can anyone help with integers?

Fill in the blanks.

6) 83 + 17 = 17 +

7) |46| – |50| =

8) 42 – 2 + (18 – 10) =

9) 18 – (3 – 1) =

10) 8 - 0 =

Answer:

-5.82

Possible by long devison and the rule that if there is one negitive then the answer is negitive

Answer:

29 feet

Step-by-step explanation:

14 × 3 = 42

100 - 42 = 58

58 ÷ 2 = 29

One of the longer chains is 29 feet long.

Hope this helps.

Answer:

With the formula of lwh/3 the answer is 305.37

Step-by-step explanation:

l×w×h /3 =305.37

Answer:

916.11 ft³

Step-by-step explanation:

(9×6)×7.83/2×13/3

= 211.41×13/3

= 916.11 ft³

Answered by GAUTHMATH

Answer:

either 5 or 6

Step-by-step explanation:

I can't have a direct answer because you didn't get all of the histogram in there, but from what I can conclude from just this there's definitely either 5 or 6.

Answer:

13

Step-by-step explanation:

(fog)=3(x-1)+1

ie puting the function of g in f

so (fog)= 3x-3 + 1= 3x-2

finding fog

(fog)(5)= 3(5)-2

ie sub stitute 5 in x

(fog)(5)=15-2=13

Answer:

B). 34.85°

Step-by-step explanation:

From trigonometric ratios:

[tex] \sin(C) = \frac{opposite}{hypotenuse} [/tex]

Opposite = 16

Hypotenuse = 28

[tex] \sin(C) = \frac{16}{28} \\ \\ C = { \sin}^{ - 1} ( \frac{16}{28} ) \\ \\ C = 34.85 \degree[/tex]

Answer:

12/17

Step-by-step explanation:

Let

Numerator of the fraction = x

Denominator of the fraction = x + 5

The fraction is

x / (x + 5)

if both the numerator and denominator are increased by 3, the the resulting fraction becomes 3/4.

x + 3 / (x + 5) + 3 = 3/4

x + 3 / x + 8 = 3/4

Cross multiply

(x + 3)4 = (x + 8)3

4x + 12 = 3x + 24

4x - 3x = 24 - 12

x = 12

Recall,

x / (x + 5)

= 12 / (12 + 5)

= 12/17

The original equation = 12/17

Answer:

$55.20 is Mrs. Barker hourly overtime rate.

Step-by-step explanation:

The term "time and a half" in your question means that Mrs. Baker's overtime rate is 1.5 times her usual hourly rate.

So, ----> $36.80 times 1.5 = $55.20

Answer:

[tex] {x}^{2} - 36 \\ = (x + 6)(x - 6)[/tex]

Step-by-step explanation:

x^2-36

(x+6) ( x-6)

it's helpful to you

Answer:

[tex](x-6)(x+6)[/tex]

Step-by-step explanation:

In order to simplify this equation, one must use the quadratic factoring patterns. These patterns are as follows:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

This pattern works because, if one is to distribute the terms in the parenthesis by multiplying each term in one of the parenthesis by every term in the other, the result is the original equation:

[tex](a-b)(a+b)\\\\=(a)(a)+(a)(-b)+(a)(b)+(b)(-b)\\\\=a^2-ab+ab-b^2\\\\=a^2-b^2[/tex]

One can apply this pattern to the given equation, remember (6) times itself equals (36). Therefore, one can state the following: ([tex]36=6^2[/tex]), thus one can apply it to the given equation:

[tex]x^2-36\\\\=x^2-6^2\\\\=(x-6)(x+6)[/tex]

Answer:

12 yrs.

Step-by-step explanation:

let present age of girl=x

age of mother=x+18

after 6 yrs

age of girl=x+6

age of mother=x+18+6=x+24

according to the condition of question

(x+6)+(x+24)=54

2x+30=54

2x=54-30=24

x=24/2=12

Answer:

2ax(y-2ay^2+3a^2x)

Step-by-step explanation:

2axy-4a^2xy^2+6a^3x^2

Given data

we have the following expression

2axy-4a^2xy^2+6a^3x^2

let us factor this expression

we have

2ax(y-2ay^2+3a^2x)

The common factor is 2ax

And the factorized expression is 2ax(y-2ay^2+3a^2x)

Answer: 2.31

Step-by-step explanation:

The ratio is (J/W) = 7/6. Or. J= (7/6)• W .

Second line: J= (7/6)• 24. J= 28.

Third line: J= (7/6)• 18. J= 21

Answer:

Sara is now 4, will be 8 in 4 years. Ralph is now 12, will be 16 in 4 years.

Answer:

37500

Step-by-step explanation:

pattern is multiplying by -5.

-7,500*-5 = 37,500

Have a nice day! :-)

Answer:

1 : 5

Step-by-step explanation:

3 students zoo

15 students aquarium

zoo : not zoo

3: 15

Divide each side by 3

3/3 : 15/3

1 : 5

Answer:

130

Step-by-step explanation:

65/50*100= 130

Answer:

B, E

Step-by-step explanation:

( 9 × 100 )  +  ( 2 × 10 )  +  ( 3 × 0.10 )  +  ( 5 ×0.01 )  = 920.35

A.  92.35

B.  920.350

C.  902.35

D.  92.350

E.  920.35

F. 920.035

Answer: 318 km²

Let's find the areas of the triangles

Formula: base x height / 2

9 x 6 = 54

54/2 = 27

Multiply by 2 since there are two triangles (I know, we already got the areas from 9 x 6)

27 x 2 = 54

Now let's try to find the areas of all the rectangular sides

Formula: length x width

9 x 11 = 99

8 x 11 = 88

7 x 11 = 77

99 + 88 + 77 = 264

Add up all the areas

264 + 54 = 318

Answer:

the answer will be

184.31

Answer:

1) 6а-9b=3(2a-3b)

2)8a-12b=4(2a-3b)

3) 5ab-5ac=5a(b-c)

4) 6ax+6ay=6a(x+y)

Answer:

3√13

Step-by-step explanation:

3√13

This expression cannot be simplified because you cannot take any common factor outside the root.

Answer:

If you draw the graph of y = -x + 6  on the above graph  the solution to system will be the coordinates of the point of intersection.

the equation of the line drawn above is y = 0.5x

so you can also find the solution by solving the system

y = 0.5x

y = -x + 6

0.5x = -x + 6

1.5x = 6

x = 6/1.5 = 4

and y = 0.5*4 = 2

The answer is  (4, 2)     - the third choice.

Step-by-step explanation:

Answer:

Does the answer help you?

Answer:

Hello,

Step-by-step explanation:

Formula used (a+b)^2=a²+2ab+b²

[tex](12-9i)^2=3^2*(4-3i)^2\\\\=9*(16-9-24i)\\\\=9*(7-24i)\\\\=63-216i\\[/tex]

Answer:

i don't know

( lol )

heheeeee

Answer:

Hi,

[tex]u_{20}=30[/tex]

Step-by-step explanation:

[tex]u_n=u_1+(n-1)*r, \ r= commun\ ratio.\\u_4=u_1+3*r=6\\u_6=u_1+5r\\(u_6)^2=u_1^2+10ru_1+25r^2\\s_n=u_1+u_1+r+u_1+2r+...+u_1+10r=11*u_1+55r\\s_{11}=(u_6)^2+18\ \\\Longrightarrow\ u_1^2+10ru_1+25r^2+18=11u_1+55r\\\Longrightarrow\ 4r^2+2r-12=0\\\Longrightarrow\ 2r^2+r-6=0\\r=\dfrac{3}{2} \ or\ r=-2\ (excluded)\\\\u_1=6-3r=\dfrac{3}{2} \\\\\\\boxed{u_{20}=u_1+19*r=30}\\[/tex]

The value of the 20th term of the arithmetic series will be 30

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Un  =  u₁+(n-1) x r

u₄  =  u₁  +(3 x r)=6

u₆ = u₁ +5r

u₆²=u₁²+10ru₁+25r²+18=11u₁+55r

Sn= u₁+u₁+r+u₁+2r+.............u₁+10r= (11 x u₁) +55 r

4r²+2r-12=0

2r²+r-6=0

r=3/2

u₁=6-3r=3/2

u₂₀=u₁+(19 x r)= 30

Hence the value of the 20th term of the arithmetic series will be 30

To know more about arithmetic progression follow

https://brainly.com/question/6561461

#SPJ2

15 divided by two is 7.5 and ten plus 7.5 is 17.5…. It says less than half the cost so I would round down to get $17 for the pain of pants

The cost of the pair of pants is $17.5 or $17 if the certain t-shirt costs $10 less than half the cost of a pair of pants.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

A certain t-shirt costs $10 less than half the cost of a pair of pants. If the t-shirt costs $15.

Let x be the cost of the pair of pants.

The value of x can be found as follows:

x = 15/2 + 10

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division.

x = $17.5  

Thus, the cost of the pair of pants is $17.5 or $17 if the certain t-shirt costs $10 less than half the cost of a pair of pants.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ2

Let y = √x, so the limit can be rewritten as

[tex]\displaystyle \lim_{y\to\infty}\left(\frac{\sqrt{y^6+y^2}}{y^2+3} - \frac{\sqrt{y^4+1}}{y+4}\right)[/tex]

Now,

[tex]\sqrt{y^6+y^2} = \sqrt{y^2\left(y^4+1\right)} = y\sqrt{y^4+1}[/tex]

so we can rewrite the limit further as

[tex]\displaystyle \lim_{y\to\infty}\left(\frac{y}{y^2+3} - \frac1{y+4}\right)\sqrt{y^4+1}[/tex]

Combine the rational terms:

[tex]\dfrac y{y^2+3} - \dfrac1{y+4} = \dfrac{y(y+4)-(y^2+3)}{(y^2+3)(y+4)} = \dfrac{4y-3}{(y^2+3)(y+4)}[/tex]

Then in the limit, we get

[tex]\displaystyle \lim_{y\to\infty}\frac{(4y-3)\sqrt{y^4+1}}{(y^2+3)(y+4)} = \lim_{y\to\infty}\frac{(4y^3-3y^2)\sqrt{1+\dfrac1{y^4}}}{y^3+4y^2+3y+12} \\\\ = \lim_{y\to\infty}\frac{\left(4-\dfrac3y\right)\sqrt{1+\dfrac1{y^4}}}{1+\dfrac4y+\dfrac3{y^2}+\dfrac{12}{y^3}} = \boxed{4}[/tex]