Answers
Answer:
(B) h is the function name; t is the input, or independent variable; and h(t) is the output, or dependent variable.
Step-by-step explanation:
You've probably seen this function notation format before, most likely f(x). Other common ones are g(x) and p(x). The f, g, and p are just function names, like the h in this question.
The t in the parentheses is the input, because it's the same as the t in 210 - 15t.
Together, h(t) is the output, which is the exact same as y if you used the formula y = mx + b.
Hope it helps (●'◡'●)
Related Questions
I need the answer ASAP anyone could help me please
Answers
Answer:
Is it the answer is C?
2+4+3+5+1=15
Answer: (C) 15
La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?
Answers
Answer:
Falso.
Step-by-step explanation:
Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:
(a) El exponente es cero.
(b) El exponente es un negativo impar.
(c) El exponente es un negativo par.
(d) El exponente es un positivo impar.
(e) El exponente es un positivo par.
(a) El exponente es cero:
Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.
(b) El exponente es un negativo impar:
Considérese las siguientes expresiones:
[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]
Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:
[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]
[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.
(c) El exponente es un negativo par.
Si [tex]n[/tex] es par, entonces:
[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]
Puesto que [tex]d' = c'[/tex], la proposición es verdadera.
(d) El exponente es un positivo impar.
Considérese las siguientes expresiones:
[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]
[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es impar, entonces:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]
(e) El exponente es un positivo par.
Considérese las siguientes expresiones:
[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]
Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.
Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.
the solution of the quadratic equation x square - 4 x + 4
Answers
Answer:
[tex]\rm x = 2 , 2 [/tex]
Step-by-step explanation:
A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,
[tex]\implies x^2 -4x + 4 = 0 [/tex]
Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,
[tex]\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 [/tex]
Hence the Solution of the equation is 2,2.
Answer:
Step-by-step explanation:
x² - 4x +4 = 0
Factorization method:
Sum = -4
Product = 4
Factor = (-2) ; (-2) {-2 * -2 = 4 & (-2) + (-2) = -4}
x² -4x + 4 = 0
x² - 2x - 2x + (-2)*(-2) = 0
x(x - 2) - 2 (x - 2) = 0
(x - 2) (x - 2) = 0
x - 2 = 0 or x -2 = 0
x = 2 or x = 2
x = 2 , 2
What is the value of x in the equation??????
.
15 points!!
Please hurry :)
Answers
Answer:
-8
Step-by-step explanation:
The vertices of a triangle are P(-6,1), Q(-2,-5) and R(8,1).
Find the equation of the perpendicular bisector of the side QR
Answers
Answer:
Step-by-step explanation:
Find the slope of QR. From that we can find the the slope of the line perpendicular to QR.
Q(-2, -5) & R(8,1)
[tex]Slope \ = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{1-[-5]}{8-[-2]}\\\\=\frac{1+5}{8+2}\\\\=\frac{6}{10}\\\\=\frac{-3}{5}[/tex]
So, the slope of the line perpendicular to QR = -1/m - 1÷ [tex]\frac{-5}{3} = -1*\frac{-3}{5}=\frac{3}{5}[/tex]
Bisector of QR divides the line QR to two half. We have find the midpoint of QR.
Midpoint = [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]
[tex]=(\frac{-2+8}{2},\frac{-5+1}{2})\\\\=(\frac{6}{2},\frac{-4}{2})\\\\=(3,-2)[/tex]
slope = 3/5 and the required line passes through (3 , -2)
y - y1 = m(x-x1)
[tex]y - [-2] = \frac{3}{5}(x - 3)\\\\y + 2 = \frac{3}{5}x-\frac{3}{5}*3\\\\y=\frac{3}{5}x-\frac{9}{5}-2\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{2*5}{1*5}\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{10}{5}\\\\y=\frac{3}{5}x-\frac{19}{5}[/tex]
What’s the equation of the line that passes through the point (5,1) and has a slope of 1
Answers
Answer:
y = x + 4
Step-by-step explanation:
y = mx + b
y = 1x + b
5 = 1 + b
b = 4
y = x + 4
Write in the form a to the power of k, where a is a prime number and k is rational
[tex]\sqrt[4]{27}[/tex]
Answers
Answer:
[tex]{ \tt{27 = {3}^{3} }} \\ { \tt{}} \sqrt[4]{27} = {27}^{ \frac{1}{4} } \\ { \tt{ = {3}^{3( \frac{1}{4}) } }} \\ = { \tt{ {3}^{ \frac{3}{4} } }} \\ { \boxed{ \bf{a = 3 \: \: and \: \: k = \frac{3}{4} }}}[/tex]
For two complementary angles find x. The first angle is 4x+9. The second angle is 2x+27
Answers
Gud luck
Answer:
x = 9
Step-by-step explanation:
When sum of two angles is 90, then they are known as complementary angles.
4x + 9 + 2x + 27 = 90
4x + 2x + 9 + 27 = 90
Combine like terms
6x + 36 = 90
Subtract 36 from both sides
6x = 90 - 36
6x = 54
Divide both sides by 6
x = 54/6
x = 9
pls help:( algebra 1 btw
17(2 + 12g) + 14
Answers
Answer:
204g + 48
Step-by-step explanation:
simplifying the expression
Step 1: Rewrite equation
To start off, let’s rewrite the equation to better understand the problem we are working with.
17(2+12g)+14
Step 2: Distribute
In this type of equation, we will not find an exact answer. Rather, we will simplify the equation by distribution and combining like terms. Let’s start by distributing. To do so, multiply the numbers outside of the parentheses with the numbers on the inside of the parentheses. This will be 17•2 and 17•12g. Let’s do so now.
17(2+12g)+14
34+204g+14
Step 3: Combine like terms
As the final step, we need to combine like terms. This means we add/subtract terms that share the same variable, or lack of. In this case, we need to add 34 and 14 together. Let’s do this now.
34+204g+14
204g+48
This is your final answer. 204g+48 is the new equation. Hope this helps! Comment below for more questions.
6. In a toy factory, 200 wooden closed cylinders of diameter 35 mm and height 7 cm have to be painted. What is the total surface area, in cm², that needs to be painted? (Take pi to be 3.142.)
7. A tank in the shape of a cylinder of diameter 2.4 m and height 6.4 m contains oil to the brim. Find the number of complete cylindrical containers of base radius 8.2 cm and height 28 cm which can be filled by the oil in the tank.
Please help with the 2 questions. thank you!!
Unhelpful answer will be deleted ❌
Correct answer + with explanation will be chosen as the Brainliest Answer ✅
Answers
Answer:
4,895 containers
Step-by-step explanation:
The number of the wooden closed cylinders to be painted, n = 200
The diameter of each cylinder, d = 35 mm = 3.5 cm
The height of each cylinder, h = 7 cm
The surface area of each closed cylinder, A = 2·π·d²/4 + 2·π·(d/2)·h
Where, π = 3.142, we get;
A = 2 × 3.142 × 3.5²/4 + 2 × 3.142 × (3.5/2) × 7 = 96.22375
The surface area of each cylinder, A = 96.22375 cm²
The total surface area, [tex]A_T[/tex] = n × A
∴ [tex]A_T[/tex] = 200 × 96.22375 = 19,244.75
The total surface area that needs to be painted, [tex]A_T[/tex] = 19,22375 cm²
7. The base diameter of the tank, d₁ = 2.4 m = 240 cm
The height of the tank, h₁ = 6.4 m = 640 cm
The base radius of each cylinder container, r = 8.2 cm
The height of each cylindrical container, h₂ = 28 cm
The number of cylindrical containers which can be filled by the oil in the tank, n, is given as follows;
n = (The volume of the tank)/(The volume of a cylinder)
The volume of the tank, V₁ = π·(d²/4)·h₁
∴ V₁ = π × (240²/4) × 640 = 9216000·π
The volume of the tank, V₁ = 9216000·π cm²
The volume of a cylinder, V₂ = π·r²·h₂
∴ V₂ = π × 8.2² × 28 = 1,882.72·π
The volume of a cylinder, V₂ = 1,882.72·π cm²
The number of containers, n = 9216000·π/1882.72·π ≈ 4,895.045
Therefore, the number of complete cylindrical containers that can be filed by the oil in the tank, n = 4,895 containers
Answer:
6) About 19,244.75 square centimeters.
7) About 4895 containers.
Step-by-step explanation:
Question 6)
We need to paint 200 wooden closed cylinders of diameter 35 mm and height 7 cm. And we want to find the total surface area that needs to be painted.
First, since the diameter is 35 mm, this is equivalent to 3.5 cm.
The radius is half the diameter, so the radius of each cylinder is 1.75 cm.
Recall that the surface area of a cylinder is given by the formula:
Where r is the radius and h is the height.
Therefore, the surface area of a single cylinder will be:
Then the total surface area for 200 cylinders will be:
Question 7)
We know that the tank has a diameter of 2.4 m and a height of 6.4 m.
Since its diamter is 2.4 m, then its radius is 1.2 m.
Find the total volume of the tank. The volume for a cylinder is given by:
Since r = 1.2 and h = 6.4:
Each container has a base radius of 8.2 cm and a height of 28 cm.
So, the radius of each container is 0.082 m and the height is 0.28 m.
Then the volume of each container is:
Then to find the number of containers that can be filled by the tank, we can divide the two values. Hence:
Help and explain !!!!( Solve using the substitute method )
Answers
Answer:
x=13
y= -9
(13, -9)
Step-by-step explanation:
If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.
Then, we can take that equation and plug it into the bottom one so
3x+4(4-x)=3
Simplify:
3x+16-4x=3
-x=-13
x=13
We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)
So, 13+y=4 which y= -9
A florist has to pay $7.50 each time a customer chooses a competitor for the delivery of flowers. Which expression
shows the amount that the florist earns if p people use a competitor for delivery, and the company makes $320.00
before any payment is made to their competitors?
0 320-7.500
0 320+ 7.500
7500-320
07500 + 320 help!
Answers
Answer:
320-7.500
Step-by-step explanation:
Peter’s father told peter to buy four-tenths of a pound of chili powder. Each package is marked with its weight. What package should Peter guy?
Answers
Answer:
The weight of the package of chili powder is 181.44 g.
Step-by-step explanation:
Amount of chili powder = 4/10 pound
1 pound = 453.6 g
So,
4/10 pound = 4/10 x 453.6 = 181.44 g
The weight of the package of chili powder is 181.44 g.
[tex]\text{Solve for 'x'.}\\\\3x + 15 = 33\\\\\\text{Thank you.}[/tex]
Answers
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]x=6[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Solving for 'x'...}}\\\\3x + 15 = 33\\--------------\\\rightarrow 3x + 15 - 15 = 33 - 15\\\\\rightarrow 3x = 18\\\\\rightarrow \frac{3x=18}{3}\\\\\rightarrow \boxed{x = 6}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Answer:
x=6
Step-by-step explanation:
3x+15=33
or as, 3x=33-15
or as, 3x=18
x=18/3=6
so we got 6 is the answer
A cable 45 m long runs from the top of a utility pole to a point on the ground 40 m from the base of the pole. How tall is the utility pole, to the nearest tenth?
20.6 m
85 m
5 m
60.2 m
Answers
Answer:
20.6 m
Step-by-step explanation:
Hi there!
Assuming that the utility pole makes a 90-degree angle with the ground, this scenario creates a right triangle.
The 45 m-long cable is the hypotenuse and the 40 m between the base of the pole and the cable is one of the legs.
We must solve for the height of the utility pole, which is essentially the other leg of the right triangle.
We can use the Pythagorean theorem: [tex]a^2+b^2=c^2[/tex] where a and b are the legs and c is the hypotenuse
Plug in the known information (leg=40, hyp=45)
[tex]40^2+b^2=45^2\\1600+b^2=2025\\b^2=2025-1600\\b^2=425\\b=20.6[/tex]
Therefore, when rounded to the nearest tenth, the height of the utility pole is 20.6 m.
I hope this helps!
What
Is the volume of this object
Answers
Answer:
100
Step-by-step explanation:
5x4=20
20x5=100
HELP ASAP 10 POINTS AND BRAINLIST
Answers
Step-by-step explanation:
hope it helps you...........
Find z
Help me please
Answers
Answer: z=56
Step-by-step explanation:
Based on the figure, we can determine that 3y+8=68 and 4x=2z. With the knowledge that a trapezoid has 360°, we can first find the value of y to get the angle measures of the top angles. We can then subtract that from 360°.
3y+8=68 [subtract both sides by 8]
3y=60 [divide both sides by 3]
y=20
We now know the value of y is 20, but that is not relevant to solving this problem because we already know that the top angles are 68° each. So, we can subtract that from 360.
360-68-68=224
Now, we know that the bottom 2 angles have to add up to 224. Therefore, we can come up with 2 equations.
Equation 1: 4x=2z
Equation 2: 4x+2z=224
We can manipulate Equation 1 to be [tex]x=\frac{1}{2}z[/tex]. Once we plug that into Equation 2, we can find the value of z.
[tex]4(\frac{1}{2} z)+2z=224[/tex] [multiply]
[tex]2z+2z=224[/tex] [add]
[tex]4z=224[/tex] [divide both sides by 4]
[tex]z=56[/tex]
Now, we know that z=56.
The volume of a cuboid is 975cm3.
The length is 15cm and the width is 130mm.
Work out the height of the cuboid in cm
Answers
Answer:
Solution given:
Volume of cuboid=975cm³
length[l]=15cm
width[w]=130mm=13cm
height [h]=?
we have:
Volume of cuboid=l*w*h
975=15*13*h
h=[tex]\frac{975}{195}=5cm[/tex]
The height of the cuboid is 5cm.
100 x 77 + 72 ÷ 4 = ? (RIGHT ANSWER GETS BRAINLIEST)
Answers
Step-by-step explanation:
100*77+72/4
100*77+18
7700+18
7718
Answer:
Step-by-step explanation:
54 ×100=5400
5400+77=5477
5477÷2 = 2738.5
How do I do this problem?
Answers
Step-by-step explanation:
here is the answer to your question
Answer:
Step-by-step explanation:
I would start from the beginning and find the slope myself, just so I know what's going on (as opposed to being dropped in the middle of the problem). The slope formula is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] and for us:
[tex]m=\frac{5-3}{4-3}=2[/tex] so the slope is indeed 2. Now we need to write the equation in slope-intercept form. I find it easier to first write the equation in point-slope form and then solve it for y. Point-slope form is
[tex]y-y_1=m(x-x_1)[/tex] where m is the slope (2) and x1 and y 1 are from one of the coordinates (whichever one you want; as long as you do the math correctly, you will NOT get an incorrect answer. In other words, you can't pick the "wrong" point to use to write the equation.) I'm going to use (3, 3):
y - 3 = 2(x - 3) and
y - 3 = 2x - 6 and
y = 2x - 6 + 3 so
y = 2x - 3 and that's your equation. Of course, you will enter a (-3) in that box with the ? in it.
Apply the distributive property to create an equivalent expression.
\dfrac15(15+10k) =
5
1
(15+10k)=start fraction, 1, divided by, 5, end fraction, left parenthesis, 15, plus, 10, k, right parenthesis, equals
Answers
Answer:
3 + 2k
Step-by-step explanation:
Given:
1/5(15 + 10k)
= (1/5 * 15) + (1/5 * 10k)
= (1 * 15)/5 + (1 * 10k)/5
= 15/5 + 10k/5
= 3 + 2k
Therefore,
1/5(15 + 10k) = 3 + 2k
The equivalent expression is 3 + 2k
Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form.
19,10,1,...
Answers
[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]
How do I simplify the expression
Answers
Is this enough for you ?
What are the coordinates of the terminal point for 0 = 4pi/3
Answers
Answer:
I hope this helps. There is a link
b
So what is that distance well we know that to get to negative 4 pi over 3 we took negative pi and travelled pi over 3.. So this is just pi over 3.. So our reference angle would be pi over 3.
Step-by-step explanation:
As part of the math assignment, jane makes a graph pf her cookie function. Before handling it in, she compares it to the table. Do the table and the graph represent the same function
Answers
Answer:No
Step-by-step explanation:
Twenty-seven minus of a number (x) is not more than 36. What is the number?
A.
x > 42
B.
x ≥ -6
C.
x < 3
D.
x ≤ -6
Answers
Answer:
D
Step-by-step explanation:
dfjhygcftujnnbiijjhfsrfhhhuu
2+2
f re e
points or whatever
Answers
Answer:
2+2 = 4
Step-by-step explanation:
Hope this helps.
Answer:
2 + 2 is 4 my guy
Step-by-step explanation:
thx for the points
10-
10
A. Exponential growth
B. Linear increasing
C. Exponential decay
D. Linear decreasing
Answers
what is the answer to this?
Answers
Answer:
any number
Step-by-step explanation:
It is because all real numbers are solutions to this
Answer:
x = infinite solutions
Step-by-step explanation:
[tex]\frac{2}{3}(6x+ 3) = 4x + 2\\\\\frac{12}{3}x + \frac{2 \times 3}{3} = 4x + 2\\\\4x + 2 = 4x + 2 \\\\Which\ is \ true \ for \ all \ values \ of \ x.[/tex]
