can someone please help me i don’t get this at all!?

Answer:

450

Step-by-step explanation:

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

Answer:

g+h+(j+k)

Step-by-step explanation:

(g+h)+j+k

(g+k)+j+h

(g+j)+h+k

(k+h)+j+h

(j+h)+g+k

Answer:

1 and 3

Step-by-step explanation:

dont mind me this needed to be longer wait still needs no be longer

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

[tex]TP X TQ=TR^2[/tex]

[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

Answer:

X=25

Step-by-step explanation:

Since these 2 angles are vertically opposite angles so they are equal. (rule)

75°=(4x-25°)

75° + 25° = 4x

100=4x

X=100/4 = 25

___________

Hope this helps...

The beef price is $10.65

Onions price is $2.49

Potatoes are $3.29

Tomatoes are $8.45

Asparagus is $4.99

3.25 pounds of beef is          3.25 * 10.65 =  34.61

0.65 pounds of onions is      0.65 * 2.49   =  1.62

0.2 pounds of potatoes is     0.2 * 3.29     =  0.66

0.15 pounds of tomatoes is   0.15 * 8.45   =  1.27

0.33 pounds of asparagus is 0.33 * 4.99  =  1.65

Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65

This is equal to 39.81

A recipe is mixture of ingredients.

Divya will pay $39.81 for all the ingredients in the recipe.

The beef price is $10.65 per pound

So, price of 3.25 pounds of beef is ,  [tex]3.25 * 10.65 = 34.61[/tex]

Onions price is $2.49 per pound

So, price of 0.65 pounds of onions is,  [tex]0.65 * 2.49 = 1.62[/tex]

Potatoes are $3.29 per pound

So, price of 0.2 pounds of potatoes is ,  [tex]0.2 * 3.29 = 0.66[/tex]

Tomatoes price are $8.45 per pound.

So, price of 0.15 pounds of tomatoes is  , [tex]0.15 * 8.45 = 1.27[/tex]

Asparagus price is $4.99 per pound.

So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]

Hence, total amount paid by Divya is,

             [tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]

Thus, Divya will pay $39.81 for all the ingredients in the recipe.

Learn more:

https://brainly.com/question/18994792

Answer:

The distance where the keys would drop from the base is 3.5m

Step-by-step explanation:

Height of the tower = 50m

Angle it makes to the ground = 86°

To solve this question, you have to understand that the tower isn't vertically upright and the height of the tower is different from the distance from the top of the tower to the ground.

The tower makes an angle 86° to the ground and that makes it not vertically straight because a vertically straight building is at 90° to the ground.

See attached document for better illustration.

The distance from where the keys drop to the base of the tower can be calculated using SOHCAHTOA

We have to use cosθ = adjacent / hypothenus

θ = 86°

Adjacent = ? = x

Hypothenus = 50m

Cos θ = x / hyp

Cos 86 = x / 50

X = 50 × cos 86

X = 50 × 0.06976

X = 3.488 = 3.5m

The distance where the keys would drop from the base of the tower is approximately 3.5m

Answer:

3.5

Step-by-step explanation:

y = 3.5x – 17

This is in the slope intercept form

y= mx+b where m is the slope and b is the y intercept

The slope is 3.5

Answer:

She must buy 90 tiles for the cost to be the same at both stores

Step-by-step explanation:

Let x be the no. of tiles bought for the cost to be the same at both stores

Margo can purchase tile at a store for $0.89 per tile at shop 1

Cost of x tiles =0.89x

She rent a tile saw for $45.

So, total cost at Store 1 = 0.89x+45

At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile.

So, cost of 1 tile = 1.39

Cost of x tiles = 1.39x

ATQ

0.89x+45=1.39x

45=1.39x-0.89x

45=0.5x

[tex]\frac{45}{0.5}=x[/tex]

90=x

Hence She must buy 90 tiles for the cost to be the same at both stores

Answer:

18,223 feet

Step-by-step explanation:

y= -16t^2 + 608t + 12,447.

y = -16(t² - 38t) + 12447

y = -16[t² - 2(t)(19) + 19² - 19²] + 12447

y = -16(t - 19)² - 16(-19²) + 12447

y = -16(t - 19)² + 18223

Vertex: (19, 18223)

Max height is 18,223 at t = 19

The parabolas are:

a = -16

b = 608

c = 12,447

x_v = -b/2a

t_v = -608/2(-16)

t_v = -608/-32

t_v = 19

Plug in t_v = 19 to find y_v

y = -16(19)^2 + 608(19) + 12,447

y = -16(361) + 11,552 + 12,477

y = -5,776 + 11,552 + 12,477

y = 18,253

We have the point (19, 18,253)

The max height is at 18,253 when t = 19

Best of Luck!

Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

Answer:

Out side the circle

Step-by-step explanation:

This is because the center is 0 and if the point 6, square root seven is on the circle that mean that as far as the circle goes on each side.

Answer:

22.

     log3(4) + log3(5x^2 + 1) = 2

<=> log3(4 x (5x^2 + 1)) = log3(9)

<=> 20x^2 + 4 = 9

<=> 20x^2 = 5

<=> x^2 = 1/4

<=> x = +/- (1/2)

23.

      log8(4x^2 + 1) - log8(2) = log8(5)

<=> log8((4x^2 + 1)/2) = log8(5)

<=> 2x^2 + 1/2 = 5

<=> 2x^2 = 9/2

<=> x^2 = 9/4

<=> x = +- (3/2)

24.

      log8(4x^2 - 9) - log8(5) = 1

<=> log8((4x^2 - 9)/5) = log8(8)

<=> (4x^2 - 9)/5 = 8

<=> 4x^2 - 9 = 40

<=> 4x^2 = 49

<=> x^2 = 49/4

<=> x = +/- (7/2)

Hope this helps!

:)

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

Answer:

after paying all expenses Ron will have $10 leftover each month.

Answer:

10 on edge

Step-by-step explanation:

Answer:45

Step-by-step explanation:

Sin^-1= 5÷7

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :)      espero que te aya adudado auque sea un poquito

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²

Answer:

36

Step-by-step explanation:

Answer:

735.13268 units^2

Step-by-step explanation:

A=2πrh+2πr2=2·π·9·4+2·π·92≈735.13268

Answer:

In the books of Wirtz, the selling party, the required entries are

Debit Accounts receivable $780

Credit Revenue $780

Being entries to recognize sales revenue on account

Debit Cost of sales $470

Credit Inventory  $470

Being entries to recognize the cost of items sold

In the books of Cha Company

Debit Inventory $780

Credit Accounts payable  $780

Being entries to record cost of inventory purchased

Step-by-step explanation:

When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.

To recognize revenue,

Debit Cash/Accounts receivable

Credit Revenue

To record the cost of the item sold

Debit Cost of sales

Credit Inventory

For the party that makes the purchase

Debit Inventory

Credit Cash/Accounts payable

Answer:

50.32 I think

Step-by-step explanation:

52,13+50,32=102.45

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

mean= 12.8

median=13

mode=there is no mode

Step-by-step explanation:

mean/average=14+10+12+15+ 13​=64/5=12.8

median=10,12,13,14,15=13

mode= is the number that repeats more often. = there is no mode

Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

Answer:

-3

Step-by-step explanation:

Answer:

b = 4a

Step-by-step explanation:

Given

a = [tex]\frac{1}{4}[/tex] b

Multiply both sides by 4 to clear the fraction

4a = b

Answer: Reduction

(0,0)

1/3

Step-by-step explanation:

Answer:

1-reduction

2-(0,0)

3-1/3

Step-by-step explanation: