Carbon dioxide gas is collected in a laboratory experiment to determine the molar mass of the compound. At 294 Kand 1.01 atm, 1.008 grams of co2 was collected when a 500 mL flask was filled with the evolved co2. What is the experimental molar mass of co2? a. 41.5 g/molb., 44.0 g/mol c. 46.9 g/mol d 48.2 g/mol

Answers

Answer 1

The experimental molar mass of CO2 collected in a laboratory experiment is 44.0 g/mol.

When carrying out laboratory experiments, carbon dioxide gas is collected to determine the molar mass of the compound. When a 500 mL flask was filled with the evolved CO2 at 294 K and 1.01 atm, 1.008 grams of CO2 was collected. It is required to determine the experimental molar mass of CO2. To solve the problem, we will make use of the ideal gas law formula:

P.V = n.R.T Where,P = 1.01 atmV = 500 mL = 0.500 Ln = number of moles of CO2R = 0.0821 L.atm.K-1.mol-1T = 294 K Substituting the values in the formula, we get;1.01 atm × 0.500 L = n × 0.0821 L.atm.K-1.mol-1 × 294 K1.01 × 0.500 = n × 24.79n = (1.01 × 0.500) / 24.79n = 0.02039 moles of CO2. We know that the mass of CO2 that was collected is 1.008 grams.Therefore, the molar mass of CO2 = mass / number of moles = 1.008 g / 0.02039 mol = 49.38 g/mol

But, we know that CO2 has a molar mass of 44.01 g/mol. Hence, the value of 49.38 g/mol is not the experimental molar mass of CO2 and so, we have to calculate the experimental molar mass of CO2 as follows:Experimental molar mass of CO2 = mass / number of moles = 1.008 g / 0.02039 mol = 49.38 g/mol. Actual molar mass of CO2 = 44.01 g/mol.

Experimental error = | experimental value - actual value | / actual value × 100%.Substituting the values in the formula, we get;

Experimental error = | 49.38 - 44.01 | / 44.01 × 100%

Experimental error = 12.2% ≈ 12%.

Therefore, the experimental molar mass of CO2 is 44.0 g/mol (Option b).

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Related Questions

What 4 elements have many properties like iron?

Answers

Answer:

Cobalt, Nickel, Chromium, and Copper

20pcm3 og a gas has a pressure of 510mmhg what will be the volume of the pressure is increased to 780mmhg, assuming there is no change in temperature​

Answers

The volume of the gas will decrease from 20 cm³ to 13.08 cm³.

What is Boyle's law?

Boyle's law is a gas law that states that the product of the pressure and volume of a gas is constant at constant temperature.

What is the significance of assuming no change in temperature in this problem?

Assuming no change in temperature is significant because it allows us to apply Boyle's law to solve the problem. If the temperature were to change, we would need to use a different gas law, such as Charles's law or the combined gas law, to account for the change in temperature.

We can use Boyle's law to solve this problem, which states that the product of the pressure and volume of a gas is constant at constant temperature. Mathematically, we can express this as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

Using this equation, we can solve for V₂:

P₁V₁ = P₂V₂

V₂ = (P₁V₁)/P₂

Substituting the given values, we get:

V₂ = (510 mmHg x 20 cm³) / 780 mmHg

V₂ = 13.08 cm³

Therefore, if the pressure is increased from 510 mmHg to 780 mmHg at constant temperature, the volume of the gas will decrease from 20 cm³ to 13.08 cm³.

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At the resting membrane potential, the membrane is most permeable to ________, which moves ________ the cell due to its A) chloride : into B) potassium : into C) sodium : out of D) sodium : into E) potassium : out of

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At the resting membrane potential, the membrane is most permeable to potassium ions (K+), which move out of the cell due to its concentration gradient and the negative charge inside the cell.  Correct answer is option: E.

This movement of K+ ions out of the cell contributes to the negative resting membrane potential of approximately -70 mV in most cells.  The resting membrane potential is maintained by the selective permeability of the cell membrane, which allows for the movement of certain ions across the membrane. In general, the membrane is less permeable to sodium (Na+) and chloride (Cl-) ions at rest, and the movement of these ions across the membrane is limited. Thus, option E "potassium" is the correct answer.

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When a utensil is stored in water between uses, what are the requirements?A. Running water at any temperature, or a container of water at 70 F (21 C) or lower.B. Running water at any temperature, or a container of water at 135 F (57 C) or lower.C. Running water at 70 F (21 C) or lower, or a container of water at 70 F (21 C) or lower.D. Running water at 135 F (57 C) or lower, or a container of water at 135 F (57 C) or lower.

Answers

D. Running water at 135 F (57 C) or lower, or a container of water at 135 F (57 C) or lower.

What procedures can be performed on trials 2 and 3 so that the rate of dissolving is the same as trial 1? A student wants to determine how different factors affect the rate of dissolving solid in water: Trial Size of Particles Rate_of_Dissolving small 10 sec medium 20 sec large 30 sec 2 3 What procedures can be performed on trials 2 and 3 so that the rate of dissolving is the same as trial 1? A_ the student can increase the pressure B. the student can decrease the pressure C the student can decrease the temperature D. the student can increase the temperature'

Answers

The size of particles has an effect on the rate of dissolving, but temperature is also a significant factor that affects how quickly a solid will dissolve in water. Lowering the temperature slows down the movement.

What is the temperature ?

Temperature is a measure of the average kinetic energy of the particles in a substance or system. In simpler terms, it is a measure of how hot or cold something is. The temperature of a substance or system is commonly measured in degrees Celsius (°C) or degrees Fahrenheit (°F), and it can be influenced by various factors such as heat transfer, pressure, and the presence of other substances. Temperature is an important physical property that affects many aspects of daily life, including weather patterns, cooking, and the functioning of electronic devices. It is also a critical factor in many scientific processes, such as chemical reactions, phase transitions, and the behavior of materials at the atomic and molecular level.

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Predict the product(s) obtained when benzoquinone is treated with excess butadiene:

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When benzoquinone is treated with excess butadiene, the products obtained are 2,5-dimethylcyclohexadiene-1,4-dione and cyclohexene.

What is benzoquinone?

Benzoquinone is also known as 1,4-benzoquinone or cyclohexa-2,5-diene-1,4-dione, is a colorless organic compound. The presence of two carbonyl groups in its structure provides it its characteristic quinone chemistry.

Butadiene, also known as 1,3-butadiene, is a conjugated diene. The reaction between benzoquinone and butadiene is called a Diels-Alder reaction.

The Diels-Alder reaction is a conjugate addition reaction that joins a diene and a dienophile to create a new six-membered ring. The most important characteristic of the Diels-Alder reaction is its stereospecificity. This reaction occurs between a cyclic diene and an alkene or alkyne dienophile.

The products obtained when benzoquinone is treated with excess butadiene are:2,5-dimethylcyclohexadiene-1,4-dioneCyclohexeneThe reaction proceeds with the dienophile (benzoquinone) being attacked by the diene (butadiene) in the Diels-Alder reaction to produce a cyclic adduct. The product is 2,5-dimethylcyclohexadiene-1,4-dione. Cyclohexene is formed as a byproduct of the reaction.

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57.0 ml of 0.90 m solution of hcl was diluted by water. the ph of this diluted solution is 0.90. how much water was added to the original solution insert your answer rounded to 3 significant figure.

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57.0 ml of 0.90 m solution of Hcl was diluted by water. the pH of this diluted solution is 0.90. 50.5 mL water was added to the original solution .

There are a few steps to solve this.

Here they are: First, calculate the initial concentration of HCl in the solution.

Molarity = moles of solute / volume of solution in liters.

The volume of the solution is 57.0 mL, which is 0.0570 L.

The molarity is 0.90 M. So,0.90 M = moles of HCl / 0.0570 L

Now we can solve for moles of HCl:

moles of HCl = 0.90 M x 0.0570 L = 0.0513 mol

Next, we need to use the pH to find the concentration of H+ ions.

pH = -log[H+]0.90 = -log[H+]

Solving for [H+],

we get:[H+] = 7.94 x 10^-1 M

Finally, we can use the concentration of H+ ions to find the new volume of the solution after dilution using the equation:[H+] x V = moles of HCl7.94 x 10^-1 M x V = 0.0513 mol

Solving for V,

we get: V = 6.47 x 10^-2 L

To find how much water was added,

we subtract the final volume from the initial volume:

Volume of water added = 57.0 mL - 6.47 mL = 50.5 mL (rounded to 3 significant figures)

Therefore, 50.5 mL of water was added to the original solution.

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Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed.a. 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq)B) Li+(aq) + SO42-(aq) + Cu+(aq) + NO3-(aq) → CuS(s) + Li+(aq) + NO3-(aq)C) Li+(aq) + S-(aq) + Cu+(aq) + NO3-(aq) → CuS(s) + LiNO3(aq)d) 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → Cu2+(aq) + S2-(aq) + 2 LiNO3(s)E) No reaction

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The complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows: 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq)

It is important to write the complete ionic equation when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed. The reaction of lithium sulfide with copper (II) nitrate is a double displacement reaction. Lithium sulfide reacts with copper (II) nitrate to form copper sulfide and lithium nitrate.

The balanced chemical equation for the reaction is given as follows:Li2S(aq) + Cu(NO3)2(aq) → CuS(s) + 2 LiNO3(aq)The complete ionic equation can be written by representing all the ions in the aqueous solutions as dissociated ions.

Thus, the complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows:2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq.

)In the above equation, the lithium and nitrate ions do not take part in the reaction and are present in the same form in the reactant and product side. Hence, they are called spectator ions.

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When the following two solutions are mixed:
K2CO3(aq)+Fe(NO3)3(aq)
the mixture contains the ions listed below. Sort these species into spectator ions and ions that react.
Drag the appropriate items to their respective bins.
NO3-)aq), Fe3+ , CO3 2-, K+
Part B
What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Assume that the contribution of protons from H2SO4 is near 100 %.
Ba(OH)2(aq)+H2SO4(aq)?

Answers

The net ionic equation for the reaction between [tex]Ba(OH)_2(aq) and H_2SO_^4 (aq)  is :2Ba^2^+(aq) + SO_4^2^-(aq) + 2H^+(aq) ⇒ 2Ba^2^+(aq) + 2H_2O[/tex]

When the following two solutions are mixed:

[tex]K_2CO_3(aq) + Fe(NO_3)_3(aq)[/tex], the mixture contains the following ions:

[tex]NO_3- (aq), Fe^3+, CO_3^ 2-, K^+[/tex]. The spectator ions are NO3- (aq) and K+, and the ions that react are Fe3+ and CO3 2-.

Hence , The correct net ionic equation, including all coefficients, charges, and phases, for the reactants [tex]Ba(OH)_2(aq) + H_2SO_4(aq) [/tex] is 2Ba^2^+(aq) + SO_4^2^-(aq) + 2H^+(aq) ⇒ 2Ba^2^+(aq) + 2H_2O[/tex] .
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How much potassium chloride will dissolve in 50 grams of water at 50°C?

Answers

The amount of potassium chloride that will dissolve in 50 grams of water at 50°C depends on the solubility of the salt at that temperature. The solubility of potassium chloride in water at 50°C is approximately 42 grams per 100 grams of water. Therefore, about 21 grams of potassium chloride will dissolve in 50 grams of water at 50°C.

The phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out, is known as: select the correct answer below: - shielding - deflecting - building up - converging

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The phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out is known as Shielding.

Electrons in an atom are negatively charged particles, and they are attracted to the positively charged nucleus. However, the outer electrons of an atom are also repelled by the inner electrons that are closer to the nucleus. This repulsion is due to the negative charges of the electrons, and it partially cancels out the attraction of the nucleus for the outer electrons.

Shielding is the phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out. This makes it possible for electrons in higher energy levels to be farther from the nucleus, so they are less strongly attracted and easier to remove.

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students conducting research observe the rate of an enzyme-catalyzed reaction under various conditions with a fixed amount of enzyme in each sample. when will increasing the substrate concentration likely result in the greatest increase in the reaction rate?

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Increasing the substrate concentration will likely result in the greatest increase in the reaction rate when the substrate concentration is lower than the concentration of the enzyme.

The concentration of the substrate affects the rate of reaction since there is a direct correlation between the number of enzyme-substrate complexes that are formed and the rate of reaction.

When there is more substrate, more enzyme-substrate complexes can form, resulting in an increase in the rate of reaction.

So, it is highly likely that when the substrate concentration is low, increasing the substrate concentration will result in the greatest increase in the reaction rate.

However, when the substrate concentration is already high, the reaction rate may not continue to increase as a result of increasing the substrate concentration.

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which area on the illustration represents the largest reservoir of nitrogen on earth? 7 3 1 4

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The atmosphere, which is represented by Area 1, is the main source of nitrogen on Earth. About 78% of the Earth's atmosphere is made up of nitrogen gas (N2), which is essential to numerous industrial and biological processes.

Sadly, I am unable to give a precise response without access to the question's referenced illustration. I can, however, give some general knowledge about the nitrogen cycle and the various nitrogen reserves on Earth.

The environment contains nitrogen, an element that is necessary for life, in a variety of forms, including nitrogen gas (N2), ammonia (NH3), nitrite (NO2), nitrate (NO3-), and organic nitrogen. A number of biological and chemical mechanisms are used in the nitrogen cycle to change nitrogen's form and transfer it through various reservoirs.

The atmosphere, which contains around 78% nitrogen gas, is the planet's biggest source of nitrogen. Unfortunately, most organisms cannot access atmospheric nitrogen directly; instead, it must be transformed into a useful form through  nitrogen fixation. Nitrogen fixation is the process of converting atmospheric nitrogen into ammonia or other organic nitrogen compounds, which can be taken up by plants and other organisms.

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Question.05: (3 mrks) Neon gas in luminous tubes radiates red light-the original "neon light." The standard gas containers used to fill the tubes have a volume of 1.0 L and store neon gas at a pressure of 101 kPa at 22 °C. A typical luminous neon tube contains enough neon gas to exert a pressure of 1.3 kPa at 19 °C. If all the gas from a standard container is allowed to expand until it exerts a pressure of 1.3 kPa at 19 °C, what will its final volume be? If Lilia's sister Amelia is adding this gas to luminous tubes that have an average volume of 500 mL, what is the approximate number of tubes she can fill?​

Answers

Answer:

Answer: The final volume of the gas will be 8.07 L.

Approximate number of tubes Amelia can fill = 8.07 L/500 mL = 16.14 tubes.

Use these two constants for the question that follows:


e = 1.6 × 10^−19 C
k = 8.99 × 10^9 N m^2/C^2

A positive charge and a negative charge are 10^−15 m away from each other. Using Coulomb's law, which of the following is the electrical force between these two particles?
230 N
−230 N
120 N
−120 N

Answers

Answer: -230 N

Explanation:

The electrical force between two point charges q1 and q2 separated by a distance r is given by Coulomb's law:

F = k * (q1 * q2) / r^2

where k is the Coulomb constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

In this case, we have a positive charge and a negative charge, which means that q1 and q2 have opposite signs. Let's assume that the positive charge has a magnitude of q and the negative charge has a magnitude of -q. Then, the electrical force between them can be calculated as:

F = k * (q * (-q)) / r^2 = -k * q^2 / r^2

Substituting the given values of e and k, we get:

F = - (8.99 × 10^9 N m^2/C^2) * (1.6 × 10^-19 C)^2 / (10^-15 m)^2 ≈ -230 N

Note that the negative sign indicates that the force is attractive, which is expected for opposite charges. Therefore, the correct answer is:

-230 N.

Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong acid, a weak acid titrated with a strong base, a weak basetaed with a strong acid, or a polyprotic acid titrated with a strong base. Strong acid/Strong base/ strong base Weak acid strong base Weak base Polyprotic acid strong acid strong acid strong base mL of titrant mL of titrant mL of titrant mL of titrant mL of titrant

Answers

When it comes to titration, a titration curve is the representation of the change in pH with regards to the volume of titrant added.

The point of equivalence is where the stoichiometric amount of titrant reacts completely with the analyte being titrated.

There are several types of titration curves. Below are the classifications of each titration curve:

Strong acid titrated with a strong base. The titration curve for this scenario starts out with a pH of around 3.0, which is the pH of a strong acid. The pH rises until the equivalence point is reached. The pH then drops steeply after the equivalence point.

Strong base titrated with a strong acid. In this titration curve, the pH starts off around  .11, which is the pH of a strong base. The pH drops rapidly until the equivalence point is reached. The pH then rises steeply after the equivalence point.

Weak acid titrated with a strong base. In this titration curve, the pH starts off slightly acidic due to the presence of the weak acid. The pH rises gradually until the equivalence point is reached. The pH then increases steeply after the equivalence point.

Weak base titrated with a strong acid. The pH starts off slightly basic in this titration curve due to the weak base. The pH decreases gradually until the equivalence point is reached. The pH then drops steeply after the equivalence point.

Polyprotic acid titrated with a strong base. In this titration curve, there are more than one equivalence point because the acid is capable of releasing more than one hydrogen ion.

Each equivalence point represents the point at which one mole of H+ is neutralized.

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The idea of __________ asserts that some evolutionary changes may not even involve intermediate forms.
punctuated equilibrium

Answers

The idea of punctuated equilibrium asserts that some evolutionary changes may not even involve intermediate forms.

What is punctuated equilibrium?

The idea of punctuated equilibrium is a theory in evolutionary biology that proposes that most evolutionary changes occur relatively rapidly, with long periods of stability punctuated by rare instances of rapid evolutionary change.

The theory was first introduced by Niles Eldredge and Stephen Jay Gould in 1972 as a challenge to the traditional Darwinian theory of gradualism, which posits that evolution proceeds slowly and steadily over long periods of time.

According to punctuated equilibrium, some evolutionary changes may not even involve intermediate forms.

There are several examples of punctuated equilibrium in the fossil record, including the Cambrian explosion, which saw the sudden appearance of most major animal phyla in a relatively short period of time, and the rapid diversification of mammals following the extinction of the dinosaurs at the end of the Cretaceous period.

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What is [Al(H2O)5(OH) 2+] in a 0. 15 M solution of Al(NO3)3 that contains enough of the strong acid HNO3 to bring [H3O +] to 0. 10 M?

Answers

Al(NO3)3 solution concentration and the concentration of H3O+ ions in the solution following the addition of HNO3 are given in the problem. We can determine the presence of [Al(H2O)5(OH)2+] in the solution using this knowledge along with the known equilibria for the hydrolysis of Al3+.

For Al3+, the hydrolysis process may be expressed as follows:

Al(H2O)63+ + water becomes Al(H2O)5(OH)2+ + H3O+.

The reaction's equilibrium constant expression is as follows:

Al(H2O)5(OH)2+) = K

Al(H2O)63+ / [H3O+]

We must take into account the dissociation of Al(NO3)3 in water in order to determine [Al(H2O)5(OH)2+] in a 0.15 M solution of Al(NO3)3:

Al3+ (aq) + 3NO3- Al(NO3)3 (s) (aq)

Al3+ has a concentration of 0.45 M (3 times that of the Al(NO3)3 solution) in an Al(NO3)3 solution with a concentration of 0.15 M. H3O+ is present in the solution at a concentration of 0.10 M.

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If 110 grams of potassium chloride are mixed with 100 grams of water at 20°C, how much will not dissolve?

Answers

76 grams of potassium chloride will not dissolve in 100 grams of water at 20°C.

What is the solubility of the potassium chloride?

The solubility of potassium chloride in water at 20°C is approximately 34 grams per 100 grams of water.

So, if 100 grams of water can dissolve 34 grams of potassium chloride, then the maximum amount of potassium chloride that can be dissolved in 100 grams of water at 20°C is 34 grams.

Therefore, the amount of potassium chloride that will not dissolve in 100 grams of water at 20°C is:

110 grams - 34 grams = 76 grams

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A student is designing a new insulated drink cup using unconventional materials. They will have an inside and an outside cup with a material from the table in between the cups as insulation.Which material should they use to prevent heat loss?

Answers

The best material for insulation in this case would be Styrofoam. Styrofoam is lightweight, strong, and an excellent thermal insulator. It is composed of tiny bubbles of air that are suspended in a matrix of plastic. The air trapped inside the bubbles acts as a thermal barrier, keeping heat out or in, depending on the application.

Its lightweight nature makes it easier to manipulate, while its strength gives it the durability needed to keep a drink hot or cold. Its insulation properties also make it the perfect material for the student's insulated drink cup.

Styrofoam can be cut and shaped easily, making it a great material for use in drink cups. The material is also easy to clean and resistant to water and other liquids, which makes it ideal for frequent use. Additionally, Styrofoam is both affordable and widely available, making it an ideal choice for the student's project.

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A hard-working human brain, perhaps one that is grappling with physical chemistry, operates at about 25 W (1 W = 1J s-'). What mass of glucose must be consumed to sustain that power output for an hour?

Answers

Approximately 5.78 grams of glucose must be consumed to sustain a power output of 25 W for one hour.

Power = Energy/Time

25 W = Energy/3600 s

Energy = 25 W x 3600 s = 90000 J

C6H12O6 + 6O2 → 6CO2 + 6H2O + energy

The energy produced by the complete oxidation of glucose is approximately 2.8 x 10^6 J/mol. Therefore, to produce 90,000 J of energy, we need to divide 90,000 J by the energy produced per mole of glucose:

90,000 J / (2.8 x 10^6 J/mol) = 0.0321 mol

The molar mass of glucose is approximately 180 g/mol. Therefore, the mass of glucose required to sustain a power output of 25 W for one hour is:

0.0321 mol x 180 g/mol = 5.78 g

Power in physics is defined as the rate at which work is done or energy is transferred. It is a scalar quantity that measures how quickly a certain amount of energy is being transferred or converted from one form to another. The standard unit for power is the watt (W), which is equivalent to one joule per second (J/s).

In more mathematical terms, power is given by the formula P = W/t, where P represents power, W represents work, and t represents time. Power is also related to force and velocity through the equation P = Fv, where F represents force and v represents the velocity.

Power is an important concept in physics and engineering, as it is used to describe the performance of machines, engines, and other energy conversion systems. The greater the power of a system, the more work it can do in a given amount of time, and the faster it can accomplish a task.

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Which of the following molecules would have the highest boiling point?
a) hexane
b) octane
c) 2-propylpentane
d) 2-methylhexane

Answers

The molecule which would have the highest boiling point is 2-methylhexane. Thus, the correct option will be D.

What is boiling point?

The boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure. The boiling point of a liquid is a measure of its vapor pressure. The higher the boiling point, the higher the vapor pressure of the liquid, and the more heat is required to vaporize it.

The boiling point of a substance is affected by the strength and types of intermolecular forces. The stronger the intermolecular forces, the higher the boiling point. 2-methylhexane has highest boiling point because it has the highest number of carbons and branches, which contribute to its strong intermolecular forces that lead to a higher boiling point.

Therefore, the correct option is D.

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Whats the difference between zinc amino acid chelate with any other type of zincs?​

Answers

Answer:

chelated zinc is more easily absorbed than zinc on it's own.

Does electronegativity increase as atomic radius increases?

Answers

Actually, when atomic radius grows, electronegativity often decreases.

The capacity of an atom to draw electrons into a chemical connection is known as electronegativity. The separation between the nucleus and the farthest electrons grows with increasing atomic radius. As a result, the nucleus's attraction to the electrons is reduced, making it more challenging for the atom to draw electrons to itself. The electronegativity values of bigger atoms are therefore often lower than those of smaller ones. Despite this general tendency, there are certain outliers since electronegativity also depends on other elements including nuclear charge and electron configuration. For instance, the rising nuclear charge in halogens causes the electronegativity to rise as the atomic radius falls.

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knowing that solid sodium acetate is soluble and that acetic acid dissociates into hydrogen ions and acetate ions, why will sodium acetate influence the equilibrium of acetic acid dissociation?

Answers

As sodium acetate is added to the solution, the sodium ions (Na+) will replace the hydrogen ions (H+) in the equation. This causes a shift in the equilibrium as the number of hydrogen ions (H+) decreases, while the number of acetate ions (CH3COO-) increases.

Sodium acetate is an ionic compound composed of Na⁺ and CH₃COO⁻ ions.

It dissociates in water to create these ions, which are then available to affect the dissociation of acetic acid.

The equilibrium of acetic acid dissociation is influenced by the addition of sodium acetate.

Acid dissociation equilibria are influenced by salt addition (usually sodium salts), particularly when the acid is weak.

This is due to the fact that the anion of the salt reacts with hydrogen ions from the acid's dissociation.

This decreases the concentration of hydrogen ions in the solution, causing the reaction to shift towards more dissociation.

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which scientist conducted the gold foil experiment and discovered that the atom has a positively charged nucleus?

Answers

Ernest Rutherford, a New Zealand physicist, conducted the gold foil experiment and discovered that the atom has a positively charged nucleus.

In 1911, he conducted an experiment in which he fired alpha particles at a thin sheet of gold foil. The majority of the particles went straight through the gold foil, but a small percentage of the particles bounced back. He discovered that the bouncing back was caused by a small, positively charged nucleus at the center of the atom. Rutherford's experiment was crucial to our understanding of the structure of the atom. Prior to his experiment, the prevailing model of the atom was that it was a solid, indivisible sphere.

However, Rutherford's experiment showed that the atom was mostly empty space, with a positively charged nucleus at its center. This discovery paved the way for future research into atomic structure and helped to lay the foundation for the development of nuclear physics.

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what is the function of the electron transport chain in cellular respiration ?

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The electron transport chain (ETC) is an essential part of cellular respiration, which is a series of molecules that transfer electrons from one molecule to another used by cells to convert nutrients into energy.

This starts with the oxidation of molecules such as glucose, which releases electrons that are then transferred to a series of electron carriers in the ETC. The electron carriers are molecules that hold the electrons and can transfer them to other molecules which is known as redox reactions. As the electrons move through the ETC, they release energy which is used to form a proton gradient that is then used to drive the synthesis of ATP, the energy currency of the cell. The ETC is an essential part of cellular respiration as it is the process responsible for generating the energy necessary for cells to function.

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ion channels that open and close in response to a change in membrane potential are called _____.

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Ion channels that open and close in response to a change in membrane potential are called voltage-gated ion channels.

What is Voltage-gated ion channels?

Voltage-gated ion channels are a specialized type of membrane protein that are embedded in the lipid bilayer of excitable cells. They have a pore that allows ions to flow through, and they can be selective for different types of ions, such as sodium (Na+), potassium (K+), or calcium (Ca2+).

The opening and closing of the channel's pore is controlled by changes in the membrane potential, which is the difference in electrical charge across the cell membrane.

These channels are crucial for the generation and propagation of electrical signals in excitable cells, such as neurons and muscle cells. Voltage-gated ion channels are capable of detecting small changes in membrane potential and responding by opening or closing their pore, allowing ions to flow across the membrane and alter the electrical state of the cell.

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The Chernobyl nuclear disaster led to the release of massive radiation, specifically iodine-131 and cesium-137, which has been connected to a variety of environmental problems in the 30 years following the disaster. A meltdown in which of the following structures at a nuclear power plant, such as Chernobyl, would most likely lead to the accidental release of radiation?
Cooling tower
Turbine
Generator
Reactor core
Reactor core

Answers

Answer:

The meltdown in which of the following structures at a nuclear power plant, such as Chernobyl, would most likely lead to the accidental release of radiation is reactor core. Answer:e

Explanation:

What is the Chernobyl nuclear disaster?

The Chernobyl nuclear disaster was a catastrophic nuclear accident that occurred on April 26, 1986, at the No. 4 reactor in the Chernobyl Nuclear Power Plant, located in the northern Ukrainian Soviet Socialist Republic.

The explosion and subsequent fires resulted in the release of significant amounts of radioactive material into the atmosphere, as well as widespread contamination of the environment.

What was the cause of the Chernobyl nuclear disaster?

During a reactor systems test, an unforeseen combination of factors caused the core of one of Chernobyl's reactors to overheat and explode, releasing radioactive material into the surrounding area. The resulting steam explosion and fires killed two plant workers at the time of the accident and injured hundreds of others.

The explosion also resulted in the deaths of dozens of firefighters and other emergency workers in the aftermath of the disaster.

What was the impact of the Chernobyl nuclear disaster on the environment?

The Chernobyl nuclear disaster resulted in the release of significant quantities of radioactive material, including iodine-131 and cesium-137, which have been linked to a variety of environmental issues. These substances are still present in the environment, and their long-term effects on humans and wildlife are still being investigated.

However, the disaster has had a significant impact on the environment in the years following the accident, including the contamination of water and soil, the displacement of wildlife, and the potential long-term health effects on local populations.

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g the half life of 2n-71 is 2.4 minutes. if we started with 50g at the beginning, how many grams would be left after 12 minutes?

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After 12 minutes, the amount of 2N-71 remaining would be 25 grams. This is because the half-life of 2N-71 is 2.4 minutes, meaning that after 2.4 minutes, half of the initial amount (50 grams) will remain. After 12 minutes, half of the remaining 25 grams will have decayed, leaving 25 grams.


The initial amount of 2n-71 is 50 g, and the half-life of 2n-71 is 2.4 minutes. We need to determine how many grams of 2n-71 would be left after 12 minutes. During radioactive decay, the amount of a radioactive substance decreases exponentially over time. The formula for determining the amount remaining of a radioactive substance after time t is:A = A₀(1/2)^(t/h)Where, A₀ = the initial amount of the substance,A = the amount of the substance after time t,h = the half-life of the substance, and t = time elapsedPlugging the given values in the formula, we get:A = 50(1/2)^(12/2.4)A = 50(1/2)^5A = 50(1/32)A = 1.5625Therefore, the amount of 2n-71 left after 12 minutes is 1.5625 g.

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