Answers
Answer:
On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.
Step-by-step explanation:
Related Questions
Ayuda es urgente porfavor
Answers
… hope this helps
Please help me on this question.
Answers
Answer:
This is the ans i think this is right
If we have a picture that is 3 inches wide and 5 inches long. What would the dimensions be if I want the picture to be 10in. Long?
Answers
Answer:
6 inches wide, 10 inches long
Step-by-step explanation:
You have to double 3 since 5 is doubled to 10. 3 doubled is 6.
Answer:
6in wide and 10in long
Step-by-step explanation:
In order to get the picture to be 10in long you need to multiply the 5in by 2, which now means you need to also multiply the 3in by 2.
A. 0.1
B. 0.5
C. 2
D. 5
Answers
Answer:
5 I think
Step-by-step explanation:
Well, 0.1 and 0.5 goes in anything so I doubt that's it, 2 goes in 10 but not 5, actually. I think if it's division than 2. Not 1,000 percent sure tho
Answer:
0.5
Step-by-step explanation:
So we know the orginal is 10 in size.
The new is 5 in size.
We can think of this as 10 : 5
To find the exact scale, we can divide both by the GCF.
The GCF is the greatest common factor between two numbers.
In this case, the GCF would be 5, now lets divide:
10/5 : 5/5
=
2 : 1
So we can see the ratio is 2 to 1.
Now, the scale is not 2.
The new ratio is 2 : 1, but 2 is the orginal. 1 is the scaled value.
To find the scale, you must divide the new scaled value by the orginal value:
1 / 2
=
1/2
So this is your scale factor.
There is actually another way to do this as well, which is quicker.
Take the new value, 5, and divide it by the orginal value, 10:
5/10
=
1/2
Either way, you get 1/2 as your answer.
Hope this helps!
One integer is 10 more than another, Their sum is 4. What are the 2 integers? PLEASE HELP!
Answers
Answer:
The two integers are : -3 , 7
Step-by-step explanation:
Let the integers be x and y
Given one of the integer is 10 more than the other, Let x = y + 10 -----(1)
Also Given sum of integers . x + y = 4 ----------- (2)
Substitute ( 1 ) in (2)
x + y = 4
(y + 10) + y = 4
y + 10 + y = 4
2y + 10 = 4
2y = 4 - 10
2y = -6
y = -3
Substitute y = -3 in ( 1 ) : x = - 3 + 10 = 7
which of the following statement is true?
Answers
What is the percent decrease from 345 to 300 rounded to the nearest percent
Answers
Answer:
-13.04.
Step-by-step explanation:
Complete the table for the given rule.
Rule: y=x+3
Answers
Answer:
1
5
2
Step-by-step explanation:
4-3=1
8-3=5
5-3=2
Hope this helps! :)
Find the L.CM of 36,60,126
Answers
Answer:
1260
hope this helps
have a good day :)
Step-by-step explanation:
Step-by-step explanation:
2 x 2 x 3 x 3 x 5 x 13
= 2340
................
1. Explain how to find the area of a complex figure. Draw an example to help illustrate
your understanding. Please help!
Answers
Answer:
Refer to the attached file
Hope it helps..
SOMEONE PLEASE HELP ME!!!!
Answers
Answer:
Step-by-step explanation:
scale factor=17/36
PLEASE HELP I'M SORRY FOR A LOT OF QUESTIONS but I need help
Answers
Answer:
Hello! answer: 268 square meters
Step-by-step explanation:
To find the total surface area you find the area of each face then add them up so...
10 × 3 = 30
10 × 3 = 30
8 × 3 = 24
8 × 3 = 24
10 × 8 = 80
10 × 8 = 80
Now that I found the area for each face I will just add them up so...
30 + 30 + 24 + 24 + 80 + 80 = 268 therefore the area is 268 square meters Hope that helps!
[tex] \large\mathrm {\boxed{ \boxed{268 \: \: m {}^{2} }}}[/tex]
Solution :The above pieces will form a cuboid, having dimensions :
[tex] \mathrm{\longrightarrow length = 10 \: m}[/tex]
[tex] \mathrm{\longrightarrow width = 8 \: m}[/tex]
[tex] \mathrm{\longrightarrow height = 3 \: m}[/tex]
We know that Surface area of Cuboid is :
[tex] \large \longmapsto \mathrm{{2(lw + wh + lh)}}[/tex]
Let's solve,
[tex]\longrightarrow2[(10 \times 8) + (8 \times 3) + (10 \times 3)][/tex]
[tex]\longrightarrow2[80 + 24 + 30][/tex]
[tex]\longrightarrow2 \times 134[/tex]
[tex]\longrightarrow268 \: m {}^{2} [/tex]
[tex] \circ { \underline{ \boxed{ \sf{ \color{green}{ \mathfrak{hope \: \: it \: \: helps \: \: you.....}}}}}}∘[/tex]
Keelie has a triangular-shaped card. The lengths of its sides are 4.4 cm, 5.5 cm, and 6.6 cm. Is the card a right triangle?
Answers
Answer:
No
Step-by-step explanation:
We can use the Pytaghorean theorem to verify it
4.4^2 + 5.5^2 = 6.6^2
19.36 + 30.25 = 43.56
49.61 = 43.56 (false)
Plz answer this question
Answers
Answer:
3,16,729
Step-by-step explanation:
A company that makes hair-care products had 7,000 people try a new shampoo. Of the 7,000 people, 28 had a mild allergic reaction. What percent of the people had a mild allergic reaction?
Answers
Answer: 0.4%
Step-by-step explanation:
First, a porportion needs to be set up.
part/whole = percent/100
28/7,000 = x/100
Second, cross multiply.
2800=7,000x
x=0.4
FInd WY Given: Giving brainly.
Answers
Answers:
x = 2WY = 28===========================================================
Explanation:
The tickmarks show that WZ and XY are the same length. The arrows show that WX is parallel to ZY. This is an isosceles trapezoid.
For any isosceles trapezoid like this, the diagonals are the same length. We can prove it using the SAS congruence theorem.
So,
WY = XZ
15x-2 = 9x+10
15x-9x = 10+2
6x = 12
x = 12/6
x = 2 .... first answer
Use that value of x to find the length of each diagonal.
WY = 15*x - 2 = 15*2-2 = 30-2 = 28 .... second answerXZ = 9x+10 = 9*2+10 = 18+10 = 28Both diagonals are 28 units long, which helps confirm we have the right x value.
Aina builds a cube model out of manila cards. If the volume of the constructed cube is (2+3p) ³ cm³, find the total surface area of the cube in terms of p.
HELPPPP
Answers
Given:
The volume of a cube = [tex](2+3p)^3\ \text{cm}^3[/tex]
To find:
The total surface area of the cube in terms of p.
Solution:
Volume of a cube is:
[tex]V=a^3[/tex] ...(i)
Where, a is the side length.
It is given that,
[tex]V=(2+3p)^3\ \text{cm}^3[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]a=2+3p\text{ cm}[/tex]
Now, the total surface area of a cube is:
[tex]A=6a^2[/tex]
Where, a is the side length.
Putting [tex]a=2+3p[/tex], we get
[tex]A=6(2+3p)^2[/tex]
Therefore, the total surface area of the cube in terms of p is [tex]6(2+3p)^2\ \text{cm}^2[/tex].
John has 8 cards that spell the word H O M E W O R K. He shuffles them and then places them face down. Assume he returns the card on each occasion.
a) What is the probability that he will choose the letter O?
Answers
Answer:
1/4
Step-by-step explanation:
The manager of a home store is buying lawn
chairs to sell at his store. Each pack of chairs
contains 10 chairs. The manager will sell each
chair at a markup of 20% of the wholesale
cost, plus a $2.50 stocking fee.
Answers
Answer:
5$
Step-by-step explanation:
Does anybody know it part 2
Answers
Answer:
x = 33
Step-by-step explanation:
(x + 13) + (4x + 2) = 180
x + 13 + 4x + 2 = 180
5x + 15 = 180
5x = 180 - 15
5x = 165
x = 165/5
x = 33
Check:
(x + 13) + (4x + 2) = 180
(33 + 13) + 4(33) + 2 = 180
46 + 132 + 2 = 180
46 + 134 = 180
a rectangle pool is 6 meters wide and 9 meters long. What is the area of the pool
Answers
Suppose Tommy walks from his home at (0, 0) to the mall at (0, 7), and then walks to a movie theater at (5, 7). After leaving the theater Tommy walks to the store at (5, 0) before returning home. If each grid square represents one block, how many blocks does he walk?
Answers
Answer:
24 blocks
Step-by-step explanation:
2(5) + 2(7) = 10 + 14
Please help me with my maths
Answers
Answer:
Step-by-step explanation:
x² + 5x³ +2x + 4 - 3x⁴
1) -3x⁴ + 5x³ + x² + 2x + 4
2) Coefficient of x⁴ term = -3
3) Index (Exponent) of term x = 1
4) Degree of the expression : Highest power/exponent/ index is the degree.
Degree of the expression = 4
5) Constant term : 4
6) There are 5 terms in the expression
7) x = 2
-3(2)⁴ +5(2)³ + 2² + 2*2 + 4 = -3*16 + 5*8 + 4 + 4 + 4
= -48 + 40 +4 + 4 + 4
= 4
Help,anyone can help me do quetion
Answers
Answer:
B1: x = 51
C1: x = 73, y = 34
Step-by-step explanation:
B1:
By exterior angle theorem:
x° + 54° = 105°
x° = 105° - 54°
x° = 51°
x = 51
C1
x° = 73°(Alternate angles)
x = 73
y° = 34° (corresponding angles)
y = 34
islah sold a shirt at sh 2000 making a loss of 9%, how much did islah paid for the shirt ?
Answers
Answer:
2,197.8
Step-by-step explanation:
Find the nth term of the following sequence 5,20,45,80,125
Answers
Answer:
{5, 20, 45, 80, 125} = 5{1, 4, 9, 16, 25} = 5{1², 2², 3², 4², 5²}
→ U{n} = 5n²
Step-by-step explanation:
What is 2y+5 = 3y+2 ?
Answers
2y + 5 = 3y + 2
=> 5 - 2 = 3y - 2y
= 3 = y
Answer:
y = 3
Step-by-step explanation:
2y + 5 = 3y + 2
2y - 3y + 5 = 3y - 3 y + 2 [ subtract both sides by 3y ]
- y + 5 = 0 + 2 [ 3y - 3y = 0 ]
- y + 5 - 5 = 2 - 5 [ subtract by 5 on both sides ]
- y + 0 = - 3 [ -5 + 5 = 0 ]
- y = - 3
y = 3 [ divide by - 1 on both sides ]
Franklin races bikes. In his city, there are 44 lengths of race tracks. The chart shows the race tracks and each track's length in miles. Race Track Length in Miles A \frac{1}{4} 4 1 B \frac{3}{2} 2 3 C 1\frac{3}{4}1 4 3 D \frac{4}{4} 4 4 Frankin races 33 laps in the same lane. The total distance he races is more than 4\frac{1}{2}4 2 1 miles. Which track does Franklin race on?
Answers
Answer:
51
Step-by-step explanation:
51 is elaginlent to 44 and 33 12 garde things
Need help with this question
Answers
Answer this for me thanks
Answers
Answer:
The value of x is 15 inch.
Step-by-step explanation:
Area, A = 81 square inch
Perimeter, P = 48 inch
let the side is y.
[tex]y^2 = 81\\\\y = 9 inch[/tex]
Let the other side is d.
P = 4 d = 48
d = 12 inch
the length x is given by
[tex]x^2 = 9^2 + 12^2\\\\x^2 =81 + 144 = 225\\\\x = 15 inch[/tex]
So, x = 15 inch.
