Can someone answer ASAP if you hurry I will mark brainliest

Can Someone Answer ASAP If You Hurry I Will Mark Brainliest

Answers

Answer 1

Answer:

Electrical and magnetic

You exert a gravitational force on the pupil and the pupil exerts an equal gravitational force on you. ... The size of the gravitational force depends on the mass of the objects involved. The greater the mass, the greater the gravitational force.

Explanation:


Related Questions

hurry please Which of the following is a compound?

CO2
Ne
O2
P4

Answers

Answer:

p4

Explanation:

How can calcium oxide change directly to limewater?
Wants equation and observation

Answers

Answer:

Lime(Calcium Oxide) is a white solid with strongly basic properties.Lime reacts readily with water to produce slaked lime,which is the chemical compound calcium hydroxide.....

When carbon dioxide gas is passed through or over limewater,it turns milky due to the formation of calcium carbonate.

Why do scientist use the scientific method

Answers

Answer:

B

Explanation:

scientists always look for evidence

Answer:

Yea its B

Explanation: The person above me legit toke the answer out of my mouth

How many grams are in 3.00 x 10^24 molecules of Zn(C2H3O2)2?​

Answers

Answer:

Mass = 917.4 g

Explanation:

Given data:

Number of molecules = 3.00 ×10²⁴ molecules

Mass in gram = ?

Solution:

1 mole contain 6.022 × 10²³ molecules

3.00 ×10²⁴ molecules × 1 mol /  6.022 × 10²³ molecules

0.5×10¹ mol

5 mol

Mass in gram:

Mass = number of moles  × molar mass

Mass = 5 mol  × 183.48 g/mol

Mass = 917.4 g

Calculate the molar mass of NaNO3-

Answers

The molar mass is 37 grams

PLZ HELP!!!!!asapnow

Answers

Answer:

Friction of wind against the ocean surface

friction of wind against the ocean surface

why do stars appear to be bigger in the night?

Answers

Answer: in the daytime the sun is out so the stars are not visible becuase the suns reflection! At night When you gaze at the constellations, every star produces an image that's the same size, but your retina isn't sensitive enough to respond to the outer parts of those images except for the brighter stars — which therefore look bigger than the fainter ones.

Explanation:

This is what I found on goog.le a while ago now it might actually help if I’m wrong I apologiz, I hope this was your quistion!

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