Can someone help me with this math homework please!

Answer:

2+2 = 4

Step-by-step explanation:

Hope this helps.

Answer:

2 + 2 is 4 my guy

Step-by-step explanation:

thx for the points

Answer:

The weight of the package of chili powder is 181.44 g.

Step-by-step explanation:

Amount of chili powder = 4/10 pound

1 pound = 453.6 g

So,

4/10  pound = 4/10 x 453.6 = 181.44 g

The weight of the package of chili powder is 181.44 g.  

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x=6[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\3x + 15 = 33\\--------------\\\rightarrow 3x + 15 - 15 = 33 - 15\\\\\rightarrow 3x = 18\\\\\rightarrow \frac{3x=18}{3}\\\\\rightarrow \boxed{x = 6}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

x=6

Step-by-step explanation:

3x+15=33

or as, 3x=33-15

or as, 3x=18

x=18/3=6

so we got 6 is the answer

Answer:No

Step-by-step explanation:

Answer: z=56

Step-by-step explanation:

Based on the figure, we can determine that 3y+8=68 and 4x=2z. With the knowledge that a trapezoid has 360°, we can first find the value of y to get the angle measures of the top angles. We can then subtract that from 360°.

3y+8=68        [subtract both sides by 8]

3y=60            [divide both sides by 3]

y=20

We now know the value of y is 20, but that is not relevant to solving this problem because we already know that the top angles are 68° each. So, we can subtract that from 360.

360-68-68=224

Now, we know that the bottom 2 angles have to add up to 224. Therefore, we can come up with 2 equations.

Equation 1: 4x=2z

Equation 2: 4x+2z=224

We can manipulate Equation 1 to be [tex]x=\frac{1}{2}z[/tex]. Once we plug that into Equation 2, we can find the value of z.

[tex]4(\frac{1}{2} z)+2z=224[/tex]         [multiply]

[tex]2z+2z=224[/tex]              [add]

[tex]4z=224[/tex]                      [divide both sides by 4]

[tex]z=56[/tex]

Now, we know that z=56.

Answer:

Solution given:

Volume of cuboid=975cm³

length[l]=15cm

width[w]=130mm=13cm

height [h]=?

we have:

Volume of cuboid=l*w*h

975=15*13*h

h=[tex]\frac{975}{195}=5cm[/tex]

The height of the cuboid is 5cm.

Step-by-step explanation:

here is the answer to your question

Answer:

Step-by-step explanation:

I would start from the beginning and find the slope myself, just so I know what's going on (as opposed to being dropped in the middle of the problem). The slope formula is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] and for us:

[tex]m=\frac{5-3}{4-3}=2[/tex] so the slope is indeed 2. Now we need to write the equation in slope-intercept form. I find it easier to first write the equation in point-slope form and then solve it for y. Point-slope form is

[tex]y-y_1=m(x-x_1)[/tex] where m is the slope (2) and x1 and y 1 are from one of the coordinates (whichever one you want; as long as you do the math correctly, you will NOT get an incorrect answer. In other words, you can't pick the "wrong" point to use to write the equation.) I'm going to use (3, 3):

y - 3 = 2(x - 3) and

y - 3 = 2x - 6 and

y = 2x - 6 + 3 so

y = 2x - 3 and that's your equation. Of course, you will enter a (-3) in that box with the ? in it.

Answer:

x = 9

Step-by-step explanation:

When sum of two angles is 90, then they are known as complementary angles.

4x + 9  + 2x + 27 = 90

4x + 2x + 9 + 27 = 90

Combine like terms

6x + 36 = 90

Subtract 36 from both sides

6x = 90 - 36

6x = 54

Divide both sides by 6

x = 54/6

x = 9

Answer:

[tex]{ \tt{27 = {3}^{3} }} \\ { \tt{}} \sqrt[4]{27} = {27}^{ \frac{1}{4} } \\ { \tt{ = {3}^{3( \frac{1}{4}) } }} \\ = { \tt{ {3}^{ \frac{3}{4} } }} \\ { \boxed{ \bf{a = 3 \: \: and \: \: k = \frac{3}{4} }}}[/tex]

Answer:

320-7.500

Step-by-step explanation:

Answer:

-8

Step-by-step explanation:

Answer:

100

Step-by-step explanation:

5x4=20

20x5=100

Answer:

204g + 48

Step-by-step explanation:

simplifying the expression

Answer:

any number

Step-by-step explanation:

It is because all real numbers are solutions to this

Answer:

x = infinite solutions

Step-by-step explanation:

[tex]\frac{2}{3}(6x+ 3) = 4x + 2\\\\\frac{12}{3}x + \frac{2 \times 3}{3} = 4x + 2\\\\4x + 2 = 4x + 2 \\\\Which\ is \ true \ for \ all \ values \ of \ x.[/tex]

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

Answer:

[tex]\rm x = 2 , 2 [/tex]

Step-by-step explanation:

A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,

[tex]\implies x^2 -4x + 4 = 0 [/tex]

Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,

[tex]\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 [/tex]

Hence the Solution of the equation is 2,2.

Answer:

Step-by-step explanation:

x² - 4x  +4 = 0

Factorization method:

Sum = -4

Product = 4

Factor = (-2) ; (-2)    {-2 * -2 = 4  & (-2) + (-2) = -4}

x² -4x + 4 = 0

x² - 2x - 2x  + (-2)*(-2) = 0

x(x - 2) - 2 (x - 2) = 0

(x - 2) (x - 2) = 0

x - 2 = 0  or x -2 = 0

 x = 2      or x = 2

x = 2 , 2

Answer:

D

Step-by-step explanation:

dfjhygcftujnnbiijjhfsrfhhhuu

[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]

Step-by-step explanation:

hope it helps you...........

Answer:

Step-by-step explanation:

Find the slope of QR. From that we can find the the slope of the line perpendicular to QR.

Q(-2, -5)   & R(8,1)

[tex]Slope \ = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{1-[-5]}{8-[-2]}\\\\=\frac{1+5}{8+2}\\\\=\frac{6}{10}\\\\=\frac{-3}{5}[/tex]

So, the slope of the line perpendicular to QR =  -1/m - 1÷ [tex]\frac{-5}{3} = -1*\frac{-3}{5}=\frac{3}{5}[/tex]

Bisector of QR divides the line QR to two half. We have find the midpoint of QR.

Midpoint = [tex](\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]

               [tex]=(\frac{-2+8}{2},\frac{-5+1}{2})\\\\=(\frac{6}{2},\frac{-4}{2})\\\\=(3,-2)[/tex]

slope = 3/5  and the required line passes through (3 , -2)

y - y1 = m(x-x1)

[tex]y - [-2] = \frac{3}{5}(x - 3)\\\\y + 2 = \frac{3}{5}x-\frac{3}{5}*3\\\\y=\frac{3}{5}x-\frac{9}{5}-2\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{2*5}{1*5}\\\\y=\frac{3}{5}x-\frac{9}{5}-\frac{10}{5}\\\\y=\frac{3}{5}x-\frac{19}{5}[/tex]

Answer:

I hope this helps. There is a link

b

So what is that distance well we know that to get to negative 4 pi over 3 we took negative pi and travelled pi over 3.. So this is just pi over 3.. So our reference angle would be pi over 3.

Step-by-step explanation:

Answer:

Is it the answer is C?

2+4+3+5+1=15

Answer:

3 + 2k

Step-by-step explanation:

Given:

1/5(15 + 10k)

= (1/5 * 15) + (1/5 * 10k)

= (1 * 15)/5 + (1 * 10k)/5

= 15/5 + 10k/5

= 3 + 2k

Therefore,

1/5(15 + 10k) = 3 + 2k

The equivalent expression is 3 + 2k

Answer:

20.6 m

Step-by-step explanation:

Hi there!

Assuming that the utility pole makes a 90-degree angle with the ground, this scenario creates a right triangle.

The 45 m-long cable is the hypotenuse and the 40 m between the base of the pole and the cable is one of the legs.

We must solve for the height of the utility pole, which is essentially the other leg of the right triangle.

We can use the Pythagorean theorem: [tex]a^2+b^2=c^2[/tex] where a and b are the legs and c is the hypotenuse

Plug in the known information (leg=40, hyp=45)

[tex]40^2+b^2=45^2\\1600+b^2=2025\\b^2=2025-1600\\b^2=425\\b=20.6[/tex]

Therefore, when rounded to the nearest tenth, the height of the utility pole is 20.6 m.

I hope this helps!

Answer:

4,895 containers

Step-by-step explanation:

The number of the wooden closed cylinders to be painted, n = 200

The diameter of each cylinder, d = 35 mm = 3.5 cm

The height of each cylinder, h = 7 cm

The surface area of each closed cylinder, A = 2·π·d²/4 + 2·π·(d/2)·h

Where, π = 3.142, we get;

A = 2 × 3.142 × 3.5²/4 + 2 × 3.142 × (3.5/2) × 7 = 96.22375

The surface area of each cylinder, A = 96.22375 cm²

The total surface area, [tex]A_T[/tex] = n × A

∴ [tex]A_T[/tex] = 200 × 96.22375 = 19,244.75

The total surface area that needs to be painted, [tex]A_T[/tex] = 19,22375 cm²

7. The base diameter of the tank, d₁ = 2.4 m = 240 cm

The height of the tank, h₁ = 6.4 m = 640 cm

The base radius of each cylinder container, r = 8.2 cm

The height of each cylindrical container, h₂ = 28 cm

The number of cylindrical containers which can be filled by the oil in the tank, n, is given as follows;

n = (The volume of the tank)/(The volume of a cylinder)

The volume of the tank, V₁ = π·(d²/4)·h₁

∴ V₁ = π × (240²/4) × 640 = 9216000·π

The volume of the tank, V₁ = 9216000·π cm²

The volume of a cylinder, V₂ = π·r²·h₂

∴ V₂ = π × 8.2² × 28 = 1,882.72·π

The volume of a cylinder, V₂ = 1,882.72·π cm²

The number of containers, n = 9216000·π/1882.72·π ≈ 4,895.045

Therefore, the number of complete cylindrical containers that can be filed by the oil in the tank, n = 4,895 containers

Answer:

6) About 19,244.75 square centimeters.

7)  About 4895 containers.

Step-by-step explanation:

Question 6)

We need to paint 200 wooden closed cylinders of diameter 35 mm and height 7 cm. And we want to find the total surface area that needs to be painted.

First, since the diameter is 35 mm, this is equivalent to 3.5 cm.

The radius is half the diameter, so the radius of each cylinder is 1.75 cm.

Recall that the surface area of a cylinder is given by the formula:

Where r is the radius and h is the height.

Therefore, the surface area of a single cylinder will be:

Then the total surface area for 200 cylinders will be:

Question 7)

We know that the tank has a diameter of 2.4 m and a height of 6.4 m.

Since its diamter is 2.4 m, then its radius is 1.2 m.

Find the total volume of the tank. The volume for a cylinder is given by:

Since r = 1.2 and h = 6.4:

Each container has a base radius of 8.2 cm and a height of 28 cm.

So, the radius of each container is 0.082 m and the height is 0.28 m.

Then the volume of each container is:

Then to find the number of containers that can be filled by the tank, we can divide the two values. Hence:

Step-by-step explanation:

100*77+72/4

100*77+18

7700+18

7718

Answer:

Step-by-step explanation:

54 ×100=5400

5400+77=5477

5477÷2 = 2738.5

Answer:

x=13

y= -9

(13, -9)

Step-by-step explanation:

If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.

Then, we can take that equation and plug it into the bottom one so

3x+4(4-x)=3

Simplify:

3x+16-4x=3

-x=-13

x=13

We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)

So, 13+y=4 which y= -9

Answer:

y = x + 4

Step-by-step explanation:

y = mx + b

y = 1x + b

5 = 1 + b

b = 4

y = x + 4