Calculate surface tension of an enlarged radius of 4cm to 6cm and amount of work necessary for enlargement was 1.5×10^-4 joules

Answers

Answer 1

Answer:

[tex]T=7.5*10^{-5}[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=2cm[/tex]

Work done [tex]W=1.5×10^-4 joules[/tex]

Generally the equation for Work done is mathematically given by

 [tex]W=T.dA[/tex]

Therefore

 [tex]T=\frac{W}{dr}[/tex]

 [tex]T=\frac{1.5*10^{-4}}{2}[/tex]

 [tex]T=7.5*10^{-5}[/tex]


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