Sadie and Connor both play soccer. Connor scored 2 times as many goals as Sadie. Together they scored 9 goals. Could Sadie have scored 4 goals? Why or why not?
Answer:
no
the goal total would be too high
Step-by-step explanation: If Sadie had scored 4 goals, Connor would have scored 2 times 4 = 8 goals. Their goal total would then be 4+8 = 12, not 9. Sadie cannot have scored 4 goals.
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If we let s represent the number of goals Sadie scored, then 2s is the number Connor scored. Their total is ...
s + 2s = 9
3s = 9 . . . . . . collect terms
s = 9/3 = 3 . . . divide by the coefficient of s
Sadie scored 3 goals. (s=4 is not the solution to the problem)
if △ABC = △DEF, which side is congruent to EF?
A. AB
B. BC
C. AC
Answer:
BC
Step-by-step explanation:
BECAUSE BC IT'S EQUAL TO EF
Answer:
B. BC
Step-by-step explanation:
By SSS rule in ∆ ABC and DEF,
AB = DEBC = EFCA = FDI will give BRAINLIEST to whoever answers correctly first!!!
Sophie wants to buy a pair of scissors that cost $1.82. If she gives the cashier a five dollar bill, how
much change should she get back?
Answer:
Sophie will get $3.18 back in change.
Step-by-step explanation:
You do 5.00-1.82 and you get 3.18, which is equal to the change that Sophie will get.
expand 3e(e+4)
Hhhhhhh
Answer:
[tex]3e^{2} + 12e[/tex]
Step-by-step explanation:
[tex]3ee+3e4[/tex]
[tex]3ee+3 * 4e[/tex]
[tex]3e^{2} + 12e\\[/tex]
[tex]3 \: {e}^{2} + 12 \: e[/tex] ✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex]3 \: e \: ( \: e + 4 \: ) \\ \\ = 3 \: e \times \: e + 3 \: e \times 4 \\ \\ = 3 \: {e}^{2} + 12 \: e[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique }}{\orange{♡}}}}}[/tex]
