by how much is the weight of body less on the moon surface than on earth surface why​

Answer:

im pretty sure it should be 50.0

Answer:

theory

Explanation:

took the quiz

Answer: B

Explanation: I think that it is B.

Answer:

825m

Explanation:

u=20m/s

a=0.5m/(s)^2

s = ut + 1/2a(t)^2

s = 20(30) + 1/2(0.5)(30)^2

s = 600 + 225

s = 825m

Answer:

as we know that

S=ut+1/2(at*t)

S=20*30+1/2(0.5*30*30)

S=600+225

S=825

Hi there!

[tex]\large\boxed{D. \text{ } 3.0 kg}}[/tex]

Use the following equation to solve:

F = ma, where:

F = Force (N)

m = mass (kg)

a = acceleration (m/s²)

Thus:

15 = 5m

15/5 = m

mass = 3 kg

As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.

To calculate Priya's total distance:

Total distance = 300 m + 500 m + 150 m = 950 m

So, Priya's total distance traveled is 950 meters.

To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.

Displacement = √((Δx)² + (Δy)²)

For Δx:

Δx = 500 m - 150 m × cos(45°)

Δx = 500 m - 150 m × 0.707

Δx = 500 m - 106.05 m

Δx = 393.95 m

For Δy:

Δy = 150 m × sin(45°)

Δy = 150 m × 0.707

Δy = 106.05 m

Displacement = √((393.95 m)² + (106.05 m)²)

Displacement ≈ 410.52 m

So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.

To calculate Priya's speed, we use the formula:

Speed = Total distance ÷ Time

Speed = 950 m ÷ 10 min

Speed = 95 m/min

So, Priya's speed is 95 meters per minute.

To calculate Priya's velocity:

Velocity = Displacement ÷ Time

Velocity = 410.52 m ÷ 10 min

Velocity = 41.05 m/min

Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.

For more details regarding velocity, visit:

https://brainly.com/question/34025828

#SPJ5

Answer:

The Mars appears in the direction of South.

Explanation:

Mars is rising in the east at 6: 30 PM. The period of rotation of earth is 24 hours.

So, 6 hours is the one fourth of the period of rotation of earth. Earth rotates counter clockwise on its axis, so after 6 hours, we see the Mars in the direction of South.

Answer:

[tex]q=0.236uC[/tex]

Explanation:

From the question we are told that:

Diameter [tex]d=0.17m[/tex]

Radius [tex]r=0.17/2=>0.085[/tex]

Potential [tex]E=25.0kV[/tex]

Generally the equation for Potential on spere is mathematically given by

[tex]E=\frac{1}{4 \pi e_0}*\frac{q}{r}[/tex]

Therefore

[tex]q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}[/tex]

Where

[tex]\frac{1}{4 \pi e_0}=9*10^9[/tex]

Therefore

[tex]q=\frac{25*10^3*0.085}{(9*10^9}}[/tex]

[tex]q=0.236uC[/tex]

Answer:

the component of light reflected by that object

Explanation:

Answer:

Period refers to the time for something to happen and is measured in seconds/cycle

Answer:

What is the period of time? 5.62 Seconds

What is the amplitude? 1 Centimeters

Explanation:

it just makes sense

Answer:

Most negative

Explanation:

The electric potential energy of a dipole U = -pEcosθ where p = dipole moment, E = electric field and θ = angle between p and E.

When the electric dipole is aligned with the electric field, the angle between p and E is 0°. That is θ = 0°.

So, U = -pEcosθ

U = -pEcos0°

U = -pE

which is the most negative value it can have.

So, the electric potential energy of an electric dipole is most negative when the dipole is aligned with an electric field.

So, most negative is the answer.

Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

28.8 cm/7.2 cm = 4

Answer:

b and d

Explanation:

Answer:

The total displacement of the car is 250 km.

Explanation:

Given that,

A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of  Toronto.

Total displacement = final position - initial position

= 400 km - 150 km

= 250 km

So, the total displacement of the car is 250 km.

Answer:

The acceleration of proton is 5.56 x 10^10 m/s^2 .

Explanation:

initial velocity, u = 0

Electric field, E = 580 N/C

final speed, v = 10^6 m/s

(a) Let the acceleration is a.

According to the Newton's second law

F = m a = q E

where, q is the charge of proton and m is the mass.

[tex]a= \frac{q E}{m}\\\\a = \frac{1.6\times10^{-19}\times 580}{1.67\times 10^{-27}}\\\\a= 5.56\times 10^{10} m/s^2[/tex]

Explanation:

Noise is sound with a continuous structure. Music is composed of sounds with a fundamental frequency and overtones. Noise is composed of sounds with frequencies that range continuously in value from as low as you can hear to as high as you can hear — not necessarily at equal intensity, however.

Mass doesn't change. It doesn't matter where you are.

If your mass is 80 kg when you're on Earth, then your mass is 80 kg. It doesn't matter where you are, where you used to be, or where you're going tomorrow.

On a hot dry day, the amount of water vapour present in atmosphere is less. Thus, water present inside the desert cooler evaporates more, thereby cooling the surroundings more. Hence, a desert cooler cools better on a hot dry day.

Answer:

what if I do and b then someone else c I don't have enough time pls

Answer:

2 Hz.

Explanation:

Frequency is simply defined as the number of appearances of a periodic event occurring per time. It is usually measured in cycles/second.

Now, in this question, we are told that there are 2 cycles for each second.

Thus, we can say that the frequency is 2 cycles/1 s = 2 Hz.

Answer:

-8.036 kV/m

Explanation:

The electric field E = -ΔV/Δx where ΔV = change in electric potential = V - V' where V = electric potential at x = 5.6 cm =  450 V and V' = electric potential at x = 0 cm, = 0 V . So, ΔV = V - V' = 450 V - 0 V = 450 V.

Δx = distance between the 0 V plate and the 450 V point = 5.6 cm = 0.056 m

So, E = -ΔV/Δx

Substituting the values of the variables into the equation, we have

E = -ΔV/Δx

E = -450 V/0.056 m

E = -8035.7 V/m

E = -8.0357 kV/m

E ≅ -8.036 kV/m

Since the electric field between two parallel conducting plates is constant, the electric field between the plates is E = -8.036 kV/m

Answer:

the brightest found are Blue - White with

Explanation:

The energy emission of objects increases with their temperature, specifically Wien described the process in an expression

          [tex]\lambda_{maximum}[/tex] T = 2,898 10⁻³

With this expression we can find the temperature of the stars by the color they emit.

Specifically the Sun has a color of 550 nm which corresponds to 5400K

bright stars have a BLUE color corresponding to 7500K

the brightest found are Blue - White with a temperature of 20000K

Answer:

(n) alluvial fan sandbar

Explanation:

Answer:

Make a nice powerpoint and think about the question

Explanation:

Its easier than you think :)

Answer:

a. i. 6.608 V ii. 5.507 V iii. 1.89 V iv. 1.89 V

b. i. 0.22 mJ ii. 0.182 mJ iii. 0.027 mJ iv. 0.036 mJ

Explanation:

a. The voltage across each capacitor

Since the 15 μf and 20 μf capacitors are in parallel, their total capacitance is C = 15 μf + 20 μf = 35 μf.

Also, since C is in series with the 10 μf and 12 μf which are in series, their total capacitance, C' is gotten from 1/C' = 1/10 μf + 1/12 μf + 1/35 μf  

1/C' = (12 + 42 + 35)/420 /μf

1/C' = 89/420 /μf

C' = 420/89 μf

C' = 4.72 μf

The total charge in the circuit' is thus Q = C'V where V = voltage = 14 V

So, Q = C'V =  4.72 μf × 14 V = 66.08 μC

Since the 10 μf and 12 μf are in series, Q is the charge flowing through them.

Since Q = CV and V = Q/C

i. The voltage across the 10 capacitor is

V = 66.08 μC/10 μF = 6.608 V

ii. The voltage across the 12 capacitor is

V = 66.08 μC/12 μF = 5.507 V

The voltage across the 15 μF and 20 μF capacitors.

Since the capacitors are in parallel, the voltage across them is the voltage across their combined capacitance, C

So, V = Q/C = 66.08 μC/35 μF = 1.89 V

iii. The voltage across the 15 μF capacitor is 1.89 V

iv. The voltage across the 20 μF capacitor is 1.89 V

b. The potential energy of each capacitor

i. The potential energy of the 10 μF capacitor

E = 1/2CV² where C = Capacitance = 10 μF = 10 × 10⁻⁶ F and V = voltage across capacitor = 6.608 V

E = 1/2CV²

E = 1/2 × 10 × 10⁻⁶ F(6.608 V)²

E = 5 × 10⁻⁶ F(43.666) V²

E = 218.33 × 10⁻⁶ J

E = 0.21833 × 10⁻³ J

E = 0.21833 mJ

E ≅ 0.22 mJ

ii. The potential energy of the 12 μF capacitor

E = 1/2CV² where C = Capacitance = 12 μF = 12 × 10⁻⁶ F and V = voltage across capacitor = 5.507 V

E = 1/2CV²

E = 1/2 × 12 × 10⁻⁶ F(5.507 V)²

E = 6 × 10⁻⁶ F(30.327) V²

E = 181.96 × 10⁻⁶ J

E = 0.18196 × 10⁻³ J

E = 0.18196 mJ

E ≅ 0.182 mJ

iii. The potential energy of the 15 μF capacitor

E = 1/2CV² where C = Capacitance = 15 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V

E = 1/2CV²

E = 1/2 × 15 × 10⁻⁶ F(1.89 V)²

E = 7.5 × 10⁻⁶ F(3.5721) V²

E = 26.79 × 10⁻⁶ J

E = 0.02679 × 10⁻³ J

E = 0.02679 mJ

E ≅ 0.027 mJ

iv. The potential energy of the 15 μF capacitor

E = 1/2CV² where C = Capacitance = 20 μF = 15 × 10⁻⁶ F and V = voltage across capacitor = 1.89 V

E = 1/2CV²

E = 1/2 × 20 × 10⁻⁶ F(1.89 V)²

E = 10 × 10⁻⁶ F(3.5721) V²

E = 35.721 × 10⁻⁶ J

E = 0.035721 × 10⁻³ J

E = 0.035721 mJ

E ≅ 0.036 mJ

Answer:

Explained below.

Explanation:

Let the initial velocity from the top of the tower of height(h) be u'

Now, since it is projected horizontally, the horizontal distance covered will be due to having a uniform horizontal velocity (u) while it will possess a vertical distance in the downward direction due to constant acceleration due to gravity (g).

If the time it takes the ball to reach the ground is "t", then we can say the horizontal distance travelled by the ball is denoted as; x(t) = x, while the vertical distance is denoted by; y(t) = y

Now, since it's a projectile the intial velocity (u) will have vertical and horizontal components which are;

u_y and u_x respectively.

Applying kinematic equations, we have;

x = u_x•t + ½at²

Acceleration is zero in the horizontal x direction. Thus;

x = u_x•t

For the vertical y-direction;

y = u_y•t + ½at²

Here since direction is in that of gravity, then a = g.

Also, since the initial velocity has no downward component, then u_y = 0 m/s

Thus;

y = ½gt²

From x = u_x•t, we have;

t = x/u_x

Thus;

y = ½g(x/u_x)²

y = ½gx²/(u_x)²

Let g/(u_x)² be treated as a constant with the letter k.

Thus;

y = kx²

This is the form of a parabolic equation.

Thus, it has been proved that the projectile follows the path of a parabola.

Answer:

1-The liquid pressure is same at all points lying on the same horizontal plane in a stationary liquid.

2-The liquid pressure at a point inside the liquid is same in all directions.

3-The liquid pressure at a point inside the liquid is directly proportional to the depth of that point from the free surface of liquid.

4-The pressure of liquid at same depth is different for different liquids. It is directly proportional to density of liquid. That is, for same depth the liquid pressure is larger for liquid of larger density.

Explanation:

The drawing shows the couple acting on a tire wrench is missing and so i have attached it.

We are to find an expression for the torque when the axis is perpendicular to the tire and passes through the points A, B & C

Answer:

Point A: τ = Fl

Point B: τ = 0

Point C: - Fl

Explanation:

Formula for torque is;

τ = F × d

Where;

F is perpendicular force

d is distance.

Thus;

> At point A, it means we are taking torque about point A and so we have;

τ = (-F × 0) + (F × L)

τ = Fl

> At point B, it means we are taking torque about point B and so we have;

τ = (-F × L/2) + (F × L/2)

τ = -(FL/2) + (FL/2)

τ = 0

> At point C, it means we are taking torque about point C and so we have;

τ = (-F × L) + (F × 0)

τ = -FL