1. C
2.A
3.D
4.B
Here's the answer.
Answer:
1 C
2 A
3 D
4 B
Step-by-step explanation:
The y-intercept is whenever the graph crossses the y-axis, so the input will always be 0.
When f(x) > 0, that's when the output is greater than 0, so it would be above the x-axis.
The x-intercept is whenever the graph crosses the x-axis, so the output will always be 0.
Hope that helps (●'◡'●)
PLEASE HELP, solve for X
Answer:
27
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(48+x) * 48 = 60^2
(48+x)48=3600
Divide each side by 48
48+x =75
Subtract 48
48+x-48 = 75-48
x =27
Please help solve for x
Answer:
8.49
Step-by-step explanation:
there is a little formula related to the famous formula of Pythagoras.
it says that the height of a triangle is the square root of the product of both segments of the baseline (the segments the height splits the baseline into).
so, x is actuality the height of the triangle.
x = sqrt(3×24) = sqrt(72) = 8.49
Tell whether the number pair (2,1) is a solution to the equation y = 3x - 5.
Answer:
Yes
Step-by-step explanation:
Plugging in the values in the equation, we have
1=3*(2)-5, 1=1 which is TRUE
Which equation is equivalent to x^2 +24-8=0?
A.(x+12)^2 =152
B.(x-12)^2=136
C.(x+8)^2=144
D.(x+12)^2 =144
Answer:
D) is your correct answer
Answer choices:
A. 216
B. 367.2
C. 297.4
D. 432
pls help me!!
Answer:
216
Step-by-step explanation:
Volume of prism = BH
B -> Base area
Area of base:
b = 10 mi
h = 3.6mi
Area of the triangular base = [tex]\dfrac{1}{2}*b*h[/tex]
[tex]=\dfrac{1}{2}*10*3.6\\\\= 18 \ mi^{2}[/tex]
H = 12 mi
Volume of prism = 18 * 12 = 216 cubic mi
help me please its confusing pleasee
Answer:
a) -8x³+x²+6x
d) 16x²-9
Step-by-step explanation:
a) -2x(x+4x²)+3(x²+2x)
Expand each bracket:
-2x(x+4x²)
As the -2x is on the outside of the bracket, you have to times everything inside the bracket by -2x.
-2x times x equals -2x²
-2x times 4x² equals -8x³
Then we expand the other bracket:
3(x²+2x)
3 times x² equals 3x²
3 times 2x equals 6x
We then put all of it together:
-2x²-8x³+3x²+6x
Collect like terms:
-8x³+x²+6x
b) (4x-3)(4x+3)
We will use the FOIL method:
F-First
O-outer
I-Inner
L-Last
Times the first two terms in each bracket:
4x times 4x equals 16x²
Times the outer terms in the bracket:
4x times 3 equals 12x
Times the inside terms in the bracket:
-3 times 4x equals -12x
Times the last terms in the bracket:
-3 times 3 equals -9
Put it together:
16x²+12x-12x-9
The 12x and -12x cancel out to leave 16x²-9
Hope this helps :)
maths class 9
Multiply: 4√12 2√12
Answer:
[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]
Tuto
Combine any like terms in the expression. If there are no like terms, rewrite the expression.
8r + 9pg - pg - pq
Answer:
8r+8pg-pq
Step-by-step explanation:
The subtractable pg cancels out one of the 9 pg's. So 9 pg-1 pg= 8 pg
Hope this helps!
which equation represent this relation
Answer:
hello,
answer A c=n+2
Step-by-step explanation:
if n=0 then c=2
if n=2 then c=4
slope=m=(4-2)/(2-0) =2/2=1
c-2=1*(n-0)
c=n+2
Factorize :solve no g and h
Answer:
Hello,
do you mean factorise but not solve ?
Just one formula:
[tex]\boxed{a^2-b^2=(a-b)(a+b)}[/tex]
Step-by-step explanation:
[tex]g)\\\\16x^3y-81xy^5\\\\=xy(16x^2-81y^4)\\\\=xy(4x^2+9y^2)(4x^2-9y^2)\\\\=xy(2x-3y)(2x+3)(4x^2+9y^2)\\\\\\\\h)\\\\x^8-y^8\\\\=(x^4+y^4)(x^4-y^4)\\\\=(x^4+y^4)(x^2+y^2)(x^2-y^2)\\\\=(x-y)(x+y)(x^2+y^2)(x^4+y^4)\\[/tex]
Answer:
here only one formula to use in both question
a^2+b^2= (a+b)(a-b)
Someone help please
Answer: Choice A
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex]
============================================================
Explanation:
Recall that [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex] and [tex]\cot(x) = \frac{\cos(x)}{\sin(x)}[/tex]. The connection between tangent and cotangent is simply involving the reciprocal
From this, we can say,
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.
All of this shows why [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is identical to [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
Therefore, [tex]\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.
You can visually confirm that [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is the same as [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.
225125 in base 6 divided by 101 in base 6
225125₆/101₆ = 2225₆
One way to arrive at this is to convert both given numbers to base 10, compute the quotient in base 10, then convert back to base 6.
101₆ = 1×6² + 0×6¹ + 1×6⁰ = 37
225125₆ = 2×6⁵ + 2×6⁴ + 5×6³ + 1×6² + 2×6¹ + 5×6⁰ = 19,277
So we have
225125₆/101₆ = 19,277/37 = 521
Next,
521 = 2×216 + 89 = 2×6³ + 89
89 = 2×36 + 17 = 2×6² + 17
17 = 2×12 + 5 = 2×6¹ + 5×6⁰
and so
521 = 2×6³ + 2×6² + 2×6¹ + 5×6⁰ = 2225₆
Or you can use the long division algorithm. Division in base 6 is the same as in base 10, except numerals range from 0 to 5 instead of 0 to 9. See if you can follow this diagram (replaced with an attachment)
I am struggling with this question anyone help
9514 1404 393
Answer:
b, c
Step-by-step explanation:
The factor (x+7) is common to both numerator and denominator. The function can be simplified by cancelling that factor.
y = (x -3)/(x -9) . . . . . . x ≠ -7
The restriction x ≠ -7 is put on the simplified function because the original function is undefined there. The denominator factor x+7 makes the denominator 0 at that point.
The point at x=-7 is called "hole" in the graph. A properly drawn graph will show the function is undefined there (has a hole).
__
The denominator of the simplified function is zero when x=9. This means there is a vertical asymptote at x=9.
__
The ratio of the highest-degree terms of the numerator and denominator will tell you the end behavior of the function — its value when x is large. Here, that ratio is y = x/x = 1. This represents a horizontal asymptote at y=1. The function approaches this line as x gets large, but never reaches it.
The appropriate descriptors are ...
Asymptote: x=9, y=1Hole: x=-7Given the a center (-1, -2) and a radius r = 2. Identify the circle.
Answer:
1st option
1st graph has the centre on (-1,-2) and the distance of the circumference from the centre is 2
Answered by GAUTHMATH
what's the median of -13.78, -3.01, -2.41, -0.28, 0.66, 0.67, 1.05, 1.39, 2.03, 2.2, 2.64, 4.02
Which could be the first step in simplifying this expression? Check all that apply.
Answer:
[tex](x^{-3})^2[/tex]
Step-by-step explanation:
applying the exponent rule to the inside of the bracket, x^3 x x^-6 = x^-3 since you add the exponents
If m2 DOC = 44º and m2 COB = 80°,
find the measure of the indicated arc
in circle o.
mCB = [?]°
Answer:
80°
Step-by-step explanation:
m<COB = 80°, it's the central angle for arc CB,
so mCB = 80°
\sqrt{2x+1} = 2+\sqrt{x-3}
Answer:
Square both sides
√(2x+1)=2+√(x-3)
or, 2x+1=(2+√(x-3))²
solving it you'll get two values of x, which are,
x = 4 and x = 12
Answer:
Hello,
x=4 or x=12
Step-by-step explanation:
[tex]\sqrt{2x+1} =2+\sqrt{x-3} \\\\2x+1=4+4\sqrt{x-3} +(x-3)\\\\2x+1-x+3-4=4\sqrt{x-3} \\\\x=4\sqrt{x-3} \\\\ x^2-16x+48=0\\\\\Delta=16^2-4*48=64=8^2\\\\x=\dfrac{16-8}{2} \ or x=\dfrac{16+8}{2}\\\\x=4 \ or\ x=12\\\\Since \ we\ have \ squared \ we\ must\ verify\ the \ solutions\ found:\\\\x=4 \Longrightarrow \sqrt{2*4+1} =? 2+\sqrt{4-3} \Longrightarrow 3 =? 2+1 \\\\x=12 \Longrightarrow \sqrt{2*12+1} =? 2+\sqrt{12-3} \Longrightarrow 5 =? 2+3 \\\\[/tex]
There were 642 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who passed was 5 times the number of students who failed. Find the number of students who passed and the number who failed.
Answer:
535 students passed and 107 students failed
Step-by-step explanation:
Create a system of equations where p is the number of students who passed and f is the number of students who failed:
p + f = 642
p = 5f
Solve by substitution by plugging in 5f as p into the first equation, then solving for f:
p + f = 642
5f + f = 642
6f = 642
f = 107
So, 107 students failed.
Find how many students passed by multiplying this by 5:
107(5)
= 535
535 students passed and 107 students failed.
Deion is saving up to buy a new phone. He already has $95 and can save an additional $7 per week using money from his after school job. How much total money would Deion have after 6 weeks of saving? Also, write an expression that represents the amount of money Deion would have saved in w weeks.
The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137.
What is an expression?A statement expressing the equality of two mathematical expressions is known as an equation.
A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.
An expression is a mathematical proof of the equality of two mathematical expressions.
As per the given,
Initial fixed money = $95
Per week saving $7/week
Total money = fixed money + money in w weeks.
⇒ 95 + 7w
For 6 weeks, w = 6
⇒ 95 + 7× 6 = $137.
Hence "The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137".
To learn more about expression,
https://brainly.com/question/14083225
#SPJ3
Which of the following has all the justifications Kelsey used to solve this equation?
(9th grade Algerbra 1)
16. What is the measure of ZAOB?
Find the value of x and y in the following figure
Step-by-step explanation:
y+80+70=180
y+150=180
y=30
Now you can, easily find x
Alex wants to test the reliability of “lie detector tests,” or polygraph tests. He performs a polygraph test on a random sample of 12 individuals. If there is more than a 50% chance that the tests result in no false positives (that is, the test does not result in a true statement being recorded as a lie), Alex will conclude that the tests are reliable. If the probability of a lie detector test resulting in a false positive is 5.5%, what will Alex conclude? Use Excel to find the probability, rounding to three decimal places.
The correct statement is test is reliable and authentic as the probability of no false positives is more than 0.5
Given that
[tex]H_o:P= 0.50\\\\H_1:P>0.50[/tex]
Now following calculations to be done to reach the conclusion:
There is no false positive as
= 100 - 5.5
= 94.5%
[tex]\hat P =0.945, n = 12[/tex]
Now
[tex]z = \frac{\hat P - P}{\sqrt\frac{P(1-P)}{n} }\\\\=\frac{0.945-0.5}{\sqrt\frac{0.5\times0.5}{12} } \\\\= 3.08[/tex]
So
P value = P(z >3.08) = 0.0010
Therefore we can conclude that test is reliable and authentic as the probability of no false positives is more than 0.5
Learn more about the polygraph test here:
brainly.com/question/3790493
In ATUV, Y is the centroid. If TY = 30, what is YW?
A.15
B.45
C.30
D.60
We know at centroid medians bisect each other in the ratio 2:1.
TY=30Let YW be x[tex]\\ \sf\longmapsto TY=2x[/tex]
[tex]\\ \sf\longmapsto 2x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{2}[/tex]
[tex]\\ \sf\longmapsto x=15[/tex]
Answer:
A
Step-by-step explanation:
On the median TW the distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , then
YW = [tex]\frac{1}{2}[/tex] × TY = [tex]\frac{1}{2}[/tex] × 30 = 15
find the slope of the tangent line of the curve r = cos (3theta) at theta = pi / 3
The slope of the tangent line to the curve at a point (x, y) is dy/dx. By the chain rule, this is equivalent to
dy/dθ × dθ/dx = (dy/dθ) / (dx/dθ)
where y = r(θ) sin(θ) and x = r(θ) cos(θ). Then
dy/dθ = dr/dθ sin(θ) + r(θ) cos(θ)
dx/dθ = dr/dθ cos(θ) - r(θ) sin(θ)
Given r(θ) = cos(3θ), we have
dr/dθ = -3 sin(3θ)
and so
dy/dx = (-3 sin(3θ) sin(θ) + cos(3θ) cos(θ)) / (-3 sin(3θ) cos(θ) - cos(3θ) sin(θ))
When θ = π/3, we end up with a slope of
dy/dx = (-3 sin(π) sin(π/3) + cos(π) cos(π/3)) / (-3 sin(π) cos(π/3) - cos(π) sin(π/3))
dy/dx = -cos(π/3) / sin(π/3)
dy/dx = -cot(π/3) = -1/√3
Calculus!
The volume of a substance, A, measured in cubic centimeters increases according to the exponential growth model dA/dt = 0.3A, where t is measured in hours. The volume of another substance, B, also measured in cubic centimeters increases at a constant rate of 1 cm^3 per hour according to the linear model dB/dt = 1. At t = 0, substance A has a volume A(0) = 3 and substance B has size B(0) = 5. At what time will both substances have the same volume?
Would it be correct to write the growth model of substance B as x + 5? And how could I write the growth model of substance A? Thank you in advance, and sorry for the poor formatting.
Answer:
The two substances will have the same volume after approximately 3.453 hours.
Step-by-step explanation:
The volume of substance A (measured in cubic centimeters) increases at a rate represented by the equation:
[tex]\displaystyle \frac{dA}{dt} = 0.3 A[/tex]
Where t is measured in hours.
And substance B is represented by the equation:
[tex]\displaystyle \frac{dB}{dt} = 1[/tex]
We are also given that at t = 0, A(0) = 3 and B(0) = 5.
And we want to find the time(s) t for which both A and B will have the same volume.
You are correct in that B(t) is indeed t + 5. The trick here is to multiply both sides by dt. This yields:
[tex]\displaystyle dB = 1 dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int 1 \, dB = \int 1 \, dt[/tex]
Integrate. Remember the constant of integration!
[tex]\displaystyle B(t) = t + C[/tex]
Since B(0) = 5:
[tex]\displaystyle B(0) = 5 = (0) + C \Rightarrow C = 5[/tex]
Hence:
[tex]B(t) = t + 5[/tex]
We can apply the same method to substance A. This yields:
[tex]\displaystyle dA = 0.3A \, dt[/tex]
We will have to divide both sides by A:
[tex]\displaystyle \frac{1}{A}\, dA = 0.3\, dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int \frac{1}{A} \, dA = \int 0.3\, dt[/tex]
Integrate:
[tex]\displaystyle \ln|A| = 0.3 t + C[/tex]
Raise both sides to e:
[tex]\displaystyle e^{\ln |A|} = e^{0.3t + C}[/tex]
Simplify:
[tex]\displaystyle |A| = e^{0.3t} \cdot e^C = Ce^{0.3t}[/tex]
Note that since C is an arbitrary constant, e raised to C will also be an arbitrary constant.
By definition:
[tex]\displaystyle A(t) = \pm C e^{0.3t} = Ce^{0.3t}[/tex]
Since A(0) = 3:
[tex]\displaystyle A(0) = 3 = Ce^{0.3(0)} \Rightarrow C = 3[/tex]
Therefore, the growth model of substance A is:
[tex]A(t) = 3e^{0.3t}[/tex]
To find the time(s) for which both substances will have the same volume, we can set the two functions equal to each other:
[tex]\displaystyle A(t) = B(t)[/tex]
Substitute:
[tex]\displaystyle 3e^{0.3t} = t + 5[/tex]
Using a graphing calculator, we can see that the intersect twice: at t ≈ -4.131 and again at t ≈ 3.453.
Since time cannot be negative, we can ignore the first solution.
In conclusion, the two substances will have the same volume after approximately 3.453 hours.
Find the value of x. PLEASE HELP ASAP!
A.4
B. 16
С. 5
D. 12
Answer: x>12
so i think x is 16.
Which of the following best describes the slope of the line below?
A. Zero
B. Negative
C. Positive
< PREVIOUS
Answer:
A. Zero.
Step-by-step explanation:
Technically, the correct answer is "undefined", as there will be infinite change in the slope amount. However, of all the given choices, Zero should be the best answer. However, if it is wrong, do ask your teacher, and state that undefined should be the answer choice, and that credit should be rewarded for such.
i need help with this question pls! :)
Hi there!
[tex]\large\boxed{\text{9 quarters}}[/tex]
We can let x = dimes and y = quarters.
We know that one dime = $0.10 and a quarter = $0.25, so:
$3.05 = $0.10x + $0.25y
And:
17 = x + y
Solve the system of equations. We can rearrange the bottom equation to create an expression equal to y:
17 - x = y
Substitute this into the top equation for y:
3.05 = 0.10x + 0.25(17 - x)
Distribute and simplify:
3.05 = 0.10x + 4.25 - 0.25x
3.05 = 4.25 - 0.15x
Solve for x:
-1.2 = -0.15x
x = 8
Find y using the above expression:
17 - 8 = y
y = 9