Can someone help me with this math homework please!

Answer:

9

Step-by-step explanation:

f(2)=(2+1)^2

(3)^2

(9)

Answer:

(x+3)^2=5

Step-by-step explanation:

x^2-4x+4=2x

x^2-6x+4=0

x^2-6x+9-5=0

(x-3)^2-5=0

(x-3)^2=5

1.4

2.8

3.7 by 10

*Others do by your self*

Step-by-step explanation:

1. 3×4/3= 4

2.⅖×20=8

3.6/5×7/18=7/15

4.10/7×9/5=18/7= 2 4/7. Mixed Fraction

5.4/15×25/8=5/6

6.6×¾= 9/2= 4 1/2. Mixed Fraction

Answer:

About Points

S = (x,y)        searched point (it will be in the third quadrant )

M = (-2,0)      Midpoint | SP |

P = (3,5)        one end of the segment | SP |

You have to draw Cartesian.

we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .

We use the information that | SM | = | MP |

Answer : S = (-7,-5)

Step-by-step explanation:

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad \underline{Q}(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+3}{2}~~,~~\cfrac{y+3}{2} \right)=\stackrel{M}{(-2,0)}\implies \begin{cases} \cfrac{x+3}{2}=-2\\[1em] x+3=-4\\ \boxed{x = -7}\\[-0.5em] \hrulefill\\ \cfrac{y+3}{2}=0\\[1em] y+3=0\\ \boxed{y=-3} \end{cases}[/tex]

Answer:

a)4

Step-by-step explanation:

(a+b)²=43 eqn 1

(a²+b²)=35 eqn 2

solving eqn 2 by putting the value of (a+b)² by eqn 1

hope it helps

Answer:

6.9

Step-by-step explanation:

Cos ∆ = Adjacent/Hypotenuse

therefore x=12Cos55°

=6.88

=6.9 to the nearest tenth

Answer:

This is the expression:

4*x+4*9

Answer:

=x4y2z2−2x3y3z+2x3yz3+x2y4−4x2y2z2+x2z4+2xy3z−2xyz3+y2z2

Make me brainliest

Answer:

x2y-x2z-xy2+xz2+y2z-yz2

step by step

step.1

Equation at the end of step 1:(((x2)•(y-z)(+((y2)•(z-x)))+z2•(x-y)

step2

Equation at the end of step2

(((x2)•(yz))+yz•(z-x))+z2•(x-y)

step.3

equation at the end of step 3.

(x2•(y-z)+y2•(z-x))+z2•(x-y)

step4

trying to factor by pulling out:

factoring: x2y-x2z-xy2+xz2+y2z-yz2

thought fully split the expression at hand into groups,each group having two terms:

group1: y2z-yz2

group 2: x2y-x2z

group 3: xz2-yz2

pull out from each groups separately:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:(x-y)•(z2)

looking for common sub-expressions:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:( x-y)•(z2)

bad news !! factoring by pulling out fails:

The groups have no common factor and cannot be added up to form a multiplication.

final result:

x2y-x2z-xy2+xz2+y2z-yz2

Answer:

if you look at carefully the left triangle has two same side. so left-angle of C is 180-130=50 degree 5x+5x+50=180 x=13 degree

Step-by-step explanation:

for right triangle again one angle is 50 degree and other is 6*13-(3)=75 degree so 75+50+(10y+5)=180 degree y=5 degree

Answer:

[tex]x=13\text{ and } y=5[/tex]

Step-by-step explanation:

First, notice that ∠BCD and ∠DCE form a linear pair. Linear pairs sum to 180°. Therefore:

[tex]m\angle BCD + m\angle DCE = 180[/tex]

And since we know that ∠BCD measures 130°:

[tex]m\angle DCE = 180-130=50^\circ[/tex]

And since ∠DCE and ∠BCA are vertical angles:

[tex]\displaystyle \angle DCE \cong \angle BCA[/tex]

Therefore, by definition:

[tex]m\angle DCE = m\angle BCA = 50^\circ[/tex]

Looking at the left triangle, we can see that BC and AC both have one tick mark. This means that they are congruent. Therefore, ΔABC is an isosceles triangle. The two base angles of an isosceles triangle are congruent. Hence:

[tex]m\angle A = m\angle B[/tex]

The interior angles of a triangle must total 180°. So:

[tex]m\angle A + m\angle B +m\angle BCA = 180[/tex]

Substitute in known values:

[tex]m\angle A + m\angle A+ (50)=180[/tex]

Simplify:

[tex]2m\angle A=130[/tex]

Divide both sides by two:

[tex]m\angle A = 65[/tex]

Substitute:

[tex](5x)=65[/tex]

Therefore:

[tex]x=13[/tex]

Similarly, for the triangle on the right, we can write that:

[tex]m\angle D + m\angle E + m\angle DCE = 180[/tex]

Substitute:

[tex](10y+5)+(6x-3)+(50)=180[/tex]

Combine like terms:

[tex]10y+6x+52=180[/tex]

Since we determined that x = 13:

[tex]10y+6(13)+52=180[/tex]

Simplify:

[tex]10y+130=180[/tex]

Therefore:

[tex]10y=50[/tex]

And by dividing both sides by 10:

[tex]y=5[/tex]

Answer:

I think 3 but I am not pretty sure man .

Bonjour,

x est un nombre d'ordinateurs: il est donc un naturel (x € N)

y is the pay cost : y=3*x ==> y€ 3N ⊂ N

Answer last reply : 4.

Answer: 19/3

Step-by-step explanation:

[tex]4x+3-x-5=30-3x\\\\3x-8=30-3x\\\\6x-8=30\\\\6x=38\\\\x=\frac{19}{3}[/tex]

Answer:

[tex]40\ cm^3[/tex]

Step-by-step explanation:

Let the actual volume is V.

The measured volume of an object is 46 cubic cm  which was 15% high from the actual volume.

According to the given condition,

[tex]V+\dfrac{15V}{100}=46\\\\\dfrac{115V}{100}=46\\\\V=\dfrac{4600}{115}\\\\V=40\ cm^3[/tex]

So, the actual volume was [tex]40\ cm^3[/tex].

Answer:

Since, the given solution is (2, 14). Therefore, 7x−y=0. Similarly, another equation can be−x+y=−2+14=12. Similarly, another equation can be−2x−y=−2(2)−14=18.

Answer:

[tex]\frac{5}{12}[/tex]

Step-by-step explanation:

Multiply straight across and reduce.

[tex]\frac{5}{8}[/tex] · [tex]\frac{2}{3}[/tex] = [tex]\frac{10}{24}[/tex] = [tex]\frac{5}{12}[/tex]

Answer:

[tex](13 + 29 - 2) \div 2 \\ (42 -2 ) \div 2 \\ 40 \div 2 \\ = 20[/tex]

Answer:

hope it helps.

Answer:

20km is in 12.5miles

Step-by-step explanation:

5miles= 8km

12.5miles=xkm

12.5÷5miles=2.5miles

2.5miles/km

2.5×8km=20km

Answer:

A.

Step-by-step explanation:

4y = 12x + 16

3x = y - 4

=>

y = 3x + 4

using that in the first equation

4(3x+4) = 12x + 16

12x + 16 = 12x + 16

=> both lines/equations are identical, so they have infinitely many solutions.

Answer:

[tex]y=4x+6[/tex]

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope (also called the gradient) and b is the y-intercept (the value of y when x is 0)

1) Plug the gradient into the equation (b)

[tex]y=mx+b[/tex]

We're given that the gradient of the line is 4. Plug this into [tex]y=mx+b[/tex] as m:

[tex]y=4x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=4x+b[/tex]

Plug in the given point (1,10) as (x,y) and solve for b

[tex]10=4(1)+b\\10=4+b[/tex]

Subtract 4 from both sides to isolate b

[tex]10-4=4+b-4\\6=b[/tex]

Therefore, the y-intercept of the line is 6. Plug this back into [tex]y=4x+b[/tex] as b:

[tex]y=4x+6[/tex]

I hope this helps!

answer = y = 4x + 6

y = mx + b

gradient = slope = m = 4

(1,10) = (x,y)

plug in the values

10 = 4 (1) + b

10 = 4 + b

b = 6

y = 4x + 6

Answer:

I only have the answer for B

Step-by-step explanation:

This is the answer: 1st blank: 7y

2nd blank: 9

3rd blank: 42xy

Answer:

18.29

Step-by-step explanation:

32000 ÷ 35 ÷ 50 = 18.2857143

Answer:

the formula for the volume of a square pyramid is V=a^2*h/3

so if we just put in the data

12^2*10/3

144*10/3

480

so the answer is B

Hope This Helps!!!

Answer:

dssadsasdsa

Step-by-step explanation:

ignore this need points for alt

Answer:

48km hr this is the answer in your question.

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as [tex]x + 2y\geq 1200[/tex].​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are [tex]\$600[/tex] a term.

So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.

The fees for a boarding student are [tex]\$1200[/tex] a term.

The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.

Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:

[tex]\text{Total fees}=600x+1200y[/tex]

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

[tex]600x+1200y\geq 720000[/tex]

[tex]600(x+2y)\geq 720000[/tex]

Divide both sides by 600.

[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]

[tex]x+2y\geq 1200[/tex]

Hence proved.