00 meters how much work is done on the cart
Answer:
100
w=f*s
20*5=100....
100 Joules of work is done on the cart.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.
Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.
For above given information,
Force= 20 N
Distance= 5 m
So, work done= 20*5= 100 Joules
Thus, 100 Joules of work is done on the cart.
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Atoms of which pair of elements will form ionic bonds in a compound?
A.
Ti and Ni
B.
Ti and O
C.
Cl and Br
D.
P and Cl
Answer:
Ti and O
Explanation:
It is what it is.
Answer:
B. Ti and O
Explanation:
A.P.E.X
A Drive to the BeachMary drove from her home to the beach that is 30 mi from her house. The first 15 mi she drove at 60 mph, and the next 15 mi she drove at 30 mph. Would the trip take more, less, or the same time if she traveled the entire 30 mi at a steady 45 mph
Answer:
Explanation:
Let us calculate the average velocity .
Average velocity = total distance / total time
Time taken to drive first 15 mi
= 15 / 60 = .25 h
Time taken to drive next 15 mi
= 15 / 30 = .5 h
Total time = .25 + .5 = .75 h
Total distance = 30 mi
average speed = 30 / .75
= 40 mi / h
So average speed is 40 mph which is less than given velocity of 45 mph .
Hence if she travels at 45 mph , she will take less time .
Observer A, who is at rest in the laboratory, is studing a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159ns a) Obsever A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory? b) Obsever B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
Answer:
a) the markers are 29.76 m far apart in the laboratory
b) According to B, the markers are 23.21 m far apart in the laboratory
Explanation:
Given that;
speed of particle = 0.624c = (0.624 × 3×10⁸m/s)
{ where c is the speed of light}
lifetime of the particle t = 159ns = 1.59 × 10⁻⁷
a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory
lets apply the formula distance = velocity × time
lets substitute
distance = (0.624×3×10⁸ m/s) × (1.59 × 10⁻⁷ s)
distance = 29.76 m
Therefore, the markers are 29.76 m far apart in the laboratory
b) Observer B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
lifetime of the particle t = 124ns = 1.24 × 10⁻⁷
distance = (0.624×3×10⁸ m/s) × (1.24 × 10⁻⁷ s)
distance = 23.21 m
Therefore, According to B, the markers are 23.21 m far apart in the laboratory
Define :density٬archimedes principle
Answer:
density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3
Answer:
Density is the amount of mass per unit volume of a substance.
Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"
often occurs at subduction zones. Check all that apply:
O convergence
trench
upward convection currents in the mantle below it
Orifts
most volcanoes...Pacific Ring of Fire
continental plate subducts because it's less dense
Answer:
convergence and trench
Explanation:
LOL
1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential energy now tored in the spring ?
[tex]\displaystyle U_s = 0.6 \ J[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightPhysics
Energy
Elastic Potential Energy: [tex]\displaystyle U_s = \frac{1}{2} k \triangle x^2[/tex]
U is energy (in J)k is spring constant (in N/m)Δx is displacement from equilibrium (in m)Explanation:Step 1: Define
k = 7.50 N/m
Δx = 0.40 m
Step 2: Find Potential Energy
Substitute in variables [Elastic Potential Energy]: [tex]\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2[/tex]Evaluate exponents: [tex]\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)[/tex]Multiply: [tex]\displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)[/tex]Multiply: [tex]\displaystyle U_s = 0.6 \ J[/tex]how do newton's 3 laws of motion effective everyday life?
Answer:
Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.
Explanation:
(b) The efficiency of the pump which operates the fountain is 70%.
Calculate the power supplied to the pump.
Answer:
Power supplied to the pump is 980000 W or 980 KW
Note: The question is incomplete. The complete question is given below:
On a day with no wind, a fountain in Switzerland propels 30000 kg of water per minute to a height of 140 metres.
a)Calculate the power used in raising the water?
b)The efficiency of the pump which operates the fountain is 70%
calculate the power supplied to the pump?
Explanation:
Efficiency = Power output/Power input * 100%
Power output = work done/ time
where work done = mass * acceleration due to gravity (g) * height
time = 1 minute = 60 seconds
mass of water = 30000 kg, height = 140 meters, g = 9.8 m/s²
Then, work done = 30000 * 140 * 9.8 = 41160000 J
Power output then = 41160000 J / 60 s
Power output = 686000 W
The power input can then be derived from the formula of efficiency
Power input = (Power output * 100)/Efficiency
Power input = (100 * 686000) / 70
Power input = 980000 W
Therefore, power supplied to the pump is 980000 W or 980 KW
11. What is the mass of an object which has 2400 J of KE when traveling at 5 points
6 m/s?
63 kg
130 kg
270 kg
400 kg
Answer:
270 Kg e 130 kg
Explanation:
how many times is the number put together
A 2.70 kg book rests on an incline of 13.0. You give it a sharp push up the frictionless ramp. It comes to a stop in 25.25 at 17.5 m up the ramp before starting its descent(a) What is the magnitude of the normal force on the book
Answer:
the magnitude of the normal force on the book is 25.78N
Explanation:
The computation of the magnitude of the normal force on the book is shown below
Normal force = N is
= mgcosβ
= 2.70 × 9.8 × cos13°
= 25.78N
hence, the magnitude of the normal force on the book is 25.78N
The above formula should be applied
image.
A concave lens always produces a(n)
A. inverted
o
B. real
C. virtual
D. magnified
Answer:
Explanation:
Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller
Need help guys please
Answer:
c is the answer,................
Use the graph one more time to help you with this question. Changes in both the North and South occurred due to the .
Answer:
industrial revolution
Explanation:
A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted by the source?
Answer:
Please see below as the answer is self-explanatory.
Explanation:
The visible range extends roughly from 400 nm (violet) to 700 nm (red).Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.The wavelengths in the range of 650 to 690 nm have red as the dominant color.Could a sea breeze occur at night? Explain why or why not.
8.
Billiard ball A, mass 0.17 kg, is moving due east with a velocity of 4.0
m/s. It strikes stationary billiard ball B, which has the same mass. After
the collision, ball A moves at an angle of 30° north of east with a
velocity of 3.5 m/s. Ball B moves at an angle of 60° south of east.
What is the speed of ball B?
Answer:
2 m/s
Explanation:
The momentum of the colliding system is conserved . Therefore, the velocity of the ball B with the same mass as A is 0.52 m/s.
What is momentum ?Momentum of a body is the ability to bring the applied force makes maximum displacement. it is the product of mass and velocity. For a collision, the sum of initial momentum of the two bodies is equal to the sum of their final momentum.
Thus, u be the initial velocity and v be the final velocity.
Then, m1 u1+ m2 u2 = m1 v1 + m1 v2
m1 = 0.17 kg
u1 = 4 m/s
m2 = 0.17 kg
u2 = 0
Then initial momentum = 0.17 × 4 m/s + 0 = 0.68 kg m/s
v1 = 3.5 m/s
0.68 kg m/s = (0.17 × 3.5 m/s ) + (0.17 × v2)
then v2 = 0.52 m/s.
Therefore, the velocity of ball B after collision will be 0.52 m/s.
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Consider this situation: A baseball player dives head-first
into second base and slows down while sliding on the infield
dirt. Of the forces listed, identify which act upon the player.
A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?
Answer:
h = 18.4 cm
Explanation:
Given that,
The speed of the bob at the bottom of the swing is 1.9m/s.
We need to find the initial height of the bob. Let it is h.
We can find it using the conservation of energy i.e.
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
Where
v is speed of the bob
So,
[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m[/tex]
or
h = 18.4 cm
So, the initial height of the bob is 18.4 cm.
The initial height of bob will be "18.4 cm".
Speed and height:Speed would be the scalar quantity that describes "how quickly an attribute moves." This could sometimes be defined as this same rate whereby an object travels a given distance.
According to the question,
The speed of the bob = 1.9 m/s
Let,
The initial height be "h".
By using the conservation of energy, we get
→ mgh = [tex]\frac{1}{2}[/tex]mv²
or,
→ h = [tex]\frac{v^2}{2g}[/tex]
By substituting the values, we get
= [tex]\frac{(1.9)^2}{2\times 9.8}[/tex]
= 0.184 m or,
= 18.4 cm
Thus the above answer is correct.
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What is the final velocity of a running back that is moving with an initial velocity of 3 m/s and accelerates at a rate of 4 m/s2 in 1 seconds as he moves toward the defensive line?
Answer:
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Which is the MOST likely reason scientists are trying to find ways to get energy from more renewable
resources?
А
Renewable resources cost less to produce than
energy from nonrenewable resources
B
Renewable resources are easier to replace than
nonrenewable resources
C
Renewable resources create more power than
nonrenewable resources
D
Renewable resources put more pollution in the air than nonrenewable resources
