can yall help me with the problem ?!

Answer:

D. -4

Step-by-step explanation:

Answer:

8 mousetraps

Step-by-step explanation:

to find how many mousetraps per person, we need to divide 48 by 6, which gives us 8.

Answer:

107

Step-by-step explanation:

Because, 36+35=71

and 71+36=107

Answer:

107

Step-by-step explanation:

not that hard bro

Answer:

1343

Step-by-step explanation:

Answer:

y- intercept = 4

Step-by-step explanation:

The y- intercept is the point on the y- axis where the graph crosses the y- axis

In this case that is the point (0, 4 ) , then

y- intercept = 4

Answer:

d. took the test

Step-by-step explanation:

Answer:

n = {-1, 7}

Step-by-step explanation:

8n² - 56 = 48n

Subtract 48n from both sides

8n² - 48n - 56 = 0

Divide both sides by 8

n² - 6n - 7 = 0

Factor

alternately use the quadratic equation or complete the square

(n - 7)(n + 1) = 0

n = {-1, 7}

The interest rate of Jill's account as described is; 0.51%

The amount invested by Jill is $7,972.

According to compound interest;

In which case;

Therefore;

[tex]1 + r = \sqrt[15]{2.117} [/tex]

The interest rate is therefore; 0.51%

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- 36 + (-74)

- 36 - 74

- 110

<3

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

1/9² = 7/567

2/9² = 14/567

3/9² = 21/567

while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

so

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

so that

4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

Then

1/5103 = 1/9⁴ + 2/45927

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927

One last time: LCM(45927, 9⁵) = 413343, and

1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder

Then the base 9 expansion of 1/7 is

0.12512..._9

Answer:

b) 2x=9=>x=9/2=4.5

c)x/5=7=>x=5×7=35

d)x/2=6.5=>x=6.5×2=13

We have that for the Question "I know how to apply the midpoint theorem, but I don't know where I should start my intervals." it can be said that

Where you start your intervals are at the (x,y) co-ordinate of the Reference points

From the question we are told

I know how to apply the midpoint theorem, but I don't know where I should start my intervals.

Generally the equation for the midpoint   is mathematically given as

[tex]m=\frac{x1+x2}{2},\frac{y1+y2}{2}[/tex]

Naturally the midpoint of two point is the point in between the reference points where distances from them are equal

Therefore

Midpoints co-ordinates simply considers the co-ordinate of the two main reference points.(x,y)

Hence

Where you start your intervals are at the (x,y) co-ordinate of the Reference points

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Answer:

1,000ML = 1 L

4,500MG = 4.5G

25CM = 250MM

Duke swims 0.05 miles in a minute.

What is Division method?

Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications.

For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.

Given that;

Duke swims 0.10 mile in 2 minutes.

Now,

Since, Duke swims 0.10 mile in 2 minutes.

Thus, Speed = 0.10 / 2

Speed = 0.05 mile per minute

And, He swims at the same speed.

Thus, Distance in 1 minute,

Speed = Distance / Time

0.05 = Distance / 1

Distance = 0.05 miles.

Thus, Duke swims 0.05 miles in a minute.

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Answer:

(2x+1+x^2+2x-1)*2=2x^2+8x

Step-by-step explanation:

∆HFE is similar to ∆HFG and ∆ HEG (they all are right triangles and have the same, shape.)

The given triangle ΔHFE is similar to triangle GFH and triangle GHE.

Similar triangles are two triangles that have the same shape but may differ in size. They have corresponding angles that are congruent and corresponding sides that are proportional.

Here,

Since triangle HFE is similar to triangle GFH,
∠HEF = ∠GHF,
∠FHE = ∠HGF, and ∠HFE = ∠HFG

Similarly

ΔHFE is similar to triangle ΔGHE.

Similar triangles are useful in many areas of mathematics and in the real world, such as in architecture, engineering, and cartography, where they are used to make scale models of buildings and other structures.

Thus, the given triangle ΔHFE is similar to triangle GFH and triangle GHE.

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Answer:

Because its an internationally accepted method.

Step-by-step explanation:

Answer:

tenth- 49.1

Hundredth- 49.08

thousandsths- 49.076

ten-thousandths- 49.0758

Answer:

yy is the comparative narrow of speech to me happy and a bit in a sentence

Step-by-step explanation:

ami and a are of a and or very place argument you the have important X does the be for to gays found teacher you be use single be

Answer:

7

Step-by-step explanation:

We take the information in the problem and translate it into a linear equation of the form 3x-8=13. Combining like terms we get 3x=21. next divide both sides by 3 for a final answer of x=7

Answer:

1. 20 km

2. 0.5 hours

3. 40 km

4. 1.5 hours

5. A, 40 km/hr

6. 80 km/hr, 40 km/hr

Step-by-step explanation:

2. The lines of Car A and Car B at 0.5 hours, meaning the cars have been traveling for 0.5 hours before they met.

1. From 0 hours to 0.5 hours, Car A traveled from 20 km to 40 km. The distance traveled before Car A met Car B was 40 km - 20 km = 20 km.

3. Cars A and B travel at the same speed starting at the 0.5 hour, 40 km point. They are traveling at the same speed from 0.5 hours to 1.5 hours since they share the same line and therefore the same slope. From the point at which Cars A and B met, they traveled from 40 km to 80 km. They traveled at the same speed for 80 km - 40 km = 40 km.

4. Both cars reached point C at the same time of 1.5 hours.

5. Car A had constant speed sicne the lines "Car A" and "Cars A and B" had the same slope. The speed is equal to the slope of the line: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{80-20}{1.5-0} = 40 km/hr[/tex]

6.

First speed: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{40-0}{0.5-0} = 80 km/hr[/tex]

Second speed: [tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{80-40}{1.5-0.5} = 40 km/hr[/tex]

Answer:

1800.

Step-by-step explanation:

If N is the first letter the next 2 letters will be the number of permutations of 2 from 25 =  25!/ (25-2)!

= 600.

If the first number is M or P the number is the same so that makes 1800 possibilities.

Answer:

Their both the same answers which is 13

Step-by-step explanation:

Answer:

174 m^2

Step-by-step explanation:

9 * 5 = 45

9 * 5 = 45

9 * 3 = 27

9 * 3 = 27

5 * 3 = 15

5 * 3 =15

45+45+27+27+15+15 = 174 m^2

Hope this is helpful.

Answer:

174 m²

Step-by-step explanation:

9 * 5 = 45 (that's the bottom and top areas)

9 * 3 = 27 (that's both the bigger sides areas)

5 * 3 = 15 (that's both the smaller sides areas)

Now  you have to double:

45 * 2 = 90

27 * 2 = 54

15 * 2 = 30

Now sum:

90 + 30 + 54 = 174

Answer:

Step-by-step explanation:

[tex]\dfrac{x^{m}}{x^{n}}=x^{m-n}\\\\\\a)\dfrac{a^{5}}{a^{3}}=a^{5-3}=a^{2}\\\\\\b)\dfrac{c^{4}}{c^{3}}=c^{4-3}= c^{1} =c[/tex]

Answer:

A) a^2

B) c

Step-by-step explanation: hope this helps

Answer:

EF= 18 in. , m<F=134'

Step-by-step explanation:

This ones for the boys with the booming system, top down ac with the cooling sytem

Answer:

$15,000

Step-by-step explanation:

Let P represent Aiden's current pay.

If they receive a pay rise of 15%, that means they receive their original pay plus 15% of that original pay.

P + 0.15P = 17250

1.15P = 17250

P = 17250/1.15 = 15000

His salary before the increase was $15,000.

Answer:

$14662.5

Step-by-step explanation:

Aiden receives a pay rise of 15%

increases their pay to $17,250

15% of $17,250 is $2587.5 therefore $17,250 - $2587.5 is his salary before the increase which is 14662.5 so aiden had $14662.5 before his salary increase