Calculate the velocity of a wave that has a frequency of 60 Hz and wavelength of 2.0 m/s

Answer:

C.

Explanation:

Answer:A

Explanation:ap3x

Answer:

C: will brake and quickly come to rest.

Explanation:

Correct answer is option C because for the swinging motion of the copper plates between the magnetic field which is set up as a result of it being between the two magnetic poles, there will be a continuous change of magnetic field flux that will be linked with the swinging pendulum.

As a result of this continuous change of magnetic field flux, it makes eddy currents to be set up in the copper plate which according to the Lenz's laws of electromagnetic induction tries to oppose the motion of the swinging pendulum and finally will make it come to rest.

Answer:

[tex]3.49\times 10^{-8}\ \Omega\text{m}[/tex]

Explanation:

r = Radius = [tex]\dfrac{2}{2}=1\ \text{mm}[/tex]

B = Magnetic field = 3 mT

1 mm = Distance from the surface of the wire

V = Voltage

x = Distance from the probe = [tex]r+1=1+1=2\ \text{mm}[/tex]

R = Resistance

L = Length of wire = 4.5 m

Magnetic field is given by

[tex]B=\dfrac{\mu_0I}{2\pi x}\\\Rightarrow I=\dfrac{B2\pi x}{\mu_0}\\\Rightarrow I=\dfrac{3\times 10^{-3}\times 2\times \pi 2\times 10^{-3}}{4\pi 10^{-7}}\\\Rightarrow I=30\ \text{A}[/tex]

Voltage is given by

[tex]V=IR\\\Rightarrow R=\dfrac{V}{I}\\\Rightarrow R=\dfrac{1.5}{30}\\\Rightarrow R=0.05\ \Omega[/tex]

Resistivity is given by

[tex]\rho=\dfrac{RA}{L}\\\Rightarrow \rho=\dfrac{0.05\times \pi (1\times 10^{-3})^2}{4.5}\\\Rightarrow \rho=3.49\times 10^{-8}\ \Omega\text{m}[/tex]

The resistivity of the material is [tex]3.49\times 10^{-8}\ \Omega\text{m}[/tex].

Answer:

We apply an electric field in the negative y direction

Explanation:

Since A uniform magnetic field is in the positive z direction and A positively charged particle is moving in the positive x direction through the field, the magnetic force acting on the positively charged particle is in the positive y direction according to Fleming's right-hand rule.

For the net force on the particle to be zero, we apply an electric field in the negative y direction to create an electric force on the positively charged particle, so as to cancel out the magnetic force.

Answer:

isopropyl alcohol would form smaller droplets, because it has lower surface tension than water has

Explanation:

Ap3x

The droplets made of isopropyl alcohol instead of water be smaller due to surface tension.

The single drop of a liquid in the form of sphere is called droplet.

Water can form large dewdrops in nature. Isopropyl alcohol would form smaller droplets, because it has lower surface tension than water.

Surface tension is the property of the liquid to acquire minimum surface area.

Thus, droplets made of isopropyl alcohol instead of water be smaller.

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Answer:

refraction is the change in direction of a wave passing from one medium to another or from a gradual change in the medium.

Answer:

The correct answer is -  91.4 nm

Explanation:

According to Bohr's model, the minimum wavelength to ionize Hydrogen atom from n= 1 state is expressed as:

(h×c)/λ=13.6eV

here,

h - Planck constant

c - the speed of light

λ - wavelength

Placing the value in the formula for the wavelength

(6.626×10^−34J.s × 3×10^8 m/s)/λ  =  13.6 ×1.6 × 10^−19 J

λ≈91.4nm

Thus, the correct answer would be = 91.4 nm

Answer:

Why does it take sometimes to be brighter again after eclipse? The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation:

Answer: The moon looks dimmer before lunar eclipse because the moon enters into shadow of penumbra region of earth. As a result, the brightness of moon decreases and looks dimmer.

Explanation:

Explanation:

mass=force*acceleration

mass=3000*10

mass=30,000

The mass of the bodies in the elevator is 400 kg.

The acceleration of the elevator is 2.5 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the elevator: M = 250 kg.

Mass of two persons: m₁ = 50 kg and m₂ = 100 kg.

Force exerted by the motor: F = 3000N.

g = 10 m/s².

Let, the acceleration of the  elevator = a.

the mass of the bodies in the elevator :m= 250 kg. + 50 kg +100 kg. = 400 kg.

Now, F = mg - ma

⇒ 3000 = 400×10 - 400a

⇒ a = 1000/400 = 2.5 m/s²

Hence, the acceleration of the elevator is 2.5 m/s².

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Answer: i think the answer is C

Explanation:

According to Coulomb's law, the force between the given charges is 0.225N which is explained below.

Force on two identical charges q separate by a distance of r is given by:

F = kq²/r²

where k is Coulomb's constant

q is the charge

r is the separation between the charges

Given that q = 1×10⁻⁵C,

and r = 2m

So, the force between the given charges will be:

F = (9×10⁹)(1×10⁻⁵)²/2²

F = 0.225N is the required force.

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Answer:

The equation says that due to variation in temperature is

delt T = .59 m/s / C = 16 C * .59 m/s = 9.44 m/s

So v = 332 m/s + 9.44 m/s = 341 m/s (to three significant figures)

Answer:

Conservation of Energy: Like all things, Stirling Engines follow the conservation of energy principle (all the energy input is accounted for in the output in one form or another). ... The hot one supplies all of the energy QH, while the cold one removes energy QC (a necessary part of the cycle).

Explanation:

Answer: Yes

Explanation: All the energy input is accounted for in the output in one form or another

Answer:

Explanation

Answer:

1) It seems that he would need the central gravitational force

   (the sun)

2) Also the planets would need to be included (orbits around the sun)

    Mercury, Venus, Earth, Mars, Jupiter, Saturn, etc.

3. Then, many of the planets have significant objects (moons) rotating about them.

Those would seem to be objects to be included in a model of the solar system.

1) He would need the central gravitational force (the sun)

2) The planets would need to be included: Mercury, Venus, Earth, Mars, Jupiter, Saturn, etc.

3) Many of the planets have specific moons rotating about them.

Larry should put the Earth between the planets Venus, and Mars.

Answer:

Wait lang po sandali po wait lang

Answer:

I know you said not to do this but I am doing a challenge and You asked this an hour ago. PLS DON'T REPORT ME.

Explanation: Sorry

Answer:

Earth's atmosphere is a layer of gases surrounding the planet Earth and retained by the Earth's gravity. It contains roughly 78% nitrogen and 21% oxygen 0.97% argon and carbon dioxide 0.04% trace amounts of other gases, and water vapor. This mixture of gases is commonly known as air.  Explanation:

Answer:

the earth's atmosphere

Explanation:

hope that helps

Explanation:

mass, m = 5kg

initial velocity, u = 16m/s

final velocuty, v = -22m/s

change in momentum, ∆p = ?

∆p = m (v-u)

5(-22-16)

5(38)

∆p = 190kgm/s

check the calculations!

Answer:

The acceleration of the football is greatest

Explanation:

The more mass the more acceleration

Answer:

5.03

Explanation:

trust me

Answer:

true

Explanation:

with increased temperature particles move faster as they gain kinetic energy

Answer:

I think the answer is B, keeps Earth in a spherical shape

Answer:

work done by friction = 5889 J

Explanation:

We are given;

Mass of car; m = 130 kg

Speed at point A; v1 = 25 m/s

Speed at point B: v2 = 8 m/s

Since radius is 12 m

At point A, distance is; y1 = 12 m

At point B, distance is; y2 = -12 m

Now, formula for work done by all the forces is given by the equation;

Total work;

W_gravity + W_others = K2 - K1

Where W_others is work done by other forces which is equal to work done by friction

Where K2 - K1 is change in kinetic energy.

W_grav is also change in potential energy and is expressed as;

W_grav = mgy1 - mgy2

K2 - K1 = ½m(v1)² - ½m(v2)²

Thus;

mgy1 - mgy2 + W_others = ½m(v1)² - ½m(v2)²

Making W_others the subject;

W_others = ½m(v1)² - ½m(v2)² + mgy2 - mgy1

Plugging in the relevant values;

W_others = (½ × 130 × 25²) - (½ × 130 × 8²) + (130 × 9.8 × -12) - (130 × 9.8 × 12)

W_others = 5889 J

Recall that I earlier said W_others = work done by friction.

Thus, work done by friction = 5889 J

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = [tex]\frac{ M x_1 -m_{table} x_3}{ x_2}[/tex]

let's calculate

             m_{maximum} = [tex]\frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}[/tex](380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

Answer:

[tex]20.32^{\circ}[/tex] and [tex]44.08^{\circ}[/tex]

[tex]12.56^{\circ}[/tex] and [tex]25.77^{\circ}[/tex]

Explanation:

[tex]\lambda[/tex] = Wavelength

[tex]\theta[/tex] = Angle

m = Order

Distance between grating is given by

[tex]d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}[/tex]

[tex]\lambda=656\ \text{nm}[/tex]

We have the relation

[tex]d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}[/tex]

m = 1

[tex]\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}[/tex]

m = 2

[tex]\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}[/tex]

The first and second order angular deflection is [tex]20.32^{\circ}[/tex] and [tex]44.08^{\circ}[/tex]

[tex]\lambda=410\ \text{nm}[/tex]

m = 1

[tex]\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}[/tex]

m = 2

[tex]\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}[/tex]

The first and second order angular deflection is [tex]12.56^{\circ}[/tex] and [tex]25.77^{\circ}[/tex].

A 4.0 kg block is moving at 5.0 m/s along a horizontal frictionless surface toward an ideal spring that is attached to a wall, the maximum speed of the block when the spring is compressed to one-half of the maximum distance is 4.33 m/s

From the conservation of energy; the kinetic energy of the mass is equal to the work done on the spring.

i.e.

[tex]\mathbf{\dfrac{1}{2} mv^2 = \dfrac{1}{2}kx^2_{max}}[/tex]

Given that:

∴

From the equation above, multiplying both sides with 2, we have:

[tex]\mathbf{mv^2 =kx^2_{max}}[/tex]

Making (k) the subject of the formula;

[tex]\mathbf{k = \dfrac{mv^2}{x^2_{max}}}[/tex]

[tex]\mathbf{k = \dfrac{4 \times 5^2}{0.68^2}}[/tex]

k = 216.26 N/m

However, when compressed to one-half of the maximum distance; the speed is computed as follows:

x = 0.68/2 = 0.34 m

∴

[tex]\mathbf{\dfrac{1}{2}mv_o^2 - \dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2}[/tex]

[tex]\mathbf{m(v_o^2 -v^2) =kx^2}[/tex]

[tex]\mathbf{(v_o^2 -v^2) =\dfrac{kx^2}{m}}[/tex]

[tex]\mathbf{(5^2 -v^2) =\dfrac{216.26 \times 0.34^2}{4.0}}[/tex]

25 - v² = 6.25

25 -6.25 = v²

v² = 18.75

[tex]\mathbf{ v= \sqrt{18.75 }}[/tex]

v = 4.33 m/s

Therefore, we can conclude that the speed of the block when the spring is compressed to only one-half of the maximum distance is 4.33 m/s

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