Answer:
Cube with 10 cm
SA = 600 cm V = 1000 cm
Cube with 13 cm
SA = 1014 cm V = 2197
Step-by-step explanation:
SA = 6[tex]s^{2}[/tex]
V = [tex]s^{3}[/tex]
s = side length
There are 4 teams. Each team plays each other team once. How many games are played?
A 3
B 4
C. 6
D. 12
E 16
Answer:
E) 16
Step-by-step explanation:
4 * 4 = 16
Hope this helps
The solution is Option C.
The number of games played by 4 teams if they play each other only once is given by combinations and is 6 games
What are Combinations?
The number of ways of selecting r objects from n unlike objects is:
ⁿCₓ = n! / ( ( n - x )! x! )
where
n = total number of objects
x = number of choosing objects from the set
Given data ,
Let the total number of teams be n = 4 teams
Each team plays the other team only once , so x = 2
The number of games played by 4 teams if they play each other only once is given by Combination
ⁿCₓ = n! / ( ( n - x )! x! )
Substituting the values in the equation , we get
⁴C₂ = ( 4! ) / 2! x 2!
On simplifying the equation , we get
⁴C₂ = ( 4 x 3 ) / 2 x 1
⁴C₂ = 2 x 3
⁴C₂ = 6 games
Therefore , the value of ⁴C₂ =6
Hence , the number of games is 6 games
To learn more about combinations click :
https://brainly.com/question/28065038
#SPJ2
The square root of -2 rounded to nearest 100th?
Answer:
√-2 ≈ 1.41i
Step-by-step explanation:
√-2 = i√2 = i × 1.414.. ≈ 1.41i
What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) Select one: a. x = 3 pi over 2 , x = π b. x = pi over 2 , x = 3 pi over 2 c. x = 0, x = 2π d. x = 0, x = π
9514 1404 393
Answer:
b. x = π/2, x = 3π/2
Step-by-step explanation:
The maximum is found where the argument of the cosine function is a multiple of 2π.
2x -π = 2nπ
2x = (2n+1)π . . . . . . . add π
x = (2n+1) · π/2 . . . . . divide by 2
x = {π/2, 3π/2}
Rounding in the calculation of monthly interest rates is discouraged. Such rounding can lead to answers different from those presented here. For long-term loans, the differences may be pronounced.
To buy a car, you borrow $27,000 with a term of five years at an APR of 6%. What is your monthly payment? (Round your answer to the nearest cent.)
$
How much total interest is paid? (Round your answer to the nearest cent.)
$
Answer:
The correct answer is -
monthly payment = 521.99
total pain intrest = 4319.14
Step-by-step explanation:
Given:
a or the borrowed amount = 27000
r or the interest rate = 6%
n = 5 years or 60 months
Monthly payment = ?
total intreset = ?
Formula:
The formula for the monthly payment is -
[tex]\frac{a}{\frac{{[(1+r)^n]-1}}{[r(1+r)^n]}} = P[/tex]
or, [tex]\frac{ar}{[1-(1+r)^{-60}}[/tex] = P
Where, the amount of the loan = a
r = 0.005 (6% annual rate—expressed as 0.06—divided by 12 monthly payments per year)
n = 60 months
Solution:
Putting all the values in the either of the following formula will give monthly payments:
[tex]\frac{27000}{\frac{{[(1+0.005)^{60}]-1}}{[0.005(1+0.005)^{60}]}} = P[/tex] or [tex]\frac{ar}{[1-(1+r)^{-60}}[/tex]
= 521.9856 or to the nearest cent 521.99.
The total intrest would be -
= (monthly payment*number of month) - amount borrowed
= 521.99*12-27000
= 31319.14-27000
= 4319.14
3384/24 step by step ......I really need help
The resale value V, in thousands of dollars, of a boat is a function of the number of years t since the start of 2011, and the formula is
V = 12.5 − 1.3t.
(a) Calculate V(3).
(b) In what year will the resale value be 7.3 thousand dollars?
(c) Solve for t in the formula above to obtain a formula expressing t as a function of V.
(d) In what year will the resale value be 3.4 thousand dollars?
Answer:
a) V(3) = 8.6.
b) The resale value will be 7.3 thousand dollars at the start of 2015.
c) [tex]t(V) = \frac{12.5 - V}{1.3}[/tex]
d) 2017
Step-by-step explanation:
We are given the following function:
[tex]V(t) = 12.5 - 1.3t[/tex]
(a) Calculate V(3).
This is V when t = 3. So
[tex]V(3) = 12.5 - 1.3(3) = 8.6[/tex]
So
V(3) = 8.6.
(b) In what year will the resale value be 7.3 thousand dollars?
t years after the start of 2011, and t is found when [tex]V(t) = 7.3[/tex]. So
[tex]V(t) = 12.5 - 1.3t[/tex]
[tex]7.3 = 12.5 - 1.3t[/tex]
[tex]1.3t = 5.2[/tex]
[tex]t = \frac{5.2}{1.3}[/tex]
[tex]t = 4[/tex]
2011 + 4 = 2015
The resale value will be 7.3 thousand dollars at the start of 2015.
(c) Solve for t in the formula above to obtain a formula expressing t as a function of V.
[tex]V(t) = 12.5 - 1.3t[/tex]
[tex]1.3t(V) = 12.5 - V[/tex]
[tex]t(V) = \frac{12.5 - V}{1.3}[/tex]
(d) In what year will the resale value be 3.4 thousand dollars?
t years after 2011, and t is found t when [tex]V = 3.4[/tex]. So
[tex]V(t) = 12.5 - 1.3t[/tex]
[tex]3.9 = 12.5 - 1.3t[/tex]
[tex]1.3t = 8.6[/tex]
[tex]t = \frac{8.6}{1.3}[/tex]
[tex]t = 6.62[/tex]
2011 + 6.62 = 2017
So the year is 2017.
please help meeeeeeeeeeeeeeeeee
pt 1
Answer:
Completing the square
Step-by-step explanation:
The proof is lengthy, and I don't think you came here to see that whole proof. Here it is anyway to show you the process of completing the square.
https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:more-on-completing-square/a/quadratic-formula-proof-review
WILL MARK BRAINLIEST TO THE FIRST PERSON OR WHO IS RIGHT!!!!
The work of a student to solve a set of equations is shown:
Equation 1: m = 8 + 2n
Equation 2: 6m = 4 + 4n
Step 1: −6(m) = −6(8 + 2n) [Equation 1 is multiplied by −6.]
6m = 4 + 4n [Equation 2]
Step 2: −6m = −48 − 12n [Equation 1 in Step 1 is simplified.]
6m = 4 + 4n [Equation 2]
Step 3: −6m + 6m = −48 − 12n + 4n [Equations in Step 2 are added.]
Step 4: 0 = −48 − 8n
Step 5: n = −6
In which step did the student first make an error?
Step 3
Step 5
Step 4
Step 2
Answer:
Step 3
Step-by-step explanation:
Step 3 should be:
−6m + 6m = −48 − 12n + 4n + 4
9514 1404 393
Answer:
Step 3
Step-by-step explanation:
When the equations are added in step 3, the result should be ...
-6m +6m = -48 -12n +4 +4n
In the work shown, the (+4) was left out in Step 3.
__
When the work is properly continued, it becomes ...
Step 4: 0 = -44 -8n . . . . [step 3 is simplified]
Step 5: n = -5.5 . . . . . . . [step 4 is divided by -8 and 5.5 subtracted]
Step 6: m = -3 . . . . . . . . . [n is substituted into Equation 1]
And the solution is (m, n) = (-3, -5.5).
The Table below shows the number of hours ten students spent studying for a test and their svores
Answer:
Step-by-step explanation:
By using linear regression calculator,
Linear regression equation representing the data set will be,
y = 7.79x + 34.27
Correlation coefficient of the line will be,
R = 0.98
Since, correlation coefficient of the line is (+0.98), relation between the two variables is a strong linear relationship.
That means hours spent studying has the strong relation with test scores obtained.
Rounding in the calculation of monthly interest rates is discouraged. Such rounding can lead to answers different from those presented here. For long-term loans, the differences may be pronounced.
You borrow $16,000 with a term of four years at an APR of 5% to buy a truck. What is your monthly payment? (Round your answer to the nearest cent.)
$
How much total interest is paid? (Round your answer to the nearest cent.)
$
Answer:
368.47
1686.56
Step-by-step explanation:
effective rate: .05/12=.00416666667
payment=x
[tex]16000=x\frac{1-(1+.00416666667)^{-48}}{.00416666667}\\x=368.47[/tex]
Interest:
368.47*48-16000=1686.56
Answer:
Answer:
368.47
1686.56
Step-by-step explanation:
effective rate: .05/12=.00416666667
payment=x
\begin{gathered}16000=x\frac{1-(1+.00416666667)^{-48}}{.00416666667}\\x=368.47\end{gathered}
16000=x
.00416666667
1−(1+.00416666667)
−48
x=368.47
Interest:
368.47*48-16000=1686.56
1. Find the length of X (in the picture) plssss I need help.
Step-by-step explanation:
[tex] \frac{5}{4} = \frac{x}{6} \\ 4x = 30 \\ x = 7.5[/tex]
What is the value of x in the triangle?
3/2
X
help please<3
Answer:
x = 3
Step-by-step explanation:
Assuming the acute angle are 45degrees
Hypotenuse = 3√2
Opposite = x
According to SOH CAH TOA
Sin 45 = opposite//hypotenuse
Sin 45 = x/3√2
1/√2 = x/3√2
Cross multiply
√2x = 3√2
x = 3
Hence the value of x is 3
Leila is arranging 11 cans of food in a row on a shelf. She has 4 cans of corn, 1 can of peas, and 6 cans of beets. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical.
Given:
Leila is arranging 11 cans of food in a row on a shelf. She has 4 cans of corn, 1 can of peas, and 6 cans of beets.
To find:
The distinct orders can the cans be arranged if two cans of the same food are considered identical.
Solution:
Total number of cans = 11
Cans of corn = 4
Cans of Peas = 1
Cans of beets = 6
We need to find divide total possible arrangements (11!) by the repeating arrangements (1!, 4!, 6!) to find the distinct orders can the cans be arranged if two cans of the same food are considered identical.
[tex]\text{Distinct order}=\dfrac{11!}{1!4!6!}[/tex]
[tex]\text{Distinct order}=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{1\times (4\times 3\times 2\times 1)\times 6!}[/tex]
[tex]\text{Distinct order}=\dfrac{55440}{24}[/tex]
[tex]\text{Distinct order}=2310[/tex]
Therefore, the total number of distinct orders is 2310.
In the last six months, Sonia's family used 529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan. To save money, Sonia's family wants to keep their mean cell phone usage below 600 minutes per month.
By how many minutes did they go over their goal in the last six months?
Answer:
They went over their goal for the last six months by 34 minutes per month.
Step-by-step explanation:
Mean of a data-set:
The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.
529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.
The mean is:
[tex]M = \frac{529+499+651+652+1163+310}{6} = 634[/tex]
By how many minutes did they go over their goal in the last six months?
The mean was of 634 minutes, and they wanted to keep it below 600. So
634 - 600 = 34
They went over their goal for the last six months by 34 minutes per month.
Practice: Write and Evaluate Expressions - Practice --- Level
Which answer matches this description?
half of the difference of 25 and 7
* * (25 – 7)
3+ (25 – 7)
3 - (25 + 7)
* * (25+7)
A baseball is hit and its height at different one-second intervals is recorded (See attachment)
Answer:
[tex]h(t)[/tex] is likely a quadratic function.
Based on values in the table, domain of [tex]h(t)[/tex] : [tex]\lbrace 0,\, 1,\, 2,\, 3,\, 4,\, 5,\, 6,\, 7,\, 8\rbrace[/tex]; range of [tex]h(t)\![/tex]: [tex]\lbrace 0,\, 35.1,\, 60.1\, 75.2,\, 80.3,\, 75.3,\, 60.2,\, 35.0 \rbrace[/tex].
Step-by-step explanation:
By the power rule, [tex]h(t)[/tex] is a quadratic function if and only if its first derivative, [tex]h^\prime(t)[/tex], is linear.
In other words, [tex]h(t)[/tex] is quadratic if and only if [tex]h^\prime(t)[/tex] is of the form [tex]a\, x + b[/tex] for some constants [tex]a[/tex] and [tex]b[/tex]. Tables of differences of [tex]h(t)\![/tex] could help approximate whether [tex]h^\prime(t)\![/tex] is indeed linear.
Make sure that values of [tex]t[/tex] in the first row of the table are equally spaced. Calculate the change in [tex]h(t)[/tex] over each interval:
[tex]h(1) - h(0) = 35.1[/tex].[tex]h(2) - h(1) = 25.0[/tex].[tex]h(3) - h(2) = 15.1[/tex].[tex]h(4) - h(3) = 5.1[/tex].[tex]h(5) - h(4) = -5.0[/tex].[tex]h(6) - h(5) = -15.1[/tex].[tex]h(7) - h(6) = -25.2[/tex].[tex]h(8) - h(7) = -35.0[/tex].Consecutive changes to the value of [tex]h(t)[/tex] appears to resemble a line with slope [tex](-10)[/tex] within a margin of [tex]0.2[/tex]. Hence, it is likely that [tex]h(t)\![/tex] is indeed a quadratic function of [tex]t[/tex].
The domain of a function is the set of input values that it accepts. For the [tex]h(t)[/tex] of this question, the domain of [tex]h(t)\![/tex] is the set of values that [tex]t[/tex] could take. These are listed in the first row of this table.
On the other hand, the range of a function is the set of values that it outputs. For the [tex]h(t)[/tex] of this question, these are the values in the second row of the table.
Since both the domain and range of a function are sets, their members are supposed to be unique. For example, the number "[tex]0[/tex]" appears twice in the second row of this table: one for [tex]t = 0[/tex] and the other for [tex]t = 8[/tex]. However, since the range of [tex]h(t)[/tex] is a set, it should include the number [tex]0\![/tex] only once.
PLEASE HURRY!! I WILL MARK BRAINIEST!
The pentagons JKLMN and PQRST are similar.
Find the length x of QR.
Answer:
x=2.8
Step-by-step explanation:
If JKLMN and PQRST are similar then you can look the to other sides to find the ratio that relates the two. For this specific one you are able to fin 0.4 is the relationship.
NJ is related to TP by a factor of 1.4. -> NJ*1.4=TP -> 4*1.4=5.6
The rest can be said to relate all the other sides together.
In a geometric sequence, the term an+1 can be smaller than the term ar O A. True O B. False
9514 1404 393
Answer:
True
Step-by-step explanation:
In a geometric sequence, the terms a[n+1] and a[n] are related by the common ratio. If the sequence is otherwise unspecified, two sequential terms may have any a relation you like.* Either could be larger or smaller than the other.
__
* If one is zero, the other must be as well. Multiplying 0 by any finite common ratio will give zero as the next term.
The measure of the vertex angle of an isosceles triangle is (a + 30)°. The base angles each measure (2a - 15)º. What is the measure in degrees of one of the base angles?
given the function f(x) = 2x^2 - 6x +4. calculate the following values
Answer:
x^1 = 1, x^2 =2
Step-by-step explanation:
its hard to explain but there's the answer
can anyone help me in this questions
Answer:
Step-by-step explanation:
In a game, there are 12 identical balls of which seven are red and five are green.
Five red balls and two green balls have number ‘2’ written on them. The rest of the
red balls have number ‘1’ written on them, and the rest of the green balls have the
number ‘3’ written on them. A random sample of three balls is selected without
replacement. Let denotes the event that all the balls selected are red and
denotes that the sum of numbers of the three balls is equal to 6. Calculate:
(i) P(A) ,
(ii) P(B),
(iii)P ( A∩ B),
(iv)P(A|B).
Answer:
its number 2 and if its a mutable answers writ 3 also
The probabilities are: (i) P(A) = 1/6
(ii) P(B) = 38/55
(iii) P(A ∩ B) = 1/110
(iv) P(A|B) ≈ 0.00152
To calculate the probabilities, let's first find the total number of ways to choose 3 balls out of the 12 balls.
Total number of ways to choose 3 balls out of 12 = 12C3 = (12 * 11 * 10) / (3 * 2 * 1) = 220
(i) P(A): Probability that all three balls selected are red.
Number of ways to choose 3 red balls out of 7 red balls = 7C3 = (7 * 6 * 5) / (3 * 2 * 1) = 35
P(A) = Number of favorable outcomes / Total number of outcomes = 35 / 220 = 1/6
(ii) P(B): Probability that the sum of the numbers on the three balls is equal to 6.
The possible combinations that sum up to 6 are: (2, 2, 2), (2, 2, 1), and (1, 1, 3).
Number of ways to choose 3 balls such that their sum is 6:
- For (2, 2, 2), we have 1 choice for each color, so 1 * 1 * 1 = 1 way.
- For (2, 2, 1), we have 1 choice for each color, so 1 * 1 * 1 = 1 way.
- For (1, 1, 3), we have 6 choices for the first red ball (all are labeled '1'), 5 choices for the second red ball (since one '1' is already taken), and 5 choices for the green ball labeled '3', so 6 * 5 * 5 = 150 ways.
Total number of ways to choose 3 balls with sum 6 = 1 + 1 + 150 = 152
P(B) = Number of favorable outcomes / Total number of outcomes = 152 / 220 = 38/55
(iii) P(A ∩ B): Probability that all three balls selected are red and the sum of their numbers is equal to 6.
From the above calculations, we know that there are 1 way to choose (2, 2, 2) and 1 way to choose (2, 2, 1) such that all three balls are red and the sum is 6.
P(A ∩ B) = Number of favorable outcomes / Total number of outcomes = 2 / 220 = 1/110
(iv) P(A|B): Probability that all three balls selected are red, given that the sum of their numbers is equal to 6.
P(A|B) = P(A ∩ B) / P(B) = (1/110) / (38/55) = (1/110) * (55/38) ≈ 0.00152 (rounded to five decimal places).
To know more about probabilities:
https://brainly.com/question/29381779
#SPJ2
Find x
x³ + 3x - 14 = 0
x³ + x² - x² - x + 4x + 4 = 18
x²(x + 1) - x(x + 1) + 4(x + 1) = 18
(x + 1)(x² - x + 4) = 18
x² - x + 4 = 18/(x + 1)
x² - x + 4 - 6 = 18/(x + 1) - 6
x² - x - 2 = 18/(x + 1) - 6
(x - 2)(x + 1) = (18 - 6(x + 1))/(x + 1)
(x - 2)(x + 1) = (18 - 6x - 6)/(x + 1)
(x - 2)(x + 1) = (12 - 6x)/(x + 1)
(x - 2)(x + 1) = (-6(x - 2))/(x + 1)
x + 1 = (-6(x - 2))/(x + 1)(x - 2)
x + 1 = -6/(x + 1)
(x + 1)² = -6
x² + 2x + 8 = 0
x = (-b +- √(b² - 4ac))/2a
x = (-2 +- √(4 - 32))/2
x = (-2 +- √(-28)/2
x = (-2 +- i√28)/2
Something's wrong.
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = - 1 \: + \: i \sqrt{6} \:(or) \: \: x = - 1 \: -\: i \sqrt{6} }}}}}}[/tex]
And[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:2}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] \: {x}^{3} + 3x - 14 = 0[/tex]
➺[tex] \: {x}^{2} (x + 1) - x(x + 1) + 4(x + 1) = 18[/tex]
➺[tex] \: (x + 1)( {x}^{2} - x + 4) = 18[/tex]
➺[tex] \: {x}^{2} - x + 4 = \frac{18}{(x + 1)} [/tex]
➺[tex] \: {x}^{2} - x + 4 - 6 = \frac{18}{(x + 1)} - 6[/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6(x + 1)}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{18 - 6x - 6}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{12 - 6x}{(x + 1)} [/tex]
➺[tex] \: (x - 2)(x + 1) = \frac{ - 6(x - 2)}{(x + 1)} [/tex]
➺[tex] \: (x + 1 )² = \frac{ - 6(x - 2)}{(x + 1)(x - 2)} [/tex]
➺[tex] \: (x + 1)² = \frac{ - 6}{(x + 1)} [/tex]
[tex]\sf\pink{Error\:corrected\:here. }[/tex]
➺[tex] \: {x}^{2} + 2x + 1 = - 6[/tex]
➺[tex] \: {x}^{2} + 2x + 7 = 0[/tex]
By quadratic formula, we have
➺[tex] \: x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ {2}^{2} - 4.1.7} }{2 \times 1} [/tex]
➺[tex]x = \frac{ - 2± \sqrt{ - 24} }{2 } [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1 \times 4 \times 6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2± \sqrt{ - 1} \times \sqrt{4} \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \: i \times 2 \times \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ - 2 \: ± \:i \: 2 \sqrt{6} }{2} [/tex]
➺[tex] \: x = \frac{ 2 \: ( - 1 \: ± \: i \: \sqrt{6}) }{2} [/tex]
➺[tex] \: x = - 1 \: ± \: i \sqrt{6} [/tex]
Therefore, the two values of [tex]x[/tex] are ([tex] \: - 1 \: + \: i \sqrt{6}[/tex]) and ([tex] \: - 1 \: -\: i \sqrt{6}[/tex]).
Let us look at another method.[tex]x[/tex]³ + 3 [tex]x[/tex] - 14 = 0
➼ [tex]x[/tex]³ + 3 [tex]x[/tex] = 14
➼ [tex]x[/tex] ( [tex]x[/tex]² + 3 ) = 14
Factors of 14 = 1, 2, 7 and 14.
a) Substituting [tex]x\:=\:1[/tex], we have
➼ 1 ( 1 + 3 ) ≠ 14
➼ 1 x 4 ≠ 14
➼ [tex]\boxed{ 4\: ≠ \:14 }[/tex]
b) Substituting [tex]x\:=\:2[/tex], we have
➼ 2 ( 2² + 3 ) = 14
➼ 2 ( 4 + 3 ) = 14
➼ 2 x 7 = 14
➼ [tex]\boxed{ 14 \:= \:14 }[/tex]
c) Substituting [tex]x\:=\:7[/tex], we have
➼ 7 ( 7² + 3 ) ≠ 14
➼ 7 ( 49 + 3 ) ≠ 14
➼ 7 x 52 ≠ 14
➼ [tex]\boxed{ 364\: ≠ \:14 }[/tex]
d) Substituting [tex]x\:=\:14[/tex], we have
➼ 14 ( 14² + 3 ) ≠ 14
➼ 14 x 199 ≠ 14
➼ [tex]\boxed{ 2786\: ≠ \:14 }[/tex]
Hence, our only real solution is 2.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
Sonia took a loan of $10 000 from ABC bank tob pay for a renovation at home. The bank offered her a period of 30 months at a rate of 10.5%. to repay the loan:
a) Calculate the Simple Interest she would pay in 30 months.
b) Calculate the Total amount Sonia would have to repay the bank.
Answer:
a. Simple interest, S.I = $2,625
b. Total amount = $12,625
Step-by-step explanation:
Given the following data;
Principal = $10,000
Interest rate = 10.5%
Time = 30 months to years = 2.5 years
a. To find the simple interest;
Mathematically, simple interest is calculated using this formula;
[tex] S.I = \frac {PRT}{100} [/tex]
Where;
S.I is simple interest. P is the principal. R is the interest rate. T is the time.Substituting into the formula, we have;
[tex] S.I = \frac {10000*10.5*2.5}{100} [/tex]
[tex] S.I = \frac {262500}{100} [/tex]
Simple interest, S.I = $2,625
b. To calculate the total amount Sonia would have to repay the bank;
Total amount = simple interest + principal
Total amount = 2625 + 10000
Total amount = $12,625
Maria's Pizza Palace offers 4 types of crust, 7 toppings, and 6 kinds of cheese for the mega calzone. How many different mega calzones can be made if a mega calzone contains 5 different toppings and 3 different cheeses
Answer:
210 different mega calzones can be made.
Step-by-step explanation:
Fundamental counting principle:
States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.
Additionally:
The order in which the toppings and the cheeses are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Toppings:
5 from a set of 7. So
[tex]C_{7,5} = \frac{7!}{5!2!} = 21[/tex]
Cheeses
3 from a set of 6. So
[tex]C_{6,3} = \frac{6!}{3!3!} = 20[/tex]
How many different mega calzones can be made if a mega calzone contains 5 different toppings and 3 different cheeses?
Toppings and cheeses are independent, and thus, by the fundamental counting principle:
21*20 = 210
210 different mega calzones can be made.
the area of a tennis court is 2000m2 . a rugby pitch has a legnth of 45m and width of 45m . which has the biggest area?
Answer:
The area of a rugby pitch is more as compared to the area of the tennis court.
Step-by-step explanation:
Given that,
The area of a tennis court is 2000 m².
The length and width of a rugby pitch are 45 m and 45 m.
The area of a rugby pitch is given by :
A = lb
So,
A = 45×45
A = 2025 m²
So, it is clear that the area of a rugby pitch is more as compared to the area of the tennis court.
These box plots show daily low temperature for a sample of days in two different towns
Answer:
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.
Step-by-step explanation:
From the boxplot Given ;
Town A :
The first quartile, Q1 = 15
Third quartile, Q3 = 30
The interquartile range, IQR = Q3 - Q1 = 30 - 15 = 15°
TOWN B :
The first quartile, Q1 = 20
Third quartile, Q3 = 40
The interquartile range, IQR = Q3 - Q1 = 40 - 20 = 20°
The interquartile range (IQR) for town A, 15° is less than the IQR for town B, 20°.
What is the distance between the points (2, 1) and(6, 7)?
Answer:
[tex]\displaystyle d = 2\sqrt{13}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Identify
Point (2, 1)
Point (6, 7)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{4^2 + 6^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{16 + 36}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{52}[/tex][√Radical] Simplify: [tex]\displaystyle d = 2\sqrt{13}[/tex]Suppose one network executive is selected at random. find the indicated probabilities
Answer:
na answer ran nyo na po
Step-by-step explanation:
Use the formula below to find the relative pressure inside the can in psi
Answer:
b
Step-by-step explanation:
you have to have psi to have p-e-n-i-s sand you get a jack hammer
